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Non-vanishing of central values of angular Hecke LL-functions

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Abstract

In this paper, we evaluate asymptotically the first and second moment of central values of the family of Hecke LL-functions associated to angular characters over imaginary quadratic number fields of class number one. We use our results to deduce a non-vanishing result concerning these LL-functions.

Mathematics Subject Classification (2010): 11M06, 11M41

Introduction

Let K=Q(d)K = \mathbb{Q}(\sqrt{d}) be an imaginary quadratic number field of class number one. Here dd is a negative, square-free integer and it is well-known that (see [3, (22.77)]) the class number of KK is one if and only if

d∈{−1,−2,−3,−7,−11,−19,−43,−67,−163}.(1)d \in\{-1,-2,-3,-7,-11,-19,-43,-67,-163\}. \tag*{(1)}

We denote OK\mathcal{O}_K, UKU_K, DKD_K the ring of integers, the group of units and the discriminant of KK, respectively. Note that (see [2, Section 2.1]) the order ∣UK∣\lvert U_K\rvert of UKU_K equals 4 when d=−1d=-1, equals 6 when d=−3d=-3 and equals 2 for other values of dd listed in (1.1). Throughout the paper, we denote MKM_K the integer such that 2MK=∣UK∣2M_K=\lvert U_K\rvert.

Denote a\mathfrak{a} an integral ideal of OK\mathcal{O}_K. As OK\mathcal{O}_K is a principal ideal domain, the generators of a=(α)⊆OK\mathfrak{a}=(\alpha)\subseteq\mathcal{O}_K differ by multiplication of an element in UKU_K. In what follows we shall therefore fix a generator α\alpha of (α)(\alpha) such that θa:=θα\theta_{\mathfrak{a}}:=\theta_\alpha lies in [−π/∣UK∣,π/∣UK∣)[-\pi/\lvert U_K\rvert,\pi/\lvert U_K\rvert), where θα\theta_\alpha denotes the argument of α\alpha.

For any l∈Zl\in\mathbb{Z}, we define the Hecke character

λMKl(a)=(αα‾)MKl=e2iMKlθa.\lambda_{M_Kl}(\mathfrak{a})=\left(\frac{\alpha}{\overline{\alpha}}\right)^{M_Kl}=e^{2iM_Kl\theta_{\mathfrak{a}}}.

Note that as λMKl\lambda_{M_Kl} is trivial on UKU_K, it defines a Hecke character of trivial infinite type. We write the associated Hecke LL-function as

L(s,λMKl)=∑a⊆OKa≠0λMKl(a)N(a)s=∏(ϖ)(1−λMKl(ϖ)N(ϖ)s)−1,ℜ(s)>1,L(s,\lambda_{M_Kl})=\sum_{\substack{\mathfrak{a}\subseteq\mathcal{O}_K\\ \mathfrak{a}\ne0}}\frac{\lambda_{M_Kl}(\mathfrak{a})}{N(\mathfrak{a})^s}=\prod_{(\varpi)}\left(1-\frac{\lambda_{M_Kl}(\varpi)}{N(\varpi)^s}\right)^{-1},\qquad\Re(s)>1,

where N(a)N(\mathfrak{a}) denotes the norm of the integral ideal a\mathfrak{a}, and we reserve the letter ϖ\varpi for a prime in OK\mathcal{O}_K throughout the paper, by which we mean that the ideal (ϖ)(\varpi) generated by it is a prime ideal.

Let X>1X>1 be a large real number, interesting properties concerning the family of Hecke LL-functions {L(s,λMKl):1≤l≤X}\{L(s,\lambda_{M_Kl}):1\le l\le X\} have been investigated in [8], [2] for its one-level density, in [9] for its extreme values.

Under the generalized Riemann hypothesis, the one-level density results established in [8], [2] (see [8, Corollary 1.3]) imply that at least 75% of the members of the family of angular Hecke LL-functions do not vanish at the central point.

It is the aim of this paper to establish a non-vanishing result unconditionally for these families of LL-functions by evaluating their first and second moments at the central point.

Our first result evaluates asymptotically the first moment as follows.

Theorem 1.1. With the notation as above. Let KK be any imaginary quadratic number field of class number one. Let MKM_K be the integer such that 2MK=∣UK∣2M_K=\lvert U_K\rvert, we have for large X>1X>1,

∑X<l≤2XL(12,λMKl)=Xlog⁡X+(log⁡(4MK))X+O(X1/2log⁡X).(2)\sum_{X<l\le2X}L\left(\frac{1}{2},\lambda_{M_Kl}\right)=X\log X+(\log(4M_K))X+O(X^{1/2}\log X). \tag*{(2)}

Our next result evaluates asymptotically the second moment.

Theorem 1.2. With the notation as above. Let KK be any imaginary quadratic number field of class number one. Let MKM_K be the integer such that 2MK=∣UK∣2M_K = |U_K|, we have for large X>1X > 1,

∑X<l≤2X∣L(12,λMKl)∣2=CKX(log⁡X)3+O(X(log⁡X)2),(3)\sum_{X<l\leq2X}\left|L\left(\frac{1}{2},\lambda_{M_Kl}\right)\right|^2=C_KX(\log X)^3+O\left(X(\log X)^2\right), \tag*{(3)}

where CKC_K is a constant depending on KK only.

It follows from Theorems 1.1–1.2 and the standard arguments using Cauchy-Schwarz inequality that we have the following non-vanishing result concerning the family of angular Hecke LL-functions.

Theorem 1.3. With the notation as above. Let KK be any imaginary quadratic number field of class number one and let MKM_K be the integer such that 2MK=∣UK∣2M_K=|U_K|. There exist infinitely many angular Hecke characters λMKl\lambda_{M_Kl} such that L(1/2,λMKl)L(1/2,\lambda_{M_Kl}) is non-zero. More precisely, the number of such characters with X<l≤2XX<l\leq2X is ≫X/log⁡X\gg X/\log X for any large XX.

Preliminaries

Angular Hecke characters

It is shown in [8 Section 2] that for l≠0l\neq0, the complete Hecke LL-function

Λl(s)=∣DK∣s/2(2π)−sΓ(s+∣MKl∣)L(s,λMKl)(4)\Lambda_l(s)=|D_K|^{s/2}(2\pi)^{-s}\Gamma(s+|M_Kl|)L(s,\lambda_{M_Kl}) \tag*{(4)}

is entire and have an analytic continuation to the whole complex plane that satisfies the functional equation

Λl(s)=Λl(1−s).(5)\Lambda_l(s)=\Lambda_l(1-s). \tag*{(5)}

The above allows us to establish the following approximate functional equation for L(1/2,λMKl)L(1/2,\lambda_{M_Kl}).

