The question
For even k k k , let S k S_k S k be the space of cusp forms of weight k k k for S L 2 ( Z ) \mathrm{SL}_2(\mathbb{Z}) SL 2 ( Z ) , and let λ p \lambda_p λ p be an eigenvalue of the Hecke operator T k ( p ) T_k(p) T k ( p ) , p p p an odd prime. Hatada proved that λ p ≡ 1 + p ( m o d 8 ) \lambda_p \equiv1+p \pmod8 λ p ≡ 1 + p ( mod 8 ) for every odd p p p [9 ] , and then that
λ p ≡ 1 + p ( m o d 16 ) if p ≡ ± 1 ( m o d 8 ) , λ p ≡ 1 + p ( m o d 32 ) if p ≡ ± 1 ( m o d 16 ) \lambda_p \equiv1+p \pmod{16}\quad\text{if }p\equiv\pm1\pmod8,\qquad\lambda_p \equiv1+p \pmod{32}\quad\text{if }p\equiv\pm1\pmod{16} λ p ≡ 1 + p ( mod 16 ) if p ≡ ± 1 ( mod 8 ) , λ p ≡ 1 + p ( mod 32 ) if p ≡ ± 1 ( mod 16 )
[10 p. 305] . He then asks the following question [10 p. 306] :
Is it true that λ p ≡ 1 + p ( m o d 2 a ) \lambda_p \equiv1+p \pmod{2^a} λ p ≡ 1 + p ( mod 2 a ) if p ≡ ± 1 ( m o d 2 a − 1 ) p\equiv\pm1\pmod{2^{a-1}} p ≡ ± 1 ( mod 2 a − 1 ) and 6 ≤ a ≤ 13 6\leq a\leq13 6 ≤ a ≤ 13 ?
together with a stronger version concerning the lattice L w + 2 L_{w+2} L w + 2 of forms whose odd periods are integers (stability of L w + 2 L_{w+2} L w + 2 under ( T w + 2 ( p ) − 1 − p ) / 2 a (T_{w+2}(p)-1-p)/2^a ( T w + 2 ( p ) − 1 − p ) / 2 a ), which implies the former. In his Remark 1, Hatada points out that for a ≥ 14 a\geq14 a ≥ 14 the congruence may fail when p ≡ − 1 ( m o d 2 a ) p\equiv-1\pmod{2^a} p ≡ − 1 ( mod 2 a ) , after Swinnerton-Dyer [22 ] . According to Rustom [17 ] , the question was asked at Serre’s suggestion. Rustom proved λ p ≡ 1 + p k − 1 ( m o d 128 ) \lambda_p\equiv1+p^{k-1}\pmod{128} λ p ≡ 1 + p k − 1 ( mod 128 ) for every odd p p p and every k k k [17 Thm 8.1] , which gives the affirmative answer for a ≤ 7 a\leq7 a ≤ 7 .1
In residue characteristic 3, Hatada proved λ p ≡ 1 + p ( m o d 3 ) \lambda_p\equiv1+p\pmod3 λ p ≡ 1 + p ( mod 3 ) for p ≠ 3 p\ne3 p = 3 , λ 3 ≡ 0 ( m o d 9 ) \lambda_3\equiv0\pmod9 λ 3 ≡ 0 ( mod 9 ) , and λ 3 ≡ 0 ( m o d 27 ) \lambda_3\equiv0\pmod{27} λ 3 ≡ 0 ( mod 27 ) if 3 ∤ k 3\nmid k 3 ∤ k [9 ] , congruences (5) to (7). Coleman and Stein [6 ] conjectured that there are only five residue classes modulo 9 of eigenforms (levels 1, 3, 9), and checked it up to weight 74 in level 1. Rustom [17, Thm 9.2] states that finiteness modulo 9 in level 1 follows from the following statement.
Conjecture 9.1 of [17 ] (Conjecture 1.1 of [4 ] ; Rustom writes the weight as w + 2 w+2 w + 2 ). For every eigenform f f f of level 1 and weight k k k , one has a 2 ( f ) ≡ 3 a_2(f) \equiv3 a 2 ( f ) ≡ 3 or 6 6 6 (mod 9 Z ‾ 3 9\overline{\mathbb{Z}}_3 9 Z 3 ) if k ≡ 0 , 2 k \equiv0,2 k ≡ 0 , 2 (mod 6), and a 2 ( f ) ≡ 0 a_2(f) \equiv0 a 2 ( f ) ≡ 0 (mod 9 Z ‾ 3 9\overline{\mathbb{Z}}_3 9 Z 3 ) if k ≡ 4 k \equiv4 k ≡ 4 (mod 6).
Chiriac [4 ] proved unconditionally that a 2 ≡ 0 a_2 \equiv0 a 2 ≡ 0 (mod 9 Z ‾ 3 9\overline{\mathbb{Z}}_3 9 Z 3 ) implies k ≡ 4 k \equiv4 k ≡ 4 (mod 6) [4 Thm 1.2] , and the whole of Conjecture 9.1 when 3 is unramified in the coefficient field [4 Cor. 1.3] ; since Rustom checked this non-ramification for k ≤ 1000 k \le1000 k ≤ 1000 [17 ] , Conjecture 9.1 is proved for k ≤ 1000 k \le1000 k ≤ 1000 .
Related work. The recent preprint [18 ] of Rustom classifies, in every weight, the prime-to-p p p Hecke eigensystems of level 1 modulo 2 8 2^8 2 8 , 3 4 3^4 3 4 , 5 3 5^3 5 3 and 7 2 7^2 7 2 , by Hecke-equivariant transfer maps between modular-symbol modules. At p = 3 p=3 p = 3 , [18 Thm 1.5] gives in particular the literal congruence modulo 27 of every prime-to-3 eigensystem with an Eisenstein twist; this implies Conjecture 9.1 of [17 ] without any ramification hypothesis, and the level 1 case of the Coleman–Stein conjecture. Our Corollary L and Theorem M were obtained independently, by a different route (explicit certificates on Hatada’s lattice), and [18 ] has priority for these two statements. At p = 2 p=2 p = 2 , [18 Thm 1.4] is a classification modulo 2 8 2^8 2 8 in the valuative sense (v 2 ( a ℓ − α ) > 7 v_2(a_\ell-\alpha)>7 v 2 ( a ℓ − α ) > 7 ); it does not address Hatada’s question, and for p ≡ ± 1 p\equiv\pm1 p ≡ ± 1 (mod 2 7 2^7 2 7 ) it gives the valuative form of the case a = 8 a=8 a = 8 . The congruences modulo 2 9 2^9 2 9 and 2 10 2^{10} 2 10 of § 8 , the negative answer for a = 11 , 12 , 13 a=11,12,13 a = 11 , 12 , 13 , and the 3-adic results beyond 81 of §§§ 7 –§ 9 are not covered by [18 ] . Earlier, Calegari and Emerton [3, Lemma 3.3] had proved a ℓ ≡ 1 + ℓ a_\ell\equiv1+\ell a ℓ ≡ 1 + ℓ (mod 9) for ℓ ≡ ± 1 \ell\equiv\pm1 ℓ ≡ ± 1 (mod 9).
The main results of this paper are the following. We first give again (Theorem F, § 4 ), on Hatada’s lattice , his congruences a 3 ( f ) ≡ 0 a_3(f)\equiv0 a 3 ( f ) ≡ 0 (mod 9), and (mod 27) if 3 ∤ k 3\nmid k 3 ∤ k [9 ] . Next (§ 5 ), on Hatada’s lattice , T 2 2 ≡ 9 ( k − 1 ) 2 T_2^2\equiv9(k-1)^2 T 2 2 ≡ 9 ( k − 1 ) 2 (mod 27), and, more precisely, modulo 81, T 2 2 ≡ σ k − 1 ( 2 ) 2 T_2^2\equiv\sigma_{k-1}(2)^2 T 2 2 ≡ σ k − 1 ( 2 ) 2 if k ≡ 0 , 2 k\equiv0,2 k ≡ 0 , 2 (mod 6) and T 2 2 + 9 T 2 ≡ 0 T_2^2+9T_2\equiv0 T 2 2 + 9 T 2 ≡ 0 if k ≡ 4 k\equiv4 k ≡ 4 (mod 6) (Theorems I and K). It follows that Conjecture 9.1 of [17 ] holds for every eigenform of level 1, without any ramification hypothesis (this also follows from [18 Thm 1.5] , see above), and even that a 2 ( f ) ≡ ± σ k − 1 ( 2 ) a_2(f)\equiv\pm\sigma_{k-1}(2) a 2 ( f ) ≡ ± σ k − 1 ( 2 ) (mod 27) when k ≡ 0 , 2 k\equiv0,2 k ≡ 0 , 2 (mod 6) (Corollary L). Together with [17 ] , we obtain the level 1 case of the Coleman–Stein conjecture (Theorem M). Next, § 6 extends these congruences to the operators T ℓ T_\ell T ℓ , ℓ ≤ 19 \ell\le19 ℓ ≤ 19 , and deduces, with the structure theorem for the 3-adic Hecke algebra of [17 ] , a law valid in every weight: for every eigenform f f f of level 1 and every n ≡ 1 n\equiv1 n ≡ 1 (mod 3), a n ( f ) ≡ σ k − 1 ( n ) a_n(f)\equiv\sigma_{k-1}(n) a n ( f ) ≡ σ k − 1 ( n ) (mod 81) , and, if k ≢ 4 k\not\equiv4 k ≡ 4 (mod 6), a n ( f ) ≡ ψ ( n ) σ k − 1 ( n ) a_n(f)\equiv\psi(n)\sigma_{k-1}(n) a n ( f ) ≡ ψ ( n ) σ k − 1 ( n ) (mod 27) for every n n n prime to 3, with ψ \psi ψ trivial or equal to the character of conductor 3 (Theorem O). Section 7 derives a Galois law: on the Galois group of Q ( − 3 ) \mathbb{Q}(\sqrt{-3}) Q ( − 3 ) , tr ρ f = 1 + χ k − 1 + ( a 2 2 − σ k − 1 ( 2 ) 2 ) u 2 \operatorname{tr}\rho_f=1+\chi^{k-1}+(a_2^2-\sigma_{k-1}(2)^2)u^2 tr ρ f = 1 + χ k − 1 + ( a 2 2 − σ k − 1 ( 2 ) 2 ) u 2 (mod 243), where u u u measures the action on ζ 9 \zeta_9 ζ 9 (Theorem P); hence a ℓ ≡ σ k − 1 ( ℓ ) a_\ell\equiv\sigma_{k-1}(\ell) a ℓ ≡ σ k − 1 ( ℓ ) (mod 243) if ℓ ≡ 1 \ell\equiv1 ℓ ≡ 1 (mod 9), a congruence modulo 729 for the other split completely in Q ( ζ 9 , 3 3 ) \mathbb{Q}(\zeta_9,\sqrt[3]{3}) Q ( ζ 9 , 3 3 ) (Theorem R), a bilinear law for ℓ , ℓ ′ = 2 \ell,\ell'=2 ℓ , ℓ ′ = 2 (mod 3) (Theorem S), and, if k ≢ 4 k\not\equiv4 k ≡ 4 (mod 6), the determination of all a n a_n a n , 3 ∤ n 3\nmid n 3 ∤ n , modulo 81 by a 2 a_2 a 2 modulo 81 (Corollary T). Then § 8 establishes a 2-adic Galois law (Theorem U), from the modulo 128 theorem of [17 ] and a certificate for T 5 T_5 T 5 modulo 512: a p ≡ 1 + p k − 1 a_p\equiv1+p^{k-1} a p ≡ 1 + p k − 1 (mod 2 10 2^{10} 2 10 ) for every p ≡ 1 p\equiv1 p ≡ 1 (mod 8), and explicit laws on the other classes; with a reduction to a computation in a finite group (Theorem W), Hatada’s question is completely answered: affirmatively for a ≤ 10 a\le10 a ≤ 10 , negatively for a = 11 , 12 , 13 a=11,12,13 a = 11 , 12 , 13 (Corollary X), and a p ( f ) = 0 a_p(f)=0 a p ( f ) = 0 implies p ≡ − 1 p\equiv-1 p ≡ − 1 (mod 2 11 2^{11} 2 11 ) for every eigenform of level 1 (Corollary Y). Finally, § 9 extends the 3-adic Galois law beyond 729: for every prime ℓ ≡ 2 \ell\equiv2 ℓ ≡ 2 (mod 3), a ℓ 2 ≡ σ k − 1 ( ℓ ) 2 a_\ell^2\equiv\sigma_{k-1}(\ell)^2 a ℓ 2 ≡ σ k − 1 ( ℓ ) 2 (mod 3 min ( 2 j + 2 , 10 ) 3^{\min(2j+2,10)} 3 m i n ( 2 j + 2 , 10 ) ), where j = v 3 ( ℓ + 1 ) j=v_3(\ell+1) j = v 3 ( ℓ + 1 ) (Theorem R′ ' ′ ); the exponent 2 j + 2 2j+2 2 j + 2 is extended for j ≤ 4 j\le4 j ≤ 4 and no longer holds for j = 5 j=5 j = 5 . It follows that v 3 ( a ℓ ) ≥ v 3 ( ℓ + 1 ) v_3(a_\ell)\ge v_3(\ell+1) v 3 ( a ℓ ) ≥ v 3 ( ℓ + 1 ) if v 3 ( ℓ + 1 ) ≤ 4 v_3(\ell+1)\le4 v 3 ( ℓ + 1 ) ≤ 4 and k ≢ 4 k\not\equiv4 k ≡ 4 (mod 6), and that, for such k k k , a ℓ ( f ) = 0 a_\ell(f)=0 a ℓ ( f ) = 0 implies ℓ ≡ − 1 \ell\equiv-1 ℓ ≡ − 1 (mod 2 11 ⋅ 3 5 2^{11}\cdot3^5 2 11 ⋅ 3 5 ) (Corollary Y′ ' ′ ). For ℓ ≡ 1 \ell\equiv1 ℓ ≡ 1 (mod 27) with 3 a cube modulo ℓ \ell ℓ , a ℓ = σ k − 1 ( ℓ ) a_\ell=\sigma_{k-1}(\ell) a ℓ = σ k − 1 ( ℓ ) (mod 3 7 3^7 3 7 ), and (mod 3 8 3^8 3 8 ) if k ≡ 4 k\equiv4 k ≡ 4 (mod 6) and ℓ = X 2 + X Y + 547 Y 2 \ell=X^2+XY+547Y^2 ℓ = X 2 + X Y + 547 Y 2 (Theorem R′ ′ '' ′′ ).
Each statement carries a status: PROVED (complete proof, possibly resting on a finite exact computation whose certificate is checked by an ancillary script), KNOWN (a result of the literature, given again or checked independently), VERIFIED (checked by computation on the stated range only) or OPEN .
2-adic results
For k ∈ { 12 , 16 , 18 , 20 , 22 , 26 } k \in\{12,16,18,20,22,26\} k ∈ { 12 , 16 , 18 , 20 , 22 , 26 } , let Δ k = ∑ n ≥ 1 a k ( n ) q n \Delta_k=\sum_{n\geq1}a_k(n)q^n Δ k = ∑ n ≥ 1 a k ( n ) q n be the unique normalised eigenform in S k S_k S k (thus Δ 12 = Δ \Delta_{12}=\Delta Δ 12 = Δ and a 12 ( n ) = τ ( n ) a_{12}(n)=\tau(n) a 12 ( n ) = τ ( n ) ). One has Δ k = E k − 12 Δ \Delta_k=E_{k-12}\Delta Δ k = E k − 12 Δ .
Theorem A (negative answer for a = 11 , 12 , 13 a=11,12,13 a = 11 , 12 , 13 ). The answer to Hatada’s question is negative for a = 11 a=11 a = 11 , a = 12 a=12 a = 12 and a = 13 a=13 a = 13 . The prime p = 12289 = 3 ⋅ 2 12 + 1 p=12289=3\cdot2^{12}+1 p = 12289 = 3 ⋅ 2 12 + 1 provides witnesses at the three levels:
In particular, for Ramanujan’s function,
τ ( 12289 ) = 13 297 575 938 818 018 265 090 , v 2 ( τ ( 12289 ) − 12290 ) = 11 , \tau(12289)=13\,297\,575\,938\,818\,018\,265\,090,\qquad v_2(\tau(12289)-12290)=11, τ ( 12289 ) = 13 297 575 938 818 018 265 090 , v 2 ( τ ( 12289 ) − 12290 ) = 11 ,
whereas 12289 ≡ 1 ( m o d 2 12 ) 12289\equiv1\pmod{2^{12}} 12289 ≡ 1 ( mod 2 12 ) : the requested congruence fails modulo 2 12 2^{12} 2 12 and modulo 2 13 2^{13} 2 13 . A second witness at level a = 11 a=11 a = 11 is p = 13313 = 13 ⋅ 2 10 + 1 p=13313=13\cdot2^{10}+1 p = 13313 = 13 ⋅ 2 10 + 1 , for which v 2 ( a k ( p ) − 1 − p ) = 10 v_2(a_k(p)-1-p)=10 v 2 ( a k ( p ) − 1 − p ) = 10 if k = 16 , 18 , 26 k=16,18,26 k = 16 , 18 , 26 .
Status: PROVED. Finite exact computation. All values were obtained by two independent methods which agree: PARI/GP [16 ] (ramanujantau; mfinit, mfeigenbasis, mfcoef)) and a computation modulo 2 23 2^{23} 2 23 by products of the η \eta η function and Eisenstein series. The “lattice” version of the question therefore also fails for these three values of a a a .
Proposition B (class congruences). For n n n odd and n ≡ r ( m o d 8 ) n\equiv r\pmod8 n ≡ r ( mod 8 ) ,
a k ( n ) ≡ c k , r σ k − 1 ( n ) ( m o d 2 A k , r ) , a_k(n)\equiv c_{k,r}\sigma_{k-1}(n)\pmod{2^{A_{k,r}}}, a k ( n ) ≡ c k , r σ k − 1 ( n ) ( mod 2 A k , r ) , with the following pairs ( A k , r , c k , r ) (A_{k,r},c_{k,r}) ( A k , r , c k , r ) (for r = 3 , 5 , 7 r=3,5,7 r = 3 , 5 , 7 , the value given is a representative of the constant):
For k = 12 k=12 k = 12 , these are Kolberg’s congruences [12 ] . The exponents are optimal: no constant works modulo 2 A k , r + 1 2^{A_{k,r}+1} 2 A k , r + 1 .
Status: PROVED. For odd r r r , the restriction f r = ∑ n ≡ r ( 8 ) a ( n ) q n f_r=\sum_{n\equiv r\ (8)}a(n)q^n f r = ∑ n ≡ r ( 8 ) a ( n ) q n of a form f f f of level 1 is a linear combination of the twists of f f f by the Dirichlet characters modulo 8, all of which lie in M k ( Γ 0 ( 64 ) ) M_k(\Gamma_0(64)) M k ( Γ 0 ( 64 )) with trivial character (these characters being quadratic). With G k = − B k 2 k + ∑ n ≥ 1 σ k − 1 ( n ) q n G_k=-\frac{B_k}{2k}+\sum_{n\geq1}\sigma_{k-1}(n)q^n G k = − 2 k B k + ∑ n ≥ 1 σ k − 1 ( n ) q n , the form g = ( Δ k ) r − c k , r ( G k ) r g=(\Delta_k)_r-c_{k,r}(G_k)_r g = ( Δ k ) r − c k , r ( G k ) r therefore belongs to M k ( Γ 0 ( 64 ) ) ∩ Z [ [ q ] ] M_k(\Gamma_0(64))\cap\mathbb{Z}[[q]] M k ( Γ 0 ( 64 )) ∩ Z [[ q ]] . By Sturm’s theorem [21 ] , applied successively to g g g , g / 2 g/2 g /2 , g / 4 , … g/4,\ldots g /4 , … , it suffices to check divisibility by 2 A k , r 2^{A_{k,r}} 2 A k , r of the coefficients of index n ≤ 12 12 [ S L 2 ( Z ) : Γ 0 ( 64 ) ] = 8 k ≤ 208 n\leq\frac{12}{12}[\mathrm{SL}_2(\mathbb{Z}):\Gamma_0(64)]=8k\leq208 n ≤ 12 12 [ SL 2 ( Z ) : Γ 0 ( 64 )] = 8 k ≤ 208 . Checked for all odd n ≤ 2000 n\leq2000 n ≤ 2000 , for the six forms and the four classes (24 congruences); optimality is witnessed by some n ≤ 2000 n\leq2000 n ≤ 2000 in each case.
Theorem C (exact threshold for the six rational forms). Let k ∈ { 12 , 16 , 18 , 20 , 22 , 26 } k \in\{12,16,18,20,22,26\} k ∈ { 12 , 16 , 18 , 20 , 22 , 26 } and 6 ≤ a ≤ 13 6 \le a \le13 6 ≤ a ≤ 13 . Hatada’s question has an affirmative answer for Δ k \Delta_k Δ k if and only if a ≤ a k a \le a_k a ≤ a k , where
a 12 = 11 , a 16 = a 18 = a 26 = 10 , a 20 = a 22 = 12. a_{12}=11,\qquad a_{16}=a_{18}=a_{26}=10,\qquad a_{20}=a_{22}=12. a 12 = 11 , a 16 = a 18 = a 26 = 10 , a 20 = a 22 = 12. More precisely, the requested congruence holds for every a ≤ 13 a \le13 a ≤ 13 when p ≡ − 1 ( m o d 2 a − 1 ) p \equiv-1 \pmod{2^{a-1}} p ≡ − 1 ( mod 2 a − 1 ) ; when p ≡ + 1 ( m o d 2 a − 1 ) p \equiv+1 \pmod{2^{a-1}} p ≡ + 1 ( mod 2 a − 1 ) , it holds exactly for a ≤ a k = A k , 1 a \le a_k=A_{k,1} a ≤ a k = A k , 1 .
Proof. Let p ≡ ± 1 ( m o d 2 a − 1 ) p \equiv\pm1 \pmod{2^{a-1}} p ≡ ± 1 ( mod 2 a − 1 ) with 6 ≤ a ≤ 13 6 \le a \le13 6 ≤ a ≤ 13 . Then p ≡ ± 1 ( m o d 8 ) p \equiv\pm1 \pmod8 p ≡ ± 1 ( mod 8 ) and p 2 ≡ 1 ( m o d 2 a ) p^2 \equiv1 \pmod{2^a} p 2 ≡ 1 ( mod 2 a ) , whence p k − 1 ≡ p ( m o d 2 a ) p^{k-1} \equiv p \pmod{2^a} p k − 1 ≡ p ( mod 2 a ) since k − 2 k-2 k − 2 is even.
If p ≡ − 1 ( m o d 2 a − 1 ) p \equiv-1 \pmod{2^{a-1}} p ≡ − 1 ( mod 2 a − 1 ) , Proposition B (class r = 7 r=7 r = 7 , A k , 7 ≥ 13 ≥ a A_{k,7}\ge13\ge a A k , 7 ≥ 13 ≥ a ) gives a k ( p ) ≡ c ( 1 + p k − 1 ) a_k(p)\equiv c(1+p^{k-1}) a k ( p ) ≡ c ( 1 + p k − 1 ) (mod 2 a 2^a 2 a ) with c c c odd. As 1 + p k − 1 = ( 1 + p ) ( 1 − p + ⋯ + p k − 2 ) 1+p^{k-1}=(1+p)(1-p+\cdots+p^{k-2}) 1 + p k − 1 = ( 1 + p ) ( 1 − p + ⋯ + p k − 2 ) , the second factor being a sum of an odd number of odd terms, one has v 2 ( 1 + p k − 1 ) = v 2 ( 1 + p ) ≥ a − 1 v_2(1+p^{k-1})=v_2(1+p)\ge a-1 v 2 ( 1 + p k − 1 ) = v 2 ( 1 + p ) ≥ a − 1 , hence ( c − 1 ) ( 1 + p k − 1 ) ≡ 0 (c-1)(1+p^{k-1})\equiv0 ( c − 1 ) ( 1 + p k − 1 ) ≡ 0 (mod 2 a 2^a 2 a ), and a k ( p ) ≡ 1 + p k − 1 ≡ 1 + p a_k(p)\equiv1+p^{k-1}\equiv1+p a k ( p ) ≡ 1 + p k − 1 ≡ 1 + p (mod 2 a 2^a 2 a ).
If p ≡ 1 ( m o d 2 a − 1 ) p\equiv1\pmod{2^{a-1}} p ≡ 1 ( mod 2 a − 1 ) and a ≤ A k , 1 a\le A_{k,1} a ≤ A k , 1 , Proposition B (class r = 1 r=1 r = 1 , c k , 1 = 1 c_{k,1}=1 c k , 1 = 1 ) gives directly a k ( p ) ≡ 1 + p k − 1 ≡ 1 + p a_k(p)\equiv1+p^{k-1}\equiv1+p a k ( p ) ≡ 1 + p k − 1 ≡ 1 + p (mod 2 a 2^a 2 a ).
Finally, if A k , 1 < a ≤ 13 A_{k,1}<a\le13 A k , 1 < a ≤ 13 , the prime p = 12289 p=12289 p = 12289 , which satisfies p ≡ 1 ( m o d 2 12 ) p\equiv1\pmod{2^{12}} p ≡ 1 ( mod 2 12 ) , is a counterexample (Theorem A).
Status: PROVED.
Corollary D (non-vanishing). For each of the six forms, if p p p is an odd prime and v 2 ( p + 1 ) < A k , r v_2(p+1)<A_{k,r} v 2 ( p + 1 ) < A k , r with r ≡ p ( m o d 8 ) r\equiv p\pmod8 r ≡ p ( mod 8 ) , then v 2 ( a k ( p ) ) = v 2 ( p + 1 ) v_2(a_k(p))=v_2(p+1) v 2 ( a k ( p )) = v 2 ( p + 1 ) ; in particular a k ( p ) ≠ 0 a_k(p)\ne0 a k ( p ) = 0 . Consequently a k ( p ) = 0 a_k(p)=0 a k ( p ) = 0 implies
p ≡ − 1 ( m o d 2 A k , 7 ) , 2 A k , 7 = 2 14 , 2 13 , 2 13 , 2 15 , 2 15 , 2 13 for k = 12 , 16 , 18 , 20 , 22 , 26. p\equiv-1\pmod{2^{A_{k,7}}},\qquad2^{A_{k,7}}=2^{14},2^{13},2^{13},2^{15},2^{15},2^{13}\quad\text{for }k=12,16,18,20,22,26. p ≡ − 1 ( mod 2 A k , 7 ) , 2 A k , 7 = 2 14 , 2 13 , 2 13 , 2 15 , 2 15 , 2 13 for k = 12 , 16 , 18 , 20 , 22 , 26. Proof. By Proposition B, a k ( p ) ≡ c ( 1 + p k − 1 ) ( m o d 2 A k , r ) a_k(p)\equiv c(1+p^{k-1})\pmod{2^{A_{k,r}}} a k ( p ) ≡ c ( 1 + p k − 1 ) ( mod 2 A k , r ) with c c c odd, and v 2 ( 1 + p k − 1 ) = v 2 ( 1 + p ) v_2(1+p^{k-1})=v_2(1+p) v 2 ( 1 + p k − 1 ) = v 2 ( 1 + p ) . If p ≢ 7 ( m o d 8 ) p\not\equiv7\pmod8 p ≡ 7 ( mod 8 ) , then v 2 ( p + 1 ) ≤ 2 < A k , r v_2(p+1)\le2<A_{k,r} v 2 ( p + 1 ) ≤ 2 < A k , r .
Status: PROVED.
Remark (Tian–Qin bounds). The five bounds B k B_k B k (k = 16 , 18 , 20 , 22 , 26 k=16,18,20,22,26 k = 16 , 18 , 20 , 22 , 26 ) of [23 Prop. 5.2] , taken from the arXiv version 1504.07381v3, are primes satisfying the congruence conditions of [23 ] , but v 2 ( B k + 1 ) = 1 , 3 , 1 , 6 , 2 v_2(B_k+1)=1,3,1,6,2 v 2 ( B k + 1 ) = 1 , 3 , 1 , 6 , 2 respectively. By Corollary D, a B k ( Δ k ) ≠ 0 a_{B_k}(\Delta_k)\ne0 a B k ( Δ k ) = 0 and v 2 ( a B k ( Δ k ) ) = v 2 ( B k + 1 ) v_2(a_{B_k}(\Delta_k))=v_2(B_k+1) v 2 ( a B k ( Δ k )) = v 2 ( B k + 1 ) . Four of them were already excluded by [9 , 10 ] , which force p ≡ − 1 ( m o d 32 ) p\equiv-1\pmod{32} p ≡ − 1 ( mod 32 ) for a zero, and all five by [17 ] , which force p ≡ − 1 ( m o d 128 ) p\equiv-1\pmod{128} p ≡ − 1 ( mod 128 ) . The values of the published version of [23 ] were not consulted.
The threshold in all weights ≤ 100 \le100 ≤ 100
For even k k k , 12 ≤ k ≤ 100 12\le k\le100 12 ≤ k ≤ 100 , k ≠ 14 k\ne14 k = 14 , and for each prime p ≤ 13313 p\le13313 p ≤ 13313 with p ≡ ± 1 ( m o d 2 7 ) p\equiv\pm1\pmod{2^7} p ≡ ± 1 ( mod 2 7 ) (48 primes), we compute the minimal valuation s ( k , p ) = min λ v 2 ( λ − 1 − p ) s(k,p)=\min_\lambda v_2(\lambda-1-p) s ( k , p ) = min λ v 2 ( λ − 1 − p ) , where λ \lambda λ runs over the eigenvalues of T p T_p T p on S k S_k S k (all eigenforms, including those with irrational coefficients; dimension up to 8). The computation is exact modulo 2 128 2^{128} 2 128 in a Miller basis; every valuation ≤ 14 \le14 ≤ 14 obtained is guaranteed.
Theorem E (failures in all weights ≤ 100 \le100 ≤ 100 ). For every k ≤ 100 k\le100 k ≤ 100 with k ≡ 0 k\equiv0 k ≡ 0 or 2 ( m o d 8 ) 2\pmod8 2 ( mod 8 ) and k ≥ 16 k\ge16 k ≥ 16 , there is an eigenvalue λ \lambda λ of T 12289 T_{12289} T 12289 on S k S_k S k with v 2 ( λ − 12290 ) = 10 v_2(\lambda-12290)=10 v 2 ( λ − 12290 ) = 10 ; Hatada’s question therefore fails at level 11 in each of these weights. For k ≡ 4 k\equiv4 k ≡ 4 or 6 ( m o d 8 ) 6\pmod8 6 ( mod 8 ) , k ∈ { 12 } ∪ [ 28 , 100 ] k\in\{12\}\cup[28,100] k ∈ { 12 } ∪ [ 28 , 100 ] , there is one with v 2 ( λ − 12290 ) = 11 v_2(\lambda-12290)=11 v 2 ( λ − 12290 ) = 11 , hence a failure at level 12.
Status: PROVED. Finite exact computation: for each such k k k , the Newton polygon at 2 of the characteristic polynomial of T 12289 − 12290 T_{12289}-12290 T 12289 − 12290 on S k S_k S k (PARI/GP, see § 11 ).
The failure at the stated level is proved (Theorems A and E); the absence of failure at lower levels is checked on the range of Statement V.
Statement V. For every eigenform of weight 12 ≤ k ≤ 100 12 \le k \le100 12 ≤ k ≤ 100 , every 6 ≤ a ≤ 10 6 \le a \le10 6 ≤ a ≤ 10 and every prime p ≤ 13313 p \le13313 p ≤ 13313 with p ≡ ± 1 ( m o d 2 a − 1 ) p \equiv\pm1 \pmod{2^{a-1}} p ≡ ± 1 ( mod 2 a − 1 ) , one has λ p ≡ 1 + p ( m o d 2 a ) \lambda_p \equiv1+p \pmod{2^a} λ p ≡ 1 + p ( mod 2 a ) . The same holds for 24 ≤ k ≤ 54 24 \le k \le54 24 ≤ k ≤ 54 and all primes p ≤ 60000 p \le60000 p ≤ 60000 (183 primes p ≡ ± 1 ( m o d 2 7 ) p \equiv\pm1 \pmod{2^7} p ≡ ± 1 ( mod 2 7 ) , 48 of which satisfy p ≡ ± 1 ( m o d 2 9 ) p \equiv\pm1 \pmod{2^9} p ≡ ± 1 ( mod 2 9 ) ). Level 10 is attained with equality: for example v 2 ( τ ( 7681 ) − 7682 ) = 10 v_2(\tau(7681)-7682)=10 v 2 ( τ ( 7681 ) − 7682 ) = 10 , where 7681 ≡ 1 ( m o d 2 9 ) 7681 \equiv1 \pmod{2^9} 7681 ≡ 1 ( mod 2 9 ) .
Status: VERIFIED. Exhaustive check on the stated range; the first failing levels of the table above are unchanged when passing from p ≤ 13313 p \le13313 p ≤ 13313 to p ≤ 60000 p \le60000 p ≤ 60000 .
Statement V′ (“lattice” form). For 12 ≤ k ≤ 100 12 \le k \le100 12 ≤ k ≤ 100 and each of the 194 primes p ≤ 13313 p \le13313 p ≤ 13313 such that p ≡ ± 1 ( m o d 32 ) p \equiv\pm1 \pmod{32} p ≡ ± 1 ( mod 32 ) , the lattice L w + 2 − L_{w+2}^{-} L w + 2 − of [10 ] is stable under ( T w + 2 ( p ) − 1 − p ) / 2 a (T_{w+2}(p)-1-p)/2^a ( T w + 2 ( p ) − 1 − p ) / 2 a for every a ≤ 10 a \le10 a ≤ 10 such that p ≡ ± 1 ( m o d 2 a − 1 ) p \equiv\pm1 \pmod{2^{a-1}} p ≡ ± 1 ( mod 2 a − 1 ) (ten of these primes reach a = 10 a=10 a = 10 ). The first failing level of the lattice form is 11, 12 or 13 according to k k k ; it is strictly smaller than that of the eigenvalues (11 against 12) for k ∈ { 36 , 52 , 60 , 68 , 76 , 84 , 92 , 100 } k \in\{36,52,60,68,76,84,92,100\} k ∈ { 36 , 52 , 60 , 68 , 76 , 84 , 92 , 100 } .
Status: VERIFIED. Exact computation on a basis of L w + 2 − L_{w+2}^{-} L w + 2 − .
Remark (conjecture). The data suggest that Hatada’s question has an affirmative answer exactly for a ≤ 10 a \le10 a ≤ 10 , including in its “lattice” form: the congruence λ p ≡ 1 + p ( m o d 2 a ) \lambda_p \equiv1+p \pmod{2^a} λ p ≡ 1 + p ( mod 2 a ) for p ≡ ± 1 ( m o d 2 a − 1 ) p \equiv\pm1 \pmod{2^{a-1}} p ≡ ± 1 ( mod 2 a − 1 ) would hold for every eigenform of level 1 as soon as a ≤ 10 a \le10 a ≤ 10 , and it fails for a = 11 a=11 a = 11 . Section 8 proves the affirmative answer for a ≤ 10 ( C o r o l l a r y X ) a \le10 (Corollary X) a ≤ 10 ( C or o l l a r y X ) ; the “lattice” form remains only verified.
