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Functional van Lint-Seidel Relative and Gerzon Universal Bounds

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Abstract

We introduce the notion of functional equiangular lines in finite rank modules over subrings of R\mathbb{R}. We show that van Lint-Seidel relative and Gerzon universal bounds hold for this most general lines.

Introduction

Let d∈Nd \in\mathbb{N} and γ∈[0,1]\gamma\in[0,1]. Recall that a collection {τj}j=1n\{\tau_j\}_{j=1}^{n} of unit vectors in Rd\mathbb{R}^{d} is said to be γ\gamma-equiangular lines [1, 3] if

∣⟨τj,τk⟩∣=γ,∀1≤j,k≤n, j≠k.\lvert\langle\tau_j,\tau_k\rangle\rvert= \gamma,\quad\forall1 \leq j,k \leq n,\ j \ne k.

A fundamental problem associated with equiangular lines is the following.

Problem 1.1. Given d∈Nd \in\mathbb{N} and γ∈[0,1]\gamma\in[0,1], what is the upper bound on nn such that there exists a collection {τj}j=1n\{\tau_j\}_{j=1}^{n} of γ\gamma-equiangular lines in Rd\mathbb{R}^{d}?

Two answers to Problem (1.1) which are driving forces in the study of equiangular lines is the following relative bound of van Lint and Seidel [3, 4] and universal bound of Gerzon [5].

Theorem 1.2. [3, 4] (van Lint-Seidel Relative Bound) Let {τj}j=1n\{\tau_j\}_{j=1}^{n} be γ\gamma-equiangular lines in Rd\mathbb{R}^{d}. Then

n(1−dγ2)≤d(1−γ2).n(1-d\gamma^{2}) \leq d(1-\gamma^{2}).

In particular, if

γ<1d,\gamma< \frac{1}{\sqrt{d}},

then

n≤d(1−γ2)1−dγ2.n \leq\frac{d(1-\gamma^{2})}{1-d\gamma^{2}}.

Theorem 1.3. [5] (Gerzon Universal Bound) Let {τj}j=1n\{\tau_j\}_{j=1}^{n} be γ\gamma-equiangular lines in Rd\mathbb{R}^{d}. Then

n≤d(d+1)2.n \leq\frac{d(d+1)}{2}.

The notion of functional equiangular lines is hinted in [2]. In this paper, we define it in most general form and derive functional forms of Theorems 1.2 and 1.3.

Functional Equiangular Lines

In the paper, R\mathcal{R} denotes a subring of R\mathbb{R} and M\mathcal{M} is a rank dd module over R\mathcal{R}. By M∗\mathcal{M}^{*} we mean the module of all homomorphisms from M\mathcal{M} to R\mathcal{R}. Module of all homomorphisms from M\mathcal{M} to M\mathcal{M} is denoted by Mor⁡(M)\operatorname{Mor}(\mathcal{M}).

Definition 2.1. Let {τj}j=1n\{\tau_j\}_{j=1}^{n} be a collection in a module M\mathcal{M} of rank dd over R\mathcal{R} and {fj}j=1n\{f_j\}_{j=1}^{n} be a collection in M∗\mathcal{M}^{*}. Let γ≥0\gamma\ge0. The pair ({fj}j=1n,{τj}j=1n)(\{f_j\}_{j=1}^{n},\{\tau_j\}_{j=1}^{n}) is said to be functional γ\gamma-equingular if following conditions hold.

(i) fj(τj)=1f_j(\tau_j)=1 for all 1≤j≤n1 \le j \le n.

(ii) ∣fj(τk)fk(τj)∣=γ2\lvert f_j(\tau_k)f_k(\tau_j)\rvert=\gamma^2 for all 1≤j,k≤n1 \le j,k \le n, j≠kj \ne k.

(iii) The operator

Sf,τ:M∋x↦∑j=1nfj(x)τj∈M.S_{f,\tau}:\mathcal{M}\ni x\mapsto\sum_{j=1}^{n}f_j(x)\tau_j\in\mathcal{M}.

is similar (through invertible operator) to a diagonal operator.