Lemma 2.2. With the notation as above. We have for any l≠0l\neq0,

L(12,λMKl)=2∑a⊆OKa≠(0)λMKl(a)N(a)1/2V∣MKl∣(2πN(a)∣DK∣),(6)L\left(\frac{1}{2},\lambda_{M_Kl}\right)=2\sum_{\substack{\mathfrak a\subseteq\mathcal O_K\\\mathfrak a\neq(0)}}\frac{\lambda_{M_Kl}(\mathfrak a)}{N(\mathfrak a)^{1/2}}V_{|M_Kl|}\left(\frac{2\pi N(\mathfrak a)}{\sqrt{|D_K|}}\right), \tag*{(6)}

where

Vx(y)=12πi∫(3)Γ(12+x+s)Γ(12+x)y−ses2dss.(7)V_x(y)=\frac{1}{2\pi i}\int_{(3)}\frac{\Gamma\left(\frac{1}{2}+x+s\right)}{\Gamma\left(\frac{1}{2}+x\right)}y^{-s}e^{s^2}\frac{ds}{s}. \tag*{(7)}

Proof. We apply [3 Theorem 5.3] by setting G(s)=es2G(s)=e^{s^2} there and use (4) and (5) to see that we have

L(12,λMKl)=∑a⊆OKa≠(0)λMKl(a)+λMKl(a)‾N(a)1/2V∣MKl∣(N(a)),L\left(\frac{1}{2},\lambda_{M_Kl}\right)=\sum_{\substack{\mathfrak a\subseteq\mathcal O_K\\\mathfrak a\neq(0)}}\frac{\lambda_{M_Kl}(\mathfrak a)+\overline{\lambda_{M_Kl}(\mathfrak a)}}{N(\mathfrak a)^{1/2}}V_{|M_Kl|}(N(\mathfrak a)),

where V∣MKl∣V_{|M_Kl|} is given in (7). We now set N(a)=nN(\mathfrak a)=n to see that we may recast the above as

L(12,λMKl)=∑n≥1AMKl(n)+AMKl(n)‾n1/2V∣MKl∣(n),L\left(\frac{1}{2},\lambda_{M_Kl}\right)=\sum_{n\geq1}\frac{A_{M_Kl}(n)+\overline{A_{M_Kl}(n)}}{n^{1/2}}V_{|M_Kl|}(n),

where

AMKl(n)=∑N(a)=nλMKl(a).A_{M_Kl}(n)=\sum_{N(\mathfrak a)=n}\lambda_{M_Kl}(\mathfrak a).

Note that it is shown in [2 p. 251] that we have AMKl(n)‾=AMKl(n)\overline{A_{M_Kl}(n)}=A_{M_Kl}(n) for all AMKl(n)A_{M_Kl}(n). It follows that

L(12,λMKl)=2∑n≥1AMKl(n)n1/2V∣MKl∣(n).(8)L\left(\frac{1}{2},\lambda_{M_Kl}\right)=2\sum_{n\geq1}\frac{A_{M_Kl}(n)}{n^{1/2}}V_{|M_Kl|}(n). \tag*{(8)}

We reverse the above process to see that the relation given in (6) is valid. This completes the proof of the lemma. □

We note that similar to [7 Lemma 2.1], one shows that the function V∣MKl∣(x)V_{|M_Kl|}(x) is real-valued for any real x>0x>0. We deduce from this and (8) by recalling that AMKl(n)‾=AMKl(n)\overline{A_{M_Kl}(n)}=A_{M_Kl}(n) there to see that we have L(1/2,λMKl)∈RL(1/2,\lambda_{M_Kl})\in\mathbb{R}. It follows from this that we have

∣L(12,λMKl)∣2=L(12,λMKl)2.(9)\left|L\left(\frac{1}{2},\lambda_{M_Kl}\right)\right|^2=L\left(\frac{1}{2},\lambda_{M_Kl}\right)^2. \tag*{(9)}

Our next result establishes the approximate functional equation for ∣L(12,λMKl)∣2\left|L\left(\frac{1}{2},\lambda_{M_Kl}\right)\right|^2.

Lemma 2.3. With the notation as above. We have for any l≠0l \ne0,

∣L(12,λMKl)∣2=2∑n⊆OKn≠(0)τK(n)λMKl(n)N(n)1/2W∣MKl∣((2π)2N(n)∣DK∣),(10)\left|L\left(\frac{1}{2},\lambda_{M_Kl}\right)\right|^2 =2\sum_{\substack{\mathfrak{n}\subseteq\mathcal{O}_K\\\mathfrak{n}\ne(0)}} \frac{\tau_K(\mathfrak{n})\lambda_{M_Kl}(\mathfrak{n})}{N(\mathfrak{n})^{1/2}} W_{\lvert M_Kl\rvert}\left(\frac{(2\pi)^2N(\mathfrak{n})}{\lvert D_K\rvert}\right), \tag*{(10)}

where

τK(n):=∑a⊆OKa∣n1.\tau_K(\mathfrak{n}) := \sum_{\substack{\mathfrak{a}\subseteq\mathcal{O}_K\\\mathfrak{a}\mid\mathfrak{n}}}1.

and where

Wx(y)=12πi∫(3)Γ(12+x+s)2Γ(12+x)2y−ses2dss.(11)W_x(y)=\frac{1}{2\pi i}\int_{(3)} \frac{\Gamma\left(\frac{1}{2}+x+s\right)^2}{\Gamma\left(\frac{1}{2}+x\right)^2} y^{-s}e^{s^2}\frac{ds}{s}. \tag*{(11)}

Proof. Consider the integral

I=12πi∫(3)ΛMKl2(12+s)es2dss.I=\frac{1}{2\pi i}\int_{(3)}\Lambda_{M_Kl}^2\left(\frac{1}{2}+s\right)e^{s^2}\frac{ds}{s}.

Then by Cauchy’s theorem, we have

ΛMKl2(12)=2I.(12)\Lambda_{M_Kl}^2\left(\frac{1}{2}\right)=2I. \tag*{(12)}

Note that by (4) and (9),

ΛMKl2(12)=∣DK∣1/2Γ(12+∣MKl∣)22π∣L(12,λMKl)∣2.(13)\Lambda_{M_Kl}^2\left(\frac{1}{2}\right) =\frac{\lvert D_K\rvert^{1/2}\Gamma\left(\frac{1}{2}+\lvert M_Kl\rvert\right)^2}{2\pi} \left|L\left(\frac{1}{2},\lambda_{M_Kl}\right)\right|^2. \tag*{(13)}

On the other hand, we may expand ΛMKl2(12+s)\Lambda_{M_Kl}^2\left(\frac{1}{2}+s\right) into Dirichlet series and grouping the ideals according to n=N(a)N(b)\mathfrak{n}=N(\mathfrak{a})N(\mathfrak{b}) to evaluate II. We deduce from this and (12)–(13) that the expression given in (10) is valid. This completes the proof of the lemma. □

Proof of Theorem 1.1

We apply Lemma 2.2 and (7) to see that

∑X<l≤2XL(12,λMKl)=2∑X<l≤2X∑a⊆OKa≠(0)λMKl(a)N(a)1/2VMKl(2πN(a)∣DK∣)=:S+R1+R2,(14)\sum_{X<l\le2X}L\left(\frac{1}{2},\lambda_{M_Kl}\right) =2\sum_{X<l\le2X}\sum_{\substack{\mathfrak{a}\subseteq\mathcal{O}_K\\\mathfrak{a}\ne(0)}} \frac{\lambda_{M_Kl}(\mathfrak{a})}{N(\mathfrak{a})^{1/2}} V_{M_Kl}\left(\frac{2\pi N(\mathfrak{a})}{\sqrt{\lvert D_K\rvert}}\right) =:S+R_1+R_2, \tag*{(14)}

