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A generalization of the Dirichlet approximation theorem for affine actions on the real line

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Abstract

We study quantitative density of orbits of the free semigroup ΓΓ generated by two maps of (0,∞)(0,\infty). For the Möbius pair x↦1/xx\mapsto 1/x, x↦x+1x\mapsto x+1 we show that every orbit is O(n−1)O(n^{-1})-dense in [0,∞)[0,\infty), that every irrational number uu is approached at a rate governed by the continued fraction of uu (at least n−2n^{-2}, exponential when uu has bounded partial quotients, and exp⁡(−cn/log⁡n)\exp(-cn/\log n) for almost every uu), and that for rational uu and rational starting points the rate n−1n^{-1} is optimal. For the affine pair T0(x)=x/aT_0(x)=x/a, T1(x)=bx+1T_1(x)=bx+1 with a,b>1a,b>1, which was studied by Bergelson, Misiurewicz and Senti, we prove that for every x>0x>0 and u≥0u\ge 0 there are infinitely many γ∈Γγ\inΓ with ∣γ(x)−u∣<C λ−∣γ∣,λ=exp⁡ ⁣(log⁡a log⁡aa−1log⁡a2ba−1)>1, |γ(x)-u|<C\,λ^{-|γ|},\qquad λ=\exp\!\Big(\frac{\log a\,\log\frac{a}{a-1}}{\log\frac{a^2b}{a-1}}\Big)>1, where ∣γ∣|γ| is the word length of γγ and CC is independent of γγ. This exponential rate holds whether or not log⁡ab\log_a b is rational, and the exponential order cannot be improved for almost every uu. We also give a corrected version of the Kronecker-type estimate ∣γ(x)−u∣<(u+1)(t1/∣γ∣−1)|γ(x)-u|<(u+1)(t^{1/|γ|}-1). Finally, we discuss the approximation of real numbers by ratios of primes and by ratios of logarithms of primes, updated in light of recent results on gaps between primes.

Introduction

The Dirichlet approximation theorem states that, given a real number uu and a positive integer NN, there exist integers p,qp,q with 0<q≤N0<q\leq N such that

∣pq−u∣<1qN.(1)\left|\frac{p}{q}-u\right|<\frac{1}{qN}. \tag*{(1)}

In particular, if uu is irrational then ∣p/q−u∣<q−2\left|p/q-u\right|<q^{-2} for infinitely many reduced fractions p/qp/q. We give a formulation of this theorem in terms of semigroup actions which leads to natural generalizations.

Let Γ\Gamma be the free semigroup generated by two letters σ\sigma and τ\tau, with identity λ0\lambda_0 (the empty word). Given two maps T0,T1:(0,∞)→(0,∞)T_0,T_1:(0,\infty)\to(0,\infty), we obtain an action of Γ\Gamma on (0,∞)(0,\infty) by letting σ\sigma act as T0T_0 and τ\tau act as T1T_1; words act as compositions, so that (w1w2)(x)=w1(w2(x))(w_1w_2)(x)=w_1(w_2(x)) (the rightmost letter acts first). We write γ∈Γ(T0,T1)\gamma\in\Gamma(T_0,T_1) when we want to emphasize the choice of T0T_0 and T1T_1. The length ∣⋅∣:Γ→Z≥0|\cdot|:\Gamma\to\mathbb{Z}_{\geq0} is defined by ∣λ0∣=0|\lambda_0|=0, ∣σ∣=∣τ∣=1|\sigma|=|\tau|=1 and ∣w1w2∣=∣w1∣+∣w2∣|w_1w_2|=|w_1|+|w_2|. For x,y>0x,y>0 we say that yy is reachable from xx if y=γ(x)y=\gamma(x) for some γ∈Γ\gamma\in\Gamma, and we define the reachability function

R(x,y)=min⁡{∣γ∣:γ∈Γ, γ(x)=y},(2)R(x,y)=\min\{|\gamma|:\gamma\in\Gamma,\ \gamma(x)=y\}, \tag*{(2)}

with R(x,y)=∞R(x,y)=\infty if yy is not reachable from $x.

Definition 1.1. For x>0x > 0 let Γx\Gamma x denote the orbit of xx under Γ(T0,T1)\Gamma(T_0,T_1). Let f:N→(0,∞)f:\mathbb{N}\to(0,\infty) be a non-increasing function with f(n)→0f(n)\to0. We say that Γx\Gamma x is O(f)O(f)-dense in [0,∞)[0,\infty) if for every u≥0u\ge0 there exist a constant C=C(T0,T1,x,u)>0C=C(T_0,T_1,x,u)>0 and infinitely many γ∈Γ\gamma\in\Gamma such that

∣γ(x)−u∣<Cf(∣γ∣).|\gamma(x)-u|<C f(|\gamma|).

Since only finitely many words have a given length, “infinitely many γ\gamma” forces ∣γ∣→∞|\gamma|\to\infty along the approximating words.

The Möbius pair

In Section 2 we take

T0(x)=1x,T1(x)=x+1.(3)T_0(x)=\frac{1}{x},\qquad T_1(x)=x+1. \tag*{(3)}

Here γ(1)\gamma(1) is always a positive rational number, and Lemma 2.2 shows R(1,p/q)≤p+qR(1,p/q)\le p+q; combined with (1) this shows that every irrational uu is approached at rate O(∣γ∣−2)O(|\gamma|^{-2}). We prove Theorem 2.4 that every orbit is O(n−1)O(n^{-1})-dense in [0,∞)[0,\infty), with the rate n−2n^{-2} at irrational targets. We then refine this in two directions. First (Theorem 2.5 and Corollary 2.6), the true rate at an irrational uu is governed by the continued fraction expansion of $u: it is exponential in ∣γ∣|\gamma| when uu has bounded partial quotients, and it is at least exp⁡(−c∣γ∣/log⁡∣γ∣)\exp(-c|\gamma|/\log|\gamma|) for Lebesgue almost every uu, for every c<π2/6c<\pi^2/6. Second (Proposition 2.9), for rational targets and rational starting points the exponent 1 is optimal: by an argument with the Stern–Brocot tree, ∣γ(x)−k/l∣≥1/(l2(s(x)+∣γ∣))|\gamma(x)-k/l|\ge1/(l^2(s(x)+|\gamma|)) whenever γ(x)≠k/l\gamma(x)\ne k/l, where s(x)s(x) is the sum of the partial quotients of xx.

The affine pair

In Section 3 we consider

T0(x)=xa,T1(x)=bx+1,a,b>1.(4)T_0(x)=\frac{x}{a},\qquad T_1(x)=bx+1,\qquad a,b>1. \tag*{(4)}

Bergelson, Misiurewicz and Senti [4] showed that every orbit of this action is dense in [0,∞)[0,\infty). Our main result (Theorem 3.8) is that every orbit is in fact exponentially dense: for every x>0x>0 and u≥0u\ge0 there are infinitely many γ\gamma with ∣γ(x)−u∣<Cλ−∣γ∣|\gamma(x)-u|<C\lambda^{-|\gamma|} where λ=λ(a,b)>1\lambda=\lambda(a,b)>1 is explicit. The proof rests on an explicit normal form for γ(x)\gamma(x) (Lemma 3.1) and a greedy algorithm, and it does not distinguish between rational and irrational values of log⁡ab\log_a b. A counting argument (Proposition 2.11) shows that for almost every uu no rate faster than μ−∣γ∣\mu^{-|\gamma|} with μ>2\mu>2 is possible, so the exponential order is optimal.