3-adic results
Notation. Let k ≥ 12 k \ge12 k ≥ 12 be even and w = k − 2 w=k-2 w = k − 2 . For γ = ( a b c d ) ∈ M 2 ( Z ) \gamma= \begin{pmatrix}a&b\\c&d\end{pmatrix} \in M_2(\mathbb{Z}) γ = ( a c b d ) ∈ M 2 ( Z ) with non-zero determinant and P ∈ Q [ X ] P \in\mathbb{Q}[X] P ∈ Q [ X ] of degree ≤ w \le w ≤ w , put ( P ∣ γ ) ( X ) = ( c X + d ) w P ( a X + b c X + d ) (P|\gamma)(X)=(cX+d)^w P\left(\frac{aX+b}{cX+d}\right) ( P ∣ γ ) ( X ) = ( c X + d ) w P ( c X + d a X + b ) . With S = ( 0 − 1 1 0 ) S=\begin{pmatrix}0&-1\\1&0\end{pmatrix} S = ( 0 1 − 1 0 ) and U = ( 1 − 1 0 1 ) U=\begin{pmatrix}1&-1\\0&1\end{pmatrix} U = ( 1 0 − 1 1 ) , let W − W^{-} W − be the space of odd polynomials P P P such that P ∣ ( 1 + S ) = P ∣ ( 1 + U + U 2 ) = 0 P|(1+S)=P|(1+U+U^2)=0 P ∣ ( 1 + S ) = P ∣ ( 1 + U + U 2 ) = 0 . The map sending f f f to the odd part of ∫ 0 i ∞ f ( z ) ( X − z ) w d z \int_0^{i\infty}f(z)(X-z)^w\,dz ∫ 0 i ∞ f ( z ) ( X − z ) w d z identifies S k ( R ) S_k(\mathbb{R}) S k ( R ) with W − ⊗ R W^{-}\otimes\mathbb{R} W − ⊗ R and transforms T n T_n T n into P ↦ P ∣ T ~ n P\mapsto P|\widetilde{T}_n P ↦ P ∣ T n , where T ~ n = ∑ M ∈ M n M \widetilde{T}_n=\sum_{M\in\mathcal{M}_n}M T n = ∑ M ∈ M n M and M n \mathcal{M}_n M n is the set of integer matrices ( a b c d ) \begin{pmatrix}a&b\\c&d\end{pmatrix} ( a c b d ) such that a d − b c = n ad-bc=n a d − b c = n , a > c ≥ 0 a>c\ge0 a > c ≥ 0 and d > b ≥ 0 d>b\ge0 d > b ≥ 0 [14 , 24 ] . For f f f with real coefficients, this odd part is the real part of the integral; since T ~ n \widetilde{T}_n T n is a sum of integer matrices, it commutes with taking real parts, and W − W^{-} W − is therefore stable under T ~ n \widetilde{T}_n T n .
The coefficient of X w − j X^{w-j} X w − j in ∫ 0 i ∞ f ( z ) ( X − z ) w d z \int_0^{i\infty}f(z)(X-z)^w\,dz ∫ 0 i ∞ f ( z ) ( X − z ) w d z is ( − 1 ) j ( w j ) r j ( f ) (-1)^j\binom{w}{j}r_j(f) ( − 1 ) j ( j w ) r j ( f ) , with r j ( f ) = ∫ 0 i ∞ f ( z ) z j d z r_j(f)=\int_0^{i\infty}f(z)z^j\,dz r j ( f ) = ∫ 0 i ∞ f ( z ) z j d z . Hatada’s lattice L w + 2 − L_{w+2}^{-} L w + 2 − , formed by the forms whose odd periods r j ( f ) r_j(f) r j ( f ) are integers [10 p. 305] , therefore corresponds to
L k = { P = ∑ j ( w j ) m j X j ∈ W − : m j ∈ Z } . L_k=\left\{P=\sum_j\binom{w}{j}m_jX^j\in W^{-}:m_j\in\mathbb{Z}\right\}. L k = { P = j ∑ ( j w ) m j X j ∈ W − : m j ∈ Z } .
The polynomials ∑ j ( w j ) m j X j \sum_j\binom{w}{j}m_jX^j ∑ j ( j w ) m j X j , m j ∈ Z m_j\in\mathbb{Z} m j ∈ Z , form a module B w B_w B w stable under P ↦ P ∣ γ P\mapsto P|\gamma P ↦ P ∣ γ for every γ ∈ M 2 ( Z ) \gamma\in M_2(\mathbb{Z}) γ ∈ M 2 ( Z ) , by virtue of the identity ( w j ) ( j s ) ( w − j l − s ) = ( w l ) ( l s ) ( w − l j − s ) \binom{w}{j}\binom{j}{s}\binom{w-j}{l-s}=\binom{w}{l}\binom{l}{s}\binom{w-l}{j-s} ( j w ) ( s j ) ( l − s w − j ) = ( l w ) ( s l ) ( j − s w − l ) . Thus L k = W − ∩ B w L_k=W^{-}\cap B_w L k = W − ∩ B w is a lattice of rank dim S k \dim S_k dim S k , saturated in B w B_w B w , stable under each T ~ n \widetilde{T}_n T n , whose eigenvalues are the a n ( f ) a_n(f) a n ( f ) .
For P ∈ L k P\in L_k P ∈ L k , we write μ P \mu_P μ P for the Z \mathbb{Z} Z -linear form on the space Z [ x , y ] w \mathbb{Z}[x,y]_w Z [ x , y ] w of integral binary forms of degree w w w defined by μ P ( x j y w − j ) = m j \mu_P(x^jy^{w-j})=m_j μ P ( x j y w − j ) = m j . Then P ( X ) = μ P ( ( x X + y ) w ) P(X)=\mu_P((xX+y)^w) P ( X ) = μ P (( x X + y ) w ) and
μ P ∣ γ ( F ) = μ P ( F ( a x + c y , b x + d y ) ) . \mu_{P|\gamma}(F)=\mu_P(F(ax+cy,bx+dy)). μ P ∣ γ ( F ) = μ P ( F ( a x + cy , b x + d y )) .
Lemma 1 (period identities). For every P ∈ W − P \in W^{-} P ∈ W − : (a) m j = 0 m_j=0 m j = 0 for even j j j , m j = m w − j m_j=m_{w-j} m j = m w − j for every j j j , and μ P ( F ( y , x ) ) = μ P ( F ) \mu_P(F(y,x))=\mu_P(F) μ P ( F ( y , x )) = μ P ( F ) ;
(b) P ( 1 ) = P ′ ( 1 ) = 0 P(1)=P'(1)=0 P ( 1 ) = P ′ ( 1 ) = 0 , P ( 1 2 ) = 0 P\left(\frac{1}{2}\right)=0 P ( 2 1 ) = 0 and P ( 1 3 ) + P ( 2 3 ) = 0 P\left(\frac{1}{3}\right)+P\left(\frac{2}{3}\right)=0 P ( 3 1 ) + P ( 3 2 ) = 0 ;
(c) μ P ( ( x + y ) w ) = μ P ( x ( x + y ) w − 1 ) = μ P ( y ( x + y ) w − 1 ) = 0 \mu_P((x+y)^w)=\mu_P(x(x+y)^{w-1})=\mu_P(y(x+y)^{w-1})=0 μ P (( x + y ) w ) = μ P ( x ( x + y ) w − 1 ) = μ P ( y ( x + y ) w − 1 ) = 0 and μ P ( x 2 ( x + y ) w − 2 ) = μ P ( y 2 ( x + y ) w − 2 ) = − 2 m 1 \mu_P(x^2(x+y)^{w-2})=\mu_P(y^2(x+y)^{w-2})=-2m_1 μ P ( x 2 ( x + y ) w − 2 ) = μ P ( y 2 ( x + y ) w − 2 ) = − 2 m 1 , μ P ( x y ( x + y ) w − 2 ) = 2 m 1 \mu_P(xy(x+y)^{w-2})=2m_1 μ P ( x y ( x + y ) w − 2 ) = 2 m 1 ; the same identities hold with x + y x+y x + y replaced by y − x y-x y − x , with the values 0 , 0 , 0 0,0,0 0 , 0 , 0 and 2 m 1 , 2 m 1 , 2 m 1 2m_1,2m_1,2m_1 2 m 1 , 2 m 1 , 2 m 1 .
Proof. (a) P P P is odd; the relation X w P ( − 1 / X ) = − P ( X ) X^wP(-1/X)=-P(X) X w P ( − 1/ X ) = − P ( X ) gives m j = m w − j m_j=m_{w-j} m j = m w − j . (b) The relations for U U U (at the point 1 + t 1+t 1 + t ) and for S S S (at the point t t t ) give the three-term relation P ( 1 + t ) = P ( t ) − ( 1 + t ) w P ( t 1 + t ) P(1+t)=P(t)-(1+t)^wP\left(\frac{t}{1+t}\right) P ( 1 + t ) = P ( t ) − ( 1 + t ) w P ( 1 + t t ) . At t = 0 t=0 t = 0 : P ( 1 ) = 0 P(1)=0 P ( 1 ) = 0 ; differentiating at t = 0 t=0 t = 0 : P ′ ( 1 ) = − w P ( 0 ) = 0 P'(1)=-wP(0)=0 P ′ ( 1 ) = − w P ( 0 ) = 0 ; at t = 1 t=1 t = 1 , with the relation for S S S at the point 2 2 2 and oddness: P ( 2 ) = − 2 w P ( 1 2 ) = 2 w P ( 1 2 ) P(2)=-2^wP\left(\frac{1}{2}\right)=2^wP\left(\frac{1}{2}\right) P ( 2 ) = − 2 w P ( 2 1 ) = 2 w P ( 2 1 ) , whence P ( 1 2 ) = 0 P\left(\frac{1}{2}\right)=0 P ( 2 1 ) = 0 ; at t = − 1 3 t=-\frac{1}{3} t = − 3 1 : P ( 2 3 ) = P ( − 1 3 ) − ( 2 3 ) w P ( − 1 2 ) = − P ( 1 3 ) P\left(\frac{2}{3}\right)=P\left(-\frac{1}{3}\right)-\left(\frac{2}{3}\right)^wP\left(-\frac{1}{2}\right)=-P\left(\frac{1}{3}\right) P ( 3 2 ) = P ( − 3 1 ) − ( 3 2 ) w P ( − 2 1 ) = − P ( 3 1 ) . (c) One has P ( 1 ) = μ P ( ( x + y ) w ) P(1)=\mu_P((x+y)^w) P ( 1 ) = μ P (( x + y ) w ) and P ′ ( 1 ) = w μ P ( x ( x + y ) w − 1 ) P'(1)=w\mu_P(x(x+y)^{w-1}) P ′ ( 1 ) = w μ P ( x ( x + y ) w − 1 ) . The relation for U U U applied to F = x 2 y w − 2 F=x^2y^{w-2} F = x 2 y w − 2 reads μ P ( F ) + μ P ( x w − 2 ( x + y ) 2 ) + μ P ( y 2 ( x + y ) w − 2 ) = 0 \mu_P(F)+\mu_P(x^{w-2}(x+y)^2)+\mu_P(y^2(x+y)^{w-2})=0 μ P ( F ) + μ P ( x w − 2 ( x + y ) 2 ) + μ P ( y 2 ( x + y ) w − 2 ) = 0 , that is 0 + 2 m 1 + μ P ( y 2 ( x + y ) w − 2 ) = 0 0+2m_1+\mu_P(y^2(x+y)^{w-2})=0 0 + 2 m 1 + μ P ( y 2 ( x + y ) w − 2 ) = 0 ; the other values follow by (a) and by writing y = ( x + y ) − x y=(x+y)-x y = ( x + y ) − x . The passage to y − x y-x y − x is made by the substitution x ↦ − x x\mapsto-x x ↦ − x , which changes μ P \mu_P μ P into − μ P -\mu_P − μ P .
Lemma 2 (T 3 T_3 T 3 modulo 27 27 27 ). For every P ∈ L k P\in L_k P ∈ L k and every form F ∈ Z [ x , y ] w F\in\mathbb{Z}[x,y]_w F ∈ Z [ x , y ] w ,
μ P ∣ T ~ 3 ( F ) ≡ m 1 ( P ) [ 3 ∑ t = 0 2 ( ∂ y F ( 1 , t ) + ∂ x F ( t , 1 ) ) + 18 ( 1 2 ∂ x 2 + ∂ x ∂ y + 1 2 ∂ y 2 ) F ( 1 , − 1 ) ] ( m o d 27 ) . \mu_{P| \widetilde{T}_3}(F)\equiv m_1(P)\left[3\sum_{t=0}^{2}\left(\partial_yF(1,t)+\partial_xF(t,1)\right)+18\left(\frac{1}{2}\partial_x^2+\partial_x\partial_y+\frac{1}{2}\partial_y^2\right)F(1,-1)\right]\pmod{27}. μ P ∣ T 3 ( F ) ≡ m 1 ( P ) [ 3 t = 0 ∑ 2 ( ∂ y F ( 1 , t ) + ∂ x F ( t , 1 ) ) + 18 ( 2 1 ∂ x 2 + ∂ x ∂ y + 2 1 ∂ y 2 ) F ( 1 , − 1 ) ] ( mod 27 ) . In particular μ P ∣ T ~ 3 ( F ) ≡ 0 ( m o d 9 ) \mu_{P|\widetilde{T}_3}(F)\equiv0\pmod9 μ P ∣ T 3 ( F ) ≡ 0 ( mod 9 ) if 3 ∣ m 1 ( P ) 3\mid m_1(P) 3 ∣ m 1 ( P ) , and μ P ∣ T ~ 3 ( F ) ≡ 0 ( m o d 27 ) \mu_{P|\widetilde{T}_3}(F)\equiv0\pmod{27} μ P ∣ T 3 ( F ) ≡ 0 ( mod 27 ) if 9 ∣ m 1 ( P ) 9\mid m_1(P) 9 ∣ m 1 ( P ) .
Proof. The seven elements of M 3 \mathcal{M}_3 M 3 give the following substitutions ( x , y ) ↦ ( a x + c y , b x + d y ) (x,y)\mapsto(ax+cy,bx+dy) ( x , y ) ↦ ( a x + cy , b x + d y ) , written in the form λ ( x , y ) u + 3 h ( x , y ) \lambda(x,y)u+3h(x,y) λ ( x , y ) u + 3 h ( x , y ) :
( x , 3 y ) = x ( 1 , 0 ) + 3 ( 0 , y ) , ( x , x + 3 y ) = x ( 1 , 1 ) + 3 ( 0 , y ) , ( x , 2 x + 3 y ) = x ( 1 , 2 ) + 3 ( 0 , y ) , ( 3 x , y ) = y ( 0 , 1 ) + 3 ( x , 0 ) , ( 3 x + y , y ) = y ( 1 , 1 ) + 3 ( x , 0 ) , ( 3 x + 2 y , y ) = y ( 2 , 1 ) + 3 ( x , 0 ) , ( 2 x + y , x + 2 y ) = ( y − x ) ( 1 , − 1 ) + 3 ( x , y ) . \begin{aligned}
(x,3y)&=x(1,0)+3(0,y),\quad(x,x+3y)=x(1,1)+3(0,y),\quad(x,2x+3y)=x(1,2)+3(0,y),\\
(3x,y)&=y(0,1)+3(x,0),\quad(3x+y,y)=y(1,1)+3(x,0),\quad(3x+2y,y)=y(2,1)+3(x,0),\\
(2x+y,x+2y)&=(y-x)(1,-1)+3(x,y).
\end{aligned} ( x , 3 y ) ( 3 x , y ) ( 2 x + y , x + 2 y ) = x ( 1 , 0 ) + 3 ( 0 , y ) , ( x , x + 3 y ) = x ( 1 , 1 ) + 3 ( 0 , y ) , ( x , 2 x + 3 y ) = x ( 1 , 2 ) + 3 ( 0 , y ) , = y ( 0 , 1 ) + 3 ( x , 0 ) , ( 3 x + y , y ) = y ( 1 , 1 ) + 3 ( x , 0 ) , ( 3 x + 2 y , y ) = y ( 2 , 1 ) + 3 ( x , 0 ) , = ( y − x ) ( 1 , − 1 ) + 3 ( x , y ) .
Since the divided derivatives of an integral form are integral, Taylor’s formula gives, modulo 27 27 27 , F ( λ u + 3 h ) ≡ λ w F ( u ) + 3 λ w − 1 ∑ i h i ∂ i F ( u ) + 9 λ w − 2 ∑ i ≤ i ′ h i h i ′ ∂ [ i , i ′ ] F ( u ) F(\lambda u+3h)\equiv\lambda^wF(u)+3\lambda^{w-1}\sum_i h_i\partial_iF(u)+9\lambda^{w-2}\sum_{i\le i'}h_ih_{i'}\partial_{[i,i']}F(u) F ( λ u + 3 h ) ≡ λ w F ( u ) + 3 λ w − 1 ∑ i h i ∂ i F ( u ) + 9 λ w − 2 ∑ i ≤ i ′ h i h i ′ ∂ [ i , i ′ ] F ( u ) , with ∂ [ i , i ] = 1 2 ∂ i 2 \partial_{[i,i]}=\frac{1}{2}\partial_i^2 ∂ [ i , i ] = 2 1 ∂ i 2 and ∂ [ 1 , 2 ] = ∂ 1 ∂ 2 \partial_{[1,2]}=\partial_1\partial_2 ∂ [ 1 , 2 ] = ∂ 1 ∂ 2 . Apply μ P \mu_P μ P . By Lemma 1, μ P ( λ w ) = 0 \mu_P(\lambda^w)=0 μ P ( λ w ) = 0 for λ ∈ { x , y , y − x } \lambda\in\{x,y,y-x\} λ ∈ { x , y , y − x } ; μ P ( x w − 1 y ) = μ P ( y w − 1 x ) = m 1 \mu_P(x^{w-1}y)=\mu_P(y^{w-1}x)=m_1 μ P ( x w − 1 y ) = μ P ( y w − 1 x ) = m 1 , μ P ( x w ) = μ P ( y w ) = 0 \mu_P(x^w)=\mu_P(y^w)=0 μ P ( x w ) = μ P ( y w ) = 0 , μ P ( ( y − x ) w − 1 g ) = 0 \mu_P((y-x)^{w-1}g)=0 μ P (( y − x ) w − 1 g ) = 0 for linear g g g ; at second order, μ P ( x w − 2 y 2 ) = m w − 2 = 0 \mu_P(x^{w-2}y^2)=m_{w-2}=0 μ P ( x w − 2 y 2 ) = m w − 2 = 0 , μ P ( y w − 2 x 2 ) = m 2 = 0 \mu_P(y^{w-2}x^2)=m_2=0 μ P ( y w − 2 x 2 ) = m 2 = 0 and μ P ( ( y − x ) w − 2 q ) = 2 q ( 1 , 1 ) m 1 \mu_P((y-x)^{w-2}q)=2q(1,1)m_1 μ P (( y − x ) w − 2 q ) = 2 q ( 1 , 1 ) m 1 for quadratic q q q . Collecting the terms gives the stated formula.
Lemma 3 (the first period). For every P ∈ L k P\in L_k P ∈ L k , 3 ∣ m 1 ( P ) 3\mid m_1(P) 3 ∣ m 1 ( P ) ; if moreover 6 ∤ k 6\nmid k 6 ∤ k , then 9 ∣ m 1 ( P ) 9\mid m_1(P) 9 ∣ m 1 ( P ) .
Proof. By Lemma 1(b), 3 w ( P ( 1 3 ) + P ( 2 3 ) ) = 0 3^w\left(P\left(\frac{1}{3}\right)+P\left(\frac{2}{3}\right)\right)=0 3 w ( P ( 3 1 ) + P ( 3 2 ) ) = 0 , that is ∑ j ( w j ) 3 w − j ( 1 + 2 j ) m j = 0 \sum_j\binom{w}{j}3^{w-j}(1+2^j)m_j=0 ∑ j ( j w ) 3 w − j ( 1 + 2 j ) m j = 0 . Putting i = w − j i=w-j i = w − j and using m w − i = m i m_{w-i}=m_i m w − i = m i , we get
∑ i o d d c i m i = 0 , c i = 3 i ( w i ) ( 1 + 2 w − i ) . \sum_{\substack{i\ \mathrm{odd}}}c_i m_i=0,\qquad c_i=3^i\binom{w}{i}(1+2^{w-i}). i odd ∑ c i m i = 0 , c i = 3 i ( i w ) ( 1 + 2 w − i ) .
The terms i = 1 i=1 i = 1 and i = w − 1 i=w-1 i = w − 1 both carry m 1 m_1 m 1 . For odd n n n , v 3 ( 1 + 2 n ) = 1 + v 3 ( n ) v_3(1+2^n)=1+v_3(n) v 3 ( 1 + 2 n ) = 1 + v 3 ( n ) (lifting the exponent). Thus v 3 ( c 1 ) = 2 + v 3 ( w ) + v 3 ( w − 1 ) v_3(c_1)=2+v_3(w)+v_3(w-1) v 3 ( c 1 ) = 2 + v 3 ( w ) + v 3 ( w − 1 ) and, for odd i ≥ 3 i\ge3 i ≥ 3 , with ( w i ) = w i ( w − 1 i − 1 ) \binom{w}{i}=\frac{w}{i}\binom{w-1}{i-1} ( i w ) = i w ( i − 1 w − 1 ) ,
δ i : = v 3 ( c i ) − v 3 ( c 1 ) = ( i − 1 ) − v 3 ( i ) + v 3 ( w − 1 i − 1 ) + v 3 ( w − i ) − v 3 ( w − 1 ) . \delta_i:=v_3(c_i)-v_3(c_1)=(i-1)-v_3(i)+v_3\binom{w-1}{i-1}+v_3(w-i)-v_3(w-1). δ i := v 3 ( c i ) − v 3 ( c 1 ) = ( i − 1 ) − v 3 ( i ) + v 3 ( i − 1 w − 1 ) + v 3 ( w − i ) − v 3 ( w − 1 ) .
Let e = v 3 ( w − 1 ) e=v_3(w-1) e = v 3 ( w − 1 ) . If v 3 ( i − 1 ) < e v_3(i-1)<e v 3 ( i − 1 ) < e , the addition in base 3 3 3 of i − 1 i-1 i − 1 and w − i w-i w − i , with sum w − 1 ≡ 0 ( m o d 3 e ) w-1\equiv0\pmod{3^e} w − 1 ≡ 0 ( mod 3 e ) , has a carry at each position from v 3 ( i − 1 ) v_3(i-1) v 3 ( i − 1 ) to e − 1 e-1 e − 1 ; by Kummer’s theorem v 3 ( w − 1 i − 1 ) ≥ e − v 3 ( i − 1 ) v_3\left(\frac{w-1}{i-1}\right) \ge e-v_3(i-1) v 3 ( i − 1 w − 1 ) ≥ e − v 3 ( i − 1 ) , whence δ i ≥ ( i − 1 ) − v 3 ( i ) − v 3 ( i − 1 ) ≥ 1 \delta_i \ge(i-1)-v_3(i)-v_3(i-1) \ge1 δ i ≥ ( i − 1 ) − v 3 ( i ) − v 3 ( i − 1 ) ≥ 1 , since at most one of the two consecutive integers i − 1 , i i-1,i i − 1 , i is divisible by 3, with valuation at most log 3 i \log_3 i log 3 i . If v 3 ( i − 1 ) ≥ e v_3(i-1) \ge e v 3 ( i − 1 ) ≥ e and e = 0 e=0 e = 0 , then δ i ≥ ( i − 1 ) − v 3 ( i ) ≥ 1 \delta_i \ge(i-1)-v_3(i) \ge1 δ i ≥ ( i − 1 ) − v 3 ( i ) ≥ 1 . If v 3 ( i − 1 ) ≥ e ≥ 1 v_3(i-1) \ge e \ge1 v 3 ( i − 1 ) ≥ e ≥ 1 , then 3 ∤ i 3 \nmid i 3 ∤ i , i − 1 ≥ 3 e i-1 \ge3^e i − 1 ≥ 3 e and δ i ≥ ( i − 1 ) − e ≥ 2 \delta_i \ge(i-1)-e \ge2 δ i ≥ ( i − 1 ) − e ≥ 2 . Hence δ i ≥ 1 \delta_i \ge1 δ i ≥ 1 for every odd i ≥ 3 i \ge3 i ≥ 3 ; in particular v 3 ( c 1 + c w − 1 ) = v 3 ( c 1 ) v_3(c_1+c_{w-1})=v_3(c_1) v 3 ( c 1 + c w − 1 ) = v 3 ( c 1 ) , and the relation gives v 3 ( c 1 ) + v 3 ( m 1 ) ≥ v 3 ( c 1 ) + min 3 ≤ i ≤ w − 3 δ i v_3(c_1)+v_3(m_1) \ge v_3(c_1)+\min_{3\le i\le w-3}\delta_i v 3 ( c 1 ) + v 3 ( m 1 ) ≥ v 3 ( c 1 ) + min 3 ≤ i ≤ w − 3 δ i , that is v 3 ( m 1 ) ≥ 1 v_3(m_1) \ge1 v 3 ( m 1 ) ≥ 1 .
If 6 ∤ k 6 \nmid k 6 ∤ k , then w ≢ 1 ( m o d 3 ) w \not\equiv1 \pmod{3} w ≡ 1 ( mod 3 ) , hence e = 0 e=0 e = 0 . For i ≥ 5 i \ge5 i ≥ 5 , δ i ≥ ( i − 1 ) − v 3 ( i ) ≥ 2 \delta_i \ge(i-1)-v_3(i) \ge2 δ i ≥ ( i − 1 ) − v 3 ( i ) ≥ 2 ; for i = 3 i=3 i = 3 , δ 3 = 1 + v 3 ( w − 2 ) + v 3 ( w − 3 ) ≥ 2 \delta_3=1+v_3(w-2)+v_3(w-3) \ge2 δ 3 = 1 + v 3 ( w − 2 ) + v 3 ( w − 3 ) ≥ 2 , since 3 divides w w w or w − 2 w-2 w − 2 . Hence v 3 ( m 1 ) ≥ 2 v_3(m_1) \ge2 v 3 ( m 1 ) ≥ 2 .
Theorem F (a 3 a_3 a 3 modulo 9 and 27; Hatada). For every even k ≥ 12 k \ge12 k ≥ 12 , T ~ 3 ( L k ) ⊂ 9 L k \widetilde{T}_3(L_k) \subset9L_k T 3 ( L k ) ⊂ 9 L k , and T ~ 3 ( L k ) ⊂ 27 L k \widetilde{T}_3(L_k) \subset27L_k T 3 ( L k ) ⊂ 27 L k if 6 ∤ k 6 \nmid k 6 ∤ k . Consequently, for every eigenform f f f of level 1 and weight k k k , a 3 ( f ) / 9 a_3(f)/9 a 3 ( f ) /9 is an algebraic integer, and so is a 3 ( f ) / 27 a_3(f)/27 a 3 ( f ) /27 when 6 ∤ k 6 \nmid k 6 ∤ k . These bounds are optimal: τ ( 3 ) = 2 2 ⋅ 3 2 ⋅ 7 \tau(3)=2^2\cdot3^2\cdot7 τ ( 3 ) = 2 2 ⋅ 3 2 ⋅ 7 (k = 12 k=12 k = 12 ) and a 3 ( Δ 16 ) = − 2 2 ⋅ 3 3 ⋅ 31 a_3(\Delta_{16})=-2^2\cdot3^3\cdot31 a 3 ( Δ 16 ) = − 2 2 ⋅ 3 3 ⋅ 31 (k = 16 k=16 k = 16 ).
Proof. Let P ∈ L k P \in L_k P ∈ L k . By Lemmas 2 and 3, μ P ∣ T ~ 3 ( F ) \mu_{P|\widetilde{T}_3}(F) μ P ∣ T 3 ( F ) is divisible by 9 (by 27 if 6 ∤ k 6 \nmid k 6 ∤ k ) for every F ∈ Z [ x , y ] w F \in\mathbb{Z}[x,y]_w F ∈ Z [ x , y ] w , hence P ∣ T ~ 3 ∈ 9 B w P|\widetilde{T}_3 \in9B_w P ∣ T 3 ∈ 9 B w (resp. 27 B w 27B_w 27 B w ). Since P ∣ T ~ 3 ∈ W − P|\widetilde{T}_3 \in W^- P ∣ T 3 ∈ W − and L k = W − ∩ B w L_k=W^- \cap B_w L k = W − ∩ B w is saturated in B w B_w B w , we get P ∣ T ~ 3 ∈ 9 L k P|\widetilde{T}_3 \in9L_k P ∣ T 3 ∈ 9 L k (resp. 27 L k 27L_k 27 L k ). The operator T ~ 3 / 9 \widetilde{T}_3/9 T 3 /9 (resp. T ~ 3 / 27 \widetilde{T}_3/27 T 3 /27 ) is therefore an endomorphism of the Z \mathbb{Z} Z -module L k L_k L k ; its characteristic polynomial is monic with integer coefficients and its roots are the a 3 ( f ) / 9 a_3(f)/9 a 3 ( f ) /9 (resp. a 3 ( f ) / 27 a_3(f)/27 a 3 ( f ) /27 ).
STATUS: KNOWN. These are congruences (6) and (7) of [9 ] , proved by Hatada on the same lattice, from the first period [9 §8] ; the proof above is a write-up of it. Checks (VERIF_A3.py): the inequality δ i ≥ 1 \delta_i \ge1 δ i ≥ 1 (and ≥ 2 \ge2 ≥ 2 if w ≢ 1 ( m o d 3 ) w \not\equiv1 \pmod{3} w ≡ 1 ( mod 3 ) ) for all even w ≤ 3000 w \le3000 w ≤ 3000 ; the identity of Lemma 3, the divisibility of m 1 m_1 m 1 and the inclusion T ~ 3 ( L k ) ⊂ 9 L k \widetilde{T}_3(L_k) \subset9L_k T 3 ( L k ) ⊂ 9 L k (resp. 27 L k 27L_k 27 L k ) on a basis of L k ⊗ Z ( 3 ) L_k \otimes\mathbb{Z}_{(3)} L k ⊗ Z ( 3 ) for 12 ≤ k ≤ 100 12 \le k \le100 12 ≤ k ≤ 100 ; eigenvalues recovered for the six rational forms. With PARI/GP, for every k ≤ 400 k \le400 k ≤ 400 , the smallest 3-adic slope of the characteristic polynomial of T 3 T_3 T 3 on S k S_k S k is 2 if 6 ∣ k 6 \mid k 6 ∣ k ; if 6 ∤ k 6 \nmid k 6 ∤ k , it is 3, except for k = 10 , 14 ( m o d 18 ) k=10,14 \pmod{18} k = 10 , 14 ( mod 18 ) , where it lies between 4 and 6 (VERIFIED ).
Theorem G (Conjecture 9.1 up to weight 1000; Chiriac). For every even weight 12 ≤ k ≤ 1000 12 \le k \le1000 12 ≤ k ≤ 1000 , k ≠ 14 k \ne14 k = 14 , every eigenform of level 1 and weight k k k satisfies Conjecture 9.1 of [17 ] .
STATUS: KNOWN. [4 Cor. 1.3] together with [17 ] . Independent check, which does not use the non-ramification hypothesis (494 spaces, all eigenforms). Certificate: let P P P be the characteristic polynomial of T 2 T_2 T 2 on S k S_k S k , of degree d d d , computed exactly modulo 3 2 d + 2 3^{2d+2} 3 2 d + 2 . If k ≡ 4 ( m o d 6 ) k \equiv4 \pmod{6} k ≡ 4 ( mod 6 ) , the Newton polygon of P P P at 3 has all its d d d slopes ≥ 2 \ge2 ≥ 2 . If k ≡ 0 , 2 ( m o d 6 ) k \equiv0,2 \pmod{6} k ≡ 0 , 2 ( mod 6 ) , the number of slopes ≥ 2 \ge2 ≥ 2 of the Newton polygon of P ( x + 3 ) P(x+3) P ( x + 3 ) , plus that of P ( x + 6 ) P(x+6) P ( x + 6 ) , is d d d ; since v 3 ( ( λ − 3 ) − ( λ − 6 ) ) = 1 v_3((\lambda-3)-(\lambda-6))=1 v 3 (( λ − 3 ) − ( λ − 6 )) = 1 , no root can be counted twice, so that every eigenvalue satisfies λ ≡ 3 \lambda\equiv3 λ ≡ 3 or 6 ( m o d 9 Z 3 ) \pmod{9\mathbb{Z}_3} ( mod 9 Z 3 ) . At precision 3 2 d + 2 3^{2d+2} 3 2 d + 2 , the slopes < 2 <2 < 2 are determined exactly.
Theorem H (level 1 case of the Coleman–Stein conjecture). Let f f f be an eigenform of level 1 and weight k k k . If k ≤ 1000 k \le1000 k ≤ 1000 , or if 3 is unramified in the coefficient field of f f f , then a 3 ( f ) ≡ 0 ( m o d 9 Z 3 ) a_3(f) \equiv0 \pmod{9\mathbb{Z}_3} a 3 ( f ) ≡ 0 ( mod 9 Z 3 ) and f f f is congruent modulo 9 Z 3 9\mathbb{Z}_3 9 Z 3 , coefficient by coefficient, to one of the five eigenforms of the table of [6 ] (weights 12, 16, 20, 24, 32). The five classes are distinct and all attained.
Proof. For k ≥ 3 k \ge3 k ≥ 3 , one has a 3 n ( f ) = a 3 ( f ) a n ( f ) − 3 k − 1 a n / 3 ( f ) ≡ a 3 ( f ) a n ( f ) ( m o d 9 ) a_{3n}(f)=a_3(f)a_n(f)-3^{k-1}a_{n/3}(f) \equiv a_3(f)a_n(f) \pmod9 a 3 n ( f ) = a 3 ( f ) a n ( f ) − 3 k − 1 a n /3 ( f ) ≡ a 3 ( f ) a n ( f ) ( mod 9 ) ; the reduction of f f f modulo 9 is an eigenvector of the operator U U U , its eigenvalue a 3 ( f ) a_3(f) a 3 ( f ) , and of t Λ = [ 1 + 3 ] t_\Lambda=[1+3] t Λ = [ 1 + 3 ] , with eigenvalue 4 k 4^k 4 k . By [17 Thm 7.2(ii)] , the Hecke algebra T ( 3 , Z 3 ) \mathbb{T}(3,\mathbb{Z}_3) T ( 3 , Z 3 ) is generated by U U U , T 2 T_2 T 2 , 1 + T 7 1+T_7 1 + T 7 and t Λ t_\Lambda t Λ ; all the coefficients of f f f modulo 9 Z 3 9\mathbb{Z}_3 9 Z 3 are therefore determined by ( a 2 , a 3 , a 7 , 4 k ) ( m o d 9 Z 3 ) (a_2,a_3,a_7,4^k)\pmod{9\mathbb{Z}_3} ( a 2 , a 3 , a 7 , 4 k ) ( mod 9 Z 3 ) . One has a 3 ≡ 0 ( m o d 9 ) a_3 \equiv0 \pmod9 a 3 ≡ 0 ( mod 9 ) ; Theorem F; by [17 Prop. 9.3] , a 7 ≡ 5 , 8 , 2 ( m o d 9 Z 3 ) a_7 \equiv5,8,2 \pmod{9\mathbb{Z}_3} a 7 ≡ 5 , 8 , 2 ( mod 9 Z 3 ) according as k ≡ 0 , 2 , 4 ( m o d 6 ) k \equiv0,2,4 \pmod6 k ≡ 0 , 2 , 4 ( mod 6 ) , and 4 k ( m o d 9 ) 4^k \pmod9 4 k ( mod 9 ) depends only on k k k mod 3; finally a 2 a_2 a 2 satisfies Conjecture 9.1 (Theorem G if k ≤ 1000 k \le1000 k ≤ 1000 , [4 Cor. 1.3] under the non-ramification hypothesis). At most five tuples remain: two for k ≡ 0 ( m o d 6 ) k \equiv0 \pmod6 k ≡ 0 ( mod 6 ) (a 2 ≡ 3 a_2 \equiv3 a 2 ≡ 3 or 6), two for k ≡ 2 ( m o d 6 ) k \equiv2 \pmod6 k ≡ 2 ( mod 6 ) , one for k ≡ 4 ( m o d 6 ) k \equiv4 \pmod6 k ≡ 4 ( mod 6 ) (a 2 ≡ 0 a_2 \equiv0 a 2 ≡ 0 ). They are realised by the weights 12 and 24, 32 and 20, and 16 respectively.