where

S=2∑X<l≤2X∑a⊆OKa=(n)n∈NλMKl(a)N(a)1/2VMKl(2πN(a)∣DK∣),S=2\sum_{X<l\le2X}\sum_{\substack{\mathfrak{a}\subseteq\mathcal{O}_K\\\mathfrak{a}=(n)\\n\in\mathbb{N}}} \frac{\lambda_{M_Kl}(\mathfrak{a})}{N(\mathfrak{a})^{1/2}} V_{M_Kl}\left(\frac{2\pi N(\mathfrak{a})}{\sqrt{\lvert D_K\rvert}}\right),
R1=2∑X<l≤2X∑a⊆OK, N(a)≤Xa≠(0)a≠(n), n∈NλMKl(a)N(a)1/2VMKl(2πN(a)∣DK∣),R_1=2\sum_{X<l\le2X}\sum_{\substack{\mathfrak{a}\subseteq\mathcal{O}_K,\ N(\mathfrak{a})\le X\\\mathfrak{a}\ne(0)\\\mathfrak{a}\ne(n),\ n\in\mathbb{N}}} \frac{\lambda_{M_Kl}(\mathfrak{a})}{N(\mathfrak{a})^{1/2}} V_{M_Kl}\left(\frac{2\pi N(\mathfrak{a})}{\sqrt{\lvert D_K\rvert}}\right),
R2=2∑X<l≤2X∑a⊆OK, N(a)>Xa≠(0)a≠(n), n∈NλMKl(a)N(a)1/2VMKl(2πN(a)∣DK∣).R_2=2\sum_{X<l\le2X}\sum_{\substack{\mathfrak{a}\subseteq\mathcal{O}_K,\ N(\mathfrak{a})>X\\\mathfrak{a}\ne(0)\\\mathfrak{a}\ne(n),\ n\in\mathbb{N}}} \frac{\lambda_{M_Kl}(\mathfrak{a})}{N(\mathfrak{a})^{1/2}} V_{M_Kl}\left(\frac{2\pi N(\mathfrak{a})}{\sqrt{\lvert D_K\rvert}}\right).

Note that when a=(n)\mathfrak{a}=(n) with n∈Nn\in\mathbb{N}, we have λMKl(a)=1\lambda_{M_Kl}(\mathfrak{a})=1 for all X<l≤2XX<l\le2X. It follows that we have

S=2∑X<l≤2X∑n∈N1nVMKl(2πn2∣DK∣)=∑X<l≤2X22πi∫(3)Γ(12+MKl+s)Γ(12+MKl)(2π∣DK∣)es2ζ(1+2s)dss,S=2\sum_{X<l\le2X}\sum_{n\in\mathbb{N}}\frac{1}{n}V_{M_Kl}\left(\frac{2\pi n^2}{\sqrt{\lvert D_K\rvert}}\right) =\sum_{X<l\le2X}\frac{2}{2\pi i}\int_{(3)} \frac{\Gamma\left(\frac{1}{2}+M_Kl+s\right)}{\Gamma\left(\frac{1}{2}+M_Kl\right)} \left(\frac{2\pi}{\sqrt{\lvert D_K\rvert}}\right)e^{s^2}\zeta(1+2s)\frac{ds}{s},

where ζ(s)\zeta(s) is the Riemann zeta function. We now shift the line of integration above to ℜ(s)=−1\Re(s)=-1. As ζ(s)\zeta(s) has a simple pole at s=1s=1 with the corresponding residue being 11, we see that we encounter a double pole at s=0s=0 in the process, whose residue can be easily computed to be

Γ′(12+MKl)2Γ(12+MKl)+O(1),\frac{\Gamma'\left(\frac{1}{2}+M_Kl\right)}{2\Gamma\left(\frac{1}{2}+M_Kl\right)}+O(1),

where the implied constant depends on KK only. It follows that

S=∑X<l≤2XΓ′(12+MKl)Γ(12+MKl)+O(1)+S1.(15)S=\sum_{X<l\leq2X}\frac{\Gamma'\left(\frac{1}{2}+M_Kl\right)}{\Gamma\left(\frac{1}{2}+M_Kl\right)}+O(1)+S_1. \tag*{(15)}

where

S1=∑X<l≤2X22πi∫(−1)Γ(12+MKl+s)Γ(12+MKl)(2π∣DK∣)−ses2ζ(1+2s)dss.S_1=\sum_{X<l\leq2X}\frac{2}{2\pi i}\int_{(-1)}\frac{\Gamma\left(\frac{1}{2}+M_Kl+s\right)}{\Gamma\left(\frac{1}{2}+M_Kl\right)}\left(\frac{2\pi}{\sqrt{|D_K|}}\right)^{-s}e^{s^2}\zeta(1+2s)\frac{ds}{s}.

Note that by Stirling’s formula (see [3 (5.112)]), we have

log⁡Γ(s)=12log⁡(2π)+(s−12)log⁡s−s+O(1∣s∣).\log\Gamma(s)=\frac{1}{2}\log(2\pi)+\left(s-\frac{1}{2}\right)\log s-s+O\left(\frac{1}{|s|}\right).

It follows from this that for ∣σ∣≤10|\sigma|\leq10 and X<u≤2XX<u\leq2X, we have

log⁡Γ(12+MKu+σ)−log⁡Γ(12+MKu)=(MKu+σ)log⁡(12+MKu+σ)−MKulog⁡(12+MKu)−σ+O(1X)=(MKu+σ)log⁡(12+MKu)−MKulog⁡(12+MKu)+O(1)=σlog⁡(12+MKu)+O(1).\begin{aligned} \log\Gamma\left(\frac{1}{2}+M_Ku+\sigma\right)-\log\Gamma\left(\frac{1}{2}+M_Ku\right) &=(M_Ku+\sigma)\log\left(\frac{1}{2}+M_Ku+\sigma\right)-M_Ku\log\left(\frac{1}{2}+M_Ku\right)-\sigma+O\left(\frac{1}{X}\right)\\ &=(M_Ku+\sigma)\log\left(\frac{1}{2}+M_Ku\right)-M_Ku\log\left(\frac{1}{2}+M_Ku\right)+O(1)\\ &=\sigma\log\left(\frac{1}{2}+M_Ku\right)+O(1). \end{aligned}

The above implies that if ∣σ∣≤10|\sigma|\leq10 and X<u≤2XX<u\leq2X, we have

Γ(12+MKu+σ)Γ(12+MKu)≪(12+MKu)σ≪Xσ.(16)\frac{\Gamma\left(\frac{1}{2}+M_Ku+\sigma\right)}{\Gamma\left(\frac{1}{2}+M_Ku\right)}\ll\left(\frac{1}{2}+M_Ku\right)^\sigma\ll X^\sigma. \tag*{(16)}

Note also that we have for x≥1x\geq1, y∈Ry\in\mathbb{R},

∣Γ(x+iy)∣≤Γ(x).(17)|\Gamma(x+iy)|\leq\Gamma(x). \tag*{(17)}

We apply (16) and (17) to see that

∣Γ(−12+MKl+it)∣Γ(12+MKl)≪Γ(−12+MKl)Γ(12+MKl)≪1−12+MKl.\frac{\left|\Gamma\left(-\frac{1}{2}+M_Kl+it\right)\right|}{\Gamma\left(\frac{1}{2}+M_Kl\right)} \ll\frac{\Gamma\left(-\frac{1}{2}+M_Kl\right)}{\Gamma\left(\frac{1}{2}+M_Kl\right)} \ll\frac{1}{-\frac{1}{2}+M_Kl}.

It follows that

S1≪∣∫(−1)es2ζ(1+2s)dss∣≪∣∫(−1)es2ζ(−2s)Γ(−2s)Γ(1+2s)dss∣.(18)S_1\ll\left|\int_{(-1)}e^{s^2}\zeta(1+2s)\frac{ds}{s}\right|\ll\left|\int_{(-1)}e^{s^2}\zeta(-2s)\frac{\Gamma(-2s)}{\Gamma(1+2s)}\frac{ds}{s}\right|. \tag*{(18)}

where the last estimation above follows from the well-known functional equation (see [6 Corollary 10.3]) for ζ(s)\zeta(s) that

ζ(s)Γ(s)π−s/2=ζ(1−s)Γ(1−s)π−(1−s)/2.\zeta(s)\Gamma(s)\pi^{-s/2}=\zeta(1-s)\Gamma(1-s)\pi^{-(1-s)/2}.