We also give corrected versions of two earlier estimates: a Kronecker-type bound ∣γ(x)−u∣<(u+1)(t1/∣γ∣−1)|\gamma(x)-u|<(u+1)(t^{1/|\gamma|}-1) with t=a12b4t=a^{12}b^4 when log⁡ab\log_a b is irrational (Theorem 3.2), and an exponential bound with exponent independent of uu when log⁡ab\log_a b is rational (Theorem 3.6). Since t1/n−1∼(log⁡t)/nt^{1/n}-1\sim(\log t)/n, the Kronecker-type bound is an O(n−1)O(n^{-1}) statement; it is superseded by Theorem 3.8, but its proof is short and the words it produces are very simple.

The contrast between the two sections is worth noting: for the Möbius pair rational targets are approached only at rate n−1n^{-1} (at least from rational starting points), whereas for the affine pair every target is approached exponentially fast.

Relation to the 3x+1 problem

The 3x+13x+1 (Collatz) problem asks whether iterating

f(m)={m/2,m even,3m+1,m odd,f(m)= \begin{cases} m/2, & m\ \text{even},\\ 3m+1, & m\ \text{odd}, \end{cases}

eventually reaches 1 from every positive integer; see [12] for a survey. In our notation, with a=2a=2 and b=3b=3, a Collatz trajectory is a particular orbit segment of Γ(T0,T1)\Gamma(T_0,T_1), namely one in which T0T_0 is applied exactly to even integers and T1T_1 exactly to odd integers. Thus the Collatz conjecture implies that 1 is reachable from every positive integer via Γ(T0,T1)\Gamma(T_0,T_1); the converse is not clear, since the semigroup allows T1T_1 to be applied to even integers as well.

Moreover, any sequence x1,…,xmx_1,\ldots,x_m with x1∈Nx_1 \in\mathbb{N}, xm=1x_m=1 and xi+1∈{T0(xi),T1(xi)}x_{i+1} \in\{T_0(x_i),T_1(x_i)\} consists of integers. Indeed, write v2v_2 for the 2-adic valuation on Q×\mathbb{Q}^{\times}. If v2(xi)<0v_2(x_i)<0 then v2(T0xi)=v2(xi)−1<0v_2(T_0x_i)=v_2(x_i)-1<0 and v2(T1xi)=v2(3xi+1)=v2(xi)<0v_2(T_1x_i)=v_2(3x_i+1)=v_2(x_i)<0, so once a non-integer appears, all later terms are non-integers; since xm=1x_m=1 is an integer, no xix_i can be a non-integer.

Theorem 3.8 shows that, starting from any x>0x>0, there are words γ\gamma of arbitrarily large length nn with ∣γ(x)−1∣<Cλ−n|\gamma(x)-1|<C\lambda^{-n}, where λ=λ(2,3)≈1.2133\lambda=\lambda(2,3)\approx1.2133.

Primes

In § 4 we discuss approximating real numbers by ratios of primes and by ratios of logarithms of primes, updating the discussion in light of the work of Goldston, Pintz and Yıldırım [8, 7], Zhang [18], Maynard [13] and Baker, Harman and Pintz [3].

The Möbius pair

Throughout this section T0(x)=1/xT_0(x)=1/x and T1(x)=x+1T_1(x)=x+1.

Matrices and continued fractions

Associate to T0T_0 and T1T_1 the matrices

Mσ=(0110),Mτ=(1101).M_\sigma=\begin{pmatrix}0&1\\1&0\end{pmatrix},\qquad M_\tau=\begin{pmatrix}1&1\\0&1\end{pmatrix}.

and to a word γ=w1⋯wn\gamma=w_1\cdots w_n the product Mγ=Mw1⋯MwnM_\gamma=M_{w_1}\cdots M_{w_n}. If Mγ=(ABCD)M_\gamma=\begin{pmatrix}A&B\\C&D\end{pmatrix} then A,B,C,DA,B,C,D are non-negative integers, AD−BC=±1AD-BC=\pm1, C+D≥1C+D\ge1, and

γ(z)=Az+BCz+D(z>0).\gamma(z)=\frac{Az+B}{Cz+D}\qquad(z>0).

Every positive rational number rr has a unique canonical continued fraction expansion r=[a0;a1,…,ak]r=[a_0;a_1,\ldots,a_k] with a0≥0a_0\ge0, a1,…,ak≥1a_1,\ldots,a_k\ge1, and either k=0k=0 (and then a0≥1a_0\ge1) or k≥1k\ge1 and $a_k\ge2. We put

s(r)=a0+a1+⋯+ak,ℓ(r)=k.s(r)=a_0+a_1+\cdots+a_k,\qquad\ell(r)=k.

Lemma 2.1. For every positive rational rr we have s(T0r)=s(r)s(T_0r)=s(r) and s(T1r)=s(r)+1s(T_1r)=s(r)+1. Consequently, for every positive rational xx and every γ∈Γ\gamma\in\Gamma,

s(γ(x))=s(x)+(number of occurrences of τ in γ)≤s(x)+∣γ∣.s(\gamma(x))=s(x)+(\text{number of occurrences of }\tau\text{ in }\gamma)\le s(x)+|\gamma|.

Proof. Let r=[a0;a1,…,ak]r=[a_0;a_1,\ldots,a_k] be canonical. Then T1r=[a0+1;a1,…,ak]T_1r=[a_0+1;a_1,\ldots,a_k] is canonical. If a0=0a_0=0 then k≥1k\ge1 and T0r=[a1;a2,…,ak]T_0r=[a_1;a_2,\ldots,a_k] is canonical. If a0≥1a_0\ge1 and k≥1k\ge1, then T0r=[0;a0,a1,…,ak]T_0r=[0;a_0,a_1,\ldots,a_k] is canonical; if a0≥2a_0\ge2 and k=0k=0 then T0r=[0;a0]T_0r=[0;a_0] is canonical; and if r=[1]r=[1] then T0r=rT_0r=r. In all cases the sum of the partial quotients is preserved by T0T_0 and increased by one by T1T_1. □

Lemma 2.2. Let r=[a0;a1,…,ak]r=[a_0;a_1,\ldots,a_k] be a positive rational number in canonical form. Then

s(r)−1≤R(1,r)≤s(r)+ℓ(r)−1.(5)s(r)-1\le R(1,r)\le s(r)+\ell(r)-1. \tag*{(5)}

In particular, if p,qp,q are positive integers then R(1,p/q)≤p+qR(1,p/q)\le p+q.

Proof. The lower bound follows from Lemma 2.1, since s(1)=1s(1)=1 and each word reaching rr from 11 contains at least s(r)−1s(r)-1 letters τ\tau. For the upper bound, put zk=akz_k=a_k and zi=ai+1/zi+1z_i=a_i+1/z_{i+1} for i<ki<k, so that z0=rz_0=r. Then zk=T1ak−1(1)z_k=T_1^{a_k-1}(1) and zi=T1aiT0(zi+1)z_i=T_1^{a_i}T_0(z_{i+1}), so rr is reached from 11 by a word of length (ak−1)+∑i<k(ai+1)=s(r)+k−1(a_k-1)+\sum_{i<k}(a_i+1)=s(r)+k-1.

For the last statement, apply the bound on p+qp+q (one may also deduce it from (5)). If p=qp=q then R(1,p/q)=0R(1,p/q)=0. If p>qp>q then p/q=T1((p−q)/q)p/q=T_1((p-q)/q), so R(1,p/q)≤1+R(1,(p−q)/q)≤1+pR(1,p/q)\le1+R(1,(p-q)/q)\le1+p. If 1<p<q1<p<q then p/q=T0T1((q−p)/p)p/q=T_0T_1((q-p)/p), so R(1,p/q)≤2+R(1,(q−p)/p)≤q+2≤p+qR(1,p/q)\le2+R(1,(q-p)/p)\le q+2\le p+q. Finally, if p=1p=1 then 1/q=T0T1q−1(1)1/q=T_0T_1^{q-1}(1) and R(1,1/q)≤qR(1,1/q)\le q. □

Lemma 2.3. Let γ∈Γ\gamma\in\Gamma and write γ(1)=p/q\gamma(1)=p/q in lowest terms. Then for every ε≥0\varepsilon\ge0,

∣γ(1+ε)−γ(1)∣=εq(q+Cε)≤εq2,\left|\gamma(1+\varepsilon)-\gamma(1)\right|=\frac{\varepsilon}{q(q+C\varepsilon)}\le\frac{\varepsilon}{q^2},

where CC is the lower left entry of MγM_\gamma.