STATUS: PROVED. A consequence of [17 Thm 7.2, Prop. 9.3] , of [4 ] , of Theorem G and of [9 ] (Theorem F). Coleman and Stein had checked their conjecture up to weight 74 in level 1.
Remark. In the proof of [17 Thm 9.2] , each a n ( f ) a_n(f) a n ( f ) modulo 9 is a polynomial with coefficients in Z / 9 Z \mathbb{Z}/9\mathbb{Z} Z /9 Z in a 2 ( f ) a_2(f) a 2 ( f ) , a 3 ( f ) a_3(f) a 3 ( f ) , a 7 ( f ) a_7(f) a 7 ( f ) and the eigenvalue of t Λ t_\Lambda t Λ ; Conjecture 9.1 controls a 2 ( f ) a_2(f) a 2 ( f ) , [17 Prop. 9.3] controls a 7 ( f ) a_7(f) a 7 ( f ) , the eigenvalue of t Λ t_\Lambda t Λ is 4 k 4^k 4 k , and a 3 ( f ) ≡ 0 ( m o d 9 Z 3 ) a_3(f) \equiv0 \pmod{9\mathbb{Z}_3} a 3 ( f ) ≡ 0 ( mod 9 Z 3 ) is taken there from [9 ] . Only Conjecture 9.1 therefore remained; it is proved in §5.
The eigenvalue a 2 a_2 a 2 modulo 9 and 27
We keep the notation of §4. For γ = ( a b c d ) \gamma= \begin{pmatrix} a & b \\ c & d \end{pmatrix} γ = ( a c b d ) with non-zero determinant and F ∈ Z [ x , y ] w F \in\mathbb{Z}[x,y]_w F ∈ Z [ x , y ] w , put σ γ F ( x , y ) = F ( a x + c y , b x + d y ) \sigma_\gamma F(x,y) = F(ax+cy,bx+dy) σ γ F ( x , y ) = F ( a x + cy , b x + d y ) ; thus μ P ∣ γ = μ P ∘ σ γ \mu_P|\gamma= \mu_P \circ\sigma_\gamma μ P ∣ γ = μ P ∘ σ γ , σ γ σ δ = σ γ δ \sigma_\gamma\sigma_\delta= \sigma_{\gamma\delta} σ γ σ δ = σ γ δ , and σ − γ = σ γ \sigma_{-\gamma} = \sigma_\gamma σ − γ = σ γ since w w w is even. We extend γ ↦ σ γ \gamma\mapsto\sigma_\gamma γ ↦ σ γ by linearity to the ring Z [ M ] \mathbb{Z}[\mathcal{M}] Z [ M ] of the monoid M = M 2 ( Z ) ∩ G L 2 ( Q ) \mathcal{M} = M_2(\mathbb{Z}) \cap\mathrm{GL}_2(\mathbb{Q}) M = M 2 ( Z ) ∩ GL 2 ( Q ) . We write T = ( 1 1 0 1 ) T = \begin{pmatrix}1&1\\0&1\end{pmatrix} T = ( 1 0 1 1 ) , T ′ = ( 1 0 1 1 ) T' = \begin{pmatrix}1&0\\1&1\end{pmatrix} T ′ = ( 1 1 0 1 ) , ε = ( − 1 0 0 1 ) \varepsilon= \begin{pmatrix}-1&0\\0&1\end{pmatrix} ε = ( − 1 0 0 1 ) , F x F_x F x , F y F_y F y for the partial derivatives, and s = σ κ − 1 ( 2 ) = 1 + 2 k − 1 s = \sigma_{\kappa-1}(2) = 1 + 2^{k-1} s = σ κ − 1 ( 2 ) = 1 + 2 k − 1 .
Since 2 n = ( 3 − 1 ) n ≡ − 1 + 3 n ( m o d 9 ) 2^n = (3-1)^n \equiv-1+3n \pmod9 2 n = ( 3 − 1 ) n ≡ − 1 + 3 n ( mod 9 ) for odd n n n ,
s ≡ 3 ( k − 1 ) ( m o d 9 ) . s \equiv3(k-1) \pmod9. s ≡ 3 ( k − 1 ) ( mod 9 ) .
Let P ∈ W − P \in W^- P ∈ W − . By definition, P ∣ ( 1 + S ) = P ∣ ( 1 + U + U 2 ) = P ∣ ( 1 + ε ) = 0 P|(1+S) = P|(1+U+U^2) = P|(1+\varepsilon) = 0 P ∣ ( 1 + S ) = P ∣ ( 1 + U + U 2 ) = P ∣ ( 1 + ε ) = 0 ; since T = U S − 1 T = US^{-1} T = U S − 1 and T ′ = − U 2 S T' = -U^2S T ′ = − U 2 S , we deduce the three-term relation P = P ∣ T + P ∣ T ′ P = P|T + P|T' P = P ∣ T + P ∣ T ′ (the one in the proof of Lemma 1(b)). Thus, for every form H H H ,
μ P ( H + σ ε H ) = μ P ( H + σ S H ) = μ P ( H − σ T H − σ T ′ H ) = 0. (1) \mu_P(H+\sigma_\varepsilon H) = \mu_P(H+\sigma_S H) = \mu_P(H-\sigma_T H-\sigma_{T'}H) = 0. \tag*{(1)} μ P ( H + σ ε H ) = μ P ( H + σ S H ) = μ P ( H − σ T H − σ T ′ H ) = 0. (1)
Applying the last one to σ ε H \sigma_\varepsilon H σ ε H (T ε = ε T − 1 T\varepsilon= \varepsilon T^{-1} T ε = ε T − 1 , T ′ ε = ε T ′ − 1 T'\varepsilon= \varepsilon T'^{-1} T ′ ε = ε T ′ − 1 ), we also get μ P ( H − σ T − 1 H − σ T ′ − 1 H ) = 0 \mu_P(H-\sigma_{T^{-1}}H-\sigma_{T'^{-1}}H)=0 μ P ( H − σ T − 1 H − σ T ′ − 1 H ) = 0 . More generally, let I \mathcal{I} I be the right ideal of Z [ M ] \mathbb{Z}[\mathcal{M}] Z [ M ] generated by 1 + S 1+S 1 + S , 1 + U + U 2 1+U+U^2 1 + U + U 2 and 1 + ε 1+\varepsilon 1 + ε : one has μ P ∘ σ ζ = 0 \mu_P \circ\sigma_\zeta= 0 μ P ∘ σ ζ = 0 for every ζ ∈ I \zeta\in\mathcal{I} ζ ∈ I .
Modulo 27
Theorem I (T 2 T_2 T 2 modulo 27). For every even k ≥ 12 k \ge12 k ≥ 12 , T ~ 2 ( L k ) ⊂ 3 L k \widetilde{T}_2(L_k) \subset3L_k T 2 ( L k ) ⊂ 3 L k and, for every P ∈ L k P \in L_k P ∈ L k ,
P ∣ T ~ 2 2 ≡ 9 ( k − 1 ) 2 P ( m o d 27 L k ) . P|\widetilde{T}_2^2 \equiv9(k-1)^2P \pmod{27L_k}. P ∣ T 2 2 ≡ 9 ( k − 1 ) 2 P ( mod 27 L k ) .
Corollary J. For every eigenform f f f of level 1 and weight k k k , a 2 ( f ) ≡ 0 ( m o d 3 Z 3 ) a_2(f) \equiv0 \pmod{3\mathbb{Z}_3} a 2 ( f ) ≡ 0 ( mod 3 Z 3 ) and a 2 ( f ) 2 ≡ 9 ( k − 1 ) 2 ( m o d 27 Z 3 ) a_2(f)^2 \equiv9(k-1)^2 \pmod{27\mathbb{Z}_3} a 2 ( f ) 2 ≡ 9 ( k − 1 ) 2 ( mod 27 Z 3 ) . If k ≡ 0 , 2 ( m o d 6 ) k \equiv0,2 \pmod6 k ≡ 0 , 2 ( mod 6 ) , then a 2 ( f ) ≡ 3 a_2(f) \equiv3 a 2 ( f ) ≡ 3 or 6 ( m o d 9 Z 3 ) 6 \pmod{9\mathbb{Z}_3} 6 ( mod 9 Z 3 ) , without any ramification hypothesis. If k ≡ 4 ( m o d 6 ) k \equiv4 \pmod6 k ≡ 4 ( mod 6 ) , then v 3 ( a 2 ( f ) ) ≥ 3 / 2 v_3(a_2(f)) \ge3/2 v 3 ( a 2 ( f )) ≥ 3/2 .
Proof. Let λ = a 2 ( f ) \lambda= a_2(f) λ = a 2 ( f ) . The operator T ~ 2 \widetilde{T}_2 T 2 is an endomorphism of the Z \mathbb{Z} Z -module L k L_k L k , with eigenvalues the a 2 ( f ) a_2(f) a 2 ( f ) ; let v ∈ L k ⊗ Z 3 v \in L_k \otimes\mathbb{Z}_3 v ∈ L k ⊗ Z 3 be an eigenvector for λ \lambda λ at least one of whose coordinates is a unit (Z 3 \mathbb{Z}_3 Z 3 is a valuation ring). By Theorem I, λ v ∈ 3 ( L k ⊗ Z 3 ) \lambda v \in3(L_k \otimes\mathbb{Z}_3) λ v ∈ 3 ( L k ⊗ Z 3 ) and ( λ 2 − 9 ( k − 1 ) 2 ) v ∈ 27 ( L k ⊗ Z 3 ) (\lambda^2 - 9(k-1)^2)v \in27(L_k \otimes\mathbb{Z}_3) ( λ 2 − 9 ( k − 1 ) 2 ) v ∈ 27 ( L k ⊗ Z 3 ) ; reading a unit coordinate, λ = 3 ν \lambda= 3\nu λ = 3 ν with ν ∈ Z 3 \nu\in\mathbb{Z}_3 ν ∈ Z 3 and ν 2 ≡ ( k − 1 ) 2 ( m o d 3 Z 3 ) \nu^2 \equiv(k-1)^2 \pmod{3\mathbb{Z}_3} ν 2 ≡ ( k − 1 ) 2 ( mod 3 Z 3 ) . If k ≢ 1 ( m o d 3 ) k \not\equiv1 \pmod3 k ≡ 1 ( mod 3 ) , then ( k − 1 ) 2 ≡ 1 (k-1)^2 \equiv1 ( k − 1 ) 2 ≡ 1 . The two factors of ( ν − 1 ) ( ν + 1 ) ∈ 3 Z 3 (\nu-1)(\nu+1) \in3\mathbb{Z}_3 ( ν − 1 ) ( ν + 1 ) ∈ 3 Z 3 are not both in the maximal ideal, since their difference 2 is a unit; one of them is therefore a unit, and the other lies in 3 Z 3 3\mathbb{Z}_3 3 Z 3 . Hence ν ≡ ± 1 \nu\equiv\pm1 ν ≡ ± 1 and λ ≡ ± 3 ( m o d 9 Z 3 ) \lambda\equiv\pm3 \pmod{9\mathbb{Z}_3} λ ≡ ± 3 ( mod 9 Z 3 ) . If k ≡ 1 ( m o d 3 ) k \equiv1 \pmod3 k ≡ 1 ( mod 3 ) , then ν 2 ∈ 3 Z 3 \nu^2 \in3\mathbb{Z}_3 ν 2 ∈ 3 Z 3 , that is v 3 ( λ ) ≥ 3 / 2 v_3(\lambda) \ge3/2 v 3 ( λ ) ≥ 3/2 .
Status: PROVED. For k ≡ 0 , 2 ( m o d 6 ) k \equiv0,2 \pmod6 k ≡ 0 , 2 ( mod 6 ) , one also has a 2 ( f ) ≡ ± s ( m o d 9 Z 3 ) a_2(f) \equiv\pm s \pmod{9\mathbb{Z}_3} a 2 ( f ) ≡ ± s ( mod 9 Z 3 ) , since s ≡ 3 ( k − 1 ) ( m o d 9 ) s \equiv3(k-1) \pmod9 s ≡ 3 ( k − 1 ) ( mod 9 ) . The case k ≡ 4 ( m o d 6 ) k \equiv4 \pmod6 k ≡ 4 ( mod 6 ) is treated in §5.2.
The proof of Theorem I occupies the rest of this subsection.
Lemma 4 (expansion of T 2 T_2 T 2 ). For F ∈ Z [ x , y ] w F \in\mathbb{Z}[x,y]_w F ∈ Z [ x , y ] w , put
A ∗ F = y F y ( x , − y ) + y F y ( x , x − y ) + x F x ( − x , y ) + x F x ( y − x , y ) . A^*F = yF_y(x,-y) + yF_y(x,x-y) + xF_x(-x,y) + xF_x(y-x,y). A ∗ F = y F y ( x , − y ) + y F y ( x , x − y ) + x F x ( − x , y ) + x F x ( y − x , y ) .
There is a Z \mathbb{Z} Z -linear endomorphism B ∗ B^* B ∗ of Z [ x , y ] w \mathbb{Z}[x,y]_w Z [ x , y ] w such that, for every P ∈ L k P \in L_k P ∈ L k and every F F F ,
μ P ∣ T ~ 2 ( F ) = − 3 μ P ( F ) + 3 μ P ( A ∗ F ) + 9 μ P ( B ∗ F ) ( m o d 27 ) . \mu_{P|\widetilde{T}_2}(F) = -3\mu_P(F) + 3\mu_P(A^*F) + 9\mu_P(B^*F) \pmod{27}. μ P ∣ T 2 ( F ) = − 3 μ P ( F ) + 3 μ P ( A ∗ F ) + 9 μ P ( B ∗ F ) ( mod 27 ) .
Proof. With 2 = − 1 + 3 2=-1+3 2 = − 1 + 3 , the four substitutions of M 2 \mathcal{M}_2 M 2 read
( x , 2 y ) = ( x , − y ) + 3 ( 0 , y ) , ( x , x + 2 y ) = ( x , x − y ) + 3 ( 0 , y ) , (x,2y)=(x,-y)+3(0,y),\qquad(x,x+2y)=(x,x-y)+3(0,y), ( x , 2 y ) = ( x , − y ) + 3 ( 0 , y ) , ( x , x + 2 y ) = ( x , x − y ) + 3 ( 0 , y ) ,
( 2 x , y ) = ( − x , y ) + 3 ( x , 0 ) , ( 2 x + y , y ) = ( y − x , y ) + 3 ( x , 0 ) . (2x,y)=(-x,y)+3(x,0),\qquad(2x+y,y)=(y-x,y)+3(x,0). ( 2 x , y ) = ( − x , y ) + 3 ( x , 0 ) , ( 2 x + y , y ) = ( y − x , y ) + 3 ( x , 0 ) .
In other words, each M ∈ M 2 M\in\mathcal{M}_2 M ∈ M 2 is written M = N + 3 H M=N+3H M = N + 3 H , where N N N runs over N 1 = ( 1 0 0 − 1 ) N_1=\begin{pmatrix}1&0\\0&-1\end{pmatrix} N 1 = ( 1 0 0 − 1 ) , N 2 = ( 1 1 0 − 1 ) N_2=\begin{pmatrix}1&1\\0&-1\end{pmatrix} N 2 = ( 1 0 1 − 1 ) , N 3 = ( − 1 0 0 1 ) N_3=\begin{pmatrix}-1&0\\0&1\end{pmatrix} N 3 = ( − 1 0 0 1 ) and N 4 = ( − 1 0 1 1 ) N_4=\begin{pmatrix}-1&0\\1&1\end{pmatrix} N 4 = ( − 1 1 0 1 ) . Taylor’s formula, whose divided derivatives are integral, gives ∑ M σ M F ≡ ∑ i σ N i F + 3 A ∗ F + 9 B ∗ F ( m o d 27 ) \sum_M\sigma_MF\equiv\sum_i\sigma_{N_i}F+3A^*F+9B^*F\pmod{27} ∑ M σ M F ≡ ∑ i σ N i F + 3 A ∗ F + 9 B ∗ F ( mod 27 ) , the first-order term being A ∗ F A^*F A ∗ F . Finally σ N 1 = σ N 3 = σ ε \sigma_{N_1}=\sigma_{N_3}=\sigma_\varepsilon σ N 1 = σ N 3 = σ ε , σ N 2 = σ ε σ T \sigma_{N_2}=\sigma_\varepsilon\sigma_T σ N 2 = σ ε σ T and σ N 4 = σ ε σ T ′ \sigma_{N_4}=\sigma_\varepsilon\sigma_{T'} σ N 4 = σ ε σ T ′ (since N 2 = N 1 T N_2=N_1T N 2 = N 1 T and N 4 = N 3 T ′ N_4=N_3T' N 4 = N 3 T ′ ); by (R), μ P ( ∑ i σ N i F ) = − 2 μ P ( F ) − μ P ( σ T F + σ T ′ F ) = − 3 μ P ( F ) \mu_P(\sum_i\sigma_{N_i}F)=-2\mu_P(F)-\mu_P(\sigma_TF+\sigma_{T'}F)=-3\mu_P(F) μ P ( ∑ i σ N i F ) = − 2 μ P ( F ) − μ P ( σ T F + σ T ′ F ) = − 3 μ P ( F ) .
Lemma 5 (an identity in characteristic 3). Let μ \mu μ be a linear form on Z [ x , y ] w \mathbb{Z}[x,y]_w Z [ x , y ] w , with values in F 3 \mathbb{F}_3 F 3 , which satisfies the relations (R) modulo 3. For every F F F ,
μ ( A ∗ A ∗ F + A ∗ F ) = w ( w + 2 ) μ ( F ) − w μ ( y ∂ x [ ( σ T − 1 ) 2 F ] ) . \mu(A^*A^*F+A^*F)=w(w+2)\mu(F)-w\mu\bigl(y\partial_x[(\sigma_T-1)^2F]\bigr). μ ( A ∗ A ∗ F + A ∗ F ) = w ( w + 2 ) μ ( F ) − w μ ( y ∂ x [( σ T − 1 ) 2 F ] ) .
Proof. Write E = ∂ x + ∂ y E=\partial_x+\partial_y E = ∂ x + ∂ y ; steps (i) to (iii) are exact identities.
(i) One has A ∗ F = − σ N 1 ( y F y ) + σ N 2 ( ( x − y ) F y ) − σ N 3 ( x F x ) + σ N 4 ( ( y − x ) F x ) A^*F=-\sigma_{N_1}(yF_y)+\sigma_{N_2}((x-y)F_y)-\sigma_{N_3}(xF_x)+\sigma_{N_4}((y-x)F_x) A ∗ F = − σ N 1 ( y F y ) + σ N 2 (( x − y ) F y ) − σ N 3 ( x F x ) + σ N 4 (( y − x ) F x ) . With the equalities of the proof of Lemma 4 and x F x + y F y = w F xF_x+yF_y=wF x F x + y F y = w F , we get A ∗ = σ ε ∘ ( Φ − w ) A^*=\sigma_\varepsilon\circ(\Phi-w) A ∗ = σ ε ∘ ( Φ − w ) , where Φ F = σ T ( ( x − y ) F y ) − σ T ′ ( ( x − y ) F x ) \Phi F=\sigma_T((x-y)F_y)-\sigma_{T'}((x-y)F_x) Φ F = σ T (( x − y ) F y ) − σ T ′ (( x − y ) F x ) .
(ii) Since x − y = − σ ε ( x + y ) x-y=-\sigma_\varepsilon(x+y) x − y = − σ ε ( x + y ) , ∂ y σ ε = σ ε ∂ y \partial_y\sigma_\varepsilon=\sigma_\varepsilon\partial_y ∂ y σ ε = σ ε ∂ y , ∂ x σ ε = − σ ε ∂ x \partial_x\sigma_\varepsilon=-\sigma_\varepsilon\partial_x ∂ x σ ε = − σ ε ∂ x , T ε = ε T − 1 T\varepsilon=\varepsilon T^{-1} T ε = ε T − 1 and T ′ ε = ε T ′ − 1 T'\varepsilon=\varepsilon T'^{-1} T ′ ε = ε T ′ − 1 , one has, for every H H H , Φ ( σ ε H ) = − σ ε X H \Phi(\sigma_\varepsilon H)=-\sigma_\varepsilon XH Φ ( σ ε H ) = − σ ε X H with X H = σ T − 1 ( ( x + y ) H y ) + σ T ′ − 1 ( ( x + y ) H x ) XH=\sigma_{T^{-1}}((x+y)H_y)+\sigma_{T'^{-1}}((x+y)H_x) X H = σ T − 1 (( x + y ) H y ) + σ T ′ − 1 (( x + y ) H x ) . With G = Φ F G=\Phi F G = Φ F , we get A ∗ A ∗ F + A ∗ F = − X G − w F − w ( G − w F ) + σ ε ( G − w F ) A^*A^*F+A^*F=-XG-wF-w(G-wF)+\sigma_\varepsilon(G-wF) A ∗ A ∗ F + A ∗ F = − X G − w F − w ( G − w F ) + σ ε ( G − w F ) , then, by (R),
μ ( A ∗ A ∗ F + A ∗ F ) = − μ ( X G + G ) − w μ ( G ) + w μ ( X F ) + w ( w + 1 ) μ ( F ) . \mu(A^*A^*F+A^*F)=-\mu(XG+G)-w\mu(G)+w\mu(XF)+w(w+1)\mu(F). μ ( A ∗ A ∗ F + A ∗ F ) = − μ ( X G + G ) − w μ ( G ) + w μ ( X F ) + w ( w + 1 ) μ ( F ) .
(iii) Put K 1 = ( x − y ) F y K_1=(x-y)F_y K 1 = ( x − y ) F y and K 2 = ( x − y ) F x K_2=(x-y)F_x K 2 = ( x − y ) F x , so that G = σ T K 1 − σ T ′ K 2 G=\sigma_TK_1-\sigma_{T'}K_2 G = σ T K 1 − σ T ′ K 2 . The rules ∂ x σ T = σ T E \partial_x\sigma_T=\sigma_TE ∂ x σ T = σ T E , ∂ y σ T = σ T ∂ y \partial_y\sigma_T=\sigma_T\partial_y ∂ y σ T = σ T ∂ y , ∂ x σ T ′ = σ T ′ ∂ x \partial_x\sigma_{T'}=\sigma_{T'}\partial_x ∂ x σ T ′ = σ T ′ ∂ x , ∂ y σ T ′ = σ T ′ E \partial_y\sigma_{T'}=\sigma_{T'}E ∂ y σ T ′ = σ T ′ E , ( x + y ) σ T Y = σ T ( y Y ) (x+y)\sigma_TY=\sigma_T(yY) ( x + y ) σ T Y = σ T ( y Y ) , ( x + y ) σ T ′ Y = σ T ′ ( x Y ) (x+y)\sigma_{T'}Y=\sigma_{T'}(xY) ( x + y ) σ T ′ Y = σ T ′ ( x Y ) , T − 1 T ′ = S T T^{-1}T'=ST T − 1 T ′ = S T and T ′ − 1 T = − S T ′ T'^{-1}T=-ST' T ′ − 1 T = − S T ′ give
X G = y ∂ y K 1 − x ∂ x K 2 − σ S σ T ( x E K 2 ) + σ S σ T ′ ( y E K 1 ) . XG=y\partial_yK_1-x\partial_xK_2-\sigma_S\sigma_T(xEK_2)+\sigma_S\sigma_{T'}(yEK_1). X G = y ∂ y K 1 − x ∂ x K 2 − σ S σ T ( x E K 2 ) + σ S σ T ′ ( y E K 1 ) .
Put Z 1 = x E K 2 + K 1 Z_1=xEK_2+K_1 Z 1 = x E K 2 + K 1 and Z 2 = y E K 1 + K 2 Z_2=yEK_1+K_2 Z 2 = y E K 1 + K 2 . Euler’s identities x F x x + y F x y = ( w − 1 ) F x xF_{xx}+yF_{xy}=(w-1)F_x x F xx + y F x y = ( w − 1 ) F x and x F x y + y F y y = ( w − 1 ) F y xF_{xy}+yF_{yy}=(w-1)F_y x F x y + y F y y = ( w − 1 ) F y give Z 1 + Z 2 = w ( x − y ) E F Z_1+Z_2=w(x-y)EF Z 1 + Z 2 = w ( x − y ) E F and y ∂ y K 1 − x ∂ x K 2 − Z 2 = − w F − w ( x − y ) F x y\partial_yK_1-x\partial_xK_2-Z_2=-wF-w(x-y)F_x y ∂ y K 1 − x ∂ x K 2 − Z 2 = − w F − w ( x − y ) F x . By (R), μ ∘ σ S = − μ \mu\circ\sigma_S=-\mu μ ∘ σ S = − μ and μ ∘ σ T ′ = μ − μ ∘ σ T \mu\circ\sigma_{T'}=\mu-\mu\circ\sigma_T μ ∘ σ T ′ = μ − μ ∘ σ T ; hence
μ ( X G + G ) = μ ( y ∂ y K 1 − x ∂ x K 2 − Z 2 ) + μ ( σ T ( Z 1 + Z 2 ) ) = w μ ( − F − ( x − y ) F x + σ T ( ( x − y ) E F ) ) . \mu(XG+G)=\mu(y\partial_yK_1-x\partial_xK_2-Z_2)+\mu(\sigma_T(Z_1+Z_2))
=w\mu\bigl(-F-(x-y)F_x+\sigma_T((x-y)EF)\bigr). μ ( X G + G ) = μ ( y ∂ y K 1 − x ∂ x K 2 − Z 2 ) + μ ( σ T ( Z 1 + Z 2 )) = w μ ( − F − ( x − y ) F x + σ T (( x − y ) E F ) ) .
(iv) Substituting into (ii), using again μ ∘ σ T ′ = μ − μ ∘ σ T \mu\circ\sigma_{T'}=\mu-\mu\circ\sigma_T μ ∘ σ T ′ = μ − μ ∘ σ T and μ ∘ σ T ′ − 1 = μ − μ ∘ σ T − 1 \mu\circ\sigma_{T'^{-1}}=\mu-\mu\circ\sigma_{T^{-1}} μ ∘ σ T ′ − 1 = μ − μ ∘ σ T − 1 , together with σ T ( ( x − y ) E F ) = − y ∂ x ( σ T F ) \sigma_T((x-y)EF)=-y\partial_x(\sigma_TF) σ T (( x − y ) E F ) = − y ∂ x ( σ T F ) and σ T − 1 ( ( x + y ) ( F x − F y ) ) = y ∂ x ( σ T − 1 F ) \sigma_{T^{-1}}((x+y)(F_x-F_y))=y\partial_x(\sigma_{T^{-1}}F) σ T − 1 (( x + y ) ( F x − F y )) = y ∂ x ( σ T − 1 F ) , we obtain the exact identity
μ ( A ∗ A ∗ F + A ∗ F ) = w ( w + 2 ) μ ( F ) + 3 w μ ( x F x ) − w μ ( y ∂ x [ ( 1 − 2 σ T + σ T − 1 ) F ] ) . \mu(A^*A^*F+A^*F)=w(w+2)\mu(F)+3w\mu(xF_x)-w\mu\bigl(y\partial_x[(1-2\sigma_T+\sigma_{T^{-1}})F]\bigr). μ ( A ∗ A ∗ F + A ∗ F ) = w ( w + 2 ) μ ( F ) + 3 w μ ( x F x ) − w μ ( y ∂ x [( 1 − 2 σ T + σ T − 1 ) F ] ) .
Modulo 3, the term 3 w μ ( x F x ) 3w\mu(xF_x) 3 w μ ( x F x ) vanishes, σ T − 1 = σ T 2 \sigma_{T^{-1}}=\sigma_{T^2} σ T − 1 = σ T 2 (since T 3 ≡ I T^3\equiv I T 3 ≡ I ) and 1 − 2 σ T + σ T 2 ≡ 1 + σ T + σ T 2 ≡ ( σ T − 1 ) 2 1-2\sigma_T+\sigma_{T^2}\equiv1+\sigma_T+\sigma_{T^2}\equiv(\sigma_T-1)^2 1 − 2 σ T + σ T 2 ≡ 1 + σ T + σ T 2 ≡ ( σ T − 1 ) 2 .
Lemma 6 (information modulo 9). For every P ∈ L k P\in L_k P ∈ L k and every F ∈ Z [ x , y ] w F\in\mathbb{Z}[x,y]_w F ∈ Z [ x , y ] w , μ P ( y ∂ x [ ( σ T − 1 ) 2 F ] ) ≡ 0 ( m o d 3 ) \mu_P(y\partial_x[(\sigma_T-1)^2F])\equiv0\pmod{3} μ P ( y ∂ x [( σ T − 1 ) 2 F ]) ≡ 0 ( mod 3 ) .
Proof. Let G \mathcal{G} G be the group of matrices in G L 2 ( Z / 9 Z ) \mathrm{GL}_2(\mathbb{Z}/9\mathbb{Z}) GL 2 ( Z /9 Z ) of determinant ± 1 \pm1 ± 1 , modulo ± I \pm I ± I ; it has 648 elements, and the action F ↦ σ γ F F\mapsto\sigma_\gamma F F ↦ σ γ F on Z [ x , y ] w / 9 \mathbb{Z}[x,y]_w/9 Z [ x , y ] w /9 factors through G \mathcal{G} G , whence an action of the ring R = ( Z / 9 Z ) [ G ] \mathcal{R}=(\mathbb{Z}/9\mathbb{Z})[\mathcal{G}] R = ( Z /9 Z ) [ G ] . Let I 9 \mathcal{I}_9 I 9 be the image of I \mathcal{I} I in R \mathcal{R} R , and C ⊂ R \mathcal{C}\subset\mathcal{R} C ⊂ R the two-sided ideal generated by 3 and the κ − 1 \kappa-1 κ − 1 , κ ≡ ± I ( m o d 3 ) \kappa\equiv\pm I\pmod{3} κ ≡ ± I ( mod 3 ) . A finite exact computation in R \mathcal{R} R (an explicit combination of 290 terms, redone by VERIF-A2.py) shows that
ξ : = T ( 1 + T ′ + T ′ 2 ) ( 1 + T + T 2 ) ∈ I 9 + C 2 . \xi:=T(1+T'+T'^{2})(1+T+T^{2})\in\mathcal{I}_9+\mathcal{C}^{2}. ξ := T ( 1 + T ′ + T ′ 2 ) ( 1 + T + T 2 ) ∈ I 9 + C 2 .
The elements of I 9 \mathcal{I}_9 I 9 annihilate μ P \mu_P μ P modulo 9 9 9 . Each σ κ \sigma_\kappa σ κ , κ ≡ ± I ( m o d 3 ) \kappa\equiv\pm I \pmod{3} κ ≡ ± I ( mod 3 ) , is congruent to the identity modulo 3 3 3 ; every element of C C C therefore acts by an operator vanishing modulo 3 3 3 , and C 2 C^2 C 2 acts by 0 0 0 modulo 9 9 9 . Thus μ P ( σ ξ F ) = 0 ( m o d 9 ) \mu_P(\sigma_\xi F) = 0 \pmod{9} μ P ( σ ξ F ) = 0 ( mod 9 ) . On the other hand, multiplying on the right the relation P = P ∣ T + P ∣ T ′ P=P|T+P|T' P = P ∣ T + P ∣ T ′ by T ′ j T'^j T ′ j (j = 0 , 1 , 2 j=0,1,2 j = 0 , 1 , 2 ) and summing, we get P ∣ T ( 1 + T ′ + T ′ 2 ) = P − P ∣ T ′ 3 P|T(1+T'+T'^2)=P-P|T'^3 P ∣ T ( 1 + T ′ + T ′2 ) = P − P ∣ T ′3 ; with H = ( 1 + σ T + σ T 2 ) F H=(1+\sigma_T+\sigma_{T^2})F H = ( 1 + σ T + σ T 2 ) F and σ T ′ 3 H ( x , y ) = H ( x + 3 y , y ) \sigma_{T'^3}H(x,y)=H(x+3y,y) σ T ′3 H ( x , y ) = H ( x + 3 y , y ) , Taylor’s formula gives
μ P ( σ ξ F ) = μ P ( H ) − μ P ( σ T ′ 3 H ) = − 3 μ P ( y ∂ x H ) ( m o d 9 ) . \mu_P(\sigma_\xi F)=\mu_P(H)-\mu_P(\sigma_{T'^3}H)=-3\mu_P(y\partial_xH)\pmod{9}. μ P ( σ ξ F ) = μ P ( H ) − μ P ( σ T ′3 H ) = − 3 μ P ( y ∂ x H ) ( mod 9 ) .
Hence μ P ( y ∂ x H ) ≡ 0 ( m o d 3 ) \mu_P(y\partial_xH)\equiv0\pmod{3} μ P ( y ∂ x H ) ≡ 0 ( mod 3 ) , and one concludes with 1 + σ T + σ T 2 = ( σ T − 1 ) 2 + 3 σ T 1+\sigma_T+\sigma_{T^2}=(\sigma_T-1)^2+3\sigma_T 1 + σ T + σ T 2 = ( σ T − 1 ) 2 + 3 σ T .
Proof of Theorem I. Let P ∈ L k P\in L_k P ∈ L k . By Lemma 4, μ P ∣ T ~ 2 ( F ) ≡ 0 ( m o d 3 ) \mu_{P|\widetilde{T}_2}(F)\equiv0\pmod{3} μ P ∣ T 2 ( F ) ≡ 0 ( mod 3 ) for every F F F , hence P ∣ T ~ 2 ∈ 3 B w ∩ W − = 3 L k P|\widetilde{T}_2\in3B_w\cap W^-=3L_k P ∣ T 2 ∈ 3 B w ∩ W − = 3 L k . Put Q = P ∣ T ~ 2 Q=P|\widetilde{T}_2 Q = P ∣ T 2 . Lemma 4 gives μ Q ( G ) ≡ 3 μ P ( A ∗ G − G ) ( m o d 9 ) \mu_Q(G)\equiv3\mu_P(A^*G-G)\pmod{9} μ Q ( G ) ≡ 3 μ P ( A ∗ G − G ) ( mod 9 ) for every G G G , and, applied to Q Q Q , μ Q ∣ T ~ 2 ( F ) ≡ 3 μ Q ( A ∗ F − F ) + 9 μ Q ( B ∗ F ) ≡ 9 μ P ( ( A ∗ − 1 ) 2 F ) ( m o d 27 ) \mu_{Q|\widetilde{T}_2}(F)\equiv3\mu_Q(A^*F-F)+9\mu_Q(B^*F)\equiv9\mu_P((A^*-1)^2F)\pmod{27} μ Q ∣ T 2 ( F ) ≡ 3 μ Q ( A ∗ F − F ) + 9 μ Q ( B ∗ F ) ≡ 9 μ P (( A ∗ − 1 ) 2 F ) ( mod 27 ) , since μ Q ≡ 0 ( m o d 3 ) \mu_Q\equiv0\pmod{3} μ Q ≡ 0 ( mod 3 ) . Modulo 3 3 3 , ( A ∗ − 1 ) 2 ≡ A ∗ A ∗ + A ∗ + 1 (A^*-1)^2\equiv A^*A^*+A^*+1 ( A ∗ − 1 ) 2 ≡ A ∗ A ∗ + A ∗ + 1 ; Lemmas 5 and 6, applied to the reduction of μ P \mu_P μ P , give μ P ( ( A ∗ − 1 ) 2 F ) ≡ ( 1 + w ( w + 2 ) ) μ P ( F ) = ( k − 1 ) 2 μ P ( F ) ( m o d 3 ) \mu_P((A^*-1)^2F)\equiv(1+w(w+2))\mu_P(F)=(k-1)^2\mu_P(F)\pmod{3} μ P (( A ∗ − 1 ) 2 F ) ≡ ( 1 + w ( w + 2 )) μ P ( F ) = ( k − 1 ) 2 μ P ( F ) ( mod 3 ) . Thus P ∣ T ~ 2 2 − 9 ( k − 1 ) 2 P ∈ 27 B w ∩ W − = 27 L k P|\widetilde{T}_2^2-9(k-1)^2P\in27B_w\cap W^-=27L_k P ∣ T 2 2 − 9 ( k − 1 ) 2 P ∈ 27 B w ∩ W − = 27 L k .