Stirling’s formula (see [3 (5.113)]) yields

Γ(−2s)Γ(1+2s)≪(1+∣s∣)−4ℜ(s)−1.\frac{\Gamma(-2s)}{\Gamma(1+2s)}\ll(1+|s|)^{-4\Re(s)-1}.

We deduce from this and (18) that

S1≪1.S_1\ll1.

We apply the above into (15) to see that

S=∑X<l≤2XΓ′(12+MKl)Γ(12+MKl)+O(1).(19)S=\sum_{X<l\leq2X}\frac{\Gamma'\left(\frac{1}{2}+M_Kl\right)}{\Gamma\left(\frac{1}{2}+M_Kl\right)}+O(1). \tag*{(19)}

We further note from [6 (C.17)] that we have

Γ′(12+MKl)Γ(12+MKl)=log⁡(12+MKl)+O(11/2+MKl)=log⁡(MKl)+O(1).\frac{\Gamma'\left(\frac{1}{2}+M_Kl\right)}{\Gamma\left(\frac{1}{2}+M_Kl\right)} =\log\left(\frac{1}{2}+M_Kl\right)+O\left(\frac{1}{1/2+M_Kl}\right) =\log(M_Kl)+O(1).

It follows from this and (19) that we have by partial summation,

S=∑X<l≤2Xlog⁡(MKl)+O(1)=Xlog⁡X+(log⁡(4MK))X+O(log⁡X).(20)S=\sum_{X<l\leq2X}\log(M_Kl)+O(1)=X\log X+(\log(4M_K))X+O(\log X). \tag*{(20)}

Next, we estimate R1R_1 and R2R_2 by keeping the line of integration in VMKlV_{M_Kl} to be at ℜ(s)=3\Re(s)=3 for R2R_2 while shifting the line of integration to ℜ(s)=−1\Re(s)=-1 for R1R_1. In this process we encounter a simple pole with residue 11 at s=0s=0, whose contribution to R1R_1 is denoted by R1,1R_{1,1}. We denote R1,2R_{1,2} the contribution to R1R_1 on the new line of integration, so that we have

R1=R1,1+R1,2,(21)R_1=R_{1,1}+R_{1,2}, \tag*{(21)}

where

R1,1=2∑X<l≤2X∑a⊂OK, N(a)≤Xa≠(0)a≠(n),n∈NλMKl(a)N(a)1/2,R_{1,1}=2\sum_{X<l\leq2X}\sum_{\substack{\mathfrak{a}\subset\mathcal{O}_K,\ N(\mathfrak{a})\leq X\\ \mathfrak{a}\ne(0)\\ \mathfrak{a}\ne(n),\,n\in\mathbb{N}}}\frac{\lambda_{M_Kl}(\mathfrak{a})}{N(\mathfrak{a})^{1/2}},
R1,2=2∑X<l≤2X∑a⊂OK, N(a)≤Xa≠(0)a≠(n),n∈NλMKl(a)N(a)1/2⋅12πi∫(−1)Γ(12+MKl+s)Γ(12+MKl)(2πN(a)∣DK∣)−sess ds.(22)R_{1,2}=2\sum_{X<l\leq2X}\sum_{\substack{\mathfrak{a}\subset\mathcal{O}_K,\ N(\mathfrak{a})\leq X\\ \mathfrak{a}\ne(0)\\ \mathfrak{a}\ne(n),\,n\in\mathbb{N}}}\frac{\lambda_{M_Kl}(\mathfrak{a})}{N(\mathfrak{a})^{1/2}}\cdot\frac{1}{2\pi i}\int_{(-1)}\frac{\Gamma\left(\frac{1}{2}+M_Kl+s\right)}{\Gamma\left(\frac{1}{2}+M_Kl\right)}\left(\frac{2\pi N(\mathfrak{a})}{\sqrt{|D_K|}}\right)^{-s}\frac{e^s}{s}\,ds. \tag*{(22)}

We note that when a≠(n)\mathfrak{a}\ne(n) with n∈Nn\in\mathbb{N}, we have θa∉πZ\theta_{\mathfrak{a}}\notin\pi\mathbb{Z}, so that similar to [8 (6.3)], we have for any real u≥1u\geq1,

∑1≤l≤uλMKl(a)≪1∣sin⁡(MKθa)∣.(23)\sum_{1\leq l\leq u}\lambda_{M_Kl}(\mathfrak{a})\ll\frac{1}{\left|\sin(M_K\theta_{\mathfrak{a}})\right|}. \tag*{(23)}

Now, our choice of θK∈[−π/∣UK∣,π/∣UK∣)\theta_K\in[-\pi/|U_K|,\pi/|U_K|) and the value of MK=∣UK∣/2M_K=|U_K|/2 ensures that we have MKθa∈[−π/2,π/2)M_K\theta_{\mathfrak{a}}\in[-\pi/2,\pi/2). It then follows from the well-known estimation 2x/π≤sin⁡x≤x2x/\pi\leq\sin x\leq x for 0<x≤π/20<x\leq\pi/2 that we have

1∣sin⁡(MKθa)∣≪1∣θa∣≪1∣sin⁡(θa)∣.(24)\frac{1}{|\sin(M_K\theta_{\mathfrak{a}})|}\ll\frac{1}{|\theta_{\mathfrak{a}}|}\ll\frac{1}{|\sin(\theta_{\mathfrak{a}})|}. \tag*{(24)}

Recall (see [4 Corollary 2, Chap. 2]) that the ring of integers OK\mathcal{O}_K is a free Z\mathbb{Z} module such that OK=Z+ωKZ\mathcal{O}_K=\mathbb{Z}+\omega_K\mathbb{Z}, where

ωK={12(1+d)if d≡1(mod4),dif d≡2,3(mod4).\omega_K= \begin{cases} \frac{1}{2}(1+\sqrt{d}) & \text{if }d\equiv1\pmod{4},\\ \sqrt{d} & \text{if }d\equiv2,3\pmod{4}. \end{cases}

We apply this to see that we may write any a≠(n)\mathfrak{a}\ne(n) with n∈Nn\in\mathbb{N} as a=(a+bωK)\mathfrak{a}=(a+b\omega_K) with a,b∈Za,b\in\mathbb{Z}, b≠0b\ne0. It follows from this that we have

∣sin⁡(θa)∣≫∣b∣N(a),|\sin(\theta_{\mathfrak{a}})|\gg\frac{|b|}{\sqrt{N(\mathfrak{a})}},

so that

1∣sin⁡(θa)∣≪N(a)∣b∣.(25)\frac{1}{|\sin(\theta_{\mathfrak{a}})|}\ll\frac{\sqrt{N(\mathfrak{a})}}{|b|}. \tag*{(25)}

We deduce from (23)-(25) that for any a=(a+bωK)\mathfrak{a}=(a+b\omega_K) with a,b∈Za,b\in\mathbb{Z}, b≠0b\ne0 and any X≤u≤2XX\leq u\leq2X,

∑X<l≤uλMKl(a)≪N(a)∣b∣.(26)\sum_{X<l\leq u}\lambda_{M_Kl}(\mathfrak{a})\ll\frac{\sqrt{N(\mathfrak{a})}}{|b|}. \tag*{(26)}

We note moreover that for any u≥5u\geq5,

∑a=(a+bωK),b≠0N(a)≤u1∣b∣≪∑1≤b≤u1b∑1≤a≤u1≪u1/2log⁡u.(27)\sum_{\substack{\mathfrak{a}=(a+b\omega_K),\,b\ne0\\N(\mathfrak{a})\leq u}}\frac{1}{|b|}\ll\sum_{1\leq b\leq\sqrt{u}}\frac{1}{b}\sum_{1\leq a\leq\sqrt{u}}1\ll u^{1/2}\log u. \tag*{(27)}