Proof. With Mγ=(ABCD)M_\gamma=\begin{pmatrix} A & B \\ C & D \end{pmatrix} we have γ(1)=(A+B)/(C+D)\gamma(1)=(A+B)/(C+D), and this fraction is in lowest terms because AD−BC=±1AD-BC=\pm1; thus p=A+Bp=A+B and q=C+Dq=C+D. Then

γ(1+ε)−γ(1)=(A+B)+Aε(C+D)+Cε−A+BC+D=ε(AD−BC)(C+D)(C+D+Cε),\gamma(1+\varepsilon)-\gamma(1)=\frac{(A+B)+A\varepsilon}{(C+D)+C\varepsilon}-\frac{A+B}{C+D}=\frac{\varepsilon(AD-BC)}{(C+D)(C+D+C\varepsilon)},

which gives the claim. □

Density

Define Q:[0,∞)→{1,2}Q:[0,\infty)\to\{1,2\} by Q(u)=1Q(u)=1 if uu is rational and Q(u)=2Q(u)=2 if uu is irrational.

Theorem 2.4. For every x>0x>0 the orbit Γx\Gamma x is O(n−1)O(n^{-1})-dense in [0,∞)[0,\infty). More precisely, for every x>0x>0 and u≥0u\ge0 there exist C=C(x,u)>0C=C(x,u)>0 and infinitely many γ∈Γ\gamma\in\Gamma such that

∣γ(x)−u∣<C∣γ∣−Q(u).(6)|\gamma(x)-u|<C|\gamma|^{-Q(u)}. \tag*{(6)}

Proof. Reduction. If x<1x<1, replace xx by T1(x)=x+1T_1(x)=x+1; a word γ\gamma for x+1x+1 gives the word γτ\gamma\tau for xx, of length ∣γ∣+1≤2∣γ∣|\gamma|+1\le2|\gamma|. So we may assume x=1+εx=1+\varepsilon with ε≥0\varepsilon\ge0.

The case u=0u=0. For m≥1m\ge1 let γ=στm\gamma=\sigma\tau^m. Then γ(x)=1/(x+m)<1/m<2/∣γ∣\gamma(x)=1/(x+m)<1/m<2/|\gamma|.

Rational u=k/l>0u=k/l>0. For m≥1m\ge1 put rm=(km+1)/(lm)r_m=(km+1)/(lm), so rm−u=1/(lm)r_m-u=1/(lm). By Lemma 2.2 there is γm\gamma_m with γm(1)=rm\gamma_m(1)=r_m and ∣γm∣≤(k+l)m+1≤(k+l+1)m|\gamma_m|\le(k+l)m+1\le(k+l+1)m. Since gcd⁡(km+1,m)=1\gcd(km+1,m)=1, the reduced denominator qmq_m of rmr_m is at least lm/gcd⁡(km+1,l)≥mlm/\gcd(km+1,l)\ge m. By Lemma 2.3,

∣γm(x)−u∣≤εqm2+1lm≤ε+1m≤x(k+l+1)∣γm∣.|\gamma_m(x)-u|\le\frac{\varepsilon}{q_m^2}+\frac{1}{lm}\le\frac{\varepsilon+1}{m}\le\frac{x(k+l+1)}{|\gamma_m|}.

The rmr_m are distinct, so the γm\gamma_m are distinct. (In the original version of this argument one took rm=(klm+1)/lm+1r_m=(klm+1)/l^{m+1}; this fails when uu is an integer, since then l=1l=1 and rmr_m does not depend on mm.)

Irrational uu. This follows from Corollary 2.6(a) below. □

Irrational targets and continued fractions

Let u=[a0;a1,a2,…]u=[a_0;a_1,a_2,\ldots] be irrational, with convergents pk/qkp_k/q_k, and put Sk=a0+a1+⋯+akS_k=a_0+a_1+\cdots+a_k.

Theorem 2.5. Let u>0u>0 be irrational and x>0x>0. For every k≥1k\ge1 there is γk∈Γ\gamma_k\in\Gamma with

∣γk∣≤Sk+kand∣γk(x)−u∣<x+1qk2.|\gamma_k|\le S_k+k\qquad\text{and}\qquad|\gamma_k(x)-u|<\frac{x+1}{q_k^2}.

Proof. The canonical expansion of pk/qkp_k/q_k is either [a0;…,ak][a_0;\ldots,a_k] (if ak≥2a_k\ge2) or [a0;…,ak−1+1][a_0;\ldots,a_{k-1}+1] (if ak=1a_k=1); in both cases its partial quotients sum to SkS_k and it has at most kk terms after a0a_0. By Lemma 2.2 there is δk\delta_k with δk(1)=pk/qk\delta_k(1)=p_k/q_k and ∣δk∣≤Sk+k−1|\delta_k|\le S_k+k-1. Recall ∣pk/qk−u∣<1/(qkqk+1)≤1/qk2|p_k/q_k-u|<1/(q_kq_{k+1})\le1/q_k^2.

If x=1+ε≥1x=1+\varepsilon\ge1, let γk=δk\gamma_k=\delta_k; by Lemma 2.3, ∣γk(x)−u∣<(ε+1)/qk2=x/qk2|\gamma_k(x)-u|<(\varepsilon+1)/q_k^2=x/q_k^2. If x<1x<1, let γk=δkτ\gamma_k=\delta_k\tau, so that γk(x)=δk(1+x)\gamma_k(x)=\delta_k(1+x) and ∣γk(x)−u∣<(1+x)/qk2|\gamma_k(x)-u|<(1+x)/q_k^2. □

Corollary 2.6. Let x>0x>0 and let u=[a0;a1,…]u=[a_0;a_1,\ldots] be irrational.

(a) There is C=C(x,u)C=C(x,u) such that ∣γ(x)−u∣<C∣γ∣−2|\gamma(x)-u|<C|\gamma|^{-2} for infinitely many γ\gamma.

(b) If ai≤Aa_i \le A for all i≥1i \ge1, then ∣γ(x)−u∣<Cφ−2∣γ∣/(A+1)|\gamma(x)-u| < C\varphi^{-2|\gamma|/(A+1)} for infinitely many γ\gamma, where φ=(1+5)/2\varphi=(1+\sqrt{5})/2 and C=C(x,u)C=C(x,u).

(c) For Lebesgue almost every u>0u>0 and every c<π2/6c<\pi^2/6, there are infinitely many γ\gamma with ∣γ(x)−u∣<exp⁡(−c∣γ∣/log⁡∣γ∣)|\gamma(x)-u|<\exp(-c|\gamma|/\log|\gamma|).

Proof. (a) We have q1=a1q_1=a_1 and, for k≥2k\ge2, qk=akqk−1+qk−2≥(ak+qk−1−1)+qk−2≥ak+qk−1q_k=a_kq_{k-1}+q_{k-2}\ge(a_k+q_{k-1}-1)+q_{k-2}\ge a_k+q_{k-1}, using (ak−1)(qk−1−1)≥0(a_k-1)(q_{k-1}-1)\ge0 and qk−2≥1q_{k-2}\ge1. Hence qk≥a1+⋯+ak=Sk−a0≥kq_k\ge a_1+\cdots+a_k=S_k-a_0\ge k, and

∣γk∣≤Sk+k≤a0+2qk.|\gamma_k|\le S_k+k\le a_0+2q_k.