Status: PROVED. Lemma 6 rests on a finite exact computation, whose certificate is checked by VERIF_A2.py. Checks: the congruence of Theorem I checked directly on L k L_k L k for $12\le k\le 290$ (PARI/GP); the identity of Lemma 5 on all solutions modulo 3 3 3 of the relations, and the condition of Lemma 6 on L k L_k L k , for $k\le 40 (VERIF_A2.py).
Modulo 81
Theorem K (T 2 T_2 T 2 modulo $81). Let k ≥ 12 k\ge12 k ≥ 12 be even and P ∈ L k P\in L_k P ∈ L k . Then
P ∣ T ~ 2 2 ≡ s 2 P ( m o d 81 L k ) if k ≡ 0 , 2 ( m o d 6 ) , P|\widetilde{T}_2^2\equiv s^2P\pmod{81L_k}\qquad\text{if }k\equiv0,2\pmod{6}, P ∣ T 2 2 ≡ s 2 P ( mod 81 L k ) if k ≡ 0 , 2 ( mod 6 ) ,
P ∣ T ~ 2 2 + 9 P ∣ T ~ 2 ≡ 0 ( m o d 81 L k ) if k ≡ 4 ( m o d 6 ) . P|\widetilde{T}_2^2+9P|\widetilde{T}_2\equiv0\pmod{81L_k}\qquad\text{if }k\equiv4\pmod{6}. P ∣ T 2 2 + 9 P ∣ T 2 ≡ 0 ( mod 81 L k ) if k ≡ 4 ( mod 6 ) .
Corollary L. Let f f f be an eigenform of level 1 1 1 and weight k k k . If k ≡ 0 , 2 ( m o d 6 ) k\equiv0,2\pmod{6} k ≡ 0 , 2 ( mod 6 ) , then a 2 ( f ) ≡ ± σ k − 1 ( 2 ) ( m o d 27 Z 3 ) a_2(f)\equiv\pm\sigma_{k-1}(2)\pmod{27\mathbb{Z}_3} a 2 ( f ) ≡ ± σ k − 1 ( 2 ) ( mod 27 Z 3 ) . If k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) , then a 2 ( f ) ≡ 0 ( m o d 9 Z 3 ) a_2(f)\equiv0\pmod{9\mathbb{Z}_3} a 2 ( f ) ≡ 0 ( mod 9 Z 3 ) . In particular, Conjecture 9.1 of [17 ] holds for every eigenform of level 1.
Proof. Let λ = a 2 ( f ) \lambda=a_2(f) λ = a 2 ( f ) . As in the proof of Corollary J, Theorem K gives λ 2 − s 2 ∈ 81 Z 3 \lambda^2-s^2\in81\mathbb{Z}_3 λ 2 − s 2 ∈ 81 Z 3 if k ≡ 0 , 2 ( m o d 6 ) k\equiv0,2\pmod{6} k ≡ 0 , 2 ( mod 6 ) , and λ 2 + 9 λ ∈ 81 Z 3 \lambda^2+9\lambda\in81\mathbb{Z}_3 λ 2 + 9 λ ∈ 81 Z 3 if k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) .
If k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) and v 3 ( λ ) < 2 v_3(\lambda)<2 v 3 ( λ ) < 2 , then v 3 ( λ + 9 ) = v 3 ( λ ) v_3(\lambda+9)=v_3(\lambda) v 3 ( λ + 9 ) = v 3 ( λ ) and v 3 ( λ 2 + 9 λ ) = 2 v 3 ( λ ) < 4 v_3(\lambda^2+9\lambda)=2v_3(\lambda)<4 v 3 ( λ 2 + 9 λ ) = 2 v 3 ( λ ) < 4 , which is excluded; hence λ ∈ 9 Z 3 \lambda\in9\mathbb{Z}_3 λ ∈ 9 Z 3 .
If k ≡ 0 , 2 ( m o d 6 ) k\equiv0,2\pmod{6} k ≡ 0 , 2 ( mod 6 ) , then 3 ∤ k − 1 3\nmid k-1 3 ∤ k − 1 , hence s ≡ 3 ( k − 1 ) ≡ ± 3 ( m o d 9 ) s\equiv3(k-1)\equiv\pm3\pmod{9} s ≡ 3 ( k − 1 ) ≡ ± 3 ( mod 9 ) and v 3 ( s ) = 1 v_3(s)=1 v 3 ( s ) = 1 . From λ 2 ≡ s 2 ( m o d 81 ) \lambda^2\equiv s^2\pmod{81} λ 2 ≡ s 2 ( mod 81 ) we get v 3 ( λ ) = 1 v_3(\lambda)=1 v 3 ( λ ) = 1 . The elements λ − s \lambda-s λ − s and λ + s \lambda+s λ + s lie in 3 Z 3 3\mathbb{Z}_3 3 Z 3 , and their sum 2 λ 2\lambda 2 λ has valuation 1 1 1 : one of the two has valuation exactly 1 1 1 , and the other, whose product with the first lies in 81 Z 3 81\mathbb{Z}_3 81 Z 3 , has valuation ≥ 3 \ge3 ≥ 3 . Hence λ ≡ ± s ( m o d 27 Z 3 ) \lambda\equiv\pm s\pmod{27\mathbb{Z}_3} λ ≡ ± s ( mod 27 Z 3 ) ; reducing modulo 9 9 9 , λ ≡ 3 \lambda\equiv3 λ ≡ 3 or 6 ( m o d 9 Z 3 ) 6\pmod{9\mathbb{Z}_3} 6 ( mod 9 Z 3 ) .
Status: PROVED. From Theorem K, whose proof is completed below (Lemma 8). The same consequences follow from [18 Thm 1.5] , obtained independently by another method.
Lemma 7 (a vanishing criterion). Let n ≥ 1 n\ge1 n ≥ 1 and r ∈ { 0 , 1 , 2 } r\in\{0,1,2\} r ∈ { 0 , 1 , 2 } . Let H \mathcal{H} H be a system of integral representatives of GL 2 ( F 3 ) / { ± 1 } \operatorname{GL}_2(\mathbb{F}_3)/\{\pm1\} GL 2 ( F 3 ) / { ± 1 } , and let X = ∑ g c g g X=\sum_g c_g g X = ∑ g c g g be a finite combination, with integer coefficients, of integer matrices g g g with determinant prime to 3 3 3 . Write g = ± h g κ g ( m o d 3 n ) g=\pm h_g\kappa_g\pmod{3^n} g = ± h g κ g ( mod 3 n ) with h g ∈ H h_g\in\mathcal{H} h g ∈ H and κ g = ( p u v q ) ≡ I ( m o d 3 ) \kappa_g=\begin{pmatrix}p&u\\v&q\end{pmatrix}\equiv I\pmod{3} κ g = ( p v u q ) ≡ I ( mod 3 ) . For δ ∈ Z \delta\in\mathbb{Z} δ ∈ Z and A , B ≥ 0 A,B\ge0 A , B ≥ 0 , put
c δ , A , B ( κ g ) = ∑ u a q b ( p − 1 ) m ( v − 1 ) m ′ ( A a ) ( B b ) , c_{\delta,A,B}(\kappa_g)=\sum u^a q^b(p-1)^m(v-1)^{m'}\binom{A}{a}\binom{B}{b}, c δ , A , B ( κ g ) = ∑ u a q b ( p − 1 ) m ( v − 1 ) m ′ ( a A ) ( b B ) ,
the sum running over the a , b , m , m ′ ≥ 0 a,b,m,m' \ge0 a , b , m , m ′ ≥ 0 such that b − a = δ b-a=\delta b − a = δ , a + m = A a+m=A a + m = A and b + m ′ = B b+m'=B b + m ′ = B ; and, for h ∈ H h\in\mathcal{H} h ∈ H ,
f h , δ ( i , t ) = ∑ h g = h ∑ A + B < n c δ , A , B ( κ g ) ( i A ) ( 3 t + r − i B ) . f_{h,\delta}(i,t)=\sum_{hg=h}\sum_{A+B<n}c_{\delta,A,B}(\kappa_g)\binom{i}{A}\binom{3t+r-i}{B}. f h , δ ( i , t ) = h g = h ∑ A + B < n ∑ c δ , A , B ( κ g ) ( A i ) ( B 3 t + r − i ) .
where ( z B ) = z ( z − 1 ) ⋯ ( z − B + 1 ) / B ! \binom{z}{B}=z(z-1)\cdots(z-B+1)/B! ( B z ) = z ( z − 1 ) ⋯ ( z − B + 1 ) / B ! . If, for all h h h , δ \delta δ and A + B < n A+B<n A + B < n , the finite difference Δ i A Δ t B f h , δ ( 0 , 0 ) \Delta_i^A\Delta_t^Bf_{h,\delta}(0,0) Δ i A Δ t B f h , δ ( 0 , 0 ) is divisible by 3 n 3^n 3 n , then σ X ( Z [ x , y ] w ) ⊂ 3 n Z [ x , y ] w \sigma_X(\mathbb{Z}[x,y]_w)\subset3^n\mathbb{Z}[x,y]_w σ X ( Z [ x , y ] w ) ⊂ 3 n Z [ x , y ] w for every even w w w such that w ≡ r ( m o d 3 ) w\equiv r\pmod{3} w ≡ r ( mod 3 ) .
Proof. Let w w w be even, w = 3 t + r w=3t+r w = 3 t + r . The operator σ g \sigma_g σ g modulo 3 n 3^n 3 n depends only on g g g modulo 3 n 3^n 3 n , and σ − g = σ g \sigma_{-g}=\sigma_g σ − g = σ g ; hence σ g ≡ σ h g σ κ g \sigma_g\equiv\sigma_{hg}\sigma_{\kappa_g} σ g ≡ σ h g σ κ g . For κ = ( p q u v ) \kappa=\left(\begin{smallmatrix}p&q\\u&v\end{smallmatrix}\right) κ = ( p u q v ) and i + j = w i+j=w i + j = w ,
σ κ ( x i y j ) = ( p x + u y ) i ( q x + v y ) j = ∑ a , b ( i a ) ( j b ) p i − a u a q b v j − b x i − a + b y j + a − b . \sigma_\kappa(x^iy^j)=(px+uy)^i(qx+vy)^j=\sum_{a,b}\binom{i}{a}\binom{j}{b}p^{i-a}u^a q^b v^{j-b}x^{i-a+b}y^{j+a-b}. σ κ ( x i y j ) = ( p x + u y ) i ( q x + v y ) j = a , b ∑ ( a i ) ( b j ) p i − a u a q b v j − b x i − a + b y j + a − b .
Expand p i − a = ∑ m ( i − a m ) ( p − 1 ) m p^{i-a}=\sum_m\binom{i-a}{m}(p-1)^m p i − a = ∑ m ( m i − a ) ( p − 1 ) m and v j − b = ∑ m ′ ( j − b m ′ ) ( v − 1 ) m ′ v^{j-b}=\sum_{m'}\binom{j-b}{m'}(v-1)^{m'} v j − b = ∑ m ′ ( m ′ j − b ) ( v − 1 ) m ′ , and use ( i a ) ( i − a m ) = ( i a + m ) ( a + m a ) \binom{i}{a}\binom{i-a}{m}=\binom{i}{a+m}\binom{a+m}{a} ( a i ) ( m i − a ) = ( a + m i ) ( a a + m ) . The terms with a + b + m + m ′ ≥ n a+b+m+m'\ge n a + b + m + m ′ ≥ n are divisible by 3 n 3^n 3 n , since u u u , q q q , p − 1 p-1 p − 1 and v − 1 v-1 v − 1 are divisible by 3 3 3 . We get
σ X ( x i y w − i ) ≡ ∑ h ∈ H σ h ( ∑ δ f h , δ ( i , t ) x i + δ y w − i − δ ) ( m o d 3 n ) . \sigma_X(x^iy^{w-i})\equiv\sum_{h\in\mathcal{H}}\sigma_h\left(\sum_\delta f_{h,\delta}(i,t)x^{i+\delta}y^{w-i-\delta}\right)\pmod{3^n}. σ X ( x i y w − i ) ≡ h ∈ H ∑ σ h ( δ ∑ f h , δ ( i , t ) x i + δ y w − i − δ ) ( mod 3 n ) .
The polynomial f h , δ f_{h,\delta} f h , δ has total degree < n <n < n and takes integer values on Z 2 \mathbb{Z}^2 Z 2 ; by Newton’s formula,
f h , δ ( i , t ) = ∑ A + B < n Δ i A Δ t B f h , δ ( 0 , 0 ) ( i A ) ( t B ) . f_{h,\delta}(i,t)=\sum_{A+B<n}\Delta_i^A\Delta_t^Bf_{h,\delta}(0,0)\binom{i}{A}\binom{t}{B}. f h , δ ( i , t ) = A + B < n ∑ Δ i A Δ t B f h , δ ( 0 , 0 ) ( A i ) ( B t ) .
Under the hypothesis, all its values are divisible by 3 n 3^n 3 n , and σ X ( x i y w − i ) ∈ 3 n Z [ x , y ] w \sigma_X(x^iy^{w-i})\in3^n\mathbb{Z}[x,y]_w σ X ( x i y w − i ) ∈ 3 n Z [ x , y ] w for every i i i .
Lemma 8 (three certificates). Let T = ∑ M ∈ M 2 M T=\sum_{M\in\mathcal{M}_2}M T = ∑ M ∈ M 2 M and Λ 2 = ( 2 0 0 2 ) \Lambda_2=\left(\begin{smallmatrix}2&0\\0&2\end{smallmatrix}\right) Λ 2 = ( 2 0 0 2 ) , and put Ξ σ = T 2 − ( 1 + 2 Λ 2 ) 2 \Xi_\sigma=T^2-(1+2\Lambda_2)^2 Ξ σ = T 2 − ( 1 + 2 Λ 2 ) 2 and Ξ 4 = T 2 + 9 T \Xi_4=T^2+9T Ξ 4 = T 2 + 9 T . There are explicit elements ζ 0 , ζ 1 , ζ 2 ∈ I \zeta_0,\zeta_1,\zeta_2\in I ζ 0 , ζ 1 , ζ 2 ∈ I , sums of 977, 1005 and 1079 terms, such that Ξ σ − ζ 0 \Xi_\sigma-\zeta_0 Ξ σ − ζ 0 , Ξ σ − ζ 1 \Xi_\sigma-\zeta_1 Ξ σ − ζ 1 and Ξ 4 − ζ 2 \Xi_4-\zeta_2 Ξ 4 − ζ 2 satisfy the hypothesis of Lemma 7 with n = 4 n=4 n = 4 and r = 0 r=0 r = 0 , 1, 2 respectively.
Proof. Each term has the form c γ h ( κ 1 − 1 ) α 1 ( κ 2 − 1 ) α 2 ( κ 3 − 1 ) α 3 ( κ 4 − 1 ) α 4 c\gamma h(\kappa_1-1)^{\alpha_1}(\kappa_2-1)^{\alpha_2}(\kappa_3-1)^{\alpha_3}(\kappa_4-1)^{\alpha_4} c γ h ( κ 1 − 1 ) α 1 ( κ 2 − 1 ) α 2 ( κ 3 − 1 ) α 3 ( κ 4 − 1 ) α 4 , with c c c an integer, γ ∈ { 1 + S , 1 + U + U 2 , 1 + ε } \gamma\in\{1+S,1+U+U^2,1+\varepsilon\} γ ∈ { 1 + S , 1 + U + U 2 , 1 + ε } , h ∈ H h\in\mathcal{H} h ∈ H , κ 1 = ( 4 0 0 1 ) \kappa_1=\left(\begin{smallmatrix}4&0\\0&1\end{smallmatrix}\right) κ 1 = ( 4 0 0 1 ) , κ 2 = ( 1 3 0 1 ) \kappa_2=\left(\begin{smallmatrix}1&3\\0&1\end{smallmatrix}\right) κ 2 = ( 1 0 3 1 ) , κ 3 = ( 1 0 3 1 ) \kappa_3=\left(\begin{smallmatrix}1&0\\3&1\end{smallmatrix}\right) κ 3 = ( 1 3 0 1 ) , κ 4 = ( 1 0 0 4 ) \kappa_4=\left(\begin{smallmatrix}1&0\\0&4\end{smallmatrix}\right) κ 4 = ( 1 0 0 4 ) and α 1 + α 2 + α 3 + α 4 ≤ 3 \alpha_1+\alpha_2+\alpha_3+\alpha_4\le3 α 1 + α 2 + α 3 + α 4 ≤ 3 ; it belongs to I I I , which is a right ideal. Checking the hypothesis of Lemma 7 is a finite exact computation: one expands Ξ − ζ r \Xi-\zeta_r Ξ − ζ r as a combination of matrices modulo 81, then computes the finite differences. This computation, and the three certificates, are in VERIF_A2.py.
Proof of Theorem K. Let P ∈ L k P\in L_k P ∈ L k , w = k − 2 w=k-2 w = k − 2 and r ∈ { 0 , 1 , 2 } r\in\{0,1,2\} r ∈ { 0 , 1 , 2 } such that w ≡ r ( m o d 3 ) w\equiv r\pmod{3} w ≡ r ( mod 3 ) : r = 0 r=0 r = 0 if k ≡ 2 ( m o d 6 ) k\equiv2\pmod{6} k ≡ 2 ( mod 6 ) , r = 1 r=1 r = 1 if k ≡ 0 ( m o d 6 ) k\equiv0\pmod{6} k ≡ 0 ( mod 6 ) and r = 2 r=2 r = 2 if k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) . Let Ξ = Ξ σ \Xi=\Xi_\sigma Ξ = Ξ σ if r ≤ 1 r\le1 r ≤ 1 , Ξ = Ξ 4 \Xi=\Xi_4 Ξ = Ξ 4 if r = 2 r=2 r = 2 , and ζ = ζ r \zeta=\zeta_r ζ = ζ r . Since μ P ∣ γ = μ P ∘ σ γ \mu_P|_\gamma=\mu_P\circ\sigma_\gamma μ P ∣ γ = μ P ∘ σ γ and Λ 2 \Lambda_2 Λ 2 acts on Z [ x , y ] w \mathbb{Z}[x,y]_w Z [ x , y ] w by 2 w 2^w 2 w , the form μ P ∘ σ Ξ \mu_P\circ\sigma_\Xi μ P ∘ σ Ξ is that of P ∣ T ~ 2 2 − s 2 P P|\widetilde{T}_2^2-s^2P P ∣ T 2 2 − s 2 P if r ≤ 1 r\le1 r ≤ 1 , of P ∣ T ~ 2 2 + 9 P ∣ T ~ 2 P|\widetilde{T}_2^2+9P|\widetilde{T}_2 P ∣ T 2 2 + 9 P ∣ T 2 if r = 2 r=2 r = 2 . One has μ P ∘ σ ζ = 0 \mu_P\circ\sigma_\zeta=0 μ P ∘ σ ζ = 0 since ζ ∈ I \zeta\in I ζ ∈ I , and, by Lemmas 7 and 8, σ Ξ − ζ ( F ) ∈ 81 Z [ x , y ] w \sigma_{\Xi-\zeta}(F)\in81\mathbb{Z}[x,y]_w σ Ξ − ζ ( F ) ∈ 81 Z [ x , y ] w for every F F F . Since μ P \mu_P μ P takes integer values on Z [ x , y ] w \mathbb{Z}[x,y]_w Z [ x , y ] w , we get μ P ( σ Ξ F ) ≡ 0 ( m o d 81 ) \mu_P(\sigma_\Xi F)\equiv0\pmod{81} μ P ( σ Ξ F ) ≡ 0 ( mod 81 ) for every F F F : the polynomial under consideration lies in 81 B w ∩ W − = 81 L k 81B_w\cap W_-=81L_k 81 B w ∩ W − = 81 L k .
Status: PROVED. Finite exact computation (Lemma 8), checked by VERIF_A2.py (part E). Checks: direct action of the remainders Ξ − ζ r \Xi-\zeta_r Ξ − ζ r on Z [ x , y ] w \mathbb{Z}[x,y]_w Z [ x , y ] w modulo 81 for all even w ≤ 60 w\le60 w ≤ 60 in the relevant class (part G); congruences of Theorem K checked directly on L k L_k L k for 12 ≤ k ≤ 290 12\le k\le290 12 ≤ k ≤ 290 and, if k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) , up to k = 334 k=334 k = 334 (PARI/GP). For k ≡ 0 , 2 ( m o d 6 ) k\equiv0,2\pmod{6} k ≡ 0 , 2 ( mod 6 ) , an operator congruence of the same kind for T ~ 2 2 \widetilde{T}_2^2 T 2 2 modulo 81, on a lattice of even modular symbols, appears independently in [18 §5.2.2] .
Remark. Theorem K implies Theorem I, given T ~ 2 ( L k ) ⊂ 3 L k \widetilde{T}_2(L_k)\subset3L_k T 2 ( L k ) ⊂ 3 L k (Lemma 4). For k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) , one does not have T ~ 2 ( L k ) ⊂ 9 L k \widetilde{T}_2(L_k)\subset9L_k T 2 ( L k ) ⊂ 9 L k in general (for example for k = 40 k=40 k = 40 ): the quadratic congruence of Theorem K is the natural form of the statement. Corollaries J and L contain [4 Thm 1.2 and Cor. 1.3] ; the difference is that the congruences of Theorems I and K concern the operator T ~ 2 \widetilde{T}_2 T 2 acting on the whole lattice L k L_k L k , and therefore pass to all eigenvalues, whatever the coefficient field. For the rational forms of weights 12, 18, 20 and 26, one has a 2 = − 24 a_2=-24 a 2 = − 24 , − 528 -528 − 528 , 456 456 456 , − 48 -48 − 48 , and even a 2 ≡ − s ( m o d 27 ) a_2\equiv-s\pmod{27} a 2 ≡ − s ( mod 27 ) ; for example τ ( 2 ) = − 24 ≡ − 2049 ( m o d 27 ) \tau(2)=-24\equiv-2049\pmod{27} τ ( 2 ) = − 24 ≡ − 2049 ( mod 27 ) . For k = 16 k=16 k = 16 and 22, a 2 = 216 a_2=216 a 2 = 216 and − 288 -288 − 288 are divisible by 9.
Theorem M (level 1 case of the Coleman–Stein conjecture). Let f f f be an eigenform of level 1 and weight k k k . Then a 3 ( f ) ≡ 0 ( m o d 9 Z 3 ) a_3(f)\equiv0\pmod{9\mathbb{Z}_3} a 3 ( f ) ≡ 0 ( mod 9 Z 3 ) , and f f f is congruent modulo 9 Z 3 9\mathbb{Z}_3 9 Z 3 , coefficient by coefficient, to one of the five eigenforms of the table of [6 ] : the one of weight 16 if k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) ; the one of weight 12 or the one of weight 24 if k ≡ 0 ( m o d 6 ) k\equiv0\pmod{6} k ≡ 0 ( mod 6 ) , and the one of weight 32 or the one of weight 20 if k ≡ 2 ( m o d 6 ) k\equiv2\pmod{6} k ≡ 2 ( mod 6 ) , according as a 2 ( f ) ≡ 3 a_2(f)\equiv3 a 2 ( f ) ≡ 3 or 6 ( m o d 9 Z 3 ) \pmod{9\mathbb{Z}_3} ( mod 9 Z 3 ) .
Proof. This is the proof of Theorem H, with Corollaries J and L in place of Conjecture 9.1. □
STATUS: PROVED. A consequence of [17 Thm 7.2, Prop. 9.3] , of [9 ] (Theorem F) and of Corollaries J and L, without any hypothesis on k k k or on the coefficient field. This statement also follows from [18 Thm 1.5] , obtained independently by another method.
An Eisenstein law modulo 81
We write χ \chi χ for the Dirichlet character of conductor 3 (χ ( n ) = 1 \chi(n)=1 χ ( n ) = 1 if n ≡ 1 n\equiv1 n ≡ 1 , − 1 -1 − 1 if n ≡ 2 ( m o d 3 ) n\equiv2\pmod{3} n ≡ 2 ( mod 3 ) ), 1 3 \mathbf{1}_3 1 3 for the principal character modulo 3, σ ( n ) = σ k − 1 ( n ) \sigma(n)=\sigma_{k-1}(n) σ ( n ) = σ k − 1 ( n ) and, for a prime ℓ ≠ 3 \ell\ne3 ℓ = 3 , s ℓ = σ k − 1 ( ℓ ) = 1 + ℓ k − 1 s_\ell=\sigma_{k-1}(\ell)=1+\ell^{k-1} s ℓ = σ k − 1 ( ℓ ) = 1 + ℓ k − 1 . If ℓ ≡ 2 ( m o d 3 ) \ell\equiv2\pmod{3} ℓ ≡ 2 ( mod 3 ) , v 3 ( s ℓ ) = v 3 ( ℓ + 1 ) + v 3 ( k − 1 ) v_3(s_\ell)=v_3(\ell+1)+v_3(k-1) v 3 ( s ℓ ) = v 3 ( ℓ + 1 ) + v 3 ( k − 1 ) ; for ℓ ≢ − 1 ( m o d 9 ) \ell\not\equiv-1\pmod{9} ℓ ≡ − 1 ( mod 9 ) (for example ℓ = 2 , 5 , 11 \ell=2,5,11 ℓ = 2 , 5 , 11 ), this equals 1 if k ≢ 4 ( m o d 6 ) k\not\equiv4\pmod{6} k ≡ 4 ( mod 6 ) and is at least 2 otherwise.
Other operators T ℓ T_\ell T ℓ
Theorem K extends to other primes by the same method: T ~ ℓ = ∑ M ∈ M ℓ M \widetilde{T}_\ell=\sum_{M\in\mathcal{M}_\ell}M T ℓ = ∑ M ∈ M ℓ M replaces T ~ 2 \widetilde{T}_2 T 2 (∣ M ℓ ∣ = 15 , 25 , 54 , 77 , 93 , 109 |\mathcal{M}_\ell|=15,25,54,77,93,109 ∣ M ℓ ∣ = 15 , 25 , 54 , 77 , 93 , 109 for ℓ = 5 , 7 , 11 , 13 , 17 , 19 \ell=5,7,11,13,17,19 ℓ = 5 , 7 , 11 , 13 , 17 , 19 ), Λ ℓ = ( ℓ 0 0 1 ) \Lambda_\ell=\begin{pmatrix}\ell&0\\0&1\end{pmatrix} Λ ℓ = ( ℓ 0 0 1 ) , which acts on Z [ x , y ] w \mathbb{Z}[x,y]_w Z [ x , y ] w by ℓ w \ell^w ℓ w , replaces Λ 2 \Lambda_2 Λ 2 , and Lemma 7 applies with any modulus 3 n 3^n 3 n .
Theorem N (T ℓ T_\ell T ℓ modulo 81 and 243, ℓ ≤ 19 \ell\le19 ℓ ≤ 19 ). Let k ≥ 12 k\ge12 k ≥ 12 be even and P ∈ L k P\in L_k P ∈ L k .
(a) For ℓ ∈ { 7 , 13 } \ell\in\{7,13\} ℓ ∈ { 7 , 13 } : P ∣ T ~ ℓ ≡ s ℓ P ( m o d 81 L k ) P\mid\widetilde{T}_\ell\equiv s_\ell P\pmod{81L_k} P ∣ T ℓ ≡ s ℓ P ( mod 81 L k ) if k ≢ 4 ( m o d 6 ) k\not\equiv4\pmod{6} k ≡ 4 ( mod 6 ) , and ( m o d 27 L k ) \pmod{27L_k} ( mod 27 L k ) if k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) . For ℓ = 19 \ell=19 ℓ = 19 : the same congruences modulo 243 L k 243L_k 243 L k and 81 L k 81L_k 81 L k respectively.
(a′) If k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) : P ∣ T ~ 7 − s 7 P − 18 P ∣ T ~ 2 ≡ 0 ( m o d 81 L k ) P\mid\widetilde{T}_7-s_7P-18P\mid\widetilde{T}_2\equiv0\pmod{81L_k} P ∣ T 7 − s 7 P − 18 P ∣ T 2 ≡ 0 ( mod 81 L k ) .
(a′′) If k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) : P ∣ T ~ 19 − s 19 P − 54 P ∣ T ~ 2 ≡ 0 ( m o d 243 L k ) P\mid\widetilde{T}_{19}-s_{19}P-54P\mid\widetilde{T}_2\equiv0\pmod{243L_k} P ∣ T 19 − s 19 P − 54 P ∣ T 2 ≡ 0 ( mod 243 L k ) .
(b) For ℓ ∈ { 5 , 11 } \ell\in\{5,11\} ℓ ∈ { 5 , 11 } and k ≢ 4 ( m o d 6 ) k\not\equiv4\pmod{6} k ≡ 4 ( mod 6 ) : P ∣ T ~ ℓ 2 = s ℓ 2 P ( m o d 81 L k ) P\mid\widetilde{T}_\ell^2=s_\ell^2P\pmod{81L_k} P ∣ T ℓ 2 = s ℓ 2 P ( mod 81 L k ) ; for ℓ = 17 \ell=17 ℓ = 17 , modulo 243 L k 243L_k 243 L k .
(c) For ℓ ∈ { 5 , 11 } \ell\in\{5,11\} ℓ ∈ { 5 , 11 } and k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) : there are explicit polynomials a ℓ , b ℓ ∈ ( Z / 81 Z ) [ X ] a_\ell,b_\ell\in(\mathbb{Z}/81\mathbb{Z})[X] a ℓ , b ℓ ∈ ( Z /81 Z ) [ X ] of degree 5, with b ℓ ( ℓ w ) ≡ 0 b_\ell(\ell^w)\equiv0 b ℓ ( ℓ w ) ≡ 0 and a ℓ ( ℓ w ) ≡ 0 ( m o d 9 ) a_\ell(\ell^w)\equiv0\pmod{9} a ℓ ( ℓ w ) ≡ 0 ( mod 9 ) for every even w ≡ 2 ( m o d 3 ) w\equiv2\pmod{3} w ≡ 2 ( mod 3 ) , such that P ∣ T ~ ℓ 2 + a ℓ ( ℓ w ) P ∣ T ~ ℓ + b ℓ ( ℓ w ) P ≡ 0 ( m o d 81 L k ) P\mid\widetilde{T}_\ell^2+a_\ell(\ell^w)P\mid\widetilde{T}_\ell+b_\ell(\ell^w)P\equiv0\pmod{81L_k} P ∣ T ℓ 2 + a ℓ ( ℓ w ) P ∣ T ℓ + b ℓ ( ℓ w ) P ≡ 0 ( mod 81 L k ) .
In particular, for every eigenform f f f of level 1 and weight k k k , a 7 ( f ) ≡ s 7 ( m o d 81 Z 3 ) a_7(f)\equiv s_7\pmod{81\mathbb{Z}_3} a 7 ( f ) ≡ s 7 ( mod 81 Z 3 ) and a 19 ( f ) ≡ s 19 ( m o d 243 Z 3 ) a_{19}(f)\equiv s_{19}\pmod{243\mathbb{Z}_3} a 19 ( f ) ≡ s 19 ( mod 243 Z 3 ) whatever k k k .
Proof. Each congruence on L k L_k L k is established by a certificate ζ ∈ I \zeta\in\mathcal{I} ζ ∈ I and the criterion of Lemma 7, exactly as in Lemma 8: nineteen certificates (from 229 to 1600 terms), all checked by VERIF_EISENSTEIN.py, which also checks, for (c), the two conditions on a ℓ ( ℓ w ) a_\ell(\ell^w) a ℓ ( ℓ w ) and b ℓ ( ℓ w ) b_\ell(\ell^w) b ℓ ( ℓ w ) (they depend only on ℓ w \ell^w ℓ w modulo 81, which takes 27 values). For the last assertion, if k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) , (a′) gives a 7 − s 7 ≡ 18 a 2 ( m o d 81 ) a_7-s_7\equiv18a_2\pmod{81} a 7 − s 7 ≡ 18 a 2 ( mod 81 ) and (a′′) gives a 19 − s 19 ≡ 54 a 2 ( m o d 243 ) a_{19}-s_{19}\equiv54a_2\pmod{243} a 19 − s 19 ≡ 54 a 2 ( mod 243 ) , and 9 ∣ a 2 9\mid a_2 9 ∣ a 2 (Corollary L). □
STATUS: PROVED. Finite exact computation. For ℓ = 7 \ell=7 ℓ = 7 , the congruence modulo 9 is [17 Prop. 9.3] ; the congruence a 7 ≡ s 7 a_7\equiv s_7 a 7 ≡ s 7 modulo 81 in the valuative sense is also in [18 (5.5)] .
The law
We use the full Hecke algebra T = T ( 3 , Z 3 ) \mathbb{T}=\mathbb{T}(3,\mathbb{Z}_3) T = T ( 3 , Z 3 ) of [17 ] : it acts on the space D ( 3 , ⋅ ) D(3,\cdot) D ( 3 , ⋅ ) of divided congruences (Katz) of cusp forms of level 3, is generated by the T n T_n T n , 3 ∤ n 3\nmid n 3 ∤ n , and by U U U , and contains the operator t = [ 1 + 3 ] t=[1+3] t = [ 1 + 3 ] of the action of Z 3 × \mathbb{Z}_3^\times Z 3 × , which acts by x k x^k x k on forms of weight k k k , so that t t t acts by t k = 4 k t_k=4^k t k = 4 k . Let V p a r V^{\mathrm{par}} V par be the space of cuspidal 3-adic modular functions of tame level 1 (in Katz’s sense: vanishing at all cusps of the Igusa tower), and V ⊃ V p a r V\supset V^{\mathrm{par}} V ⊃ V par that of all 3-adic modular functions of tame level 1. For every finite quotient R R R of the ring of integers O O O of a finite extension of Q 3 \mathbb{Q}_3 Q 3 , one has D ( 3 , R ) = D ( 3 , O ) ⊗ R = V p a r ( O ) ⊗ R D(3,R)=D(3,O)\otimes R=V^{\mathrm{par}}(O)\otimes R D ( 3 , R ) = D ( 3 , O ) ⊗ R = V par ( O ) ⊗ R [17 Prop. 2.1 and Lemma 3.1] . We use three of its properties.
(F1) [17 Thm 7.2(ii)] : T \mathbb{T} T is local, with residue field F 3 \mathbb{F}_3 F 3 , and the set S = { U , T 2 , 1 + T 7 , t − 1 } \mathcal{S}=\{U,T_2,1+T_7,t-1\} S = { U , T 2 , 1 + T 7 , t − 1 } generates it as a Z 3 \mathbb{Z}_3 Z 3 -algebra (by Nakayama’s lemma: m = ( 3 , S ) + m 2 \mathfrak{m}=(3,\mathcal{S})+\mathfrak{m}^2 m = ( 3 , S ) + m 2 ). By induction, T = Z 3 [ S ] + m N \mathbb{T}=\mathbb{Z}_3[\mathcal{S}]+\mathfrak{m}^N T = Z 3 [ S ] + m N for every N N N ; since every finite quotient of T \mathbb{T} T is local Artinian, hence killed by a power of m \mathfrak{m} m , the image of T \mathbb{T} T in every finite quotient is that of Z 3 [ S ] \mathbb{Z}_3[\mathcal{S}] Z 3 [ S ] .