In particular, this together with (26) implies that

R1,1≪X1/2log⁡X.(28)R_{1,1}\ll X^{1/2}\log X. \tag*{(28)}

We further deduce from (26) and partial summation that when a=(a+bωK)\mathfrak{a}=(a+b\omega_K) with a,b∈Za,b\in\mathbb{Z}, b≠0b\ne0, we have

∑X<l≤2XλMKl(a)N(a)Γ(12+MKl+s)Γ(12+MKl)≪1∣b∣∣Γ(12+MKX+s)Γ(12+MKX)∣+1∣b∣∣Γ(12+2MKX+s)Γ(12+2MKX)∣+1∣b∣∫X2X∣h′(u)∣ du,(29)\sum_{X<l\leq2X}\frac{\lambda_{M_Kl}(\mathfrak{a})}{\sqrt{N(\mathfrak{a})}}\frac{\Gamma\left(\frac{1}{2}+M_Kl+s\right)}{\Gamma\left(\frac{1}{2}+M_Kl\right)} \ll\frac{1}{|b|}\left|\frac{\Gamma\left(\frac{1}{2}+M_KX+s\right)}{\Gamma\left(\frac{1}{2}+M_KX\right)}\right|+\frac{1}{|b|}\left|\frac{\Gamma\left(\frac{1}{2}+2M_KX+s\right)}{\Gamma\left(\frac{1}{2}+2M_KX\right)}\right|+\frac{1}{|b|}\int_X^{2X}|h'(u)|\,du, \tag*{(29)}

where we set

h(u):=Γ(12+MKu+s)Γ(12+MKu).h(u) := \frac{\Gamma\left(\frac{1}{2}+M_Ku+s\right)}{\Gamma\left(\frac{1}{2}+M_Ku\right)}.

We apply [9 Lemma 3] to see that when a=(a+bωK)\mathfrak{a}=(a+b\omega_K) with a,b∈Za,b\in\mathbb{Z}, b≠0b\ne0,

∣h′(u)∣≪∣h(u)∣⋅∣log⁡(1+sMKu)∣≪∣h(u)∣⋅log⁡(1+∣sMKu∣)≪∣h(u)∣⋅∣su∣,(30)\left|h'(u)\right|\ll|h(u)|\cdot\left|\log\left(1+\frac{s}{M_Ku}\right)\right|\ll|h(u)|\cdot\log\left(1+\left|\frac{s}{M_Ku}\right|\right)\ll|h(u)|\cdot\left|\frac{s}{u}\right|, \tag*{(30)}

where the last estimation above follows from the well-known bound that 1+x≤ex1+x\le e^x for any x∈Rx\in\mathbb{R}.

We substitute (30) into (29) to deduce that for a=(a+bωK)\mathfrak{a}=(a+b\omega_K) with a,b∈Za,b\in\mathbb{Z}, b≠0b\ne0,

∑X<l≤2XλMKl(a)N(a)Γ(12+MKl+s)Γ(12+MKl)≪∣sb∣max⁡X<u≤2X(∣Γ(12+MKu+s)Γ(12+MKu)∣).\sum_{X<l\le2X}\frac{\lambda_{M_Kl}(\mathfrak{a})}{\sqrt{N(\mathfrak{a})}}\frac{\Gamma\left(\frac{1}{2}+M_Kl+s\right)}{\Gamma\left(\frac{1}{2}+M_Kl\right)} \ll\left|\frac{s}{b}\right|\max_{X<u\le2X}\left(\left|\frac{\Gamma\left(\frac{1}{2}+M_Ku+s\right)}{\Gamma\left(\frac{1}{2}+M_Ku\right)}\right|\right).

Using the relation given in (17), we infer from the above that for a=(a+bωK)\mathfrak{a}=(a+b\omega_K) with a,b∈Za,b\in\mathbb{Z}, b≠0b\ne0,

∑X<l≤2XλMKl(a)N(a)Γ(12+MKl+s)Γ(12+MKl)≪∣sb∣max⁡X<u≤2X(∣Γ(12+MKu+σ)Γ(12+MKu)∣),(31)\sum_{X<l\le2X}\frac{\lambda_{M_Kl}(\mathfrak{a})}{\sqrt{N(\mathfrak{a})}}\frac{\Gamma\left(\frac{1}{2}+M_Kl+s\right)}{\Gamma\left(\frac{1}{2}+M_Kl\right)} \ll\left|\frac{s}{b}\right|\max_{X<u\le2X}\left(\left|\frac{\Gamma\left(\frac{1}{2}+M_Ku+\sigma\right)}{\Gamma\left(\frac{1}{2}+M_Ku\right)}\right|\right), \tag*{(31)}

where we set s=σ+its=\sigma+it with σ,t∈R\sigma,t\in\mathbb{R}.

We apply (16) into (31) to see that for ∣σ∣≤10|\sigma|\le10, we have for a=(a+bωK)\mathfrak{a}=(a+b\omega_K) with a,b∈Za,b\in\mathbb{Z}, b≠0b\ne0,

∑X<l≤2XλMKl(a)N(a)Γ(12+MKl+s)Γ(12+MKl)≪∣sb∣Xσ.(32)\sum_{X<l\le2X}\frac{\lambda_{M_Kl}(\mathfrak{a})}{\sqrt{N(\mathfrak{a})}}\frac{\Gamma\left(\frac{1}{2}+M_Kl+s\right)}{\Gamma\left(\frac{1}{2}+M_Kl\right)} \ll\left|\frac{s}{b}\right|X^\sigma. \tag*{(32)}

It follows from the above and (22) that we have

R1,2≪∑a=(a+bωK),b≠0,N(a)≤XN(a)∣b∣X≪X1/2log⁡X,(33)R_{1,2}\ll\sum_{\substack{\mathfrak{a}=(a+b\omega_K),\,b\ne0,\\N(\mathfrak{a})\le X}}\frac{N(\mathfrak{a})}{|b|X}\ll X^{1/2}\log X, \tag*{(33)}

where the last estimation above follows from (27) and partial summation.

Similarly, we have

R2≪X1/2log⁡X.(34)R_2\ll X^{1/2}\log X. \tag*{(34)}

The asymptotical expression given in (2) now follows from (14), (20), (21), (28), (33) and (34). This completes the proof of the Theorem 1.1.

Proof of Theorem 1.2

We apply Lemma 2.3 and (11) to see that

∑X<l≤2X∣L(12,λMKl)∣2=2∑X<l≤2X∑n⊆OKn≠(0)τK(n)λMKl(n)N(n)1/2WMKl((2π)2N(n)∣DK∣):=M+T1+T2,(35)\sum_{X<l\le2X}\left|L\left(\frac{1}{2},\lambda_{M_Kl}\right)\right|^2 =2\sum_{X<l\le2X}\sum_{\substack{n\subseteq\mathcal{O}_K\\n\ne(0)}}\frac{\tau_K(n)\lambda_{M_Kl}(n)}{N(n)^{1/2}}W_{M_Kl}\left(\frac{(2\pi)^2N(n)}{|D_K|}\right):=M+T_1+T_2, \tag*{(35)}