By Theorem 2.5, ∣γk(x)−u∣<(x+1)qk−2≤4(x+1)(∣γk∣−a0)−2|\gamma_k(x)-u|<(x+1)q_k^{-2}\le4(x+1)(|\gamma_k|-a_0)^{-2}, which is at most C∣γk∣−2C|\gamma_k|^{-2} for kk large. The words γk\gamma_k are pairwise distinct, because the values δk(1)=pk/qk\delta_k(1)=p_k/q_k are distinct.

(b) Now qk≥φk−1q_k\ge\varphi^{k-1} and ∣γk∣≤a0+(A+1)k|\gamma_k|\le a_0+(A+1)k, so

qk−2≤φ2φ−2k≤φ2+2a0/(A+1)φ−2∣γk∣/(A+1).q_k^{-2}\le\varphi^2\varphi^{-2k}\le\varphi^{2+2a_0/(A+1)}\varphi^{-2|\gamma_k|/(A+1)}.

(c) By Lévy’s theorem, 1klog⁡qk→β:=π212log⁡2\frac{1}{k}\log q_k\to\beta:=\frac{\pi^2}{12\log2} for almost every uu. By Khinchin’s weak law for the sums of partial quotients, Sk/(klog⁡k)→1/log⁡2S_k/(k\log k)\to1/\log2 in measure; hence there is a fixed sequence kj→∞k_j\to\infty along which Skj/(kjlog⁡kj)→1/log⁡2S_{k_j}/(k_j\log k_j)\to1/\log2 almost everywhere (see [10, 11]).

Fix η>0\eta>0 and such a uu. For jj large, nj:=∣γkj∣≤(1+η)kjlog⁡kj/log⁡2n_j:=|\gamma_{k_j}|\le(1+\eta)k_j\log k_j/\log2, hence kj≥log⁡21+ηnjlog⁡njk_j\ge\frac{\log2}{1+\eta}\frac{n_j}{\log n_j} (as kj≤njk_j\le n_j), and

∣γkj(x)−u∣<(x+1)e−2(1−η)βkj≤(x+1)exp⁡(−π261−η1+ηnjlog⁡nj).|\gamma_{k_j}(x)-u|<(x+1)e^{-2(1-\eta)\beta k_j}\le(x+1)\exp\left(-\frac{\pi^2}{6}\frac{1-\eta}{1+\eta}\frac{n_j}{\log n_j}\right).

Choosing η\eta small in terms of c<π2/6c<\pi^2/6 gives the claim. □

Remark 2.7. Part (a) is the estimate ∣γ(x)−u∣≤C∣γ∣−2|\gamma(x)-u|\le C|\gamma|^{-2} asserted for irrational uu in Theorem 2.4. Parts (b) and (c) show that it is far from optimal for most uu; for instance, for the golden ratio the orbit of 11 approaches φ\varphi exponentially fast. On the other hand, by Proposition 2.11 below, for almost every uu no rate μ−∣γ∣\mu^{-|\gamma|} with μ>2\mu>2 is possible.

Optimality for rational targets

We use the Stern–Brocot tree (see [9 §4.5]). Its nodes are the positive rationals, each occurring exactly once; the root is 1/11/1, and the node r=[a0;a1,…,ak]r=[a_0;a_1,\ldots,a_k] (canonical) has depth s(r)−1s(r)-1. Every node u=k/lu=k/l has a nearest left ancestor kL/lL<uk_L/l_L<u and a nearest right ancestor kR/lR>uk_R/l_R>u (with the conventions 0/10/1 and 1/01/0 at the boundary) such that k=kL+kRk=k_L+k_R, l=lL+lRl=l_L+l_R and klL−lkL=kRl−lRk=1kl_L-lk_L=k_Rl-l_Rk=1; moreover, the rationals in the open interval (kL/lL,kR/lR)(k_L/l_L,k_R/l_R) are exactly the nodes of the subtree rooted at uu.

Lemma 2.8. Let u=k/l≥0u=k/l\ge0 be rational in lowest terms and let r>0r>0 be rational with r≠ur\ne u. Then

∣r−u∣≥1l2s(r).|r-u|\ge\frac{1}{l^2s(r)}.

Proof. If u=0u=0 (so l=1l=1): if r≥1r\ge1 then r≥1≥1/s(r)r\ge1\ge1/s(r); otherwise r=[0;a1,…,am]r=[0;a_1,\ldots,a_m] with s(r)=a1+⋯+ams(r)=a_1+\cdots+a_m, and r=1/a1≥1/s(r)r=1/a_1\ge1/s(r) if m=1m=1, while r>1/(a1+1)≥1/s(r)r>1/(a_1+1)\ge1/s(r) if m≥2m\ge2 (as then $a_m\ge2).

Let u>0u>0, let d0d_0 be the depth of uu, and let D=s(r)−1D=s(r)-1 be the depth of rr. If r∉(kL/lL,kR/lR)r\notin(k_L/l_L,k_R/l_R) then ∣r−u∣≥min⁡{1/(llL),1/(llR)}≥1/l2|r-u|\ge\min\{1/(ll_L),1/(ll_R)\}\ge1/l^2 since lL,lR≤ll_L,l_R\le l. Otherwise rr lies in the subtree of uu; suppose r<ur<u (the case r>ur>u is symmetric). The nodes cj=(kL+jk)/(lL+jl)c_j=(k_L+jk)/(l_L+jl), j≥1j\ge1, form the right spine of the left subtree of uu; cjc_j has depth d0+jd_0+j, and the rationals in (cj,u)(c_j,u) are exactly the nodes of the subtree rooted at cj+1c_{j+1}, all of depth at least d0+j+1d_0+j+1. Here D≥d0+1D\ge d_0+1; taking j=D−d0≥1j=D-d_0\ge1, the node rr is not in (cj,u)(c_j,u), so r≤cjr\le c_j

and therefore

u−r≥u−cj=klL−lkLl(lL+jl)=1l(lL+jl)≥1l2(j+1)≥1l2(D+1)=1l2s(r).u-r \ge u-c_j=\frac{kl_L-lk_L}{l(l_L+jl)}=\frac{1}{l(l_L+jl)}\ge\frac{1}{l^2(j+1)}\ge\frac{1}{l^2(D+1)}=\frac{1}{l^2s(r)}.

where we used lL≤ll_L\le l and j+1≤D+1j+1\le D+1.

Proposition 2.9. Let x>0x>0 be rational and u=k/l≥0u=k/l\ge0 rational in lowest terms. Then for every γ∈Γ\gamma\in\Gamma with γ(x)≠u\gamma(x)\ne u,

∣γ(x)−u∣≥1l2(s(x)+∣γ∣).|\gamma(x)-u|\ge\frac{1}{l^2(s(x)+|\gamma|)}.

In particular, the exponent Q(u)=1Q(u)=1 in Theorem 2.4 cannot be improved when xx and uu are rational.

Proof. Combine Lemma 2.8 with Lemma 2.1.

Remark. 2.10. We expect the same lower bound, with a constant depending on xx, for irrational starting points xx, but we have not proved it.

A general upper limit on the rate

The following observation applies to any pair of maps.

Proposition 2.11. Let T0,T1:(0,∞)→(0,∞)T_0,T_1:(0,\infty)\to(0,\infty) be arbitrary, let x>0x>0 and let μ>2\mu>2. Then for Lebesgue almost every u≥0u\ge0 there are only finitely many γ∈Γ(T0,T1)\gamma\in\Gamma(T_0,T_1) with ∣γ(x)−u∣<μ−∣γ∣|\gamma(x)-u|<\mu^{-|\gamma|}.