(F2) [17 Thm 2.2, Prop. 3.3] (Katz): the q q q -expansion is injective on V p a r ( O ) V^{\mathrm{par}}(O) V par ( O ) . If F ∈ V p a r ( O ) F\in V^{\mathrm{par}}(O) F ∈ V par ( O ) satisfies a 1 ( F ) = 1 a_1(F)=1 a 1 ( F ) = 1 and is an eigenvector of the T n T_n T n (3 ∤ n 3\nmid n 3 ∤ n ) and of U U U , its reduction modulo 81 is an element of D ( 3 , O / 81 ) = V p a r ( O ) ⊗ O / 81 D(3,O/81)=V^{\mathrm{par}}(O)\otimes O/81 D ( 3 , O /81 ) = V par ( O ) ⊗ O /81 which is an eigenvector of T \mathbb{T} T , and τ ↦ a 1 ( τ F ) \tau\mapsto a_1(\tau F) τ ↦ a 1 ( τ F ) defines a character φ F : T → O / 81 O \varphi_F:\mathbb{T}\to O/81O φ F : T → O /81 O , with φ F ( T n ) = a n ( F ) \varphi_F(T_n)=a_n(F) φ F ( T n ) = a n ( F ) for 3 ∤ n 3\nmid n 3 ∤ n (since a 1 ( T n G ) = a n ( G ) a_1(T_nG)=a_n(G) a 1 ( T n G ) = a n ( G ) ). Moreover V p a r ( O ) V^{\mathrm{par}}(O) V par ( O ) is saturated in O [ [ q ] ] O[[q]] O [[ q ]] : if the expansion of F ∈ V p a r ( O ) F\in V^{\mathrm{par}}(O) F ∈ V par ( O ) lies in 3 O [ [ q ] ] 3O[[q]] 3 O [[ q ]] , then F ∈ 3 V p a r ( O ) F\in3V^{\mathrm{par}}(O) F ∈ 3 V par ( O ) , since D ( 3 , O / 3 ) = V p a r ( O ) ⊗ O / 3 D(3,O/3)=V^{\mathrm{par}}(O)\otimes O/3 D ( 3 , O /3 ) = V par ( O ) ⊗ O /3 injects into ( O / 3 ) [ [ q ] ] (O/3)[[q]] ( O /3 ) [[ q ]] .
(F3) If G ∈ V ( O ) G\in V(O) G ∈ V ( O ) is an eigenvector of weight k k k of the T ℓ T_\ell T ℓ (ℓ ≠ 3 \ell\ne3 ℓ = 3 ), with eigenvalues λ ℓ \lambda_\ell λ ℓ , the series
θ j G = ∑ n j a n ( G ) q n , θ = q d / d q , \theta^jG=\sum n^j a_n(G)q^n,\qquad\theta=q\,d/dq, θ j G = ∑ n j a n ( G ) q n , θ = q d / d q ,
is a 3-adic modular form in Serre’s sense [19 ] , a limit of forms of level 1 with coefficients in O O O , hence an element of V ( O ) V(O) V ( O ) [13 ] ; it has weight k + 2 j k+2j k + 2 j (the action of x ∈ Z 3 × x\in\mathbb{Z}_3^\times x ∈ Z 3 × is multiplied by x 2 j x^{2j} x 2 j ), and is an eigenvector with eigenvalues ℓ j λ ℓ \ell^j\lambda_\ell ℓ j λ ℓ . Since x x x acts by a scalar, the constant term of θ j G \theta^jG θ j G , which vanishes at the cusp ∞ \infty ∞ , vanishes at all cusps: θ j G ∈ V p a r ( O ) \theta^jG\in V^{\mathrm{par}}(O) θ j G ∈ V par ( O ) . For j = 2 ⋅ 3 m j=2\cdot3^m j = 2 ⋅ 3 m (resp. j = 3 m j=3^m j = 3 m ), n j n^j n j tends, as m → ∞ m\to\infty m → ∞ , to 1 3 ( n ) \mathbf{1}_3(n) 1 3 ( n ) (resp. χ ( n ) \chi(n) χ ( n ) ), uniformly in n n n . The limits G ⊗ 1 3 = ∑ 3 ∤ n a n ( G ) q n G\otimes\mathbf{1}_3=\sum_{3\nmid n}a_n(G)q^n G ⊗ 1 3 = ∑ 3 ∤ n a n ( G ) q n and G ⊗ χ G\otimes\chi G ⊗ χ are therefore in V p a r ( O ) V^{\mathrm{par}}(O) V par ( O ) , eigenvectors of the T ℓ T_\ell T ℓ with eigenvalues λ ℓ \lambda_\ell λ ℓ and χ ( ℓ ) λ ℓ \chi(\ell)\lambda_\ell χ ( ℓ ) λ ℓ , killed by U U U , and t t t acts on them by the same scalar as on G G G (since 4 2 j → 1 4^{2j}\to1 4 2 j → 1 ).
Theorem O (Eisenstein law modulo 81). Let f f f be a normalised cuspidal eigenform of level 1 and weight k k k , and fix an embedding of its coefficient field into Q ‾ 3 \overline{\mathbb{Q}}_3 Q 3 .
(i) For every n ≡ 1 ( m o d 3 ) n\equiv1\pmod3 n ≡ 1 ( mod 3 ) : a n ( f ) ≡ σ k − 1 ( n ) ( m o d 81 Z ‾ 3 ) a_n(f)\equiv\sigma_{k-1}(n)\pmod{81\overline{\mathbb{Z}}_3} a n ( f ) ≡ σ k − 1 ( n ) ( mod 81 Z 3 ) .
(ii) If k ≢ 4 ( m o d 6 ) k\not\equiv4\pmod6 k ≡ 4 ( mod 6 ) , let ψ = 1 3 \psi=\mathbf{1}_3 ψ = 1 3 if a 2 ( f ) ≡ s 2 ( m o d 27 ) a_2(f)\equiv s_2\pmod{27} a 2 ( f ) ≡ s 2 ( mod 27 ) and ψ = χ \psi=\chi ψ = χ if a 2 ( f ) ≡ − s 2 ( m o d 27 ) a_2(f)\equiv-s_2\pmod{27} a 2 ( f ) ≡ − s 2 ( mod 27 ) (Corollary L); then a n ( f ) ≡ ψ ( n ) σ k − 1 ( n ) ( m o d 27 Z ‾ 3 ) a_n(f)\equiv\psi(n)\sigma_{k-1}(n)\pmod{27\overline{\mathbb{Z}}_3} a n ( f ) ≡ ψ ( n ) σ k − 1 ( n ) ( mod 27 Z 3 ) for every n n n prime to 3.
(iii) If k ≡ 4 ( m o d 6 ) k\equiv4\pmod6 k ≡ 4 ( mod 6 ) : a n ( f ) ≡ σ k − 1 ( n ) ( m o d 9 Z ‾ 3 ) a_n(f)\equiv\sigma_{k-1}(n)\pmod{9\overline{\mathbb{Z}}_3} a n ( f ) ≡ σ k − 1 ( n ) ( mod 9 Z 3 ) for every n n n prime to 3.
Proof. Let O O O be the ring of integers of a finite extension of Q 3 \mathbb{Q}_3 Q 3 containing the coefficients of f f f , and R = O / 81 O R=O/81O R = O /81 O . The weight k k k being fixed, let E = − 2 k B k G k E=-\frac{2k}{B_k}G_k E = − B k 2 k G k , where G k = − B k 2 k + ∑ σ ( n ) q n G_k=-\frac{B_k}{2k}+\sum\sigma(n)q^n G k = − 2 k B k + ∑ σ ( n ) q n ; by von Staudt–Clausen, v 3 ( B k ) = − 1 v_3(B_k)=-1 v 3 ( B k ) = − 1 , hence c = − 2 k / B k c=-2k/B_k c = − 2 k / B k satisfies v 3 ( c ) = 1 + v 3 ( k ) ≥ 1 v_3(c)=1+v_3(k)\ge1 v 3 ( c ) = 1 + v 3 ( k ) ≥ 1 , and E = 1 + c ∑ σ ( n ) q n E=1+c\sum\sigma(n)q^n E = 1 + c ∑ σ ( n ) q n is a form of level 1 with coefficients in Z 3 \mathbb{Z}_3 Z 3 , hence an element of V ( Z 3 ) V(\mathbb{Z}_3) V ( Z 3 ) . By (F3), applied to f f f and to E E E , then the saturation (F2) (to divide by c c c ), the four series
f ⊗ 1 3 , f ⊗ χ , E 1 = ∑ 3 ∤ n σ ( n ) q n , E χ = ∑ 3 ∤ n χ ( n ) σ ( n ) q n f\otimes\mathbf{1}_3,\qquad f\otimes\chi,\qquad E^{\mathbf{1}}=\sum_{3\nmid n}\sigma(n)q^n,\qquad E^\chi=\sum_{3\nmid n}\chi(n)\sigma(n)q^n f ⊗ 1 3 , f ⊗ χ , E 1 = 3 ∤ n ∑ σ ( n ) q n , E χ = 3 ∤ n ∑ χ ( n ) σ ( n ) q n
lie in V p a r ( O ) V^{\mathrm{par}}(O) V par ( O ) , with a 1 = 1 a_1=1 a 1 = 1 , are eigenvectors of the T ℓ T_\ell T ℓ , are killed by U U U , and t t t acts on them by t k t_k t k . By (F2), they define four characters φ , φ χ , φ E , φ E χ : T → R \varphi,\varphi^\chi,\varphi_E,\varphi_E^\chi:\mathbb{T}\to R φ , φ χ , φ E , φ E χ : T → R . On the generators of (F1), they take the values
U ↦ 0 , t ↦ t k , T 2 ↦ a 2 , − a 2 , s 2 , − s 2 , 1 + T 7 ↦ 1 + a 7 , 1 + a 7 , 1 + s 7 , 1 + s 7 , U\mapsto0,\qquad t\mapsto t_k,\qquad T_2\mapsto a_2,\,-a_2,\,s_2,\,-s_2,\qquad1+T_7\mapsto1+a_7,\,1+a_7,\,1+s_7,\,1+s_7, U ↦ 0 , t ↦ t k , T 2 ↦ a 2 , − a 2 , s 2 , − s 2 , 1 + T 7 ↦ 1 + a 7 , 1 + a 7 , 1 + s 7 , 1 + s 7 ,
and a 7 ≡ s 7 ( m o d 81 ) a_7 \equiv s_7 \pmod{81} a 7 ≡ s 7 ( mod 81 ) (Theorem N). Let n n n be prime to 3. The image of T \mathbb{T} T in R 4 R^4 R 4 is finite; (F1) therefore provides a polynomial P P P with coefficients in Z 3 \mathbb{Z}_3 Z 3 such that T n T_n T n and P ( U , T 2 , 1 + T 7 , t ) P(U,T_2,1+T_7,t) P ( U , T 2 , 1 + T 7 , t ) have the same image under the four characters. Put Q ( x ) = P ( 0 , x , 1 + s 7 , t k ) ∈ R [ x ] Q(x)=P(0,x,1+s_7,t_k)\in R[x] Q ( x ) = P ( 0 , x , 1 + s 7 , t k ) ∈ R [ x ] . Then
a n ( f ) = Q ( a 2 ) , χ ( n ) a n ( f ) = Q ( − a 2 ) , σ ( n ) ≡ Q ( s 2 ) , χ ( n ) σ ( n ) ≡ Q ( − s 2 ) ( m o d 81 ) . a_n(f)=Q(a_2),\qquad\chi(n)a_n(f)=Q(-a_2),\qquad\sigma(n)\equiv Q(s_2),\qquad\chi(n)\sigma(n)\equiv Q(-s_2)\pmod{81}. a n ( f ) = Q ( a 2 ) , χ ( n ) a n ( f ) = Q ( − a 2 ) , σ ( n ) ≡ Q ( s 2 ) , χ ( n ) σ ( n ) ≡ Q ( − s 2 ) ( mod 81 ) .
(i) If n ≡ 1 ( m o d 3 ) n\equiv1\pmod{3} n ≡ 1 ( mod 3 ) , write Q ( x ) = Q 0 ( x 2 ) + x Q 1 ( x 2 ) Q(x)=Q_0(x^2)+xQ_1(x^2) Q ( x ) = Q 0 ( x 2 ) + x Q 1 ( x 2 ) . From Q ( a 2 ) ≡ Q ( − a 2 ) Q(a_2)\equiv Q(-a_2) Q ( a 2 ) ≡ Q ( − a 2 ) we get 2 a 2 Q 1 ( a 2 2 ) ≡ 0 2a_2Q_1(a_2^2)\equiv0 2 a 2 Q 1 ( a 2 2 ) ≡ 0 , and likewise for s 2 s_2 s 2 ; hence a n ( f ) ≡ Q 0 ( a 2 2 ) a_n(f)\equiv Q_0(a_2^2) a n ( f ) ≡ Q 0 ( a 2 2 ) and σ ( n ) ≡ Q 0 ( s 2 2 ) \sigma(n)\equiv Q_0(s_2^2) σ ( n ) ≡ Q 0 ( s 2 2 ) . Now a 2 2 ≡ s 2 2 ( m o d 81 ) a_2^2\equiv s_2^2\pmod{81} a 2 2 ≡ s 2 2 ( mod 81 ) : this is Theorem K if k ≢ 4 ( m o d 6 ) k\not\equiv4\pmod{6} k ≡ 4 ( mod 6 ) ; if k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) , one has a 2 2 ≡ 0 a_2^2\equiv0 a 2 2 ≡ 0 and s 2 2 ≡ 0 ( m o d 81 ) s_2^2\equiv0\pmod{81} s 2 2 ≡ 0 ( mod 81 ) , since 9 ∣ a 2 9\mid a_2 9 ∣ a 2 (Corollary L) and 9 ∣ s 2 9\mid s_2 9 ∣ s 2 . Hence a n ( f ) ≡ σ ( n ) ( m o d 81 ) a_n(f)\equiv\sigma(n)\pmod{81} a n ( f ) ≡ σ ( n ) ( mod 81 ) .
(ii) If ψ ( 2 ) s 2 ≡ a 2 ( m o d 27 ) \psi(2)s_2\equiv a_2\pmod{27} ψ ( 2 ) s 2 ≡ a 2 ( mod 27 ) , then Q ( a 2 ) ≡ Q ( ψ ( 2 ) s 2 ) ( m o d 27 ) Q(a_2)\equiv Q(\psi(2)s_2)\pmod{27} Q ( a 2 ) ≡ Q ( ψ ( 2 ) s 2 ) ( mod 27 ) , that is, a n ( f ) ≡ ψ ( n ) σ ( n ) ( m o d 27 ) a_n(f)\equiv\psi(n)\sigma(n)\pmod{27} a n ( f ) ≡ ψ ( n ) σ ( n ) ( mod 27 ) .
(iii) If k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) , a 2 ≡ s 2 ≡ 0 ( m o d 9 ) a_2\equiv s_2\equiv0\pmod{9} a 2 ≡ s 2 ≡ 0 ( mod 9 ) , hence a n ( f ) ≡ Q ( a 2 ) ≡ Q ( s 2 ) ≡ σ ( n ) ( m o d 9 ) a_n(f)\equiv Q(a_2)\equiv Q(s_2)\equiv\sigma(n)\pmod{9} a n ( f ) ≡ Q ( a 2 ) ≡ Q ( s 2 ) ≡ σ ( n ) ( mod 9 ) .
Status: PROVED. From [17 Prop. 2.1, Thm 2.2, Lemma 3.1, Prop. 3.3, Thm 7.2(ii)] , from the theory of 3-adic modular forms [19 , 13 ] and from Theorems K and N. The principle — a n ( f ) a_n(f) a n ( f ) is a polynomial in the eigenvalues of the generators of T \mathbb{T} T — is that of the proof of Theorem 8.1 of [17 ] (a ℓ ≡ 1 + ℓ k − 1 ( m o d 128 ) a_\ell\equiv1+\ell^{k-1}\pmod{128} a ℓ ≡ 1 + ℓ k − 1 ( mod 128 ) for odd ℓ \ell ℓ , at p = 2 p=2 p = 2 ). Statements (ii) and (iii) can also be read off from the literal classification modulo 27 of [18 Thm 1.5] . Independent check, by Sturm’s theorem: the series ∑ n ≡ 1 ( 3 ) ( a n ( f ) − σ ( n ) ) q n = 1 2 ( ( f − E ′ ) ⊗ 13 + ( f − E ′ ) ⊗ χ ) \sum_{n\equiv1(3)}(a_n(f)-\sigma(n))q^n=\frac{1}{2}((f-E')\otimes13+(f-E')\otimes\chi) ∑ n ≡ 1 ( 3 ) ( a n ( f ) − σ ( n )) q n = 2 1 (( f − E ′ ) ⊗ 13 + ( f − E ′ ) ⊗ χ ) , where E ′ = ∑ n ≥ 1 σ ( n ) q n E'=\sum_{n\geq1}\sigma(n)q^n E ′ = ∑ n ≥ 1 σ ( n ) q n , lies in M k ( Γ 0 ( 9 ) ) M_k(\Gamma_0(9)) M k ( Γ 0 ( 9 )) (the constant term of G k G_k G k disappears under twisting), and the index of Γ 0 ( 9 ) \Gamma_0(9) Γ 0 ( 9 ) is 12; it therefore suffices to check (i) for n ≤ k n\leq k n ≤ k . This check was made for every k ≤ 212 k\leq212 k ≤ 212 (Newton polygons of charpoly ( T n − σ ( n ) ) \operatorname{charpoly}(T_n-\sigma(n)) charpoly ( T n − σ ( n )) on S k S_k S k , PARI/GP), and (ii) for k ≤ 140 k\leq140 k ≤ 140 on an eigenbasis embedded in Q 3 \mathbb{Q}_3 Q 3 ; part C of VERIF EISENSTEIN.py redoes (i) for k ≤ 44 k\leq44 k ≤ 44 on the lattice L k L_k L k .
Remark. (1) Statement (i) is equivalent, by multiplicativity, by Chebotarev’s theorem and by the identity tr g tr h = tr g h + det g tr g − 1 h \operatorname{tr}g\operatorname{tr}h=\operatorname{tr}gh+\det g\operatorname{tr}g^{-1}h tr g tr h = tr g h + det g tr g − 1 h (which reduces a ℓ a ℓ ′ a_\ell a_{\ell'} a ℓ a ℓ ′ , ℓ ≡ ℓ ′ ≡ 2 ( m o d 3 ) \ell\equiv\ell'\equiv2\pmod{3} ℓ ≡ ℓ ′ ≡ 2 ( mod 3 ) , to traces on the subgroup of index 2), to: tr ρ f ( g ) ≡ 1 + χ c y c ( g ) ( m o d 81 ) \operatorname{tr}\rho_f(g)\equiv1+\chi_{\mathrm{cyc}}(g)\pmod{81} tr ρ f ( g ) ≡ 1 + χ cyc ( g ) ( mod 81 ) for every g g g in the absolute Galois group of Q ( − 3 ) \mathbb{Q}(\sqrt{-3}) Q ( − 3 ) , where ρ f \rho_f ρ f is the 3-adic representation of f f f . For ℓ ≡ 2 ( m o d 3 ) \ell\equiv2\pmod{3} ℓ ≡ 2 ( mod 3 ) , it gives a ℓ 2 ≡ s ℓ 2 ( m o d 81 ) a_{\ell^2}\equiv s_{\ell^2}\pmod{81} a ℓ 2 ≡ s ℓ 2 ( mod 81 ) (via a ℓ 2 = a ℓ 2 − ℓ k − 1 a_{\ell^2}=a_\ell^2-\ell^{k-1} a ℓ 2 = a ℓ 2 − ℓ k − 1 ), hence a ℓ ≡ ± s ℓ ( m o d 27 ) a_\ell\equiv\pm s_\ell\pmod{27} a ℓ ≡ ± s ℓ ( mod 27 ) if v 3 ( s ℓ ) = 1 v_3(s_\ell)=1 v 3 ( s ℓ ) = 1 (that is, ℓ ≢ − 1 ( m o d 9 ) \ell\not\equiv-1\pmod{9} ℓ ≡ − 1 ( mod 9 ) and k ≢ 4 ( m o d 6 ) k\not\equiv4\pmod{6} k ≡ 4 ( mod 6 ) ), and a ℓ ≡ 0 ( m o d 9 ) a_\ell\equiv0\pmod{9} a ℓ ≡ 0 ( mod 9 ) otherwise: Theorem O contains Conjecture 9.1 of [17 ] and, modulo 9, its analogue for every prime ℓ ≡ 2 ( m o d 3 ) \ell\equiv2\pmod{3} ℓ ≡ 2 ( mod 3 ) .
(2) For Δ \Delta Δ , (i) and (ii) are contained in Swinnerton-Dyer’s theorem τ ( n ) ≡ n − 610 σ 1231 ( n ) ( m o d 3 6 ) \tau(n)\equiv n^{-610}\sigma_{1231}(n)\pmod{3^6} τ ( n ) ≡ n − 610 σ 1231 ( n ) ( mod 3 6 ) for 3 ∤ n 3\nmid n 3 ∤ n [22 ] : since ( Z / 81 Z ) × (\mathbb{Z}/81\mathbb{Z})^\times ( Z /81 Z ) × is cyclic of order 54, one has n 27 ≡ χ ( n ) ( m o d 81 ) n^{27}\equiv\chi(n)\pmod{81} n 27 ≡ χ ( n ) ( mod 81 ) ; for d ≡ n d\equiv n d ≡ n , n − 610 d 1231 ≡ d 27 e 38 ≡ χ ( n ) e 1 ( m o d 81 ) n^{-610}d^{1231}\equiv d^{27}e^{38}\equiv\chi(n)e^{1}\pmod{81} n − 610 d 1231 ≡ d 27 e 38 ≡ χ ( n ) e 1 ( mod 81 ) , whence τ ( n ) ≡ χ ( n ) σ 11 ( n ) ( m o d 81 ) \tau(n)\equiv\chi(n)\sigma_{11}(n)\pmod{81} τ ( n ) ≡ χ ( n ) σ 11 ( n ) ( mod 81 ) for 3 ∤ n 3\nmid n 3 ∤ n . Modulo 3, (i) to (iii) give back Hatada’s theorem a ℓ ≡ 1 + ℓ k ( m o d 3 ) a_\ell\equiv1+\ell^k\pmod{3} a ℓ ≡ 1 + ℓ k ( mod 3 ) [9 ] . Modulo 9, (ii), (iii) and a 3 ≡ 0 ( m o d 9 ) a_3\equiv0\pmod{9} a 3 ≡ 0 ( mod 9 ) give exactly the five classes of [6 ] : two for k ≡ 0 k\equiv0 k ≡ 0 and two for k ≡ 2 ( m o d 6 ) k\equiv2\pmod{6} k ≡ 2 ( mod 6 ) (according to ψ \psi ψ ), one for k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) .
(3) The statements are optimal: (ii) is false modulo 81 (for k = 18 k=18 k = 18 , a 2 + s 2 = − 528 + 131073 = 27 ⋅ 4835 a_2+s_2=-528+131073=27\cdot4835 a 2 + s 2 = − 528 + 131073 = 27 ⋅ 4835 , 3 ∤ 4835 3\nmid4835 3 ∤ 4835 ), and for k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) nothing survives beyond a ℓ ≡ 0 ( m o d 9 ) a_\ell\equiv0\pmod{9} a ℓ ≡ 0 ( mod 9 ) , ℓ ≡ 2 ( m o d 3 ) \ell\equiv2\pmod{3} ℓ ≡ 2 ( mod 3 ) (for k = 40 k=40 k = 40 , the three values of a 2 / 9 a_2/9 a 2 /9 modulo 3 are 0, 1 and 2).
(4) The depth of (i) increases by one when ℓ ≡ ± 1 ( m o d 9 ) \ell\equiv\pm1\pmod{9} ℓ ≡ ± 1 ( mod 9 ) : this is Corollary Q of §7, which also describes the other classes modulo 243, and Theorem R gives depth 6 when ℓ \ell ℓ splits completely in Q ( ζ 9 , 3 3 ) \mathbb{Q}(\zeta_9,\sqrt[3]{3}) Q ( ζ 9 , 3 3 ) or ℓ ≡ − 1 ( m o d 9 ) \ell\equiv-1\pmod{9} ℓ ≡ − 1 ( mod 9 ) .
A Galois law modulo 243 and 729
Let f f f be a normalised cuspidal eigenform of level 1 and weight k k k , O O O the ring of integers of a finite extension of Q 3 \mathbb{Q}_3 Q 3 containing its coefficients, and ρ f : G Q → GL 2 ( O ) \rho_f:G_{\mathbb{Q}}\to\operatorname{GL}_2(O) ρ f : G Q → GL 2 ( O ) its 3-adic representation [7 ] : it is unramified outside 3, tr ρ f ( Frob ℓ ) = a ℓ \operatorname{tr}\rho_f(\operatorname{Frob}_\ell)=a_\ell tr ρ f ( Frob ℓ ) = a ℓ and det ρ f = χ k − 1 \det\rho_f=\chi^{k-1} det ρ f = χ k − 1 , where χ \chi χ is the 3-adic cyclotomic character. We put T = tr ρ f T=\operatorname{tr}\rho_f T = tr ρ f , D = χ k − 1 D=\chi^{k-1} D = χ k − 1 , T E = 1 + χ k − 1 T_E=1+\chi^{k-1} T E = 1 + χ k − 1 (trace of 1 ⊕ χ k − 1 1\oplus\chi^{k-1} 1 ⊕ χ k − 1 ), K = Q ( − 3 ) = Q ( ζ 3 ) K=\mathbb{Q}(\sqrt{-3})=\mathbb{Q}(\zeta_3) K = Q ( − 3 ) = Q ( ζ 3 ) and G K = Gal ( Q ‾ / K ) G_K=\operatorname{Gal}(\overline{\mathbb{Q}}/K) G K = Gal ( Q / K ) . On G K G_K G K , χ ≡ 1 ( m o d 3 ) \chi\equiv1\pmod{3} χ ≡ 1 ( mod 3 ) ; we define two homomorphisms u , v : G K → Z / 3 Z u,v:G_K\to\mathbb{Z}/3\mathbb{Z} u , v : G K → Z /3 Z by
χ ( g ) ≡ 1 + 3 u ( g ) ( m o d 9 ) , g ( 3 3 ) = ζ 3 v ( g ) 3 3 . \chi(g)\equiv1+3u(g)\pmod{9},\qquad g\left(\sqrt[3]{3}\right)=\zeta_3^{v(g)}\sqrt[3]{3}. χ ( g ) ≡ 1 + 3 u ( g ) ( mod 9 ) , g ( 3 3 ) = ζ 3 v ( g ) 3 3 .
Thus u ( Frob ℓ ) = 0 u(\operatorname{Frob}_{\ell})=0 u ( Frob ℓ ) = 0 if and only if ℓ ≡ 1 ( m o d 9 ) \ell\equiv1\pmod{9} ℓ ≡ 1 ( mod 9 ) , and v ( Frob ℓ ) = 0 v(\operatorname{Frob}_{\ell})=0 v ( Frob ℓ ) = 0 if and only if 3 3 3 is a cube modulo ℓ \ell ℓ (ℓ ∤ ℓ \ell\nmid\ell ℓ ∤ ℓ , ℓ ≡ 1 ( m o d 3 ) \ell\equiv1\pmod{3} ℓ ≡ 1 ( mod 3 ) ); ker u ∩ ker v = G Q ( ζ 9 , 3 3 ) \ker u\cap\ker v=G_{\mathbb{Q}(\zeta_9,\sqrt[3]{3})} ker u ∩ ker v = G Q ( ζ 9 , 3 3 ) .
Lemma 9 (Fricke reduction). Let Γ \Gamma Γ be a group, A A A a commutative ring, D : Γ → A × D:\Gamma\to A^{\times} D : Γ → A × a homomorphism and T : Γ → A T:\Gamma\to A T : Γ → A a function such that T ( 1 ) = 2 T(1)=2 T ( 1 ) = 2 , T ( g h ) = T ( h g ) T(gh)=T(hg) T ( g h ) = T ( h g ) and
T ( g h ) + D ( g ) T ( g − 1 h ) = T ( g ) T ( h ) ( g , h ∈ Γ ) . (2) T(gh)+D(g)T(g^{-1}h)=T(g)T(h)\qquad(g,h\in\Gamma). \tag*{(2)} T ( g h ) + D ( g ) T ( g − 1 h ) = T ( g ) T ( h ) ( g , h ∈ Γ ) . (2) For every word W W W in the free group on two letters, there is a polynomial P W ∈ Z [ t 1 , t 2 , t 3 , d 1 ± 1 , d 2 ± 1 ] P_W\in\mathbb{Z}[t_1,t_2,t_3,d_1^{\pm1},d_2^{\pm1}] P W ∈ Z [ t 1 , t 2 , t 3 , d 1 ± 1 , d 2 ± 1 ] , depending only on W W W , such that T ( W ( x , y ) ) = P W ( T ( x ) , T ( y ) , T ( x y ) , D ( x ) , D ( y ) ) T(W(x,y))=P_W(T(x),T(y),T(xy),D(x),D(y)) T ( W ( x , y )) = P W ( T ( x ) , T ( y ) , T ( x y ) , D ( x ) , D ( y )) for all Γ , A , D , T \Gamma,A,D,T Γ , A , D , T as above and all x , y ∈ Γ x,y\in\Gamma x , y ∈ Γ .
Proof. For a , b , z ∈ Γ a,b,z\in\Gamma a , b , z ∈ Γ , (1) with ( g , h ) = ( z , z b a ) (g,h)=(z,zba) ( g , h ) = ( z , z ba ) and invariance under conjugation give
(R1) T ( a z 2 b ) = T ( z ) T ( a z b ) − D ( z ) T ( a b ) , (R2) T ( a z − 1 b ) = D ( z ) − 1 ( T ( z ) T ( a b ) − T ( a z b ) ) . \text{(R1)}\quad T(az^2b)=T(z)T(azb)-D(z)T(ab),\qquad
\text{(R2)}\quad T(az^{-1}b)=D(z)^{-1}\bigl(T(z)T(ab)-T(azb)\bigr). (R1) T ( a z 2 b ) = T ( z ) T ( a z b ) − D ( z ) T ( ab ) , (R2) T ( a z − 1 b ) = D ( z ) − 1 ( T ( z ) T ( ab ) − T ( a z b ) ) .
(R2) being obtained by applying (R1) to $(az^{-1},z,b). We argue by induction on the pair (length of W W W , number of negative exponents), ordered lexicographically, W W W being taken cyclically reduced (which does not change T T T ). If a syllable of W W W has an exponent ≥ 2 \ge2 ≥ 2 , (R1) reduces to shorter words; if a syllable has a negative exponent, (R2) reduces to a shorter word and to a word of the same length with one negative exponent fewer; otherwise W W W is $1$, x x x , y y y , or conjugate to ( x y ) m (xy)^m ( x y ) m , m ≥ 1 m\ge1 m ≥ 1 , and (R1) with z = x y z=xy z = x y gives T ( ( x y ) m ) = T ( x y ) T ( ( x y ) m − 1 ) − D ( x ) D ( y ) T ( ( x y ) m − 2 ) T((xy)^m)=T(xy)T((xy)^{m-1})-D(x)D(y)T((xy)^{m-2}) T (( x y ) m ) = T ( x y ) T (( x y ) m − 1 ) − D ( x ) D ( y ) T (( x y ) m − 2 ) . The algorithm depends only on W W W .
For traces of 2 × 2 2\times2 2 × 2 matrices, this is the classical theorem of Fricke and Vogt [8 ] ; (1) holds for T = tr ρ T=\operatorname{tr}\rho T = tr ρ , D = det ρ D=\det\rho D = det ρ , by Cayley–Hamilton ( g + det ( g ) g − 1 = tr ( g ) ) (g+\det(g)g^{-1}=\operatorname{tr}(g)) ( g + det ( g ) g − 1 = tr ( g )) .
Lemma 10 (the group). Let E E E be the maximal pro-3 3 3 -extension of K K K unramified outside 3 3 3 and G ^ = Gal ( E / K ) \widehat{G}=\operatorname{Gal}(E/K) G = Gal ( E / K ) .
(a) The cyclic extensions of degree 3 3 3 of K K K unramified outside 3 3 3 are the subfields of degree 3 3 3 of K ( ζ 9 , 3 3 ) K(\zeta_9,\sqrt[3]{3}) K ( ζ 9 , 3 3 ) ; u u u and v v v factor through G ^ \widehat{G} G and ( u , v ) : G ^ → ( Z / 3 Z ) 2 (u,v):\widehat{G}\to(\mathbb{Z}/3\mathbb{Z})^2 ( u , v ) : G → ( Z /3 Z ) 2 is surjective.
(b) Two elements x , y ∈ G ^ x,y\in\widehat{G} x , y ∈ G such that ( u , v ) ( x ) = ( 1 , 0 ) (u,v)(x)=(1,0) ( u , v ) ( x ) = ( 1 , 0 ) and ( u , v ) ( y ) = ( 0 , 1 ) (u,v)(y)=(0,1) ( u , v ) ( y ) = ( 0 , 1 ) topologically generate G ^ \widehat{G} G .
(c) T T T , D D D and T E T_E T E , restricted to G K G_K G K , factor through G ^ \widehat{G} G .
Proof. (a) K K K contains μ 3 \mu_3 μ 3 and has class number one; by Kummer theory, such an extension is K ( a 3 ) K(\sqrt[3]{a}) K ( 3 a ) with a ∈ O K [ 1 / 3 ] × a\in O_K[1/3]^\times a ∈ O K [ 1/3 ] × , and O K [ 1 / 3 ] × / ( O K [ 1 / 3 ] × ) 3 O_K[1/3]^\times/(O_K[1/3]^\times)^3 O K [ 1/3 ] × / ( O K [ 1/3 ] × ) 3 has dimension 2 2 2 , generated by ζ 3 \zeta_3 ζ 3 and 1 − ζ 3 1-\zeta_3 1 − ζ 3 , or equally by ζ 3 \zeta_3 ζ 3 and 3 = − ζ 3 2 ( 1 − ζ 3 ) 2 3=-\zeta_3^2(1-\zeta_3)^2 3 = − ζ 3 2 ( 1 − ζ 3 ) 2 ; and K ( ζ 3 3 ) = K ( ζ 9 ) K(\sqrt[3]{\zeta_3})=K(\zeta_9) K ( 3 ζ 3 ) = K ( ζ 9 ) . (b) G ^ \widehat{G} G is a pro-3 3 3 -group and Hom ( G ^ , Z / 3 Z ) \operatorname{Hom}(\widehat{G},\mathbb{Z}/3\mathbb{Z}) Hom ( G , Z /3 Z ) is generated by u , v u,v u , v ; this is Burnside’s basis theorem [11 ] . (c) By Chebotarev and Hatada’s congruence a ℓ ≡ 1 + ℓ k − 1 ( m o d 3 ) a_{\ell}\equiv1+\ell^{k-1}\pmod{3} a ℓ ≡ 1 + ℓ k − 1 ( mod 3 ) [9 ] , T ≡ 2 T\equiv2 T ≡ 2 and D ≡ 1 ( m o d 3 ) D\equiv1\pmod{3} D ≡ 1 ( mod 3 ) on G K G_K G K : every ρ f ( g ) \rho_f(g) ρ f ( g ) , g ∈ G K g\in G_K g ∈ G K , has characteristic polynomial ( X − 1 ) 2 (X-1)^2 ( X − 1 ) 2 modulo the maximal ideal, so the image of ρ f ( G K ) \rho_f(G_K) ρ f ( G K ) in GL 2 \operatorname{GL}_2 GL 2 of the residue field consists of unipotents and is a 3 3 3 -group; the kernel of the reduction being a pro-3 3 3 -group, ρ f ( G K ) \rho_f(G_K) ρ f ( G K ) is a pro-3 3 3 -group, and ρ f \rho_f ρ f being unramified outside 3 3 3 , ρ f ∣ G K \rho_f|_{G_K} ρ f ∣ G K factors through G ^ \widehat{G} G . Likewise for χ ∣ G K \chi|_{G_K} χ ∣ G K , with values in 1 + 3 Z 3 1+3\mathbb{Z}_3 1 + 3 Z 3 .
By Shafarevich [20 ] , G ^ \widehat{G} G is even free on two generators; this fact is used only in §9. This group, and the two conditions “ℓ \ell ℓ modulo 9 9 9 ” and “3 3 3 a cube modulo ℓ \ell ℓ ”, also govern the structure of the Hecke algebra of level 1 1 1 modulo 3 3 3 [1 , 15 ] ; the statements below concern the eigenvalues in characteristic 0 0 0 .