where

M=2∑X<l≤2X∑n⊆OKn=(n)n∈NτK(n)λMKl(n)N(n)1/2WMKl((2π)2N(n)∣DK∣),M=2\sum_{X<l\le2X}\sum_{\substack{n\subseteq\mathcal{O}_K\\n=(n)\\n\in\mathbb{N}}}\frac{\tau_K(n)\lambda_{M_Kl}(n)}{N(n)^{1/2}}W_{M_Kl}\left(\frac{(2\pi)^2N(n)}{|D_K|}\right),
T1=2∑X<l≤2X∑n⊆OK,N(n)≤X2n≠(0)n≠(n),n∈NτK(n)λMKl(n)N(n)1/2WMKl((2π)2N(n)∣DK∣),T_1=2\sum_{X<l\le2X}\sum_{\substack{n\subseteq\mathcal{O}_K,\,N(n)\le X^2\\n\ne(0)\\n\ne(n),\,n\in\mathbb{N}}}\frac{\tau_K(n)\lambda_{M_Kl}(n)}{N(n)^{1/2}}W_{M_Kl}\left(\frac{(2\pi)^2N(n)}{|D_K|}\right),
T2=2∑X<l≤2X∑n⊆OK,N(n)>X2n≠(0)n≠(n),n∈NτK(n)λMKl(n)N(n)1/2WMKl((2π)2N(n)∣DK∣).T_2=2\sum_{X<l\le2X}\sum_{\substack{n\subseteq\mathcal{O}_K,\,N(n)>X^2\\n\ne(0)\\n\ne(n),\,n\in\mathbb{N}}}\frac{\tau_K(n)\lambda_{M_Kl}(n)}{N(n)^{1/2}}W_{M_Kl}\left(\frac{(2\pi)^2N(n)}{|D_K|}\right).

Note again that when n=(n)n=(n) with n∈Nn\in\mathbb{N}, we have λMKl(n)=1\lambda_{M_Kl}(n)=1 for all X<l≤2XX<l\le2X. It follows that we have

M=2∑X<l≤2X∑n∈NτK(n)nWMKl((2π)2n2∣DK∣)=∑X<l≤2X22πi∫(3)Γ(12+MKl+s)2Γ(12+MKl)2((2π)2∣DK∣)−ses2(∑n≥1τK(n)n1+2s)dss.M=2\sum_{X<l\le2X}\sum_{n\in\mathbb{N}}\frac{\tau_K(n)}{n}W_{M_Kl}\left(\frac{(2\pi)^2n^2}{|D_K|}\right) =\sum_{X<l\le2X}\frac{2}{2\pi i}\int_{(3)}\frac{\Gamma\left(\frac{1}{2}+M_Kl+s\right)^2}{\Gamma\left(\frac{1}{2}+M_Kl\right)^2}\left(\frac{(2\pi)^2}{|D_K|}\right)^{-s}e^{s^2}\left(\sum_{n\ge1}\frac{\tau_K(n)}{n^{1+2s}}\right)\frac{ds}{s}.

Note that (see [3 Section 3.8]) a rational prime pp ramifies in OKO_K if and only if χd(p)=0\chi_d(p)=0, where χd=(d⋅)\chi_d=\left(\frac{d}{\cdot}\right) is the Kronecker symbol. Also, pp splits (resp. is inert) in OKO_K if and only if χd(p)=1\chi_d(p)=1 (resp. χd(p)=−1\chi_d(p)=-1). We apply this to rewrite the Dirichlet series ∑n≥1τK(n)n1+2s\sum_{n\geq1}\frac{\tau_K(n)}{n^{1+2s}} into Euler products to see that we have

∑n≥1τK(n)n1+2s=∏p rational prime(1+3+χd(p)p1+2s+O(1p2+4s))=ζ3(1+2s)L(1+2s,χd)FK(s),\sum_{n\geq1}\frac{\tau_K(n)}{n^{1+2s}}=\prod_{p\ {\rm rational\ prime}}\left(1+\frac{3+\chi_d(p)}{p^{1+2s}}+O\left(\frac{1}{p^{2+4s}}\right)\right)=\zeta^3(1+2s)L(1+2s,\chi_d)F_K(s),

where L(s,χd)L(s,\chi_d) is the Dirichlet LL-function associated to χd\chi_d and FK(s)F_K(s) is analytical in the region ℜ(s)≥−1/4+ε\Re(s)\geq-1/4+\varepsilon for any ε>0\varepsilon>0.

We now shift the line of integration above to ℜ(s)=−1/4+ε\Re(s)=-1/4+\varepsilon to encounter a pole of order 4 at s=0s=0, whose residue can be easily computed to be

L(1,χd)FK(0)Γ(3)(12+MKl)2Γ(12+MKl)+O(Γ(2)(12+MKl)2Γ(12+MKl)+Γ′(12+MKl)Γ(12+MKl)+1).(36)\frac{L(1,\chi_d)F_K(0)\Gamma^{(3)}\left(\frac{1}{2}+M_Kl\right)}{2\Gamma\left(\frac{1}{2}+M_Kl\right)}+O\left(\frac{\Gamma^{(2)}\left(\frac{1}{2}+M_Kl\right)}{2\Gamma\left(\frac{1}{2}+M_Kl\right)}+\frac{\Gamma'\left(\frac{1}{2}+M_Kl\right)}{\Gamma\left(\frac{1}{2}+M_Kl\right)}+1\right). \tag*{(36)}

where the implied constant depends on KK only.

Note that (see [10 §12.31]) we have for ℜ(z)≥0\Re(z)\geq0,

Γ′(z)Γ(z)=log⁡z−12z−∫0∞(12−1u+1eu−1)e−uz du.\frac{\Gamma'(z)}{\Gamma(z)}=\log z-\frac{1}{2z}-\int_0^\infty\left(\frac{1}{2}-\frac{1}{u}+\frac{1}{e^u-1}\right)e^{-uz}\,du.

The above implies that

Γ′(z)=Γ(z)(log⁡z−12z−∫0∞(12−1u+1eu−1)e−uz du).\Gamma'(z)=\Gamma(z)\left(\log z-\frac{1}{2z}-\int_0^\infty\left(\frac{1}{2}-\frac{1}{u}+\frac{1}{e^u-1}\right)e^{-uz}\,du\right).

Differentiating both sides above with respect to zz now implies that for ℜ(z)≥0\Re(z)\geq0,

Γ(n)(z)=Γ(z)((log⁡z)n+O((log⁡z)n−1)).\Gamma^{(n)}(z)=\Gamma(z)\left((\log z)^n+O\left((\log z)^{n-1}\right)\right).

We apply the above to see that the expression in (4.2) equals

L(1,χd)FK(0)2log⁡3(12+MKl)+O(log⁡2(12+MKl)).\frac{L(1,\chi_d)F_K(0)}{2}\log^3\left(\frac{1}{2}+M_Kl\right)+O\left(\log^2\left(\frac{1}{2}+M_Kl\right)\right).

It follows that

M=∑X<l≤2X(L(1,χd)FK(0)log⁡3(12+MKl)+O(log⁡2(12+MKl)))+M1.(37)M=\sum_{X<l\leq2X}\left(L(1,\chi_d)F_K(0)\log^3\left(\frac{1}{2}+M_Kl\right)+O\left(\log^2\left(\frac{1}{2}+M_Kl\right)\right)\right)+M_1. \tag*{(37)}

where

M1=∑X<l≤2X22πi∫(−1/4+ε)Γ(12+MKl+s)2Γ(12+MKl)2((2π)2∣DK∣)−ses2ζ3(1+2s)L(1+2s,χd)FK(s)dss.M_1=\sum_{X<l\leq2X}\frac{2}{2\pi i}\int_{(-1/4+\varepsilon)}\frac{\Gamma\left(\frac{1}{2}+M_Kl+s\right)^2}{\Gamma\left(\frac{1}{2}+M_Kl\right)^2}\left(\frac{(2\pi)^2}{|D_K|}\right)^{-s}e^{s^2}\zeta^3(1+2s)L(1+2s,\chi_d)F_K(s)\frac{ds}{s}.