Proof. Let Iγ=(γ(x)−μ−∣γ∣,γ(x)+μ−∣γ∣)I_\gamma=(\gamma(x)-\mu^{-|\gamma|},\gamma(x)+\mu^{-|\gamma|}). There are 2n2^n words of length nn, so ∑γ∣Iγ∣=∑n2n⋅2μ−n<∞\sum_\gamma|I_\gamma|=\sum_n2^n\cdot2\mu^{-n}<\infty, and the Borel–Cantelli lemma shows that almost every uu lies in only finitely many IγI_\gamma.

The affine pair

Throughout this section T0(x)=x/aT_0(x)=x/a and T1(x)=bx+1T_1(x)=bx+1 with a,b>1a,b>1, and σ,τ\sigma,\tau act as T0,T1T_0,T_1. We put α=log⁡ab>0\alpha=\log_a b>0.

A normal form

Lemma 3.1. Let γ∈Γ\gamma\in\Gamma contain NN letters τ\tau and MM letters σ\sigma. For 0≤j<N0\le j<N let ℓj\ell_j be the number of letters σ\sigma to the left of the (j+1)(j+1)-st letter τ\tau, counted from the left. Then 0≤ℓ0≤ℓ1≤⋯≤ℓN−1≤M0\le\ell_0\le\ell_1\le\cdots\le\ell_{N-1}\le M and

γ(x)=bNaMx+∑j=0N−1bjaℓj(x∈R).(7)\gamma(x)=\frac{b^N}{a^M}x+\sum_{j=0}^{N-1}\frac{b^j}{a^{\ell_j}}\qquad(x\in\mathbb{R}). \tag*{(7)}

Conversely, for all integers N≥0N\ge0 and 0≤ℓ0≤⋯≤ℓN−1≤M0\le\ell_0\le\cdots\le\ell_{N-1}\le M, the word γ=σℓ0τσℓ1−ℓ0τ⋯σℓN−1−ℓN−2τσM−ℓN−1\gamma=\sigma^{\ell_0}\tau\sigma^{\ell_1-\ell_0}\tau\cdots\sigma^{\ell_{N-1}-\ell_{N-2}}\tau\sigma^{M-\ell_{N-1}} has length N+MN+M and satisfies (7).

Proof. Write γ=w1⋯wL\gamma=w_1\cdots w_L. Each TiT_i is affine, T0′=1/aT_0'=1/a and T1′=bT_1'=b, so γ′=bNa−M\gamma'=b^Na^{-M}. The constant term of γ\gamma is the sum, over the positions ii with wi=τw_i=\tau, of the constant 11 of T1T_1 multiplied by the derivative of w1⋯wi−1w_1\cdots w_{i-1}. If wiw_i is the (j+1)(j+1)-st τ\tau from the left, this derivative is bja−ℓjb^ja^{-\ell_j}. The converse is immediate.

The Kronecker-type estimate

We use the following inhomogeneous form of Kronecker’s theorem ([5, Ch. III, Thm. II], [16, §2.4]): if α\alpha is irrational and β∈R\beta\in\mathbb{R}, then there are infinitely many pairs of integers (m,n)(m,n) with m>0m > 0 and

∣mα−n−β∣<3m.(8)|m\alpha-n-\beta|<\frac{3}{m}. \tag*{(8)}

Theorem 3.2. Suppose α=log⁡ab\alpha=\log_a b is irrational, and put t=a12b4t=a^{12}b^4. Then for every x>0x>0 and u≥0u\geq0 there are infinitely many γ∈Γ\gamma\in\Gamma with

∣γ(x)−u∣<(u+1)(t1/∣γ∣−1).(9)|\gamma(x)-u|<(u+1)(t^{1/|\gamma|}-1). \tag*{(9)}

Proof. If u=0u=0, then γ=σm\gamma=\sigma^m gives γ(x)=xa−m<t1/m−1\gamma(x)=xa^{-m}<t^{1/m}-1 for mm large. Let u>0u>0 and β=log⁡a((b−1)u)\beta=\log_a((b-1)u). By (8) there are infinitely many pairs of positive integers (m,n)(m,n) with

∣mα−n−β∣<3m,(10)|m\alpha-n-\beta|<\frac{3}{m}, \tag*{(10)}

and since ∣log⁡a(bm−1)−mα∣=∣log⁡a(1−b−m)∣<1/m|\log_a(b^m-1)-m\alpha|=|\log_a(1-b^{-m})|<1/m for mm large,

∣log⁡a(bm−1)−n−β∣<4m.(11)|\log_a(b^m-1)-n-\beta|<\frac{4}{m}. \tag*{(11)}

Let η=σnτm−1\eta=\sigma^n\tau^{m-1}. Since τm−1(1)=(bm−1)/(b−1)\tau^{m-1}(1)=(b^m-1)/(b-1), we have η(1)=(bm−1)/((b−1)an)\eta(1)=(b^m-1)/((b-1)a^n), and (11) says ∣log⁡aη(1)−log⁡au∣<4/m|\log_a\eta(1)-\log_a u|<4/m. Hence

∣η(1)−u∣<u(a4/m−1).|\eta(1)-u|<u(a^{4/m}-1).

Now let γ=ητσm=σnτmσm\gamma=\eta\tau\sigma^m=\sigma^n\tau^m\sigma^m, so that γ(x)=η(bxa−m+1)\gamma(x)=\eta(bxa^{-m}+1). Since η\eta is affine with derivative bm−1a−nb^{m-1}a^{-n},

∣γ(x)−η(1)∣=bmxam+n≤(b−1)uxa3/m−m,|\gamma(x)-\eta(1)|=\frac{b^m x}{a^{m+n}}\leq(b-1)ux a^{3/m-m},

using bma−n=amα−n<(b−1)ua3/mb^m a^{-n}=a^{m\alpha-n}<(b-1)ua^{3/m} from (10). The right side is exponentially small in mm, so for mm large

∣γ(x)−u∣≤(b−1)uxa3/m−m+u(a4/m−1)<(u+1)(a4/m−1).|\gamma(x)-u|\leq(b-1)uxa^{3/m-m}+u(a^{4/m}-1)<(u+1)(a^{4/m}-1).

Finally, (10) gives n<(α+1)mn<(\alpha+1)m for mm large, hence ∣γ∣=2m+n<(α+3)m|\gamma|=2m+n<(\alpha+3)m, and

a4/m<a4(α+3)/∣γ∣=(a12b4)1/∣γ∣.a^{4/m}<a^{4(\alpha+3)/|\gamma|}=(a^{12}b^4)^{1/|\gamma|}.

Remark 3.3. Since t1/n−1∼(log⁡t)/nt^{1/n}-1\sim(\log t)/n, Theorem 3.2 says that every orbit is O(n−1)O(n^{-1})-dense, with the explicit constant ∣γ(x)−u∣≲4(u+1)(3log⁡a+log⁡b)/∣γ∣|\gamma(x)-u|\lesssim4(u+1)(3\log a+\log b)/|\gamma|.

Rational log⁡ab\log_a b

Lemma 3.4. Let a>1a>1 and u>0u>0. There are non-negative integers d0,d1,…d_0,d_1,\ldots with d0<ud_0<u and di≤⌈a⌉−1<ad_i\leq\lceil a\rceil-1<a for i≥1i\geq1, such that

0<u−∑i=0kdia−i≤a−kfor all k≥0,(12)0<u-\sum_{i=0}^{k}d_i a^{-i}\leq a^{-k}\qquad\text{for all }k\geq0, \tag*{(12)}

and dk>0d_k>0 for infinitely many $k.