Lemma 11 (a quadratic form). Let O ′ O' O ′ be the ring of integers of a finite extension of Q 3 \mathbb{Q}_3 Q 3 , and T 1 , T 2 : G ^ → O ′ T_1,T_2:\widehat{G}\to O' T 1 , T 2 : G → O ′ two continuous functions satisfying the hypotheses of Lemma 9 with the same D D D , where D ≡ 1 D\equiv1 D ≡ 1 and T 2 ≡ 2 ( m o d 3 ) T_2\equiv2\pmod{3} T 2 ≡ 2 ( mod 3 ) . If T 1 − T 2 ∈ 3 n O ′ T_1-T_2\in3^nO' T 1 − T 2 ∈ 3 n O ′ with n ≥ 1 n\geq1 n ≥ 1 , there are α , β , γ ∈ O ′ / 3 O ′ \alpha,\beta,\gamma\in O'/3O' α , β , γ ∈ O ′ /3 O ′ such that
T 1 ( g ) − T 2 ( g ) ≡ 3 n ( α u ( g ) 2 + β u ( g ) v ( g ) + γ v ( g ) 2 ) ( m o d 3 n + 1 O ′ ) ( g ∈ G ^ ) . T_1(g)-T_2(g)\equiv3^n\left(\alpha u(g)^2+\beta u(g)v(g)+\gamma v(g)^2\right)\pmod{3^{n+1}O'}\qquad(g\in\widehat{G}). T 1 ( g ) − T 2 ( g ) ≡ 3 n ( α u ( g ) 2 + β u ( g ) v ( g ) + γ v ( g ) 2 ) ( mod 3 n + 1 O ′ ) ( g ∈ G ) . If moreover T 1 T_1 T 1 and T 2 T_2 T 2 are invariant under an automorphism σ \sigma σ of G ^ \widehat{G} G such that u ∘ σ = u u\circ\sigma=u u ∘ σ = u and v ∘ σ = − v v\circ\sigma=-v v ∘ σ = − v , then β = 0 \beta=0 β = 0 .
Proof. Let x , y x,y x , y be as in Lemma 10 (b), x 1 = x x_1=x x 1 = x , x 2 = y x_2=y x 2 = y , x 3 = x y x_3=xy x 3 = x y , and ε = ( T 1 − T 2 ) / 3 n \varepsilon=(T_1-T_2)/3^n ε = ( T 1 − T 2 ) / 3 n modulo 3. For a word W W W , Lemma 9 and Taylor’s formula (the two points differ only in the first three coordinates, by at most 3 n 3^n 3 n , and 2 n ≥ n + 1 2n\geq n+1 2 n ≥ n + 1 ) give ε ( W ) = ∑ j c j ( W ) ε ( x j ) \varepsilon(W)=\sum_j c_j(W)\varepsilon(x_j) ε ( W ) = ∑ j c j ( W ) ε ( x j ) with c j ( W ) = ∂ j P W ( 2 , 2 , 2 , 1 , 1 ) ( m o d 3 ) c_j(W)=\partial_jP_W(2,2,2,1,1)\pmod{3} c j ( W ) = ∂ j P W ( 2 , 2 , 2 , 1 , 1 ) ( mod 3 ) , since T 2 ≡ 2 T_2\equiv2 T 2 ≡ 2 and D ≡ 1 ( m o d 3 ) D\equiv1\pmod{3} D ≡ 1 ( mod 3 ) . For a quadratic form Q = α u 2 + β u v + γ v 2 Q=\alpha u^2+\beta uv+\gamma v^2 Q = α u 2 + β uv + γ v 2 with coefficients in O ′ / 3 O'/3 O ′ /3 , the function T Q = 2 + δ Q T_Q=2+\delta Q T Q = 2 + δ Q , with values in ( O ′ / 3 ) [ δ ] / ( δ 2 ) (O'/3)[\delta]/(\delta^2) ( O ′ /3 ) [ δ ] / ( δ 2 ) , with D = 1 D=1 D = 1 , satisfies the hypotheses of Lemma 9 : this is the parallelogram identity Q ( a + b ) + Q ( b − a ) = 2 Q ( a ) + 2 Q ( b ) Q(a+b)+Q(b-a)=2Q(a)+2Q(b) Q ( a + b ) + Q ( b − a ) = 2 Q ( a ) + 2 Q ( b ) . Since P W ( 2 , 2 , 2 , 1 , 1 ) = 2 P_W(2,2,2,1,1)=2 P W ( 2 , 2 , 2 , 1 , 1 ) = 2 (constant function T = 2 T=2 T = 2 , D = 1 D=1 D = 1 ), we also have Q ( W ) = ∑ j c j ( W ) Q ( x j ) Q(W)=\sum_j c_j(W)Q(x_j) Q ( W ) = ∑ j c j ( W ) Q ( x j ) . Choose α = ε ( x ) \alpha=\varepsilon(x) α = ε ( x ) , γ = ε ( y ) \gamma=\varepsilon(y) γ = ε ( y ) , β = ε ( x y ) − α − γ \beta=\varepsilon(xy)-\alpha-\gamma β = ε ( x y ) − α − γ : then ε = Q \varepsilon=Q ε = Q on the subgroup generated by x , y x,y x , y , which is dense by Lemma 10 (b), hence everywhere by continuity. Finally, if σ \sigma σ exists, ε ∘ σ = ε \varepsilon\circ\sigma=\varepsilon ε ∘ σ = ε gives Q ( a , − b ) = Q ( a , b ) Q(a,-b)=Q(a,b) Q ( a , − b ) = Q ( a , b ) , whence 2 β = 0 2\beta=0 2 β = 0 and β = 0 \beta=0 β = 0 .
Conjugation by a complex conjugation c c c provides such a σ \sigma σ : E E E is Galois over Q \mathbb{Q} Q , χ ( c g c − 1 ) = χ ( g ) \chi(cgc^{-1})=\chi(g) χ ( c g c − 1 ) = χ ( g ) , and, c c c fixing the real 3 3 \sqrt[3]{3} 3 3 and sending ζ 3 \zeta_3 ζ 3 to ζ 3 − 1 \zeta_3^{-1} ζ 3 − 1 , v ( c g c − 1 ) = − v ( g ) v(cgc^{-1})=-v(g) v ( c g c − 1 ) = − v ( g ) ; T T T , D D D , T E T_E T E are class functions on G Q G_{\mathbb{Q}} G Q .
Theorem P (Galois law modulo 243). For every g ∈ G K g\in G_K g ∈ G K ,
tr ρ f ( g ) = 1 + χ ( g ) k − 1 + ( a 2 2 − s 2 2 ) u ( g ) 2 ( m o d 243 O ) . \operatorname{tr}\rho_f(g)=1+\chi(g)^{k-1}+(a_2^2-s_2^2)u(g)^2\pmod{243O}. tr ρ f ( g ) = 1 + χ ( g ) k − 1 + ( a 2 2 − s 2 2 ) u ( g ) 2 ( mod 243 O ) . Proof. By Theorem O(i) and Chebotarev (the Frob l \operatorname{Frob}_{\mathfrak l} Frob l of degree 1, are dense in G K G_K G K ), T − T E ∈ 81 O T-T_E\in81O T − T E ∈ 81 O on G K G_K G K . Lemma 11 (n = 4 n=4 n = 4 , T 1 = T T_1=T T 1 = T , T 2 = T E T_2=T_E T 2 = T E , σ \sigma σ conjugation by c c c ) gives T − T E ≡ 81 ( α u 2 + γ v 2 ) ( m o d 243 ) T-T_E\equiv81(\alpha u^2+\gamma v^2)\pmod{243} T − T E ≡ 81 ( α u 2 + γ v 2 ) ( mod 243 ) . For the Frobenius element g 1 g_1 g 1 of the prime ideal 2 O K 2O_K 2 O K (inert, residue field F 4 \mathbb{F}_4 F 4 ), g 1 = Frob 2 2 g_1=\operatorname{Frob}_2^2 g 1 = Frob 2 2 , χ ( g 1 ) = 4 \chi(g_1)=4 χ ( g 1 ) = 4 , hence u ( g 1 ) = 1 u(g_1)=1 u ( g 1 ) = 1 , and v ( g 1 ) = 0 v(g_1)=0 v ( g 1 ) = 0 since 3 = 1 3=1 3 = 1 is a cube in F 4 \mathbb{F}_4 F 4 ; T ( g 1 ) = a 2 2 − 2 ⋅ 2 k − 1 T(g_1)=a_2^2-2\cdot2^{k-1} T ( g 1 ) = a 2 2 − 2 ⋅ 2 k − 1 , T E ( g 1 ) = 1 + 4 k − 1 T_E(g_1)=1+4^{k-1} T E ( g 1 ) = 1 + 4 k − 1 , whence 81 α ≡ a 2 2 − s 2 2 81\alpha\equiv a_2^2-s_2^2 81 α ≡ a 2 2 − s 2 2 . For g 2 = Frob l g_2=\operatorname{Frob}_{\mathfrak l} g 2 = Frob l , l ∣ 19 \mathfrak l\mid19 l ∣ 19 : u ( g 2 ) = 0 u(g_2)=0 u ( g 2 ) = 0 since 19 ≡ 1 ( m o d 9 ) 19\equiv1\pmod{9} 19 ≡ 1 ( mod 9 ) , v ( g 2 ) ≠ 0 v(g_2)\ne0 v ( g 2 ) = 0 since 3 6 ≡ 7 ( m o d 19 ) 3^6\equiv7\pmod{19} 3 6 ≡ 7 ( mod 19 ) , whence 81 γ ≡ a 19 − s 19 ≡ 0 ( m o d 243 ) 81\gamma\equiv a_{19}-s_{19}\equiv0\pmod{243} 81 γ ≡ a 19 − s 19 ≡ 0 ( mod 243 ) by Theorem N: (a) if k ≢ 4 ( m o d 6 ) k\not\equiv4\pmod{6} k ≡ 4 ( mod 6 ) , (a′′) if k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) .
Status: PROVED. From Theorem O, hence from [17 ] , and from Theorem N.
Corollary Q (primes). Let ℓ ≠ 3 \ell\ne3 ℓ = 3 be prime.
(i) If ℓ ≡ 1 ( m o d 3 ) \ell\equiv1\pmod{3} ℓ ≡ 1 ( mod 3 ) : a ℓ ≡ s ℓ ( m o d 243 ) a_\ell\equiv s_\ell\pmod{243} a ℓ ≡ s ℓ ( mod 243 ) if ℓ ≡ 1 ( m o d 9 ) \ell\equiv1\pmod{9} ℓ ≡ 1 ( mod 9 ) , and a ℓ ≡ s ℓ + a 2 2 − s 2 2 ( m o d 243 ) a_\ell\equiv s_\ell+a_2^2-s_2^2\pmod{243} a ℓ ≡ s ℓ + a 2 2 − s 2 2 ( mod 243 ) if ℓ ≡ 4 , 7 ( m o d 9 ) \ell\equiv4,7\pmod{9} ℓ ≡ 4 , 7 ( mod 9 ) .
(ii) If ℓ ≡ 2 ( m o d 3 ) \ell\equiv2\pmod{3} ℓ ≡ 2 ( mod 3 ) : a ℓ 2 ≡ s ℓ 2 ( m o d 243 ) a_\ell^2\equiv s_\ell^2\pmod{243} a ℓ 2 ≡ s ℓ 2 ( mod 243 ) if ℓ ≡ − 1 ( m o d 9 ) \ell\equiv-1\pmod{9} ℓ ≡ − 1 ( mod 9 ) , and a ℓ 2 ≡ s ℓ 2 + a 2 2 − s 2 2 ( m o d 243 ) a_\ell^2\equiv s_\ell^2+a_2^2-s_2^2\pmod{243} a ℓ 2 ≡ s ℓ 2 + a 2 2 − s 2 2 ( mod 243 ) if ℓ ≡ 2 , 5 ( m o d 9 ) \ell\equiv2,5\pmod{9} ℓ ≡ 2 , 5 ( mod 9 ) .
Proof. (i) g = Frob ℓ g=\operatorname{Frob}_{\ell} g = Frob ℓ . (ii) g = Frob ℓ 2 g=\operatorname{Frob}_{\ell}^2 g = Frob ℓ 2 , the Frobenius of the inert ideal ℓ O K \ell O_K ℓ O K : T ( g ) = a ℓ 2 − 2 ℓ k − 1 T(g)=a_\ell^2-2\ell^{k-1} T ( g ) = a ℓ 2 − 2 ℓ k − 1 , T E ( g ) = 1 + ℓ 2 k − 2 T_E(g)=1+\ell^{2k-2} T E ( g ) = 1 + ℓ 2 k − 2 , χ ( g ) = ℓ 2 \chi(g)=\ell^2 χ ( g ) = ℓ 2 , and u ( g ) = 0 u(g)=0 u ( g ) = 0 if and only if ℓ ≡ ± 1 ( m o d 9 ) \ell\equiv\pm1\pmod{9} ℓ ≡ ± 1 ( mod 9 ) .
In particular, the depth of the Eisenstein law increases by one for every ℓ ≡ ± 1 ( m o d 9 ) \ell\equiv\pm1\pmod{9} ℓ ≡ ± 1 ( mod 9 ) , in every weight. The correction a 2 2 − s 2 2 a_2^2-s_2^2 a 2 2 − s 2 2 is necessary: without it, the congruence fails modulo 243 for ℓ = 7 \ell=7 ℓ = 7 , 31 and ℓ 2 = 25 \ell^2=25 ℓ 2 = 25 in all the weights 12 ≤ k ≤ 70 12\leq k\leq70 12 ≤ k ≤ 70 examined except k = 12 k=12 k = 12 and k = 22 k=22 k = 22 , where a 2 2 ≡ s 2 2 ( m o d 243 ) a_2^2\equiv s_2^2\pmod{243} a 2 2 ≡ s 2 2 ( mod 243 ) .
Theorem R (modulo 729). For every g ∈ G Q ( ζ 9 , 3 3 ) g \in G_{\mathbb{Q}(\zeta_{9},\sqrt[3]{3})} g ∈ G Q ( ζ 9 , 3 3 ) , tr ρ f ( g ) ≡ 1 + χ ( g ) k − 1 ( m o d 729 O ) \operatorname{tr}\rho_f(g) \equiv1+\chi(g)^{k-1} \pmod{729\mathcal{O}} tr ρ f ( g ) ≡ 1 + χ ( g ) k − 1 ( mod 729 O ) . In particular a ℓ ≡ s ℓ ( m o d 729 ) a_{\ell} \equiv s_{\ell} \pmod{729} a ℓ ≡ s ℓ ( mod 729 ) if ℓ ≡ 1 ( m o d 9 ) \ell\equiv1 \pmod{9} ℓ ≡ 1 ( mod 9 ) and 3 3 3 is a cube modulo ℓ \ell ℓ , and a ℓ 2 ≡ s ℓ 2 ( m o d 729 ) a_{\ell}^{2} \equiv s_{\ell}^{2} \pmod{729} a ℓ 2 ≡ s ℓ 2 ( mod 729 ) if ℓ ≡ − 1 ( m o d 9 ) \ell\equiv-1 \pmod{9} ℓ ≡ − 1 ( mod 9 ) .
Proof. Put κ = k − 1 \kappa=k-1 κ = k − 1 and, for g ∈ G K g \in G_K g ∈ G K , λ ( g ) = 1 3 log 3 χ ( g ) ∈ Z 3 \lambda(g)=\frac{1}{3}\log_{3}\chi(g)\in\mathbb{Z}_{3} λ ( g ) = 3 1 log 3 χ ( g ) ∈ Z 3 ; λ \lambda λ is a continuous homomorphism and λ ≡ u ( m o d 3 ) \lambda\equiv u\pmod{3} λ ≡ u ( mod 3 ) . For s s s in the ring of integers O ′ \mathcal{O}' O ′ of a finite extension of Q 3 \mathbb{Q}_{3} Q 3 containing O \mathcal{O} O , let ψ s = exp ( 3 s λ ) \psi_s=\exp(3s\lambda) ψ s = exp ( 3 s λ ) , a continuous character of G K G_K G K with values in O ′ × \mathcal{O}'^{\times} O ′ × , and M s = ψ s + χ κ ψ s − 1 M_s=\psi_s+\chi^{\kappa}\psi_s^{-1} M s = ψ s + χ κ ψ s − 1 , the trace of ψ s ⊕ χ κ ψ s − 1 \psi_s\oplus\chi^{\kappa}\psi_s^{-1} ψ s ⊕ χ κ ψ s − 1 ; M s M_s M s satisfies (1) with the same D D D , is invariant under σ \sigma σ , and
M s − T E = − ( e A − 1 ) ( e B − 1 ) , A = 3 s λ , B = 3 ( κ − s ) λ . M_s-T_E=-(e^A-1)(e^B-1),\qquad A=3s\lambda,\quad B=3(\kappa-s)\lambda. M s − T E = − ( e A − 1 ) ( e B − 1 ) , A = 3 s λ , B = 3 ( κ − s ) λ . Let α ∈ O / 3 \alpha\in\mathcal{O}/3 α ∈ O /3 be defined by 81 α ≡ a 2 2 − s 2 2 ( m o d 243 ) 81\alpha\equiv a_2^2-s_2^2\pmod{243} 81 α ≡ a 2 2 − s 2 2 ( mod 243 ) . If 3 ∤ κ 3\nmid\kappa 3 ∤ κ , take s = 9 t s=9t s = 9 t with t ≡ − α κ − 1 ( m o d 3 ) t\equiv-\alpha\kappa^{-1}\pmod{3} t ≡ − α κ − 1 ( mod 3 ) : v 3 ( A ) ≥ 3 v_3(A)\geq3 v 3 ( A ) ≥ 3 , v 3 ( B ) ≥ 1 v_3(B)\geq1 v 3 ( B ) ≥ 1 , and M s − T E ≡ − A B ≡ − 81 t κ λ 2 ≡ 81 α u 2 ( m o d 243 ) M_s-T_E\equiv-AB\equiv-81t\kappa\lambda^2\equiv81\alpha u^2\pmod{243} M s − T E ≡ − A B ≡ − 81 t κ λ 2 ≡ 81 α u 2 ( mod 243 ) (the other terms of the expansion have valuation ≥ 5 \geq5 ≥ 5 ). If 3 ∣ κ 3\mid\kappa 3 ∣ κ (k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) ), take s = 3 t s=3t s = 3 t , where t ∈ O ′ t\in\mathcal{O}' t ∈ O ′ is a root of X 2 − 3 κ X − α ~ X^2-\frac{3}{\kappa}X-\widetilde{\alpha} X 2 − κ 3 X − α (α ~ ∈ O \widetilde{\alpha}\in\mathcal{O} α ∈ O lifting α \alpha α ): v 3 ( A ) , v 3 ( B ) ≥ 2 v_3(A),v_3(B)\geq2 v 3 ( A ) , v 3 ( B ) ≥ 2 and M s − T E ≡ − 81 t ( 3 κ − t ) λ 2 ≡ 81 α u 2 ( m o d 243 ) M_s-T_E\equiv-81t(\frac{3}{\kappa}-t)\lambda^2\equiv81\alpha u^2\pmod{243} M s − T E ≡ − 81 t ( κ 3 − t ) λ 2 ≡ 81 α u 2 ( mod 243 ) . In both cases, Theorem P gives T ≡ M s ( m o d 243 O ′ ) T\equiv M_s\pmod{243\mathcal{O}'} T ≡ M s ( mod 243 O ′ ) on G K G_K G K , and Lemma 11 (n = 5 n=5 n = 5 , T 1 = T T_1=T T 1 = T , T 2 = M s T_2=M_s T 2 = M s ) gives T − M s ≡ 243 Q ′ ( u , v ) ( m o d 729 ) T-M_s\equiv243Q'(u,v)\pmod{729} T − M s ≡ 243 Q ′ ( u , v ) ( mod 729 ) for a quadratic form Q ′ Q' Q ′ , which vanishes if u = v = 0 u=v=0 u = v = 0 . Finally, if u ( g ) = 0 u(g)=0 u ( g ) = 0 , then 3 ∣ λ ( g ) 3\mid\lambda(g) 3 ∣ λ ( g ) , hence v 3 ( A ) + v 3 ( B ) ≥ 6 v_3(A)+v_3(B)\geq6 v 3 ( A ) + v 3 ( B ) ≥ 6 in both cases, and v 3 ( M s ( g ) − T E ( g ) ) = v 3 ( A ) + v 3 ( B ) ≥ 6 v_3(M_s(g)-T_E(g))=v_3(A)+v_3(B)\geq6 v 3 ( M s ( g ) − T E ( g )) = v 3 ( A ) + v 3 ( B ) ≥ 6 . For the Frobenius of ℓ O K \ell\mathcal{O}_K ℓ O K , ℓ ≡ − 1 ( m o d 9 ) \ell\equiv-1\pmod{9} ℓ ≡ − 1 ( mod 9 ) , one has u = 0 u=0 u = 0 , and v = 0 v=0 v = 0 since 3 3 3 is a cube in F ℓ × \mathbb{F}_{\ell}^{\times} F ℓ × , hence in F ℓ 2 \mathbb{F}_{\ell^2} F ℓ 2 .
Status: PROVED. From Theorem P.
Theorem S (bilinear law). For a prime ℓ ≡ 2 ( m o d 3 ) \ell\equiv2\pmod{3} ℓ ≡ 2 ( mod 3 ) , let u ~ ( ℓ ) = − 1 , 1 , 0 \widetilde{u}(\ell)=-1,1,0 u ( ℓ ) = − 1 , 1 , 0 according as ℓ ≡ 2 , 5 , 8 ( m o d 9 ) \ell\equiv2,5,8\pmod{9} ℓ ≡ 2 , 5 , 8 ( mod 9 ) . For all primes ℓ , ℓ ′ ≡ 2 ( m o d 3 ) \ell,\ell'\equiv2\pmod{3} ℓ , ℓ ′ ≡ 2 ( mod 3 ) ,
a ℓ a ℓ ′ ≡ s ℓ s ℓ ′ + u ~ ( ℓ ) u ~ ( ℓ ′ ) ( a 2 2 − s 2 2 ) ( m o d 243 ) . a_{\ell}a_{\ell'}\equiv s_{\ell}s_{\ell'}+\widetilde{u}(\ell)\widetilde{u}(\ell')(a_2^2-s_2^2)\pmod{243}. a ℓ a ℓ ′ ≡ s ℓ s ℓ ′ + u ( ℓ ) u ( ℓ ′ ) ( a 2 2 − s 2 2 ) ( mod 243 ) . Proof. Let g , g ′ g,g' g , g ′ be Frobenius elements at ℓ , ℓ ′ \ell,\ell' ℓ , ℓ ′ ; g g ′ gg' g g ′ and g − 1 g ′ g^{-1}g' g − 1 g ′ lie in G K G_K G K , and T ( g ) T ( g ′ ) = T ( g g ′ ) + D ( g ) T ( g − 1 g ′ ) T(g)T(g')=T(gg')+D(g)T(g^{-1}g') T ( g ) T ( g ′ ) = T ( g g ′ ) + D ( g ) T ( g − 1 g ′ ) , likewise for T E T_E T E . One has − ℓ ≡ 1 + 3 u ~ ( ℓ ) ( m o d 9 ) -\ell\equiv1+3\widetilde{u}(\ell)\pmod{9} − ℓ ≡ 1 + 3 u ( ℓ ) ( mod 9 ) , hence u ( g g ′ ) = u ~ ( ℓ ) + u ~ ( ℓ ′ ) u(gg')=\widetilde{u}(\ell)+\widetilde{u}(\ell') u ( g g ′ ) = u ( ℓ ) + u ( ℓ ′ ) and u ( g − 1 g ′ ) = u ~ ( ℓ ′ ) − u ~ ( ℓ ) u(g^{-1}g')=\widetilde{u}(\ell')-\widetilde{u}(\ell) u ( g − 1 g ′ ) = u ( ℓ ′ ) − u ( ℓ ) . By Theorem P, and D ( g ) ≡ − 1 ( m o d 3 ) D(g)\equiv-1\pmod{3} D ( g ) ≡ − 1 ( mod 3 ) , a ℓ a ℓ ′ − s ℓ s ℓ ′ ≡ ( a 2 2 − s 2 2 ) ( ( u ~ + u ~ ′ ) 2 − ( u ~ ′ − u ~ ) 2 ) = 4 u ~ u ~ ′ ( a 2 2 − s 2 2 ) ( m o d 243 ) a_{\ell}a_{\ell'}-s_{\ell}s_{\ell'}\equiv(a_2^2-s_2^2)\bigl((\widetilde{u}+\widetilde{u}')^2-(\widetilde{u}'-\widetilde{u})^2\bigr)=4\widetilde{u}\widetilde{u}'(a_2^2-s_2^2)\pmod{243} a ℓ a ℓ ′ − s ℓ s ℓ ′ ≡ ( a 2 2 − s 2 2 ) ( ( u + u ′ ) 2 − ( u ′ − u ) 2 ) = 4 u u ′ ( a 2 2 − s 2 2 ) ( mod 243 ) , and 4 ≡ 1 ( m o d 3 ) 4\equiv1\pmod{3} 4 ≡ 1 ( mod 3 ) .
Status: PROVED.
Corollary T (law modulo 81). If k ≢ 4 ( m o d 6 ) k\not\equiv4\pmod{6} k ≡ 4 ( mod 6 ) , for every prime ℓ ≡ 2 ( m o d 3 ) \ell\equiv2\pmod{3} ℓ ≡ 2 ( mod 3 ) ,
a ℓ ≡ s 2 s ℓ − u ~ ( ℓ ) ( a 2 2 − s 2 2 ) a 2 ( m o d 81 Z 3 ) , a_{\ell}\equiv\frac{s_2s_{\ell}-\widetilde{u}(\ell)(a_2^2-s_2^2)}{a_2}\pmod{81\mathbb{Z}_3}, a ℓ ≡ a 2 s 2 s ℓ − u ( ℓ ) ( a 2 2 − s 2 2 ) ( mod 81 Z 3 ) , and, for every n n n prime to 3 3 3 , a n ( f ) a_n(f) a n ( f ) modulo 81 81 81 depends only on k k k and on a 2 ( f ) a_2(f) a 2 ( f ) modulo 81 81 81 .
Proof. Take ℓ ′ = 2 \ell'=2 ℓ ′ = 2 in Theorem S (u ~ ( 2 ) = − 1 \widetilde{u}(2)=-1 u ( 2 ) = − 1 ) and divide by a 2 a_2 a 2 , which has valuation 1 1 1 (Corollary L). The numerator modulo 243 243 243 and the quotient modulo 81 81 81 do not change if a 2 a_2 a 2 is replaced by a 2 + 81 e a_2+81e a 2 + 81 e . For ℓ ≡ 1 ( m o d 3 ) \ell\equiv1\pmod{3} ℓ ≡ 1 ( mod 3 ) , use Corollary Q(i), then multiplicativity and a ℓ r + 1 = a ℓ a ℓ r − ℓ k − 1 a ℓ r − 1 a_{\ell^{r+1}}=a_{\ell}a_{\ell^r}-\ell^{k-1}a_{\ell^{r-1}} a ℓ r + 1 = a ℓ a ℓ r − ℓ k − 1 a ℓ r − 1 .
Modulo 27 27 27 , this formula gives back Theorem O(ii) for ℓ ≡ 2 ( m o d 3 ) \ell\equiv2\pmod{3} ℓ ≡ 2 ( mod 3 ) ; the corollary is the analogue modulo 81 81 81 of the classification of [6 ] . If k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) and 9 ∣ a 2 9\mid a_2 9 ∣ a 2 , the same division determines a ℓ a_{\ell} a ℓ modulo 27 27 27 for ℓ ≡ 2 ( m o d 3 ) \ell\equiv2\pmod{3} ℓ ≡ 2 ( mod 3 ) : a 2 a_2 a 2 obeys no uniform law modulo 27 27 27 (Remark (3) of §6), but it governs the others.
Remark. VERIFIED (PARI/GP, exact Newton polygons on S k S_k S k ). Theorem P for all primes ℓ < 200 \ell<200 ℓ < 200 and 12 ≤ k ≤ 70 12\leq k\leq70 12 ≤ k ≤ 70 ; Theorem S for 1836 pairs ( ℓ , ℓ ′ < 110 , 12 ≤ k ≤ 80 ) (\ell,\ell'<110,\ 12\leq k\leq80) ( ℓ , ℓ ′ < 110 , 12 ≤ k ≤ 80 ) ; a 19 ≡ s 19 ( m o d 243 ) a_{19}\equiv s_{19}\pmod{243} a 19 ≡ s 19 ( mod 243 ) for k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) , k ≤ 298 k\leq298 k ≤ 298 . Minimal depths with primes ℓ \ell ℓ observed for 12 ≤ k ≤ 100 12\leq k\leq100 12 ≤ k ≤ 100 (for ℓ ≡ − 1 ( m o d 9 ) \ell\equiv-1\pmod{9} ℓ ≡ − 1 ( mod 9 ) ), on a 2 2 − s 2 2 a_2^2-s_2^2 a 2 2 − s 2 2 : 5 for ℓ = 19 , 37 , 109 , 127 , 163 , 181 , 199 \ell=19,37,109,127,163,181,199 ℓ = 19 , 37 , 109 , 127 , 163 , 181 , 199 (3 not a cube); 6 for ℓ = 73 \ell=73 ℓ = 73 and for ℓ = 17 , 71 , 89 , 179 , 197 , 233 , 251 \ell=17,71,89,179,197,233,251 ℓ = 17 , 71 , 89 , 179 , 197 , 233 , 251 ; 8 for ℓ = 53 , 107 , 269 \ell=53,107,269 ℓ = 53 , 107 , 269 (ℓ ≡ − 1 ( m o d 27 ) \ell\equiv-1\pmod{27} ℓ ≡ − 1 ( mod 27 ) ) and for ℓ = 271 \ell=271 ℓ = 271 (ℓ ≡ 1 ( m o d 27 ) \ell\equiv1\pmod{27} ℓ ≡ 1 ( mod 27 ) ), 3 a cube if k ≢ 4 ( m o d 6 ) k\not\equiv4\pmod{6} k ≡ 4 ( mod 6 ) , 7 for ℓ = 271 \ell=271 ℓ = 271 if k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) . Theorems P and R explain exactly the depths 5 and 6; the depths 7 and 8 are treated in §9 (Theorems R′ and R″).
A 2-adic Galois law and the answer to Hatada's question
A 2-adic certificate
Lemma 7 holds, with the same proof, with 3 replaced by 2:
Lemma 12 (vanishing criterion, p = 2 p=2 p = 2 ). Let n ≥ 1 n \ge1 n ≥ 1 , H 2 \mathcal{H}_2 H 2 a system of integral representatives of G L 2 ( F 2 ) \mathrm{GL}_2(\mathbb{F}_2) GL 2 ( F 2 ) , and X = ∑ g c g g X=\sum_g c_g g X = ∑ g c g g a finite combination, with integer coefficients, of integer matrices with odd determinant. Write g = h g κ g ( m o d 2 n ) g=h_g\kappa_g\pmod{2^n} g = h g κ g ( mod 2 n ) with h g ∈ H 2 h_g\in\mathcal{H}_2 h g ∈ H 2 and κ g ≡ I ( m o d 2 ) \kappa_g\equiv I\pmod2 κ g ≡ I ( mod 2 ) , and define c δ , A , B c_{\delta,A,B} c δ , A , B as in Lemma 7, and then f h , δ ( i , t ) = ∑ h g = h c g ∑ A + B < n c δ , A , B ( κ g ) ( A i ) ( 2 t − i B ) f_{h,\delta}(i,t)=\sum_{h_g=h}c_g\sum_{A+B<n}c_{\delta,A,B}(\kappa_g){A\choose i}{2^t-i\choose B} f h , δ ( i , t ) = ∑ h g = h c g ∑ A + B < n c δ , A , B ( κ g ) ( i A ) ( B 2 t − i ) . If all the finite differences Δ i A Δ t B f h , δ ( 0 , 0 ) \Delta_i^A\Delta_t^Bf_{h,\delta}(0,0) Δ i A Δ t B f h , δ ( 0 , 0 ) , A + B < n A+B<n A + B < n , are divisible by 2 n 2^n 2 n , then σ X ( Z [ x , y ] w ) ⊂ 2 n Z [ x , y ] w \sigma_X(\mathbb{Z}[x,y]_w)\subset2^n\mathbb{Z}[x,y]_w σ X ( Z [ x , y ] w ) ⊂ 2 n Z [ x , y ] w for every even w w w .
Proof. That of Lemma 7: u u u , q q q , p − 1 p-1 p − 1 , v − 1 v-1 v − 1 are divisible by 2, so the terms with a + b + m + m ′ ≥ n a+b+m+m'\ge n a + b + m + m ′ ≥ n are divisible by 2 n 2^n 2 n , and w = 2 t w=2t w = 2 t .
Lemma 13 (a 5 a_5 a 5 modulo 512). There is an explicit element ζ ∈ I \zeta\in\mathcal{I} ζ ∈ I , a sum of 190 terms c γ h ( κ 1 ′ − 1 ) α 1 ⋯ ( κ 4 ′ − 1 ) α 4 c\gamma h(\kappa'_1-1)^{\alpha_1}\cdots(\kappa'_4-1)^{\alpha_4} c γ h ( κ 1 ′ − 1 ) α 1 ⋯ ( κ 4 ′ − 1 ) α 4 , with γ ∈ { 1 + S , 1 + U + U 2 , 1 + ε } \gamma\in\{1+S,1+U+U^2,1+\varepsilon\} γ ∈ { 1 + S , 1 + U + U 2 , 1 + ε } , h ∈ H 2 h\in\mathcal{H}_2 h ∈ H 2 , κ 1 ′ = ( 3 0 0 1 ) \kappa'_1=\begin{pmatrix}3&0\\0&1\end{pmatrix} κ 1 ′ = ( 3 0 0 1 ) , κ 2 ′ = ( 1 2 0 1 ) \kappa'_2=\begin{pmatrix}1&2\\0&1\end{pmatrix} κ 2 ′ = ( 1 0 2 1 ) , κ 3 ′ = ( 1 0 2 1 ) \kappa'_3=\begin{pmatrix}1&0\\2&1\end{pmatrix} κ 3 ′ = ( 1 2 0 1 ) , κ 4 ′ = ( 1 0 0 3 ) \kappa'_4=\begin{pmatrix}1&0\\0&3\end{pmatrix} κ 4 ′ = ( 1 0 0 3 ) and ∑ α i ≤ 8 \sum\alpha_i\le8 ∑ α i ≤ 8 , such that T ~ 5 − ( 1 + 5 Λ 5 ) − ζ \widetilde{T}_5-(1+5\Lambda_5)-\zeta T 5 − ( 1 + 5 Λ 5 ) − ζ satisfies the hypothesis of Lemma 12 with n = 9 n=9 n = 9 . Consequently P ∣ T ~ 5 = s 5 P ( m o d 512 L k ) P\lvert\widetilde{T}_5=s_5P\pmod{512L_k} P ∣ T 5 = s 5 P ( mod 512 L k ) for every k k k and every P ∈ L k P\in L_k P ∈ L k , and a 5 ( f ) ≡ 1 + 5 k − 1 ( m o d 512 Z 2 ) a_5(f)\equiv1+5^{k-1}\pmod{512\mathbb{Z}_2} a 5 ( f ) ≡ 1 + 5 k − 1 ( mod 512 Z 2 ) for every eigenform f f f of level 1.
Proof. Finite exact computation (VERIF_HATADA2.py, parts A and B); the conclusion is drawn as in the proof of Theorem K.
Status: PROVED .