We recall the convexity bound for L(s,χd)L(s,\chi_d) (see [3 Exercise 3, p. 100]) asserts that

L(s,χd)≪{1ℜ(s)>1,(∣d∣(1+∣s∣))(1−ℜ(s))/2+ε0<ℜ(s)<1,(∣d∣(1+∣s∣))1/2−ℜ(s)+εℜ(s)≤0.L(s,\chi_d)\ll \begin{cases} 1 & \Re(s)>1,\\ \left(|d|(1+|s|)\right)^{(1-\Re(s))/2+\varepsilon} & 0<\Re(s)<1,\\ \left(|d|(1+|s|)\right)^{1/2-\Re(s)+\varepsilon} & \Re(s)\leq0. \end{cases}

Note that the above estimation also holds by replacing L(s,χd)L(s,\chi_d) with ζ(s)\zeta(s) and dd with 1.

We apply the above and (3.4) to see that

M1≪∑X<l≤2XΓ(14+MKl+ε)2Γ(12+MKl)2≪X1/2+2ε,M_1\ll\sum_{X<l\leq2X}\frac{\Gamma\left(\frac{1}{4}+M_Kl+\varepsilon\right)^2}{\Gamma\left(\frac{1}{2}+M_Kl\right)^2}\ll X^{1/2+2\varepsilon},

where the last estimation above follows from (3.3).

We apply the above into (4.3) to see that

M=CKX(log⁡X)3+O(X(log⁡X)2),(38)M=C_KX(\log X)^3+O\left(X(\log X)^2\right), \tag*{(38)}

where CKC_K is a constant depending on KK only.

Next, we estimate T1T_1 and T2T_2 by keeping the line of integration in WMKlW_{M_Kl} to be at ℜ(s)=3\Re(s)=3 for T2T_2 while shifting the line of integration to ℜ(s)=−1\Re(s)=-1 for T1T_1. In this process we encounter a simple pole with residue 1 at s=0s=0, whose contribution to T1T_1 is denoted by T1,1T_{1,1}. We denote T1,2T_{1,2} the contribution to T1T_1 on the new line of integration, so that we have

T1=T1,1+T1,2,(39)T_1=T_{1,1}+T_{1,2}, \tag*{(39)}

where

T1,1=2∑X<l≤2X ∑n⊆OK, N(n)≤X2n≠(0)n≠(n), n∈NτK(n)λMKl(n)N(n)1/2,(40)T_{1,1}=2\sum_{X<l\leq2X}\ \sum_{\substack{n\subseteq\mathcal{O}_K,\ N(n)\leq X^2\\ n\neq(0)\\ n\neq(n),\ n\in\mathbb{N}}}\frac{\tau_K(n)\lambda_{M_{K l}}(n)}{N(n)^{1/2}}, \tag*{(40)}
T1,2=2∑X<l≤2X ∑n⊆OK, N(n)≤X2n≠(0)n≠(n), n∈NτK(n)λMKl(n)N(n)1/2⋅12πi∫(−1)Γ(12+MKl+s)2Γ(12+MKl)2((2π)2N(n)∣DK∣)−ses2dss.(41)T_{1,2}=2\sum_{X<l\leq2X}\ \sum_{\substack{n\subseteq\mathcal{O}_K,\ N(n)\leq X^2\\ n\neq(0)\\ n\neq(n),\ n\in\mathbb{N}}}\frac{\tau_K(n)\lambda_{M_{K l}}(n)}{N(n)^{1/2}}\cdot\frac{1}{2\pi i}\int_{(-1)}\frac{\Gamma\left(\frac{1}{2}+M_{K l}+s\right)^2}{\Gamma\left(\frac{1}{2}+M_{K l}\right)^2}\left(\frac{(2\pi)^2N(n)}{|D_K|}\right)^{-s}e^{s^2}\frac{ds}{s}. \tag*{(41)}

We now apply (3.13) to see that

T1,1≪∑n=(a+bωK), b≠0N(n)≤X2τK(n)∣b∣.(42)T_{1,1}\ll\sum_{\substack{n=(a+b\omega_K),\ b\neq0\\N(n)\leq X^2}}\frac{\tau_K(n)}{|b|}. \tag*{(42)}

Note that for any a∣na\mid n, we have N(a)∣N(n)N(a)\mid N(n). Moreover, if a=(α)a=(\alpha) and b=(β)b=(\beta) satisfy that N(a)=N(b)N(a)=N(b), then we have α=βu\alpha=\beta u with u∈UKu\in U_K. It follows that we have

τK(n)≪τ(N(n)),\tau_K(n)\ll\tau(N(n)),

where τ\tau is the usual divisor function on Z\mathbb{Z}. Thus we have

∑n=(a+bωK), b≠0N(n)≤uτK(n)∣b∣≪∑1≤b≤u1b∑1≤a≤uτ(N(n)).(43)\sum_{\substack{n=(a+b\omega_K),\ b\neq0\\N(n)\leq u}}\frac{\tau_K(n)}{|b|}\ll\sum_{1\leq b\leq\sqrt{u}}\frac{1}{b}\sum_{1\leq a\leq\sqrt{u}}\tau(N(n)). \tag*{(43)}

Note that for n=(a+bωK)n=(a+b\omega_K) we have N(n)=fK(a;b)N(n)=f_K(a;b), where

fK(a;b)={a2−db2,d≡2,3(mod4),a2+ab+b2,d≡1(mod4).f_K(a;b)= \begin{cases} a^2-db^2, & d\equiv2,3\pmod{4},\\ a^2+ab+b^2, & d\equiv1\pmod{4}. \end{cases}

Observe that for any fixed b∈Zb\in\mathbb{Z}, fK(a;b)f_K(a;b) is an irreducible quadratic polynomial of aa with integer coefficients. We now recall a result of J. McKee [5 (12)] that for any x≥2x\geq2,

∑a≤xτ(fK(a;b))=2x∑m≤xρ(m)m+O(∑m≤xρ(m))+O(x),(44)\sum_{a\leq x}\tau(f_K(a;b))=2x\sum_{m\leq x}\frac{\rho(m)}{m}+O\left(\sum_{m\leq x}\rho(m)\right)+O(x), \tag*{(44)}

where for any positive integer mm, ρ(m)\rho(m) denotes the number of solutions to the congruence equation

fK(n;b)≡0(modm),0≤n<m.f_K(n;b)\equiv0\pmod{m},\qquad0\leq n<m.

Let f(x,y)=Ax2+Bxy+Cy2f(x,y)=Ax^2+Bxy+Cy^2 with A,B,C∈ZA,B,C\in\mathbb{Z} and be a positive definite binary quadratic form, such that its discriminant Δ=B2−4AC<0\Delta=B^2-4AC<0, and A>0A>0. Given

β=(β1β2β3β4)∈SL2(Z),\beta=\begin{pmatrix}\beta_1&\beta_2\\\beta_3&\beta_4\end{pmatrix}\in\mathrm{SL}_2(\mathbb{Z}),

we define fβ(x,y)=f(β1x+β3y,β2x+β4y)f^\beta(x,y)=f(\beta_1x+\beta_3y,\beta_2x+\beta_4y). Then fβf^\beta has the same discriminant as ff. Forms related in this way are called equivalent. The form ff is called reduced if ∣B∣≤A≤C|B|\leq A\leq C, with ∣B∣=0|B|=0 if either A=∣B∣A=|B| or A=CA=C. We recall from [5 Section 2] that each positive definite binary quadratic form is equivalent to precisely one reduced form. The number of reduced forms with discriminant Δ\Delta is finite, and is denoted H(Δ)H(\Delta). The subgroup of SL2(Z)\mathrm{SL}_2(\mathbb{Z}) consisting of those β\beta such that fβ=ff^\beta=f is called the automorphism group of ff.