Proof. Let d0=⌈u−1⌉d_0=\lceil u-1\rceil and ρ0=u−d0∈(0,1]\rho_0=u-d_0\in(0,1]. Given ρk∈(0,a−k]\rho_k\in(0,a^{-k}], let dk+1=⌈ρkak+1−1⌉d_{k+1}=\lceil\rho_k a^{k+1}-1\rceil and ρk+1=ρk−dk+1a−k−1\rho_{k+1}=\rho_k-d_{k+1}a^{-k-1}. Since 0<ρkak+1≤a0<\rho_k a^{k+1}\leq a, we get 0≤dk+1<ρkak+1≤a0\leq d_{k+1}<\rho_k a^{k+1}\leq a and ρk+1=a−k−1(ρkak+1−dk+1)∈(0,a−k−1]\rho_{k+1}=a^{-k-1}(\rho_k a^{k+1}-d_{k+1})\in(0,a^{-k-1}]. If dk=0d_k=0 for all k≥Kk\geq K, then ρk=ρK>0\rho_k=\rho_K>0 for k≥Kk\geq K, contradicting ρk≤a−k→0\rho_k\leq a^{-k}\to0. □\square

Lemma 3.5. Suppose a=b>1a=b>1 and let d0,…,dkd_0,\ldots,d_k be non-negative integers with dk>0d_k>0. Then there is η∈Γ\eta\in\Gamma with η(1)=∑i=0kdia−i\eta(1)=\sum_{i=0}^{k}d_i a^{-i}, ∣η∣≤k+2∑i=0kdi|\eta|\le k+2\sum_{i=0}^{k}d_i, and η′=a−k\eta'=a^{-k}.

Proof. Note τσ(z)=z+1\tau\sigma(z)=z+1. For k=0k=0 take η=(τσ)d0−1\eta=(\tau\sigma)^{d_0-1}. For the inductive step write P=∑i=0k+1dia−i=d0+Q/aP=\sum_{i=0}^{k+1}d_i a^{-i}=d_0+Q/a with Q=∑i=0kdi+1a−iQ=\sum_{i=0}^{k}d_{i+1}a^{-i}; if μ(1)=Q\mu(1)=Q with ∣μ∣≤k+2∑i≥1di|\mu|\le k+2\sum_{i\ge1}d_i and μ′=a−k\mu'=a^{-k}, then η=(τσ)d0σμ\eta=(\tau\sigma)^{d_0}\sigma\mu satisfies η(1)=P\eta(1)=P, ∣η∣≤k+1+2∑i≥0di|\eta|\le k+1+2\sum_{i\ge0}d_i and η′=a−k−1\eta'=a^{-k-1}.

Theorem 3.6. Suppose log⁡ab=n0/m0\log_a b=n_0/m_0 with m0,n0m_0,n_0 positive integers, and put A=am0=bn0A=a^{m_0}=b^{n_0} and

ρ=A1/((2A+1)max⁡{m0,n0})>1.\rho=A^{1/((2A+1)\max\{m_0,n_0\})}>1.

Then for every x>0x>0 and u≥0u\ge0 there are C=C(a,b,x,u)C=C(a,b,x,u) and infinitely many γ∈Γ\gamma\in\Gamma with

∣γ(x)−u∣<Cρ−∣γ∣.|\gamma(x)-u|<C\rho^{-|\gamma|}.

In particular, if a=ba=b one may take ρ=a1/(2a+1)\rho=a^{1/(2a+1)}.

Proof. The case a=ba=b. If u=0u=0, use γ=σM\gamma=\sigma^M. Let u>0u>0 and let did_i be as in Lemma 3.4. For each kk with dk>0d_k>0, Lemma 3.5 gives γk\gamma_k with γk(1)=∑i≤kdia−i\gamma_k(1)=\sum_{i\le k}d_i a^{-i}, γk′=a−k\gamma_k'=a^{-k} and

∣γk∣≤k+2d0+2k(⌈a⌉−1)≤(2a+1)k+2u.|\gamma_k|\le k+2d_0+2k(\lceil a\rceil-1)\le(2a+1)k+2u.

Then

∣γk(x)−u∣≤γk′∣x−1∣+∣γk(1)−u∣≤(∣x−1∣+1)a−k≤(x+2)a2u/(2a+1)a−∣γk∣/(2a+1).|\gamma_k(x)-u|\le\gamma_k'|x-1|+|\gamma_k(1)-u|\le(|x-1|+1)a^{-k}\le(x+2)a^{2u/(2a+1)}a^{-|\gamma_k|/(2a+1)}.

The values γk(1)\gamma_k(1) are strictly increasing in kk, so the γk\gamma_k are distinct.

The general case. Let c=∑i=0n0−1bic=\sum_{i=0}^{n_0-1}b^i and θ(z)=cz\theta(z)=cz. Then

S0:=θ−1∘T0m0∘θ:z↦z/A,S1:=θ−1∘T1n0∘θ:z↦Az+1,S_0:=\theta^{-1}\circ T_0^{m_0}\circ\theta:z\mapsto z/A,\qquad S_1:=\theta^{-1}\circ T_1^{n_0}\circ\theta:z\mapsto Az+1,

because T1n0(y)=bn0y+cT_1^{n_0}(y)=b^{n_0}y+c. Applying the first case to (S0,S1)(S_0,S_1), with base AA, to v=x/cv=x/c and w=u/cw=u/c, we get infinitely many words μ\mu in S0,S1S_0,S_1 with ∣μ(v)−w∣<C′A−∣μ′∣/(2A+1)|\mu(v)-w|<C'A^{-|\mu'|/(2A+1)}, where ∣μ′∣|\mu'| is the length in S0,S1S_0,S_1. Each such μ\mu equals θ−1γθ\theta^{-1}\gamma\theta for a word γ\gamma in T0,T1T_0,T_1 with ∣γ∣≤max⁡{m0,n0}∣μ′∣|\gamma|\le\max\{m_0,n_0\}|\mu'|, and ∣γ(x)−u∣=c∣μ(v)−w∣|\gamma(x)-u|=c|\mu(v)-w|.

Remark 3.7. The original version of this theorem gave the bound exp⁡(−C∣γ∣/(u+1))\exp(-C|\gamma|/(u+1)), whose exponent deteriorates as uu grows; the estimate ∣γk∣≤(2a+1)k+2u|\gamma_k|\le(2a+1)k+2u shows that uu only affects the constant. (Also, in the case u=0u=0 the original choice of constant C=1/2C=1/2 fails when a<e1/2a<e^{1/2}.)

Exponential density for all a,b>1a,b>1

Theorem 3.8. Let a,b>1a,b>1 and put

κ=log⁡aaba−1,λ=(aa−1)1/(1+κ)=exp⁡(log⁡alog⁡aa−1log⁡a2ba−1)>1.\kappa=\log_a\frac{ab}{a-1},\qquad\lambda=\left(\frac{a}{a-1}\right)^{1/(1+\kappa)}=\exp\left(\frac{\log a\log\frac{a}{a-1}}{\log\frac{a^2b}{a-1}}\right)>1.

Then for every x>0x>0 and u≥0u\ge0 there are C=C(a,b,x,u)C=C(a,b,x,u) and infinitely many γ∈Γ\gamma\in\Gamma such that

∣γ(x)−u∣<Cλ−∣γ∣.(13)|\gamma(x)-u|<C\lambda^{-|\gamma|}. \tag*{(13)}

In particular, every orbit is O(λ−n)O(\lambda^{-n})-dense in [0,∞)[0,\infty).

Proof. The case u=0u=0. We have log⁡λ≤log⁡a\log\lambda\le\log a, because log⁡aa−1≤log⁡a2ba−1\log\frac{a}{a-1} \le\log\frac{a^{2b}}{a-1}. So γ=σM\gamma=\sigma^{M} gives

γ(x)=xa−M≤xλ−M.\gamma(x)=xa^{-M}\le x\lambda^{-M}.

A greedy expansion. Let u>0u>0. Set ℓ−1=0\ell_{-1}=0 and r−1=ur_{-1}=u. For j=0,1,2,…j=0,1,2,\ldots, given an integer ℓj−1\ell_{j-1} and rj−1>0r_{j-1}>0, let ℓj∗\ell_j^* be the least integer ℓ\ell with bja−ℓ<rj−1b^j a^{-\ell}<r_{j-1}, and put

ℓj=max⁡{ℓj−1,ℓj∗},tj=bja−ℓj,rj=rj−1−tj.\ell_j=\max\{\ell_{j-1},\ell_j^*\},\qquad t_j=b^j a^{-\ell_j},\qquad r_j=r_{j-1}-t_j.