The law
Let f f f be an eigenform of level 1 and weight k k k , O O O the ring of integers of a finite extension of Q 2 \mathbb{Q}_2 Q 2 containing its coefficients, ρ f : G Q → G L 2 ( O ) \rho_f:G_{\mathbb{Q}}\to\mathrm{GL}_2(O) ρ f : G Q → GL 2 ( O ) its 2-adic representation, T = tr ρ f T=\operatorname{tr}\rho_f T = tr ρ f , D = χ k − 1 D=\chi^{k-1} D = χ k − 1 (χ \chi χ the 2-adic cyclotomic character), T ~ E = 1 + χ k − 1 \widetilde{T}_E=1+\chi^{k-1} T E = 1 + χ k − 1 , Δ = T − T ~ E \Delta=T-\widetilde{T}_E Δ = T − T E , and s p = 1 + p k − 1 s_p=1+p^{k-1} s p = 1 + p k − 1 , d 3 = a 3 − s 3 d_3=a_3-s_3 d 3 = a 3 − s 3 . Let L L L be the maximal pro-2-extension of Q \mathbb{Q} Q unramified outside { 2 , ∞ } \{2,\infty\} { 2 , ∞ } and G = Gal ( L / Q ) G=\operatorname{Gal}(L/\mathbb{Q}) G = Gal ( L / Q ) . We call the class of g ∈ G g\in G g ∈ G the class of χ ( g ) \chi(g) χ ( g ) modulo 8.
(G1) Since a ℓ ≡ 1 + ℓ ( m o d 8 ) a_\ell\equiv1+\ell\pmod8 a ℓ ≡ 1 + ℓ ( mod 8 ) [9 ] , T ≡ 0 T\equiv0 T ≡ 0 and D ≡ 1 ( m o d 2 ) D\equiv1\pmod2 D ≡ 1 ( mod 2 ) ; the residual image is unipotent, ρ f ( G Q ) \rho_f(G_{\mathbb{Q}}) ρ f ( G Q ) is a pro-2-group, and T T T , D D D , T ~ E \widetilde{T}_E T E factor through G G G . By [17 Thm 8.1] and Chebotarev, Δ ( G ) ⊂ 2 7 O \Delta(G)\subset2^7O Δ ( G ) ⊂ 2 7 O .
(G2) The quadratic extensions of Q \mathbb{Q} Q unramified outside 2 are Q ( i ) \mathbb{Q}(i) Q ( i ) , Q ( 2 ) \mathbb{Q}(\sqrt{2}) Q ( 2 ) , Q ( − 2 ) \mathbb{Q}(\sqrt{-2}) Q ( − 2 ) : Φ ( G ) \Phi(G) Φ ( G ) is the set of elements of class 1, and G / Φ ( G ) ≃ ( Z / 8 Z ) × G/\Phi(G)\simeq(\mathbb{Z}/8\mathbb{Z})^\times G /Φ ( G ) ≃ ( Z /8 Z ) × via the class.
(G3) For a complex conjugation c c c , T ( c ) = T ~ E ( c ) = 0 T(c)=\widetilde{T}_E(c)=0 T ( c ) = T E ( c ) = 0 (ρ f \rho_f ρ f is odd).
(G4) If χ ( g ) ≡ 1 ( m o d 4 ) \chi(g)\equiv1\pmod4 χ ( g ) ≡ 1 ( mod 4 ) , v 2 ( T ~ E ( g ) ) = 1 v_2(\widetilde{T}_E(g))=1 v 2 ( T E ( g )) = 1 ; if χ ( g ) ≡ 3 ( m o d 4 ) \chi(g)\equiv3\pmod4 χ ( g ) ≡ 3 ( mod 4 ) , v 2 ( T ~ E ( g ) ) = v 2 ( 1 + χ ( g ) ) v_2(\widetilde{T}_E(g))=v_2(1+\chi(g)) v 2 ( T E ( g )) = v 2 ( 1 + χ ( g )) , since k − 1 k-1 k − 1 is odd. As T ≡ T ~ E ( m o d 2 7 ) T\equiv\widetilde{T}_E\pmod{2^7} T ≡ T E ( mod 2 7 ) , T T T has the same valuation as long as it is < 7 <7 < 7 .
(G5) H = { g : χ ( g ) ≡ ± 1 ( m o d 8 ) } = Gal ( L / Q ( 2 ) ) H=\{g:\chi(g)\equiv\pm1\pmod8\}=\operatorname{Gal}(L/\mathbb{Q}(\sqrt{2})) H = { g : χ ( g ) ≡ ± 1 ( mod 8 )} = Gal ( L / Q ( 2 )) and N = Φ ( G ) = Gal ( L / Q ( ζ 8 ) ) N=\Phi(G)=\operatorname{Gal}(L/\mathbb{Q}(\zeta_8)) N = Φ ( G ) = Gal ( L / Q ( ζ 8 )) ; L L L is also the maximal pro-2-extension of Q ( 2 ) \mathbb{Q}(\sqrt{2}) Q ( 2 ) and of Q ( ζ 8 ) \mathbb{Q}(\zeta_8) Q ( ζ 8 ) unramified outside 2 and ∞ \infty ∞ (that extension is Galois over Q \mathbb{Q} Q , with group an extension of a finite 2-group by a pro-2-group, hence a pro-2-extension of Q \mathbb{Q} Q unramified outside { 2 , ∞ } \{2,\infty\} { 2 , ∞ } , contained in L L L ). These fields have class number one, and Kummer theory gives isomorphisms H / Φ ( H ) ≃ ( Z / 2 ) 3 H/\Phi(H)\simeq(\mathbb{Z}/2)^3 H /Φ ( H ) ≃ ( Z /2 ) 3 via ( θ − 1 , θ 1 + 2 , θ 2 ) (\theta_{-1},\theta_{1+\sqrt{2}},\theta_{\sqrt{2}}) ( θ − 1 , θ 1 + 2 , θ 2 ) and N / Φ ( N ) ≃ ( Z / 2 ) 3 N/\Phi(N)\simeq(\mathbb{Z}/2)^3 N /Φ ( N ) ≃ ( Z /2 ) 3 via ( θ ζ 8 , θ 1 + 2 , θ 1 − ζ 8 ) (\theta_{\zeta_8},\theta_{1+\sqrt{2}},\theta_{1-\zeta_8}) ( θ ζ 8 , θ 1 + 2 , θ 1 − ζ 8 ) , where θ x ( g ) ∈ Z / 2 \theta_x(g)\in\mathbb{Z}/2 θ x ( g ) ∈ Z /2 is defined by g ( x ) = ( − 1 ) θ x ( g ) x g(\sqrt{x})=(-1)^{\theta_x(g)}\sqrt{x} g ( x ) = ( − 1 ) θ x ( g ) x ; and θ x ( s − 1 a s ) = θ s ( x ) ( a ) \theta_x(s^{-1}as)=\theta_{s(x)}(a) θ x ( s − 1 a s ) = θ s ( x ) ( a ) .
Lemma 14 (parity). Let n ≥ 1 n \ge1 n ≥ 1 and g , h ∈ G g,h \in G g , h ∈ G be such that Δ ( g h ) , Δ ( g − 1 h ) ∈ 2 n O \Delta(gh),\Delta(g^{-1}h) \in2^n O Δ ( g h ) , Δ ( g − 1 h ) ∈ 2 n O and Δ ( g ) T ( h ) + T E ( g ) Δ ( h ) ∈ 2 n + 1 O \Delta(g)T(h)+T_E(g)\Delta(h) \in2^{n+1}O Δ ( g ) T ( h ) + T E ( g ) Δ ( h ) ∈ 2 n + 1 O . Then Δ ( g h ) ≡ Δ ( g − 1 h ) ( m o d 2 n + 1 ) \Delta(gh) \equiv\Delta(g^{-1}h) \pmod{2^{n+1}} Δ ( g h ) ≡ Δ ( g − 1 h ) ( mod 2 n + 1 ) . In particular, if Δ ( K ) ⊂ 2 n O \Delta(K) \subset2^n O Δ ( K ) ⊂ 2 n O for a closed subgroup K K K of G G G , the function Δ / 2 n m o d 2 \Delta/2^n \bmod2 Δ/ 2 n mod 2 is constant on the classes of K K K modulo Φ ( K ) \Phi(K) Φ ( K ) , and vanishes on Φ ( K ) \Phi(K) Φ ( K ) .
Proof. Subtracting (1) for T E T_E T E from (1) for T T T : Δ ( g h ) + D ( g ) Δ ( g − 1 h ) = Δ ( g ) T ( h ) + T E ( g ) Δ ( h ) \Delta(gh)+D(g)\Delta(g^{-1}h)=\Delta(g)T(h)+T_E(g)\Delta(h) Δ ( g h ) + D ( g ) Δ ( g − 1 h ) = Δ ( g ) T ( h ) + T E ( g ) Δ ( h ) , and D ( g ) D(g) D ( g ) is odd. If g , h ∈ K g,h \in K g , h ∈ K , the hypothesis is satisfied since T T T and T E T_E T E are even; with ( g , g h ) (g,gh) ( g , g h ) instead of ( g , h ) (g,h) ( g , h ) , we get invariance under left multiplication by squares, which topologically generate Φ ( K ) \Phi(K) Φ ( K ) .
Theorem U (2-adic law). For every odd prime p p p :
a p ≡ s p ( m o d 2 10 ) if p ≡ 1 ( m o d 8 ) ; a p ≡ s p ( m o d 2 8 ) if p ≡ 5 ( m o d 8 ) ; a p − s p ≡ d 3 ( m o d 2 8 ) if p ≡ 3 ( m o d 8 ) ; a p − s p ≡ 2 d 3 ( m o d 2 9 ) if p ≡ 7 ( m o d 16 ) ; a p ≡ s p ( m o d 2 9 ) if p ≡ 15 ( m o d 16 ) . \begin{aligned}
a_p &\equiv s_p \pmod{2^{10}} &&\text{if } p \equiv1 \pmod{8};\\
a_p &\equiv s_p \pmod{2^8} &&\text{if } p \equiv5 \pmod{8};\\
a_p-s_p &\equiv d_3 \pmod{2^8} &&\text{if } p \equiv3 \pmod{8};\\
a_p-s_p &\equiv2d_3 \pmod{2^9} &&\text{if } p \equiv7 \pmod{16};\\
a_p &\equiv s_p \pmod{2^9} &&\text{if } p \equiv15 \pmod{16}.
\end{aligned} a p a p a p − s p a p − s p a p ≡ s p ( mod 2 10 ) ≡ s p ( mod 2 8 ) ≡ d 3 ( mod 2 8 ) ≡ 2 d 3 ( mod 2 9 ) ≡ s p ( mod 2 9 ) if p ≡ 1 ( mod 8 ) ; if p ≡ 5 ( mod 8 ) ; if p ≡ 3 ( mod 8 ) ; if p ≡ 7 ( mod 16 ) ; if p ≡ 15 ( mod 16 ) . Proof. Step 1 (modulo 2 8 2^8 2 8 ). By (G1) and Lemma 14 (K = G K=G K = G , n = 7 n=7 n = 7 ), ε = Δ / 2 7 m o d 2 \varepsilon=\Delta/2^7 \bmod2 ε = Δ/ 2 7 mod 2 depends only on the class, and ε = 0 \varepsilon=0 ε = 0 on class 1. On class 7, ε ( c ) = 0 \varepsilon(c)=0 ε ( c ) = 0 by (G3). On class 5, ε ( Frob 5 ) = 0 \varepsilon(\operatorname{Frob}_5)=0 ε ( Frob 5 ) = 0 by Lemma 13. On class 3, Δ ≡ Δ ( Frob 3 ) = d 3 ( m o d 2 8 ) \Delta\equiv\Delta(\operatorname{Frob}_3)=d_3 \pmod{2^8} Δ ≡ Δ ( Frob 3 ) = d 3 ( mod 2 8 ) .
Step 2 (modulo 2 9 2^9 2 9 on H H H ). By step 1, Δ ( H ) ⊂ 2 8 O \Delta(H) \subset2^8O Δ ( H ) ⊂ 2 8 O ; by Lemma 14, ε 2 = Δ / 2 8 m o d 2 \varepsilon_2=\Delta/2^8 \bmod2 ε 2 = Δ/ 2 8 mod 2 is a function on V = H / Φ ( H ) ≃ ( Z / 2 ) 3 V=H/\Phi(H)\simeq(\mathbb{Z}/2)^3 V = H /Φ ( H ) ≃ ( Z /2 ) 3 , vanishing at 0 0 0 and at c ˉ \bar c c ˉ . Let s s s be of class 3 or 5 and a , b ∈ N a,b\in N a , b ∈ N ; for g = s a g=sa g = s a , h = s b h=sb h = s b , of the same class, the hypothesis of Lemma 14 (n = 8 n=8 n = 8 ) is satisfied by (G4) and step 1, and g h = s 2 ( s − 1 a s ) b gh=s^2(s^{-1}as)b g h = s 2 ( s − 1 a s ) b , g − 1 h = a − 1 b g^{-1}h=a^{-1}b g − 1 h = a − 1 b . Since s ( 1 + 2 ) = − ( 1 + 2 ) − 1 s(1+\sqrt{2})=-(1+\sqrt{2})^{-1} s ( 1 + 2 ) = − ( 1 + 2 ) − 1 , s ( 2 ) = − 2 s(\sqrt{2})=-\sqrt{2} s ( 2 ) = − 2 and θ − 1 ( a ) = 0 \theta_{-1}(a)=0 θ − 1 ( a ) = 0 , one has s − 1 a s = a ˉ s^{-1}as=\bar a s − 1 a s = a ˉ , whence ε 2 ( a ˉ 2 + w ) = ε 2 ( w ) \varepsilon_2(\bar a^2+w)=\varepsilon_2(w) ε 2 ( a ˉ 2 + w ) = ε 2 ( w ) for every w ∈ V N = { θ − 1 = 0 } w\in V_N=\{\theta_{-1}=0\} w ∈ V N = { θ − 1 = 0 } , the image of N N N . By Euler’s criterion in F 9 \mathbb{F}_9 F 9 and F 25 \mathbb{F}_{25} F 25 (VERIF_HATADA2.py, part C), Frob 3 2 = ( 0 , 1 , 0 ) \operatorname{Frob}_3^2=(0,1,0) Frob 3 2 = ( 0 , 1 , 0 ) and Frob 5 2 = ( 0 , 0 , 1 ) \operatorname{Frob}_5^2=(0,0,1) Frob 5 2 = ( 0 , 0 , 1 ) , which generate V N V_N V N : hence ε 2 = 0 \varepsilon_2=0 ε 2 = 0 on V N V_N V N , that is, a p ≡ s p ( m o d 2 9 ) a_p\equiv s_p\pmod{2^9} a p ≡ s p ( mod 2 9 ) if p ≡ 1 ( m o d 8 ) p\equiv1\pmod8 p ≡ 1 ( mod 8 ) . For g g g of class 3 and h h h of class 5 (or the reverse), g h gh g h and g − 1 h g^{-1}h g − 1 h are of class 7, and (G4) and step 1 give Δ ( g ) T ( h ) + T E ( g ) Δ ( h ) ≡ 2 8 ε ( 3 ) ( m o d 2 9 ) \Delta(g)T(h)+T_E(g)\Delta(h)\equiv2^8\varepsilon(3)\pmod{2^9} Δ ( g ) T ( h ) + T E ( g ) Δ ( h ) ≡ 2 8 ε ( 3 ) ( mod 2 9 ) , whence ε 2 ( g h ) + ε 2 ( g − 1 h ) = ε ( 3 ) \varepsilon_2(gh)+\varepsilon_2(g^{-1}h)=\varepsilon(3) ε 2 ( g h ) + ε 2 ( g − 1 h ) = ε ( 3 ) ; with g = Frob 3 a g=\operatorname{Frob}_3a g = Frob 3 a , h = Frob 5 b h=\operatorname{Frob}_5b h = Frob 5 b , we get ε 2 ( z + Frob 3 2 ) = ε 2 ( z ) + ε ( 3 ) \varepsilon_2(z+\operatorname{Frob}_3^2)=\varepsilon_2(z)+\varepsilon(3) ε 2 ( z + Frob 3 2 ) = ε 2 ( z ) + ε ( 3 ) for every z z z in the image V 7 V_7 V 7 of class 7, and likewise with Frob 5 2 \operatorname{Frob}_5^2 Frob 5 2 . Since 2 + 2 = 2 ( 1 + 2 ) 2+\sqrt{2}=\sqrt{2}(1+\sqrt{2}) 2 + 2 = 2 ( 1 + 2 ) , one has θ 2 + 2 = θ 1 + 2 + θ 2 \theta_{2+\sqrt{2}}=\theta_{1+\sqrt{2}}+\theta_{\sqrt{2}} θ 2 + 2 = θ 1 + 2 + θ 2 , which takes the value 1 at Frob 3 2 \operatorname{Frob}_3^2 Frob 3 2 and at Frob 5 2 \operatorname{Frob}_5^2 Frob 5 2 (part C). Since ε 2 ( c ˉ ) = 0 \varepsilon_2(\bar c)=0 ε 2 ( c ˉ ) = 0 , ε 2 ( g ) = ε ( 3 ) θ 2 + 2 ( g ) \varepsilon_2(g)=\varepsilon(3)\theta_{2+\sqrt{2}}(g) ε 2 ( g ) = ε ( 3 ) θ 2 + 2 ( g ) on class 7 (2 + 2 2+\sqrt{2} 2 + 2 is totally positive, so θ 2 + 2 ( c ) = 0 \theta_{2+\sqrt{2}}(c)=0 θ 2 + 2 ( c ) = 0 ). Now θ 2 + 2 ( g ) = 0 \theta_{2+\sqrt{2}}(g)=0 θ 2 + 2 ( g ) = 0 if and only if g g g fixes Q ( ζ 16 ) + = Q ( 2 + 2 ) \mathbb{Q}(\zeta_{16})^+=\mathbb{Q}(\sqrt{2+\sqrt{2}}) Q ( ζ 16 ) + = Q ( 2 + 2 ) , that is, χ ( g ) ≡ 15 ( m o d 16 ) \chi(g)\equiv15\pmod{16} χ ( g ) ≡ 15 ( mod 16 ) for g g g of class 7; and 2 8 ε ( 3 ) ≡ 2 d 3 ( m o d 2 9 ) 2^8\varepsilon(3)\equiv2d_3\pmod{2^9} 2 8 ε ( 3 ) ≡ 2 d 3 ( mod 2 9 ) .
Step 3 (modulo 2 10 2^{10} 2 10 on N N N ). By step 2, Δ ( N ) ⊂ 2 9 O \Delta(N)\subset2^9O Δ ( N ) ⊂ 2 9 O , and ε 3 = Δ / 2 9 m o d 2 \varepsilon_3=\Delta/2^9\bmod2 ε 3 = Δ/ 2 9 mod 2 is a function on V ′ = N / Φ ( N ) ≃ ( Z / 2 ) 3 V'=N/\Phi(N)\simeq(\mathbb{Z}/2)^3 V ′ = N /Φ ( N ) ≃ ( Z /2 ) 3 , vanishing at 0. (i) For g = c a g=ca g = c a , h = c b h=cb h = c b (a , b ∈ N a,b\in N a , b ∈ N ), of class 7, Δ ( g ) , Δ ( h ) ∈ 2 8 O \Delta(g),\Delta(h)\in2^8O Δ ( g ) , Δ ( h ) ∈ 2 8 O and v 2 ( T ( h ) ) , v 2 ( T E ( g ) ) ≥ 3 v_2(T(h)),v_2(T_E(g))\ge3 v 2 ( T ( h )) , v 2 ( T E ( g )) ≥ 3 : Lemma 14 (n = 9 n=9 n = 9 ) gives ε 3 ( c a c − 1 + b ˉ ) = ε 3 ( a ˉ + b ˉ ) \varepsilon_3(cac^{-1}+\bar b)=\varepsilon_3(\bar a+\bar b) ε 3 ( c a c − 1 + b ˉ ) = ε 3 ( a ˉ + b ˉ ) . Since ζ 8 c ( ζ 8 ) = 1 \zeta_8c(\zeta_8)=1 ζ 8 c ( ζ 8 ) = 1 , ( 1 + 2 ) c ( 1 + 2 ) = ( 1 + 2 ) 2 (1+\sqrt{2})c(1+\sqrt{2})=(1+\sqrt{2})^2 ( 1 + 2 ) c ( 1 + 2 ) = ( 1 + 2 ) 2 and ( 1 − ζ 8 ) c ( 1 − ζ 8 ) = − ζ 8 − 1 ( 1 − ζ 8 ) 2 (1-\zeta_8)c(1-\zeta_8)=-\zeta_8^{-1}(1-\zeta_8)^2 ( 1 − ζ 8 ) c ( 1 − ζ 8 ) = − ζ 8 − 1 ( 1 − ζ 8 ) 2 , the element c a c − 1 + a ˉ cac^{-1}+\bar a c a c − 1 + a ˉ equals ( 0 , 0 , θ ζ 8 ( a ) ) (0,0,\theta_{\zeta_8}(a)) ( 0 , 0 , θ ζ 8 ( a )) : ε 3 \varepsilon_3 ε 3 is invariant under e 3 = ( 0 , 0 , 1 ) e_3=(0,0,1) e 3 = ( 0 , 0 , 1 ) . (ii) For g = Frob 3 a g=\operatorname{Frob}_3a g = Frob 3 a , h = Frob 3 b h=\operatorname{Frob}_3b h = Frob 3 b : Δ ( g ) ≡ Δ ( h ) ≡ d 3 ( m o d 2 8 ) \Delta(g)\equiv\Delta(h)\equiv d_3\pmod{2^8} Δ ( g ) ≡ Δ ( h ) ≡ d 3 ( mod 2 8 ) , T ( h ) = 4 u T(h)=4u T ( h ) = 4 u , T E ( g ) = 4 u ′ T_E(g)=4u' T E ( g ) = 4 u ′ ; here u ′ = T E ( g ) / 4 u'=T_E(g)/4 u ′ = T E ( g ) /4 lies in Z 2 × \mathbb{Z}_2^\times Z 2 × , and u = T E ( h ) / 4 ( m o d 2 5 ) u=T_E(h)/4\pmod{2^5} u = T E ( h ) /4 ( mod 2 5 ) with T E ( h ) / 4 ∈ Z 2 × T_E(h)/4\in\mathbb{Z}_2^\times T E ( h ) /4 ∈ Z 2 × , so u , u ′ ∈ Z 2 × + 2 5 O u,u'\in\mathbb{Z}_2^\times+2^5O u , u ′ ∈ Z 2 × + 2 5 O and u + u ′ ∈ 2 O u+u'\in2O u + u ′ ∈ 2 O ; hence Δ ( g ) T ( h ) + T E ( g ) Δ ( h ) ≡ 4 ( u + u ′ ) d 3 ≡ 0 ( m o d 2 10 ) \Delta(g)T(h)+T_E(g)\Delta(h)\equiv4(u+u')d_3\equiv0\pmod{2^{10}} Δ ( g ) T ( h ) + T E ( g ) Δ ( h ) ≡ 4 ( u + u ′ ) d 3 ≡ 0 ( mod 2 10 ) . Here ζ 8 ζ 8 c \zeta_8\zeta_8^c ζ 8 ζ 8 c and ( 1 + 2 ) ( 1 − 2 ) (1+\sqrt{2})(1-\sqrt{2}) ( 1 + 2 ) ( 1 − 2 ) are squares, so s − 1 a s + a ˉ ∈ ⟨ e 3 ⟩ s^{-1}as+\bar a\in\langle e_3\rangle s − 1 a s + a ˉ ∈ ⟨ e 3 ⟩ , and ε 3 \varepsilon_3 ε 3 is invariant under Frob 3 2 \operatorname{Frob}_3^2 Frob 3 2 , whose first two coordinates are ( 1 , 1 ) (1,1) ( 1 , 1 ) (part C). Thus ε 3 = β ( θ ζ 8 + θ 1 + 2 ) \varepsilon_3=\beta(\theta_{\zeta_8}+\theta_{1+\sqrt{2}}) ε 3 = β ( θ ζ 8 + θ 1 + 2 ) for some β ∈ O / 2 \beta\in O/2 β ∈ O /2 . (iii) For g g g of class 5, g 2 ∈ N g^2\in N g 2 ∈ N has first two coordinates ( 1 , 0 ) (1,0) ( 1 , 0 ) (part C), and the same computation as in (ii), and Δ ( g 2 ) = Δ ( g ) ( T ( g ) + T E ( g ) ) \Delta(g^2)=\Delta(g)(T(g)+T_E(g)) Δ ( g 2 ) = Δ ( g ) ( T ( g ) + T E ( g )) , since T ( g 2 ) = T ( g ) 2 − 2 D ( g ) T(g^2)=T(g)^2-2D(g) T ( g 2 ) = T ( g ) 2 − 2 D ( g ) ; now Δ ( g ) ∈ 2 8 O \Delta(g)\in2^8O Δ ( g ) ∈ 2 8 O (step 1) and v 2 ( T ( g ) + T E ( g ) ) = v 2 ( 2 T E ( g ) + Δ ( g ) ) = 2 v_2(T(g)+T_E(g))=v_2(2T_E(g)+\Delta(g))=2 v 2 ( T ( g ) + T E ( g )) = v 2 ( 2 T E ( g ) + Δ ( g )) = 2 , hence Δ ( g 2 ) ∈ 2 10 O \Delta(g^2)\in2^{10}O Δ ( g 2 ) ∈ 2 10 O and β = ε 3 ( g 2 ) = 0 \beta=\varepsilon_3(g^2)=0 β = ε 3 ( g 2 ) = 0 .
Status: PROVED. From [17 Thm 8.1] and Lemma 13.
Corollary V (Hatada’s question, a = 8 a=8 a = 8 and 9). For every eigenform of level 1 and every weight, Hatada’s question has an affirmative answer for a = 8 a=8 a = 8 and for a = 9 a=9 a = 9 ; for a = 10 a=10 a = 10 , the requested congruence holds for every p ≡ 1 ( m o d 2 9 ) p\equiv1\pmod{2^9} p ≡ 1 ( mod 2 9 ) .
Proof. If p ≡ ± 1 ( m o d 2 a − 1 ) p \equiv\pm1 \pmod{2^{a-1}} p ≡ ± 1 ( mod 2 a − 1 ) and a ≥ 4 a \ge4 a ≥ 4 , then p 2 ≡ 1 ( m o d 2 a ) p^2 \equiv1 \pmod{2^a} p 2 ≡ 1 ( mod 2 a ) and p k − 1 ≡ p ( m o d 2 a ) p^{k-1} \equiv p \pmod{2^a} p k − 1 ≡ p ( mod 2 a ) . If p ≡ 1 ( m o d 2 a − 1 ) p \equiv1 \pmod{2^{a-1}} p ≡ 1 ( mod 2 a − 1 ) , then p ≡ 1 ( m o d 8 ) p \equiv1 \pmod{8} p ≡ 1 ( mod 8 ) and Theorem U gives the congruence modulo 2 10 2^{10} 2 10 . If p ≡ − 1 ( m o d 2 a − 1 ) p \equiv-1 \pmod{2^{a-1}} p ≡ − 1 ( mod 2 a − 1 ) and a ∈ { 8 , 9 } a \in\{8,9\} a ∈ { 8 , 9 } , then p ≡ 15 ( m o d 16 ) p \equiv15 \pmod{16} p ≡ 15 ( mod 16 ) , and Theorem U gives the congruence modulo 2 9 2^9 2 9 . □
Status: PROVED.
The case p ≡ − 1 p \equiv-1 p ≡ − 1 and the complete answer
Let t ∈ G t \in G t ∈ G be a Frobenius element at 5 5 5 : χ ( t ) = 5 \chi(t)=5 χ ( t ) = 5 , and the images of t t t and of c c c generate G / Φ ( G ) ≃ ( Z / 8 Z ) × G/\Phi(G) \simeq(\mathbb{Z}/8\mathbb{Z})^\times G /Φ ( G ) ≃ ( Z /8 Z ) × , so c c c and t t t topologically generate G G G . Put x = Δ ( t ) = a 5 − s 5 x=\Delta(t)=a_5-s_5 x = Δ ( t ) = a 5 − s 5 and y = Δ ( c t ) y=\Delta(ct) y = Δ ( c t ) : by Lemma 13, x ∈ 2 9 O x \in2^9O x ∈ 2 9 O ; c t ct c t is of class 3, so y ∈ 2 7 O y \in2^7O y ∈ 2 7 O . Let D = 5 k − 1 D=5^{k-1} D = 5 k − 1 and, in GL 2 ( Z 2 [ η ] / ( η 2 ) ) \operatorname{GL}_2(\mathbb{Z}_2[\eta]/(\eta^2)) GL 2 ( Z 2 [ η ] / ( η 2 )) ,
C = ( 1 0 0 − 1 ) , T X = ( 1 1 0 D ) + η ( 1 D + 1 0 0 1 ) , T Y = ( 1 1 0 D ) + η ( 1 D − 1 0 0 − 1 ) . C=\begin{pmatrix}1&0\\0&-1\end{pmatrix},\qquad
T_X=\begin{pmatrix}1&1\\0&D\end{pmatrix}+\eta\begin{pmatrix}\frac{1}{D+1}&0\\0&1\end{pmatrix},\qquad
T_Y=\begin{pmatrix}1&1\\0&D\end{pmatrix}+\eta\begin{pmatrix}\frac{1}{D-1}&0\\0&-1\end{pmatrix}. C = ( 1 0 0 − 1 ) , T X = ( 1 0 1 D ) + η ( D + 1 1 0 0 1 ) , T Y = ( 1 0 1 D ) + η ( D − 1 1 0 0 − 1 ) .
For a word W W W in two letters, let τ X ( W ) \tau_X(W) τ X ( W ) (resp. τ Y ( W ) \tau_Y(W) τ Y ( W ) ) be the coefficient of η \eta η in the trace of W ( C , T X ) W(C,T_X) W ( C , T X ) (resp. W ( C , T Y ) W(C,T_Y) W ( C , T Y ) ), and χ ( W ) = ( − 1 ) a 5 b \chi(W)=(-1)^a5^b χ ( W ) = ( − 1 ) a 5 b if W W W contains a a a letters c c c and b b b letters t t t (with sign).
Lemma 15 (universal family). For every word W W W ,
Δ ( W ( c , t ) ) ≡ 2 7 x 2 8 τ X ( W ) + 2 6 y 2 7 τ Y ( W ) ( m o d 2 14 O ) . \Delta(W(c,t)) \equiv2^7\frac{x}{2^8}\tau_X(W)+2^6\frac{y}{2^7}\tau_Y(W)\pmod{2^{14}O}. Δ ( W ( c , t )) ≡ 2 7 2 8 x τ X ( W ) + 2 6 2 7 y τ Y ( W ) ( mod 2 14 O ) .
Proof. For indeterminates u , v u,v u , v , let ρ u , v \rho_{u,v} ρ u , v be the representation of the free group on c , t c,t c , t given by c ↦ ( 1 0 0 − 1 ) c\mapsto\begin{pmatrix}1&0\\0&-1\end{pmatrix} c ↦ ( 1 0 0 − 1 ) and t ↦ ( α 1 γ δ ) t\mapsto\begin{pmatrix}\alpha&1\\ \gamma&\delta\end{pmatrix} t ↦ ( α γ 1 δ ) with α = 1 + u + v 2 \alpha=1+\frac{u+v}{2} α = 1 + 2 u + v , δ = D + u − v 2 \delta=D+\frac{u-v}{2} δ = D + 2 u − v , γ = α δ − D \gamma=\alpha\delta-D γ = α δ − D : its trace at t t t is 1 + D + u = T E ( t ) + u 1+D+u=T_E(t)+u 1 + D + u = T E ( t ) + u , at c t ct c t it is 1 − D + v = T E ( c t ) + v 1-D+v=T_E(ct)+v 1 − D + v = T E ( c t ) + v , its determinant at c c c is − 1 -1 − 1 and at t t t is D D D . By Lemma 9, applied on the one hand to T T T on G G G (with T ( c ) = 0 T(c)=0 T ( c ) = 0 , D ( c ) = − 1 D(c)=-1 D ( c ) = − 1 ) and on the other hand to ρ u , v \rho_{u,v} ρ u , v , T ( W ( c , t ) ) = P W ( 0 , T E ( t ) + x , T E ( c t ) + y , − 1 , D ) = tr ρ x , y ( W ) T(W(c,t))=P_W(0,T_E(t)+x,T_E(ct)+y,-1,D)=\operatorname{tr}\rho_{x,y}(W) T ( W ( c , t )) = P W ( 0 , T E ( t ) + x , T E ( c t ) + y , − 1 , D ) = tr ρ x , y ( W ) . The polynomial P W P_W P W has integer coefficients; the Taylor expansion at ( u , v ) = ( 0 , 0 ) (u,v)=(0,0) ( u , v ) = ( 0 , 0 ) therefore has terms of order ≥ 2 \ge2 ≥ 2 in ( x , y ) 2 O ⊂ 2 14 O (x,y)^2O\subset2^{14}O ( x , y ) 2 O ⊂ 2 14 O , the constant term T E ( W ) T_E(W) T E ( W ) , and first-order terms equal to the coefficients of η \eta η computed with the derivatives ∂ u ρ ( t ) = 1 2 ( 1 D + 1 1 0 1 ) \partial_u\rho(t)=\frac{1}{2}\begin{pmatrix}\frac{1}{D+1}&1\\0&1\end{pmatrix} ∂ u ρ ( t ) = 2 1 ( D + 1 1 0 1 1 ) and ∂ v ρ ( t ) = 1 2 ( 1 D − 1 − 1 0 0 ) \partial_v\rho(t)=\frac{1}{2}\begin{pmatrix}\frac{1}{D-1}&-1\\0&0\end{pmatrix} ∂ v ρ ( t ) = 2 1 ( D − 1 1 0 − 1 0 ) , whence the formula with x = 2 8 ⋅ x 2 8 x=2^8\cdot\frac{x}{2^8} x = 2 8 ⋅ 2 8 x and y = 2 7 ⋅ y 2 7 y=2^7\cdot\frac{y}{2^7} y = 2 7 ⋅ 2 7 y . □
Theorem W (depth on the class of − 1 -1 − 1 ). Let g ∈ G g \in G g ∈ G . If χ ( g ) ≡ 1 ( m o d 8 ) \chi(g)\equiv1\pmod{8} χ ( g ) ≡ 1 ( mod 8 ) , then Δ ( g ) ∈ 2 10 O \Delta(g)\in2^{10}O Δ ( g ) ∈ 2 10 O ; if χ ( g ) ≡ 5 ( m o d 8 ) \chi(g)\equiv5\pmod{8} χ ( g ) ≡ 5 ( mod 8 ) , then Δ ( g ) ∈ 2 9 O \Delta(g)\in2^9O Δ ( g ) ∈ 2 9 O . If v 2 ( 1 + χ ( g ) ) = m ≥ 2 v_2(1+\chi(g))=m\ge2 v 2 ( 1 + χ ( g )) = m ≥ 2 , then Δ ( g ) ∈ 2 min ( m + 5 , 11 ) O \Delta(g)\in2^{\min(m+5,11)}O Δ ( g ) ∈ 2 m i n ( m + 5 , 11 ) O . In particular, for every prime p ≡ − 1 ( m o d 32 ) p\equiv-1\pmod{32} p ≡ − 1 ( mod 32 ) , a p ≡ 1 + p k − 1 ( m o d 2 10 ) a_p\equiv1+p^{k-1}\pmod{2^{10}} a p ≡ 1 + p k − 1 ( mod 2 10 ) .