Write (A,B,C)(A,B,C) as a shorthand for Ax2+Bxy+Cy2Ax^2+Bxy+Cy^2. Let w(A,B,C)w(A,B,C) denote the size of the automorphism group of (A,B,C)(A,B,C). Then w(A,A,A)=6w(A,A,A)=6, w(A,0,A)=4w(A,0,A)=4, and otherwise, if (A,B,C)(A,B,C) is reduced, we have w(A,B,C)=2w(A,B,C)=2. Define the Hurwitz class number H∗(Δ)H^*(\Delta) as

H∗(Δ)=∑(A,B,C) reducedB2−4AC=Δ2w(A,B,C).H^*(\Delta)=\sum_{\substack{(A,B,C)\ \mathrm{reduced}\\B^2-4AC=\Delta}}\frac{2}{w(A,B,C)}.

Note that the discriminant ΔK\Delta_K of our function fK(n;b)f_K(n;b) equals

ΔK={−4db2,d≡2,3(mod4),−db2,d≡1(mod4).(45)\Delta_K = \begin{cases} -4db^2, & d \equiv2,3 \pmod{4},\\ -db^2, & d \equiv1 \pmod{4}. \end{cases} \tag*{(45)}

It is then shown in [5 (16)] that for any x≥2x \ge2,

∑m≤xρ(m)=∑(A,B,C) reducedB2−4AC=ΔK1W(A,B,C)∑q≤xμ(q)∑1≤Ax2+Bxy+Cy2≤x/q21\sum_{m \le x} \rho(m) = \sum_{\substack{(A,B,C)\ \mathrm{reduced}\\B^2-4AC=\Delta_K}} \frac{1}{W(A,B,C)} \sum_{q \le\sqrt{x}} \mu(q) \sum_{1 \le Ax^2+Bxy+Cy^2 \le x/q^2} 1

where μ\mu is the Möbius function.

Observe that the inner sum is the number of non-trivial integer points within the ellipse Ax2+Bxy+Cy2=x/q2Ax^2+Bxy+Cy^2=x/q^2, we diagonalize it to see that its equation can be recasted as

ν1X2+ν2Y2=xq2(46)\nu_1X^2+\nu_2Y^2=\frac{x}{q^2} \tag*{(46)}

where ν1ν2=−ΔK/4\nu_1\nu_2=-\Delta_K/4. The area of the ellipse given in (46) then equals

πxq2ν1⋅xq2ν2=2πxq2ΔK.\pi\sqrt{\frac{x}{q^2\nu_1}\cdot\frac{x}{q^2\nu_2}} =\frac{2\pi x}{q^2\sqrt{\Delta_K}}.

It follows that the number of non-trivial integer points within the ellipse Ax2+Bxy+Cy2=x/q2Ax^2+Bxy+Cy^2=x/q^2 is

≪xq2ΔK.\ll\frac{x}{q^2\sqrt{\Delta_K}}.

We apply the above and proceed as in the paragraph below [5 (16)] to see that for any x≥2x \ge2,

∑m≤xρ(m)≪H∗(ΔK)−ΔKx.(47)\sum_{m \le x}\rho(m)\ll\frac{H^*(\Delta_K)}{\sqrt{-\Delta_K}}x. \tag*{(47)}

It follows from the above and partial summation that we have

∑m≤xρf(m)m≪H∗(ΔK)−ΔKlog⁡x.(48)\sum_{m \le x}\frac{\rho_f(m)}{m}\ll\frac{H^*(\Delta_K)}{\sqrt{-\Delta_K}}\log x. \tag*{(48)}

We deduce from (43)–(45), (47) and (48) that for u≥2u \ge2,

∑n=(a+bωK),b≠0N(n)≤uτK(n)∣b∣≪∑1≤b≤u1b∑1≤a≤uτ(fK(a;b))≪ulog⁡u∑1≤b≤uH∗(ΔK)b2.(49)\sum_{\substack{n=(a+b\omega_K),\,b\ne0\\N(n)\le u}}\frac{\tau_K(n)}{|b|} \ll \sum_{1\le b\le\sqrt{u}}\frac{1}{b} \sum_{1\le a\le\sqrt{u}}\tau(f_K(a;b)) \ll\sqrt{u}\log u\sum_{1\le b\le\sqrt{u}}\frac{H^*(\Delta_K)}{b^2}. \tag*{(49)}

Note that we have H∗(ΔK)≪H(ΔK)H^*(\Delta_K)\ll H(\Delta_K). We then note from [1 §6, (15)] that

H∗(ΔK)≪H(ΔK)≪ΔKL(1,χΔK)≪∣b∣L(1,χΔK)≪∣b∣,(50)H^*(\Delta_K)\ll H(\Delta_K)\ll\sqrt{\Delta_K}L(1,\chi_{\Delta_K})\ll|b|L(1,\chi_{\Delta_K})\ll|b|, \tag*{(50)}

where the last estimation above follows by noting that χΔK\chi_{\Delta_K} is induced by the character χ−d\chi_{-d} so that L(1,χΔK)≪1L(1,\chi_{\Delta_K})\ll1.

We substitute (50) into (49) to see that

∑n=(a+bωK),b≠0N(n)≤uτK(n)∣b∣≪u(log⁡u)2.(51)\sum_{\substack{n=(a+b\omega_K),\,b\ne0\\N(n)\le u}}\frac{\tau_K(n)}{|b|} \ll\sqrt{u}(\log u)^2. \tag*{(51)}

We apply (51) into (42) to see that

T1,1≪X(log⁡X)2.(52)T_{1,1}\ll X(\log X)^2. \tag*{(52)}

We now estimate T1,2T_{1,2} by noting that similar to (32), we have for n=(a+bωK)n=(a+b\omega_K) with a,b∈Za,b\in\mathbb{Z}, b≠0b\ne0,

∑X<l≤2Xλl(n)N(n)Γ(12+MKl+s)Γ(12+MKl)≪∣s∣∣b∣X2σ.\sum_{X<l\le2X}\frac{\lambda_l(n)}{\sqrt{N(n)}} \frac{\Gamma\left(\frac{1}{2}+M_Kl+s\right)} {\Gamma\left(\frac{1}{2}+M_Kl\right)} \ll\frac{|s|}{|b|}X^{2\sigma}.

We apply the above to see from (4.6) that

T1,2≪X−2∑n=(a+bωK),b≠0N(n)≤X2τK(n)N(n)∣b∣≪X(log⁡X)2,(53)T_{1,2}\ll X^{-2} \sum_{\substack{n=(a+b\omega_K),\,b\ne0\\N(n)\le X^2}} \frac{\tau_K(n)N(n)}{|b|} \ll X(\log X)^2, \tag*{(53)}

where the last estimation above follows from (51) and partial summation.

Note that the above procedure also implies that

T2≪X3∑n=(a+bωK),b≠0N(n)>X2τK(n)∣b∣N(n)3≪X(log⁡X)2.(54)T_2 \ll X^3 \sum_{\substack{n=(a+b\omega_K),\,b\ne0\\N(n)>X^2}} \frac{\tau_K(n)}{|b|N(n)^3} \ll X(\log X)^2. \tag*{(54)}

The asymptotical expression given in (3) now follows from (35), (38), (39), (52)–(54). This completes the proof of Theorem 1.2.

Acknowledgments. P. G. is supported in part by NSFC grant 12471003.

School of Mathematical Sciences, Beihang University, Beijing 100191, China

Email address: [email protected]

References

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