Since ℓj≥ℓj∗\ell_j\ge\ell_j^* we have tj<rj−1t_j<r_{j-1}, so rj>0r_j>0 and the recursion continues; also 0=ℓ−1≤ℓ0≤ℓ1≤⋯0=\ell_{-1}\le\ell_0\le\ell_1\le\cdots and rj=u−∑i≤jtir_j=u-\sum_{i\le j}t_i. Call step jj free if ℓj=ℓj∗\ell_j=\ell_j^*.

(i) If step jj is free, then tj≥rj−1/at_j\ge r_{j-1}/a; hence rj≤(1−1/a)rj−1r_j\le(1-1/a)r_{j-1} and rj≤(a−1)tjr_j\le(a-1)t_j. Indeed, by minimality of ℓj∗\ell_j^*, atj=bja−(ℓj∗−1)≥rj−1a t_j=b^j a^{-(\ell_j^*-1)}\ge r_{j-1}.

(ii) If step jj is free, so is step j+1j+1. We must show ℓj+1∗≥ℓj\ell_{j+1}^*\ge\ell_j, i.e. that ℓ=ℓj−1\ell=\ell_j-1 violates bj+1a−ℓ<rjb^{j+1}a^{-\ell}<r_j. But bj+1a−(ℓj−1)=abtj>(a−1)tj≥rjb^{j+1}a^{-(\ell_j-1)}=ab t_j>(a-1)t_j\ge r_j by (i).

(iii) Some step is free. If steps 0,…,j0,\ldots,j are not free, then ℓ0=⋯=ℓj=0\ell_0=\cdots=\ell_j=0 and ti=bit_i=b^i, so 1+b+⋯+bj<u1+b+\cdots+b^j<u. Hence the first free step JJ satisfies bJ≤1+(b−1)ub^J\le1+(b-1)u.

By (i)–(iii), for every N>JN>J,

rN−1≤u(1−1a)N−JandrN−1≤(a−1)tN−1=a−1bbNa−ℓN−1.(14)r_{N-1}\le u\left(1-\frac{1}{a}\right)^{N-J} \qquad\text{and}\qquad r_{N-1}\le(a-1)t_{N-1}=\frac{a-1}{b}b^N a^{-\ell_{N-1}}. \tag*{(14)}

The words. For N>JN>J let MN=max⁡{ℓN−1,⌈κN⌉}M_N=\max\{\ell_{N-1},\lceil\kappa N\rceil\} and let γN\gamma_N be the word of Lemma 3.1 with data NN, ℓ0≤⋯≤ℓN−1\ell_0\le\cdots\le\ell_{N-1} and M=MNM=M_N. Then L:=∣γN∣=N+MNL:=|\gamma_N|=N+M_N and

γN(x)=bNa−MNx+u−rN−1,so∣γN(x)−u∣≤xbNa−MN+rN−1.\gamma_N(x)=b^N a^{-M_N}x+u-r_{N-1}, \qquad\text{so}\qquad |\gamma_N(x)-u|\le xb^N a^{-M_N}+r_{N-1}.

Put ϑ=κ−α=log⁡aaa−1>0\vartheta=\kappa-\alpha=\log_a\frac{a}{a-1}>0, so that a−ϑ=1−1/aa^{-\vartheta}=1-1/a and λ=aϑ/(1+κ)\lambda=a^{\vartheta/(1+\kappa)}.

Case MN=ℓN−1M_N=\ell_{N-1}. By (14), ∣γN(x)−u∣≤(x+a−1b)aNα−MN|\gamma_N(x)-u|\le\left(x+\frac{a-1}{b}\right)a^{N\alpha-M_N}. Since MN≥κNM_N\ge\kappa N and ϑ+α=κ\vartheta+\alpha=\kappa, a direct computation gives

(1+κ)(MN−Nα)−ϑ(N+MN)=(1+α)(MN−κN)≥0,(1+\kappa)(M_N-N\alpha)-\vartheta(N+M_N)=(1+\alpha)(M_N-\kappa N)\ge0,

that is, MN−Nα≥ϑL/(1+κ)M_N-N\alpha\ge\vartheta L/(1+\kappa). Hence ∣γN(x)−u∣≤(x+a−1b)λ−L|\gamma_N(x)-u|\le\left(x+\frac{a-1}{b}\right)\lambda^{-L}.

Case MN=⌈κN⌉>ℓN−1M_N=\lceil\kappa N\rceil>\ell_{N-1}. Then bNa−MN≤a−ϑN=(1−1/a)Nb^N a^{-M_N}\le a^{-\vartheta N}=(1-1/a)^N, and by (14),

∣γN(x)−u∣≤(x+u(aa−1)J)(1−1a)N.|\gamma_N(x)-u|\le\left(x+u\left(\frac{a}{a-1}\right)^J\right)\left(1-\frac{1}{a}\right)^N.

As L≤(1+κ)N+1L\le(1+\kappa)N+1, we have (1−1/a)N=λ−(1+κ)N≤λ1−L(1-1/a)^N=\lambda^{-(1+\kappa)N}\le\lambda^{1-L}.

In both cases ∣γN(x)−u∣≤Cλ−∣γN∣|\gamma_N(x)-u|\le C\lambda^{-|\gamma_N|} with C=λ(x+u(aa−1)J)+a−1bC=\lambda\left(x+u\left(\frac{a}{a-1}\right)^J\right)+\frac{a-1}{b}, and the words γN\gamma_N, N>JN>J, are distinct since they contain different numbers of letters τ\tau. Replacing CC by 2C2C gives strict inequality. □

Remark 3.9. (1) Theorem 3.8 makes no use of the arithmetic of log⁡ab\log_a b, and it supersedes Theorem 3.2 and, for small aa, Theorem 3.6. For instance, λ(2,3)≈1.2133\lambda(2,3)\approx1.2133 and λ(2,2)=21/3\lambda(2,2)=2^{1/3}, whereas Theorem 3.6 gives ρ=21/5\rho=2^{1/5} when a=b=2a=b=2; for a=b=10a=b=10, on the other hand, Theorem 3.6 gives the larger base 101/21≈1.11610^{1/21}\approx1.116 against λ≈1.053\lambda\approx1.053.

(2) By Proposition 2.11, for almost every uu the base λ\lambda in (13) can never exceed 22; thus exponential density is the optimal order, although we have not tried to optimize λ\lambda. Numerical experiments suggest that the greedy words of the proof perform considerably better than the bound λ−∣γ∣\lambda^{-|\gamma|}.

(3) The constant CC depends on uu only through u(aa−1)J≤u(1+(b−1)u)log⁡baa−1u\left(\frac{a}{a-1}\right)^J\le u(1+(b-1)u)^{\log_b\frac{a}{a-1}}, a polynomial in uu.

Prime approximation of real numbers

Let pnp_n denote the nn-th prime. Goldston, Pintz and Yıldırım [8] (see also [7]) proved that

lim inf⁡n→∞pn+1−pnlog⁡pn=0,(15)\liminf_{n\to\infty}\frac{p_{n+1}-p_n}{\log p_n}=0, \tag*{(15)}

equivalently ∣pn+1/pn−1∣=o(log⁡pn/pn)|p_{n+1}/p_n-1|=o(\log p_n/p_n) for infinitely many nn. Zhang [18] proved that lim inf⁡(pn+1−pn)<∞\liminf(p_{n+1}-p_n)<\infty, and Maynard [13] and the Polymath project [15] improved this to lim inf⁡(pn+1−pn)≤246\liminf(p_{n+1}-p_n)\le246. Hence ∣pn+1/pn−1∣≤246/pn|p_{n+1}/p_n-1|\le246/p_n for infinitely many nn. This suggests the following.