Theorem 2.2. (Functional van Lint-Seidel Relative Bound) If ({fj}j=1n,{τj}j=1n)(\{f_j\}_{j=1}^{n},\{\tau_j\}_{j=1}^{n}) is functional γ\gamma-equiangular for rank dd module M\mathcal{M}, then

n(1−dγ2)≤d(1−γ2).n(1-d\gamma^2)\le d(1-\gamma^2).

In particular, if

γ<1d,\gamma<\frac{1}{\sqrt{d}},

then

n≤d(1−γ2)1−dγ2.n\le\frac{d(1-\gamma^2)}{1-d\gamma^2}.

Proof. Define

Sf,τ:M∋x↦Sf,τx:=∑j=1nfj(x)τj∈M.S_{f,\tau}:\mathcal{M}\ni x\mapsto S_{f,\tau}x:=\sum_{j=1}^{n}f_j(x)\tau_j\in\mathcal{M}.

Let λ1,…,λd\lambda_1,\ldots,\lambda_d be eigenvalues of Sf,τS_{f,\tau}. Since Sf,τS_{f,\tau} is diagonalizable,

n2=(∑j=1nfj(τj))2=(Tra⁡(Sf,τ))2=(∑k=1dλk)2≤d∑k=1dλk2=dTra⁡(Sf,τ2)=d∑j=1n∑k=1nfj(τk)fk(τj)=d∑j=1nfj(τj)2+d∑j,k=1j≠knfj(τk)fk(τj)=dn+d∑j,k=1j≠knfj(τk)fk(τj)≤dn+d∑j,k=1j≠kn∣fj(τk)fk(τj)∣=dn+d(n2−n)γ2.\begin{aligned} n^2=\left(\sum_{j=1}^{n}f_j(\tau_j)\right)^2=(\operatorname{Tra}(S_{f,\tau}))^2=\left(\sum_{k=1}^{d}\lambda_k\right)^2 \\ &\le d\sum_{k=1}^{d}\lambda_k^2=d\operatorname{Tra}(S_{f,\tau}^2)=d\sum_{j=1}^{n}\sum_{k=1}^{n}f_j(\tau_k)f_k(\tau_j) \\ &=d\sum_{j=1}^{n}f_j(\tau_j)^2+d\sum_{\substack{j,k=1\\j\ne k}}^{n}f_j(\tau_k)f_k(\tau_j)=dn+d\sum_{\substack{j,k=1\\j\ne k}}^{n}f_j(\tau_k)f_k(\tau_j) \\ &\le dn+d\sum_{\substack{j,k=1\\j\ne k}}^{n}\lvert f_j(\tau_k)f_k(\tau_j)\rvert=dn+d(n^2-n)\gamma^2. \end{aligned}

Therefore

n≤d+d(n−1)γ2⟹n(1−dγ2)≤d(1−γ2).n\le d+d(n-1)\gamma^2\Longrightarrow n(1-d\gamma^2)\le d(1-\gamma^2).

We are unable to derive Gerzon universal bound for functional equiangular lines. However, we derive following Gerzon bound for functionals.

Theorem 2.3. (Functional Gerzon Universal Bound) Let {τj}j=1n\{\tau_j\}_{j=1}^{n} be a collection in a module M\mathcal{M} of rank dd over R\mathbb{R} and {fj}j=1n\{f_j\}_{j=1}^{n} be a collection in M∗\mathcal{M}^*. Assume the following.

(i) fj(τj)=1f_j(\tau_j)=1 for all 1≤j≤n1 \le j \le n.

(ii) There is a γ≠1\gamma\ne1 such that fj(τk)fk(τj)=γ2f_j(\tau_k)f_k(\tau_j)=\gamma^2 for all 1≤j,k≤n1 \le j,k \le n, j≠kj \ne k.