Conjecture 4.1 (Prime approximation). For every u≥0u\ge0 and ε>0\varepsilon>0 there are infinitely many pairs of distinct primes (p,q)(p,q) with

∣pq−u∣<εlog⁡qq.(16)\left|\frac{p}{q}-u\right|<\varepsilon\frac{\log q}{q}. \tag*{(16)}

The cases u=0u=0 (take p=2p=2) and u=1u=1 (by the bounded gaps theorem) are known, the latter in the stronger form ∣p/q−1∣≤246/q|p/q-1|\le246/q. A naive probabilistic model suggests that even ∣p/q−u∣<c/q|p/q-u|<c/q should have infinitely many solutions for every c>0c>0, since for each prime qq the interval (uq−c,uq+c)(uq-c,uq+c) should contain a prime with probability about 2c/log⁡q2c/\log q, and ∑q1/log⁡q\sum_q1/\log q diverges.

Unconditionally, Baker, Harman and Pintz [3] proved that [x−x0.525,x][x-x^{0.525},x] contains a prime for all sufficiently large xx. Choosing a prime pp in [uq−(uq)0.525,uq][uq-(uq)^{0.525},uq] shows that, for every fixed u>0u>0 and every sufficiently large qq (prime or not),

0≤u−pq≤u0.525q−0.475.(17)0\le u-\frac{p}{q}\le u^{0.525}q^{-0.475}. \tag*{(17)}

Assuming the Riemann Hypothesis, Cramér [6] showed pn+1−pn=O(pnlog⁡pn)p_{n+1}-p_n=O(\sqrt{p_n}\log p_n), which improves (17) to ∣p/q−u∣≤Cuq−1/2log⁡q|p/q-u|\le Cuq^{-1/2}\log q, still far from (16).

Ratios of logarithms of primes

We need a Mills-type lemma [14, 17]; we include the short proof.

Lemma 4.2. Suppose 0<β<10<\beta<1 and pn+1−pn=O(pnβ)p_{n+1}-p_n=O(p_n^\beta). Then for every real u>1/(1−β)u>1/(1-\beta) there is θ>1\theta>1 such that ⌊θun⌋\lfloor\theta^{u^n}\rfloor is prime for every n≥1n\ge1.

Proof. The hypothesis gives a prime in [y,y+Kyβ][y,y+Ky^\beta] for all y≥2y\ge2 and some KK. For a large integer PP, the interval [Pu,(P+1)u−2][P^u,(P+1)^u-2] has length at least uPu−1−2uP^{u-1}-2, which exceeds K(Pu)βK(P^u)^\beta for PP large because u−1>uβu-1>u\beta. So we may choose primes P1<P2<⋯P_1<P_2<\cdots, with P1P_1 large, such that Pnu≤Pn+1≤(Pn+1)u−2P_n^u\le P_{n+1}\le(P_n+1)^u-2. Then Pnu−nP_n^{u^{-n}} is non-decreasing and (Pn+1)u−n(P_n+1)^{u^{-n}} is strictly decreasing, so θ=lim⁡Pnu−n\theta=\lim P_n^{u^{-n}} satisfies Pn≤θun<Pn+1P_n\le\theta^{u^n}<P_n+1, i.e. ⌊θun⌋=Pn\lfloor\theta^{u^n}\rfloor=P_n, for all n≥1n\ge1. □

Theorem 4.3. For every u>40/19u>40/19 there is an infinite sequence of primes q1<q2<⋯q_1<q_2<\cdots such that, for all nn,

−1qn+1log⁡qn<log⁡qn+1log⁡qn−u<uqnlog⁡qn.(18)-\frac{1}{q_{n+1}\log q_n}<\frac{\log q_{n+1}}{\log q_n}-u<\frac{u}{q_n\log q_n}. \tag*{(18)}

Assuming the Riemann Hypothesis, the same holds for every u>2u>2.

Proof. By [3], the hypothesis of Lemma 4.2 holds with β=0.525\beta=0.525, and 1/(1−0.525)=40/191/(1-0.525)=40/19. (Under the Riemann Hypothesis, Cramér’s bound gives it for every β>1/2\beta>1/2.) Let qn=⌊θun⌋q_n=\lfloor\theta^{u^n}\rfloor.

From qn≤θun<qn+1q_n \leq\theta^{u^n} < q_n + 1 and θun+1=(θun)u\theta^{u^{n+1}} = \left(\theta^{u^n}\right)^u we get

log⁡qn+1log⁡(qn+1)<u<log⁡(qn+1+1)log⁡qn,qn+1<(qn+1)u.\frac{\log q_{n+1}}{\log(q_n+1)} < u < \frac{\log(q_{n+1}+1)}{\log q_n}, \qquad q_{n+1} < (q_n+1)^u.

The right inequality gives u−log⁡qn+1log⁡qn<log⁡(1+1/qn+1)log⁡qn<1qn+1log⁡qnu-\frac{\log q_{n+1}}{\log q_n}<\frac{\log(1+1/q_{n+1})}{\log q_n}<\frac{1}{q_{n+1}\log q_n}. The left one gives

log⁡qn+1log⁡qn−u<log⁡qn+1log⁡(1+1/qn)log⁡qnlog⁡(qn+1)<uqnlog⁡qn,\frac{\log q_{n+1}}{\log q_n}-u<\log q_{n+1}\frac{\log(1+1/q_n)}{\log q_n\log(q_n+1)}<\frac{u}{q_n\log q_n},

using log⁡qn+1<ulog⁡(qn+1)\log q_{n+1}<u\log(q_n+1) and log⁡(1+1/qn)<1/qn\log(1+1/q_n)<1/q_n. □

The feature of Theorem 4.3 is that the approximations form a chain: each qnq_n serves as the numerator of one approximation and the denominator of the next. For a single pair, a much stronger estimate holds for all u>0u>0:

Proposition 4.4. Let u>0u>0. For every sufficiently large prime qq there is a prime pp with

0≤u−log⁡plog⁡q≤2q−0.475ulog⁡q.0 \leq u-\frac{\log p}{\log q}\leq\frac{2q^{-0.475u}}{\log q}.

Proof. Let X=quX=q^u and pick a prime p∈[X−X0.525,X]p\in[X-X^{0.525},X] [3]. Then 0≤log⁡X−log⁡p≤−log⁡(1−X−0.475)≤2X−0.4750\leq\log X-\log p\leq-\log(1-X^{-0.475})\leq2X^{-0.475}; divide by log⁡q\log q. □

For u>40/19u>40/19 we have q−0.475u=o(q−1)q^{-0.475u}=o(q^{-1}), so Proposition 4.4 is stronger than (18) pair by pair; its proof, however, does not produce chains.

Finally, if 0<v<19/400<v<19/40, applying Theorem 4.3 to u=1/vu=1/v gives a sequence of primes with

∣log⁡qnlog⁡qn+1−v∣<1qnlog⁡qn+1.\left|\frac{\log q_n}{\log q_{n+1}}-v\right|<\frac{1}{q_n\log q_{n+1}}.

This implies qn>qn+1vexp⁡(−1/qn)q_n>q_{n+1}^v\exp(-1/q_n), and therefore, for every fixed ε>0\varepsilon>0 and nn large,

∣log⁡qnlog⁡qn+1−v∣<1+εqn+1vlog⁡qn+1.\left|\frac{\log q_n}{\log q_{n+1}}-v\right|<\frac{1+\varepsilon}{q_{n+1}^v\log q_{n+1}}.

References

Department of Mathematics and Statistics, Siena University, Loudonville, NY 12211

Email address: [email protected]

References

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