Then

n≤d2n \le d^2

Proof. For 1≤j≤n1 \le j \le n, define

τj⊗fj:M∋x↦(τj⊗fj)(x):=fj(x)τj∈M\tau_j \otimes f_j:\mathcal{M} \ni x \mapsto(\tau_j \otimes f_j)(x):=f_j(x)\tau_j \in\mathcal{M}

We show that the collection {τj⊗fj}j=1n\{\tau_j \otimes f_j\}_{j=1}^{n} in Mor⁡(M)\operatorname{Mor}(\mathcal{M}) is linearly independent over R\mathbb{R}. Let c1,…,cn∈Rc_1,\ldots,c_n \in\mathbb{R} be such that

∑j=1ncj(τj⊗fj)=0.\sum_{j=1}^{n}c_j(\tau_j \otimes f_j)=0.

Let 1≤k≤n1 \le k \le n be fixed. Then previous equation gives

∑j=1ncj(τj⊗fj)(τk⊗fk)=0.\sum_{j=1}^{n}c_j(\tau_j \otimes f_j)(\tau_k \otimes f_k)=0.

By taking trace we get

0=∑j=1ncjTra⁡((τj⊗fj)(τk⊗fk))=∑j=1ncjfj(τk)fk(τj)=∑j=1j≠kncjfj(τk)fk(τj)+ckfk(τk)2=∑j=1j≠kncjγ2+ck=γ2(∑j=1ncj−ck)+ck=γ2(∑j=1ncj)+(1−γ2)ck.\begin{aligned} 0=\sum_{j=1}^{n}c_j\operatorname{Tra}((\tau_j \otimes f_j)(\tau_k \otimes f_k))=\sum_{j=1}^{n}c_jf_j(\tau_k)f_k(\tau_j) \\ &=\sum_{\substack{j=1\\j\ne k}}^{n}c_jf_j(\tau_k)f_k(\tau_j)+c_kf_k(\tau_k)^2=\sum_{\substack{j=1\\j\ne k}}^{n}c_j\gamma^2+c_k \\ &=\gamma^2\left(\sum_{j=1}^{n}c_j-c_k\right)+c_k=\gamma^2\left(\sum_{j=1}^{n}c_j\right)+(1-\gamma^2)c_k. \end{aligned}

Therefore

ck=γ2γ2−1∑j=1ncj=:c,∀1≤k≤n.c_k=\frac{\gamma^2}{\gamma^2-1}\sum_{j=1}^{n}c_j=:c,\qquad\forall1\le k\le n.

Now

0=Tra⁡(∑j=1ncj(τj⊗fj))=Tra⁡(∑j=1nc(τj⊗fj))=∑j=1ncTra⁡(τj⊗fj)=∑j=1ncfj(τj)=cn.\begin{aligned} 0=\operatorname{Tra}\left(\sum_{j=1}^{n}c_j(\tau_j\otimes f_j)\right)=\operatorname{Tra}\left(\sum_{j=1}^{n}c(\tau_j\otimes f_j)\right) \\ &=\sum_{j=1}^{n}c\operatorname{Tra}(\tau_j\otimes f_j)=\sum_{j=1}^{n}cf_j(\tau_j)=cn. \end{aligned}

Hence c=0c=0. Therefore {τj⊗fj}j=1n\{\tau_j\otimes f_j\}_{j=1}^{n} is linearly independent. Since the rank of Mor⁡(M)\operatorname{Mor}(\mathcal{M}) is d2d^2 we must have n≤d2n\le d^2.

References

References

  1. [1]J. Haantjes. Equilateral point-sets in elliptic two- and three-dimensional spaces. Nieuw Arch. Wiskunde (2), 22:355–362, 1948.
  2. [2]K. Mahesh Krishna. Discrete and continuous Welch bounds for Banach spaces with applications. J. Class. Anal., 22(2):81–111, 2023.DOI
  3. [3]P. W. H. Lemmens and J. J. Seidel. Equiangular lines. J. Algebra, 24:494–512, 1973.
  4. [4]J. H. van Lint and J. J. Seidel. Equilateral point sets in elliptic geometry. Indag. Math., 28:335–348, 1966.
  5. [5]Shayne F. D. Waldron. An introduction to finite tight frames. Applied and Numerical Harmonic Analysis. Birkhäuser/Springer, New York, 2018.DOI

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