Proof. For powers of two N N N and N ′ N' N ′ , the map W ↦ ( W ( C , T ) m o d N , χ ( W ) m o d N ′ ) W\mapsto(W(C,T)\bmod N,\chi(W)\bmod N') W ↦ ( W ( C , T ) mod N , χ ( W ) mod N ′ ) is a morphism to a finite group, which depends on k k k only through D m o d N D\bmod N D mod N , hence through k − 1 k-1 k − 1 modulo N / 4 N/4 N /4 (the order of 5 5 5 modulo N N N ). For ( N , N ′ ) = ( 16 , 64 ) (N,N')=(16,64) ( N , N ′ ) = ( 16 , 64 ) and then ( 32 , 512 ) (32,512) ( 32 , 512 ) , and for all these classes of k − 1 k-1 k − 1 , VERIF_HATADA2.py (part E) enumerates these images (512 to 32 768 elements) and checks that τ X ≡ 0 ( m o d 8 ) \tau_X\equiv0\pmod{8} τ X ≡ 0 ( mod 8 ) and τ Y ≡ 0 ( m o d 16 ) \tau_Y\equiv0\pmod{16} τ Y ≡ 0 ( mod 16 ) when χ ≡ 1 ( m o d 8 ) \chi\equiv1\pmod{8} χ ≡ 1 ( mod 8 ) or χ ≡ − 1 ( m o d 32 ) \chi\equiv-1\pmod{32} χ ≡ − 1 ( mod 32 ) , and that 2 7 τ X 2^7\tau_X 2 7 τ X and 2 6 τ Y 2^6\tau_Y 2 6 τ Y are divisible by 2 min ( m + 5 , 11 ) 2^{\min(m+5,11)} 2 m i n ( m + 5 , 11 ) when v 2 ( 1 + χ ) = m ≥ 2 v_2(1+\chi)=m\ge2 v 2 ( 1 + χ ) = m ≥ 2 (each of these assertions is tested by the script); finally that τ X ≡ 0 ( m o d 2 ) \tau_X\equiv0\pmod{2} τ X ≡ 0 ( mod 2 ) and τ Y ≡ 0 ( m o d 8 ) \tau_Y\equiv0\pmod{8} τ Y ≡ 0 ( mod 8 ) when χ ≡ 5 ( m o d 8 ) \chi\equiv5\pmod{8} χ ≡ 5 ( mod 8 ) , which, with x ∈ 2 9 O x\in2^9O x ∈ 2 9 O , gives 2 9 ∣ Δ 2^9\mid\Delta 2 9 ∣ Δ on class 5. By Lemma 15, the conclusion holds for every word W ( c , t ) W(c,t) W ( c , t ) . For arbitrary g ∈ G g\in G g ∈ G , T T T modulo 2 11 2^{11} 2 11 and χ \chi χ modulo 2 12 2^{12} 2 12 factor through a finite quotient of G G G , in which the image of the dense subgroup generated by c c c and t t t is everything: there is a word W W W such that T ( W ) ≡ T ( g ) ( m o d 2 11 ) T(W)\equiv T(g)\pmod{2^{11}} T ( W ) ≡ T ( g ) ( mod 2 11 ) and χ ( W ) ≡ χ ( g ) ( m o d 2 12 ) \chi(W)\equiv\chi(g)\pmod{2^{12}} χ ( W ) ≡ χ ( g ) ( mod 2 12 ) , hence T E ( W ) ≡ T E ( g ) ( m o d 2 11 ) T_E(W)\equiv T_E(g)\pmod{2^{11}} T E ( W ) ≡ T E ( g ) ( mod 2 11 ) . □
Status: PROVED. Finite exact computation, from [17 Thm 8.1] and Lemma 13. This computation also gives back, by a route independent of Kummer theory, the congruence modulo 2 10 2^{10} 2 10 of Theorem U for p ≡ 1 ( m o d 8 ) p\equiv1\pmod{8} p ≡ 1 ( mod 8 ) .
Corollary X (complete answer to Hatada’s question). Hatada’s question has an affirmative answer for 6 ≤ a ≤ 10 6 \le a \le10 6 ≤ a ≤ 10 , for every eigenform of level 1 and every weight, and a negative answer for a = 11 , 12 a = 11, 12 a = 11 , 12 and 13 13 13 .
Proof. For a = 6 , 7 a = 6, 7 a = 6 , 7 , this is [17 Thm 8.1] (Section 1 and its footnote); for a = 8 , 9 a = 8, 9 a = 8 , 9 , it is Corollary V; for a = 10 a = 10 a = 10 , p ≡ 1 ( m o d 2 9 ) p \equiv1 \pmod{2^9} p ≡ 1 ( mod 2 9 ) falls under Corollary V and p ≡ − 1 ( m o d 2 9 ) p \equiv-1 \pmod{2^9} p ≡ − 1 ( mod 2 9 ) under Theorem W. For a ∈ { 11 , 12 , 13 } a \in\{11, 12, 13\} a ∈ { 11 , 12 , 13 } , Theorem A gives counterexamples (Δ 16 \Delta_{16} Δ 16 and p = 12289 p = 12289 p = 12289 ).
Status: PROVED.
Corollary Y (non-vanishing). For every eigenform f f f of level 1 and every odd prime p p p such that v 2 ( p + 1 ) ≤ 10 v_2(p+1) \le10 v 2 ( p + 1 ) ≤ 10 , one has v 2 ( a p ( f ) ) = v 2 ( p + 1 ) v_2(a_p(f)) = v_2(p+1) v 2 ( a p ( f )) = v 2 ( p + 1 ) . In particular, a p ( f ) = 0 a_p(f) = 0 a p ( f ) = 0 implies p ≡ − 1 ( m o d 2 11 ) p \equiv-1 \pmod{2^{11}} p ≡ − 1 ( mod 2 11 ) , and even p ≡ − 1 ( m o d 2 11 ⋅ 27 ) p \equiv-1 \pmod{2^{11}\cdot27} p ≡ − 1 ( mod 2 11 ⋅ 27 ) if k ≢ 4 ( m o d 6 ) k \not\equiv4 \pmod6 k ≡ 4 ( mod 6 ) .
Proof. One has v 2 ( s p ) = v 2 ( 1 + p ) v_2(s_p) = v_2(1+p) v 2 ( s p ) = v 2 ( 1 + p ) : if p ≡ 1 ( m o d 4 ) p \equiv1 \pmod4 p ≡ 1 ( mod 4 ) , both equal 1; otherwise, k − 1 k-1 k − 1 being odd, 1 + p k − 1 = ( 1 + p ) ( 1 − p + ⋯ + p k − 2 ) 1+p^{k-1} = (1+p)(1-p+\cdots+p^{k-2}) 1 + p k − 1 = ( 1 + p ) ( 1 − p + ⋯ + p k − 2 ) with an odd second factor. If p ≡ 1 ( m o d 4 ) p \equiv1 \pmod4 p ≡ 1 ( mod 4 ) , a p ≡ s p ( m o d 2 8 ) a_p \equiv s_p \pmod{2^8} a p ≡ s p ( mod 2 8 ) (Theorem U), hence v 2 ( a p ) = 1 v_2(a_p) = 1 v 2 ( a p ) = 1 . If v 2 ( p + 1 ) = m ∈ [ 2 , 10 ] v_2(p+1) = m \in[2,10] v 2 ( p + 1 ) = m ∈ [ 2 , 10 ] , Theorem W gives a p − s p ∈ 2 min ( m + 5 , 11 ) O a_p-s_p \in2^{\min(m+5,11)}O a p − s p ∈ 2 m i n ( m + 5 , 11 ) O and min ( m + 5 , 11 ) > m \min(m+5,11) > m min ( m + 5 , 11 ) > m , hence v 2 ( a p ) = m v_2(a_p) = m v 2 ( a p ) = m . If k ≢ 4 ( m o d 6 ) k \not\equiv4 \pmod6 k ≡ 4 ( mod 6 ) , v 3 ( k − 1 ) = 0 v_3(k-1) = 0 v 3 ( k − 1 ) = 0 , and Theorem O gives a p ≡ s p ≢ 0 ( m o d 3 ) a_p \equiv s_p \not\equiv0 \pmod3 a p ≡ s p ≡ 0 ( mod 3 ) if p ≡ 1 ( m o d 3 ) p \equiv1 \pmod3 p ≡ 1 ( mod 3 ) , and a p ≡ ± s p ( m o d 27 ) a_p \equiv\pm s_p \pmod{27} a p ≡ ± s p ( mod 27 ) with v 3 ( s p ) = v 3 ( p + 1 ) v_3(s_p) = v_3(p+1) v 3 ( s p ) = v 3 ( p + 1 ) if p ≡ 2 ( m o d 3 ) p \equiv2 \pmod3 p ≡ 2 ( mod 3 ) ; hence a p = 0 a_p = 0 a p = 0 implies p ≡ − 1 ( m o d 27 ) p \equiv-1 \pmod{27} p ≡ − 1 ( mod 27 ) .
Status: PROVED.
Status: PROVED by the optional part F of the script, disabled by default. With ( N , N ′ ) = ( 64 , 2048 ) (N,N') = (64, 2048) ( N , N ′ ) = ( 64 , 2048 ) (about 500 000 elements), the same computation gives Δ ( g ) ∈ 2 12 O \Delta(g) \in2^{12}O Δ ( g ) ∈ 2 12 O as soon as v 2 ( 1 + χ ( g ) ) ≥ 7 v_2(1+\chi(g)) \ge7 v 2 ( 1 + χ ( g )) ≥ 7 , whence p ≡ − 1 ( m o d 2 12 ) p \equiv-1 \pmod{2^{12}} p ≡ − 1 ( mod 2 12 ) . This sieve is effective but concerns only p p p ; for fixed p p p , the (non-effective) finiteness of the set of forms of level 1 such that a p ( f ) = 0 a_p(f) = 0 a p ( f ) = 0 is due to Calegari and Sardari [2 ] .
Remark. VERIFIED (PARI/GP, 12 ≤ k ≤ 80 12 \le k \le80 12 ≤ k ≤ 80 , p < 300 p < 300 p < 300 ): the minimal depths observed are 10 for p ≡ 1 ( m o d 8 ) p \equiv1 \pmod8 p ≡ 1 ( mod 8 ) (optimal, Theorem E ), 7 for p ≡ 3 ( m o d 8 ) p \equiv3 \pmod8 p ≡ 3 ( mod 8 ) , 9 for p ≡ 5 ( m o d 8 ) p \equiv5 \pmod8 p ≡ 5 ( mod 8 ) , and 8, 9, 10 for p ≡ 7 ( m o d 16 ) p \equiv7 \pmod{16} p ≡ 7 ( mod 16 ) , 15 ( m o d 32 ) 15 \pmod{32} 15 ( mod 32 ) , 31 ( m o d 32 ) 31 \pmod{32} 31 ( mod 32 ) , in accordance with Theorems U and W. The laws of Theorem U were checked in 1247 cases (k ≤ 70 k \le70 k ≤ 70 , p < 200 p < 200 p < 200 ) without failure; the correction 2 d 3 2d_3 2 d 3 is necessary in 84 of them. The depth 9 on class 5 (Theorem W) is therefore optimal.
Beyond 729: the law of inert primes
Notation of §7; κ = k − 1 \kappa= k-1 κ = k − 1 and s ℓ = 1 + ℓ k s_\ell= 1+\ell^k s ℓ = 1 + ℓ k . We still write σ \sigma σ for the automorphism of G ^ \widehat{G} G induced by conjugation by a complex conjugation c c c . Let x ∈ G ^ x \in\widehat{G} x ∈ G be the Frobenius element of a prime ideal of O K O_K O K above 7, and y = σ ( x ) y = \sigma(x) y = σ ( x ) . Since 7 ≡ 7 ( m o d 9 ) 7 \equiv7 \pmod9 7 ≡ 7 ( mod 9 ) and 3 is not a cube modulo 7, one has u ( y ) = u ( x ) ≠ 0 u(y) = u(x) \ne0 u ( y ) = u ( x ) = 0 and v ( y ) = − v ( x ) ≠ 0 v(y) = -v(x) \ne0 v ( y ) = − v ( x ) = 0 ; the images of x x x and y y y in ( Z / 3 Z ) 2 (\mathbb{Z}/3\mathbb{Z})^2 ( Z /3 Z ) 2 form a basis, so x x x and y y y topologically generate G ^ \widehat{G} G (Burnside’s basis theorem).
The anticyclotomic character. The group G ^ \widehat{G} G is free on two generators [20 ] , so Hom ( G ^ , Z 3 ) \operatorname{Hom}(\widehat{G},\mathbb{Z}_3) Hom ( G , Z 3 ) is free of rank 2; σ \sigma σ acts on it as an involution, and its + 1 +1 + 1 and − 1 -1 − 1 eigenparts, of rank 1, reduce modulo 3 onto ⟨ u ⟩ \langle u\rangle ⟨ u ⟩ and ⟨ v ⟩ \langle v\rangle ⟨ v ⟩ . The + 1 +1 + 1 part is generated by λ = 1 3 log 3 χ \lambda= \frac{1}{3}\log_3 \chi λ = 3 1 log 3 χ (proof of Theorem R); we fix a generator μ \mu μ of the − 1 -1 − 1 part. Then ( λ , μ ) (\lambda,\mu) ( λ , μ ) is a basis of Hom ( G ^ , Z 3 ) \operatorname{Hom}(\widehat{G},\mathbb{Z}_3) Hom ( G , Z 3 ) , and Hom ( G ^ , A ) = A λ ⊕ A μ \operatorname{Hom}(\widehat{G},A)=A\lambda\oplus A\mu Hom ( G , A ) = A λ ⊕ A μ for every finite Z 3 \mathbb{Z}_3 Z 3 -module A A A . The fixed field of ker ( μ m o d 9 ) \ker(\mu\bmod9) ker ( μ mod 9 ) is therefore the unique cyclic extension of degree 9 of K K K , unramified outside 3, on whose Galois group c c c acts by − 1 -1 − 1 . The ring class field H 27 H_{27} H 27 of the order Z + 27 O K \mathbb{Z}+27O_K Z + 27 O K , of discriminant − 2187 -2187 − 2187 , has these properties: it is unramified outside 3, c c c acts by − 1 -1 − 1 on Gal ( H 27 / K ) \operatorname{Gal}(H_{27}/K) Gal ( H 27 / K ) [5 §9] , and this group, isomorphic to the Picard group of the order, is cyclic of order 9. For a prime ℓ ≡ 1 ( m o d 3 ) \ell\equiv1 \pmod3 ℓ ≡ 1 ( mod 3 ) and ℓ ∤ ℓ \ell\nmid\ell ℓ ∤ ℓ , one therefore has μ ( Frob ℓ ) ∈ 9 Z 3 \mu(\operatorname{Frob}_\ell) \in9\mathbb{Z}_3 μ ( Frob ℓ ) ∈ 9 Z 3 if and only if ℓ \ell ℓ splits completely in H 27 H_{27} H 27 , that is [5 §9] , if and only if ℓ = X 2 + X Y + 547 Y 2 \ell= X^2+XY+547Y^2 ℓ = X 2 + X Y + 547 Y 2 with X , Y ∈ Z X,Y \in\mathbb{Z} X , Y ∈ Z . Likewise, ν ( Frob ℓ ) = 0 \nu(\operatorname{Frob}_\ell)=0 ν ( Frob ℓ ) = 0 if and only if ℓ = X 2 + X Y + 61 Y 2 \ell= X^2+XY+61Y^2 ℓ = X 2 + X Y + 61 Y 2 .
The base point. Let s ∈ O ′ s \in O' s ∈ O ′ be as in the proof of Theorem R (s = 9 t s = 9t s = 9 t if 3 ∤ κ 3 \nmid\kappa 3 ∤ κ , s = 3 t s = 3t s = 3 t if 3 ∣ κ 3 \mid\kappa 3 ∣ κ ; in the latter case, changing the lift α ~ \widetilde{\alpha} α if necessary, we assume 2 s ≠ κ 2s \ne\kappa 2 s = κ , which ensures w < ∞ w < \infty w < ∞ and Δ ≠ 0 \Delta\ne0 Δ = 0 in Lemma 17). Put ψ 1 = ψ s \psi_1 = \psi_s ψ 1 = ψ s , ψ 2 = χ κ ψ s − 1 \psi_2 = \chi^\kappa\psi_s^{-1} ψ 2 = χ κ ψ s − 1 , θ = ψ 1 / ψ 2 = exp 3 ( 2 s − κ ) λ \theta= \psi_1/\psi_2 = \exp_3(2s-\kappa)\lambda θ = ψ 1 / ψ 2 = exp 3 ( 2 s − κ ) λ and w = v 3 ( 2 s − κ ) w = v_3(2s-\kappa) w = v 3 ( 2 s − κ ) : w = 0 w = 0 w = 0 if 3 ∤ κ 3 \nmid\kappa 3 ∤ κ , w ≥ 1 w \ge1 w ≥ 1 if 3 ∣ κ 3 \mid\kappa 3 ∣ κ . Thus M s = ψ 1 + ψ 2 M_s = \psi_1+\psi_2 M s = ψ 1 + ψ 2 , and, by the proof of Theorem R, T ≡ M s T \equiv M_s T ≡ M s (mod 243 O ′ 243O' 243 O ′ ) on G K G_K G K . The functions ψ 1 , ψ 2 , θ , λ \psi_1,\psi_2,\theta,\lambda ψ 1 , ψ 2 , θ , λ are invariant under σ \sigma σ , and θ ≡ 1 \theta\equiv1 θ ≡ 1 (mod 3 3 3 ) on G ^ \widehat{G} G .
Lemma 16 (an irreducible tangent). There are continuous functions β , γ , z : G ^ → O ′ \beta,\gamma,z:\widehat{G}\to O' β , γ , z : G → O ′ such that, for h , h ′ ∈ G ^ h,h'\in\widehat{G} h , h ′ ∈ G ,
β ( h h ′ ) = β ( h ) + θ ( h ) β ( h ′ ) , γ ( h h ′ ) = γ ( h ) + θ ( h ) − 1 γ ( h ′ ) , z ( h h ′ ) = z ( h ) + z ( h ′ ) + θ ( h ) γ ( h ) β ( h ′ ) , \beta(hh')=\beta(h)+\theta(h)\beta(h'),\qquad\gamma(hh')=\gamma(h)+\theta(h)^{-1}\gamma(h'),\qquad z(hh')=z(h)+z(h')+\theta(h)\gamma(h)\beta(h'), β ( h h ′ ) = β ( h ) + θ ( h ) β ( h ′ ) , γ ( h h ′ ) = γ ( h ) + θ ( h ) − 1 γ ( h ′ ) , z ( h h ′ ) = z ( h ) + z ( h ′ ) + θ ( h ) γ ( h ) β ( h ′ ) , β ( x ) = γ ( x ) = 1 \beta(x)=\gamma(x)=1 β ( x ) = γ ( x ) = 1 , z ( x ) = 0 z(x)=0 z ( x ) = 0 , β ∘ σ = − β \beta\circ\sigma=-\beta β ∘ σ = − β , γ ∘ σ = − γ \gamma\circ\sigma=-\gamma γ ∘ σ = − γ , z ∘ σ = z z\circ\sigma=z z ∘ σ = z , and such that the function
e = ψ 2 ( ( 1 − θ ) z + θ β γ ) e=\psi_2((1-\theta)z+\theta\beta\gamma) e = ψ 2 (( 1 − θ ) z + θ β γ ) satisfies e ( 1 ) = 0 e(1)=0 e ( 1 ) = 0 , e ( h h ′ ) = e ( h ′ h ) e(hh')=e(h'h) e ( h h ′ ) = e ( h ′ h ) , e ∘ σ = e e\circ\sigma=e e ∘ σ = e and, with D = χ κ D=\chi^\kappa D = χ κ ,
e ( h h ′ ) + D ( h ) e ( h − 1 h ′ ) = e ( h ) M s ( h ′ ) + M s ( h ) e ( h ′ ) ( h , h ′ ∈ G ^ ) . (3) e(hh')+D(h)e(h^{-1}h')=e(h)M_s(h')+M_s(h)e(h') \qquad(h,h'\in\widehat{G}). \tag*{(3)} e ( h h ′ ) + D ( h ) e ( h − 1 h ′ ) = e ( h ) M s ( h ′ ) + M s ( h ) e ( h ′ ) ( h , h ′ ∈ G ) . (3) Moreover:
(a) for every h ∈ G ^ h\in\widehat{G} h ∈ G , e ( σ ( h ) h ) = 2 ψ 2 ( h ) 2 ( 1 − θ ( h ) ) F ( h ) e(\sigma(h)h)=2\psi_2(h)^2(1-\theta(h))F(h) e ( σ ( h ) h ) = 2 ψ 2 ( h ) 2 ( 1 − θ ( h )) F ( h ) , where F = ( 1 + θ ) z − θ β γ F=(1+\theta)z-\theta\beta\gamma F = ( 1 + θ ) z − θ β γ ;
(b) β ≡ γ ≡ v / v ( x ) \beta\equiv\gamma\equiv v/v(x) β ≡ γ ≡ v / v ( x ) (mod 3 O ′ 3O' 3 O ′ ), and there is a a ∈ O ′ a\in O' a ∈ O ′ such that F ≡ a u F\equiv au F ≡ a u (mod 3 O ′ 3O' 3 O ′ );
(c) if w ≥ 1 w\ge1 w ≥ 1 , there are b , b ′ ∈ O ′ b,b'\in O' b , b ′ ∈ O ′ such that β ≡ b μ \beta\equiv b\mu β ≡ b μ and γ ≡ b ′ μ \gamma\equiv b'\mu γ ≡ b ′ μ (mod 9 O ′ 9O' 9 O ′ ).
Proof. Let ε \varepsilon ε be such that ε 2 = 0 \varepsilon^2=0 ε 2 = 0 , C = diag ( 1 , − 1 ) C=\operatorname{diag}(1,-1) C = diag ( 1 , − 1 ) , and Γ 1 \Gamma_1 Γ 1 the subgroup of GL 2 ( O ′ [ ε ] ) \operatorname{GL}_2(O'[\varepsilon]) GL 2 ( O ′ [ ε ]) formed by the matrices congruent, modulo the ideal generated by the maximal ideal of O ′ O' O ′ and ε \varepsilon ε , to an upper unipotent matrix; it is a pro-3-group. The matrices
R = ( ψ 1 ( x ) ψ 2 ( x ) 0 ψ 2 ( x ) ) ( 1 + ε 0 θ ( x ) 0 ) and C R C R=\begin{pmatrix}\psi_1(x)&\psi_2(x)\\0&\psi_2(x)\end{pmatrix}
\begin{pmatrix}1+\varepsilon&0\\\theta(x)&0\end{pmatrix}
\qquad\text{and}\qquad CRC R = ( ψ 1 ( x ) 0 ψ 2 ( x ) ψ 2 ( x ) ) ( 1 + ε θ ( x ) 0 0 ) and C R C
lie in Γ 1 \Gamma_1 Γ 1 . Since G ^ \widehat{G} G is a free pro-3-group of rank 2 [20 ] generated by x x x and y y y , the pair ( x , y ) (x,y) ( x , y ) is a basis of it (a free pro-3-group of finite rank is Hopfian [11 ] ), and there is a continuous homomorphism ρ : G ^ → Γ 1 \rho:\widehat{G}\to\Gamma_1 ρ : G → Γ 1 such that ρ ( x ) = R \rho(x)=R ρ ( x ) = R and ρ ( y ) = C R C \rho(y)=CRC ρ ( y ) = C R C ; one has ρ ∘ σ = C ρ C \rho\circ\sigma=C\rho C ρ ∘ σ = C ρC , the two sides agreeing at x x x and y y y . Write ρ = ρ 0 ( 1 + ε Z ) \rho=\rho_0(1+\varepsilon Z) ρ = ρ 0 ( 1 + εZ ) , where ρ 0 \rho_0 ρ 0 is the reduction of ρ \rho ρ modulo ε \varepsilon ε . Then ρ 0 \rho_0 ρ 0 is upper triangular, with diagonal ( ψ 1 , ψ 2 ) (\psi_1,\psi_2) ( ψ 1 , ψ 2 ) (two characters which agree with ψ 1 , ψ 2 \psi_1,\psi_2 ψ 1 , ψ 2 at x x x and at y y y ), Z ( h h ′ ) = ρ 0 ( h ′ ) − 1 Z ( h ) ρ 0 ( h ′ ) + Z ( h ′ ) Z(hh')=\rho_0(h')^{-1}Z(h)\rho_0(h')+Z(h') Z ( h h ′ ) = ρ 0 ( h ′ ) − 1 Z ( h ) ρ 0 ( h ′ ) + Z ( h ′ ) , and tr Z \operatorname{tr}Z tr Z is a homomorphism vanishing at x x x and y y y , hence zero; thus det ρ = det ρ 0 = D \det\rho=\det\rho_0=D det ρ = det ρ 0 = D . Put β = ( ρ 0 ) 12 / ψ 2 \beta=(\rho_0)_{12}/\psi_2 β = ( ρ 0 ) 12 / ψ 2 , γ = Z 21 / θ \gamma=Z_{21}/\theta γ = Z 21 / θ and z = Z 22 z=Z_{22} z = Z 22 : the three relations are obtained by reading these identities coefficient by coefficient, and tr ρ = M s + ε e \operatorname{tr}\rho=M_s+\varepsilon e tr ρ = M s + ε e . The function tr ρ \operatorname{tr}\rho tr ρ satisfies (1) over O ′ [ ε ] O'[\varepsilon] O ′ [ ε ] with the same D D D , so e e e satisfies (2); the symmetries come from ρ ∘ σ = C ρ C \rho\circ\sigma=C\rho C ρ ∘ σ = C ρC , which also gives β ( y ) = γ ( y ) = − 1 \beta(y)=\gamma(y)=-1 β ( y ) = γ ( y ) = − 1 and z ( y ) = 0 z(y)=0 z ( y ) = 0 .
(a) The relations give β ( σ ( h ) h ) = ( θ ( h ) − 1 ) β ( h ) \beta(\sigma(h)h)=(\theta(h)-1)\beta(h) β ( σ ( h ) h ) = ( θ ( h ) − 1 ) β ( h ) , γ ( σ ( h ) h ) = ( θ ( h ) − 1 − 1 ) γ ( h ) \gamma(\sigma(h)h)=(\theta(h)^{-1}-1)\gamma(h) γ ( σ ( h ) h ) = ( θ ( h ) − 1 − 1 ) γ ( h ) , z ( σ ( h ) h ) = 2 z ( h ) − θ ( h ) γ ( h ) β ( h ) z(\sigma(h)h)=2z(h)-\theta(h)\gamma(h)\beta(h) z ( σ ( h ) h ) = 2 z ( h ) − θ ( h ) γ ( h ) β ( h ) , and θ ( σ ( h ) h ) = θ ( h ) 2 \theta(\sigma(h)h)=\theta(h)^2 θ ( σ ( h ) h ) = θ ( h ) 2 , ψ 2 ( σ ( h ) h ) = ψ 2 ( h ) 2 \psi_2(\sigma(h)h)=\psi_2(h)^2 ψ 2 ( σ ( h ) h ) = ψ 2 ( h ) 2 . With t = θ ( h ) t=\theta(h) t = θ ( h ) and P = β ( h ) γ ( h ) P=\beta(h)\gamma(h) P = β ( h ) γ ( h ) ,
e ( σ ( h ) h ) ψ 2 ( h ) 2 = ( 1 − t 2 ) ( 2 z ( h ) − t P ) − t ( 1 − t ) 2 P = 2 ( 1 − t ) ( ( 1 + t ) z ( h ) − t P ) . \frac{e(\sigma(h)h)}{\psi_2(h)^2}=(1-t^2)(2z(h)-tP)-t(1-t)^2P=2(1-t)((1+t)z(h)-tP). ψ 2 ( h ) 2 e ( σ ( h ) h ) = ( 1 − t 2 ) ( 2 z ( h ) − tP ) − t ( 1 − t ) 2 P = 2 ( 1 − t ) (( 1 + t ) z ( h ) − tP ) .
(b) Since θ ≡ 1 \theta\equiv1 θ ≡ 1 (mod $3$), β \beta β and γ \gamma γ are, modulo 3 3 3 , homomorphisms G ^ → O ′ / 3 \widehat{G}\to O'/3 G → O ′ /3 negated by σ \sigma σ and equal to 1 1 1 at x x x : they are multiples of v v v , equal to v / v ( x ) v/v(x) v / v ( x ) . Then z − 1 2 β γ z-\frac{1}{2}\beta\gamma z − 2 1 β γ is, modulo 3 3 3 , a homomorphism (the term γ ( h ) β ( h ′ ) − 1 2 ( β ( h ) γ ( h ′ ) + β ( h ′ ) γ ( h ) ) \gamma(h)\beta(h')-\frac{1}{2}(\beta(h)\gamma(h')+\beta(h')\gamma(h)) γ ( h ) β ( h ′ ) − 2 1 ( β ( h ) γ ( h ′ ) + β ( h ′ ) γ ( h )) vanishes modulo 3 3 3 since β ≡ γ \beta\equiv\gamma β ≡ γ invariant under σ \sigma σ ), whence a a a multiple a ′ u a'u a ′ u of u u u , and F ≡ 2 z − β γ = 2 a ′ u F\equiv2z-\beta\gamma=2a'u F ≡ 2 z − β γ = 2 a ′ u (mod 3 3 3 ). (c) If w ≥ 1 w\ge1 w ≥ 1 , then θ ≡ 1 \theta\equiv1 θ ≡ 1 (mod $9) on G ^ \widehat{G} G ; β \beta β and γ \gamma γ are, modulo 9 9 9 , homomorphisms negated by σ \sigma σ , whence lie in ( O ′ / 9 ) μ (O'/9)\mu ( O ′ /9 ) μ . □ \square □
Lemma 17 (expansion at the point M s M_s M s ). There are A ′ , B ′ A',B' A ′ , B ′ in the fraction field of O ′ O' O ′ , with v 3 ( A ′ ) ≥ 4 − w v_3(A')\ge4-w v 3 ( A ′ ) ≥ 4 − w and v 3 ( B ′ ) ≥ 5 v_3(B')\ge5 v 3 ( B ′ ) ≥ 5 , such that, for every h ∈ G ^ h\in\widehat{G} h ∈ G ,
T ( h ) − M s ( h ) ≡ A ′ λ ( h ) ( ψ 1 ( h ) − ψ 2 ( h ) ) + B ′ e ( h ) ( m o d 3 10 O ′ ) . T(h)-M_s(h)\equiv A'\lambda(h)(\psi_1(h)-\psi_2(h))+B'e(h)\pmod{3^{10}O'}. T ( h ) − M s ( h ) ≡ A ′ λ ( h ) ( ψ 1 ( h ) − ψ 2 ( h )) + B ′ e ( h ) ( mod 3 10 O ′ ) .
Proof. Let e r = λ ( ψ 1 − ψ 2 ) e_r=\lambda(\psi_1-\psi_2) e r = λ ( ψ 1 − ψ 2 ) ; it is the ε \varepsilon ε -part of the trace of ψ 1 e ε λ ⊕ ψ 2 e − ε λ \psi_1e^{\varepsilon\lambda}\oplus\psi_2e^{-\varepsilon\lambda} ψ 1 e ε λ ⊕ ψ 2 e − ε λ , which has determinant D D D , so e r e_r e r satisfies (2); it is central and invariant under σ \sigma σ . One has e ( x ) = ψ 1 ( x ) e(x)=\psi_1(x) e ( x ) = ψ 1 ( x ) , a unit; e r ( x ) = λ ( x ) ψ 2 ( x ) ( θ ( x ) − 1 ) e_r(x)=\lambda(x)\psi_2(x)(\theta(x)-1) e r ( x ) = λ ( x ) ψ 2 ( x ) ( θ ( x ) − 1 ) , of valuation 1 + w 1+w 1 + w (λ ( x ) \lambda(x) λ ( x ) is a unit since u ( x ) ≠ 0 u(x)\ne0 u ( x ) = 0 ); x y = σ ( y ) y xy=\sigma(y)y x y = σ ( y ) y and F ( y ) = − θ ( y ) F(y)=-\theta(y) F ( y ) = − θ ( y ) , hence, by Lemma 16 (a), e ( x y ) = − 2 ψ 2 ( x ) 2 θ ( x ) ( 1 − θ ( x ) ) e(xy)=-2\psi_2(x)^2\theta(x)(1-\theta(x)) e ( x y ) = − 2 ψ 2 ( x ) 2 θ ( x ) ( 1 − θ ( x )) , of valuation 1 + w 1+w 1 + w ; finally e r ( x y ) = 2 λ ( x ) ψ 2 ( x ) 2 ( θ ( x ) 2 − 1 ) e_r(xy)=2\lambda(x)\psi_2(x)^2(\theta(x)^2-1) e r ( x y ) = 2 λ ( x ) ψ 2 ( x ) 2 ( θ ( x ) 2 − 1 ) , of valuation 1 + w 1+w 1 + w . The determinant Δ = e r ( x ) e ( x y ) − e ( x ) e r ( x y ) \Delta=e_r(x)e(xy)-e(x)e_r(xy) Δ = e r ( x ) e ( x y ) − e ( x ) e r ( x y ) therefore has valuation exactly 1 + w 1+w 1 + w . Let δ = T − M s \delta=T-M_s δ = T − M s , with values in 3 5 O ′ 3^5O' 3 5 O ′ on G G G , and A ′ , B ′ A',B' A ′ , B ′ defined by A ′ e r + B ′ e = δ A'e_r+B'e=\delta A ′ e r + B ′ e = δ at x x x and at x y xy x y ; Cramer's formulas give v 3 ( A ′ ) ≥ 5 − ( 1 + w ) v_3(A')\ge5-(1+w) v 3 ( A ′ ) ≥ 5 − ( 1 + w ) and v 3 ( B ′ ) ≥ ( 5 + 1 + w ) − ( 1 + w ) v_3(B')\ge(5+1+w)-(1+w) v 3 ( B ′ ) ≥ ( 5 + 1 + w ) − ( 1 + w ) . The function L = A ′ e r + B ′ e L=A'e_r+B'e L = A ′ e r + B ′ e satisfies (2) and L ( y ) = L ( x ) = δ ( x ) = δ ( y ) L(y)=L(x)=\delta(x)=\delta(y) L ( y ) = L ( x ) = δ ( x ) = δ ( y ) (σ \sigma σ -invariance). Apply Lemma 9 to the pseudo-representation M s + ε L M_s+\varepsilon L M s + ε L (over Frac ( O ′ ) [ ε ] \operatorname{Frac}(O')[\varepsilon] Frac ( O ′ ) [ ε ] ) and to T , M s T,M_s T , M s , with x 1 = x x_1=x x 1 = x , x 2 = y x_2=y x 2 = y , x 3 = x y x_3=xy x 3 = x y and m = ( M s ( x ) , M s ( y ) , M s ( x y ) , D ( x ) , D ( y ) ) m=(M_s(x),M_s(y),M_s(xy),D(x),D(y)) m = ( M s ( x ) , M s ( y ) , M s ( x y ) , D ( x ) , D ( y )) : for every word W W W , L ( W ) = ∑ j ∂ j P W ( m ) δ ( x j ) L(W)=\sum_j\partial_jP_W(m)\,\delta(x_j) L ( W ) = ∑ j ∂ j P W ( m ) δ ( x j ) and
T ( W ) − M s ( W ) = P W ( m + ( δ ( x 1 ) , δ ( x 2 ) , δ ( x 3 ) , 0 , 0 ) ) − P W ( m ) ≡ ∑ j ∂ j P W ( m ) δ ( x j ) ( m o d 3 10 O ′ ) . T(W)-M_s(W)=P_W\bigl(m+(\delta(x_1),\delta(x_2),\delta(x_3),0,0)\bigr)-P_W(m)
\equiv\sum_j\partial_jP_W(m)\,\delta(x_j)\pmod{3^{10}O'}. T ( W ) − M s ( W ) = P W ( m + ( δ ( x 1 ) , δ ( x 2 ) , δ ( x 3 ) , 0 , 0 ) ) − P W ( m ) ≡ j ∑ ∂ j P W ( m ) δ ( x j ) ( mod 3 10 O ′ ) .
since P W P_W P W has integer coefficients, D ( x ) , D ( y ) D(x),D(y) D ( x ) , D ( y ) are units, and the Taylor coefficients of order ≥ 2 \ge2 ≥ 2 of P W P_W P W at m m m therefore lie in O ′ O' O ′ , while δ ( x j ) ∈ 3 5 O ′ \delta(x_j)\in3^5O' δ ( x j ) ∈ 3 5 O ′ . One concludes by density of the subgroup generated by x x x and y y y .
Theorem R′ (law of inert primes). Let ℓ ≡ 2 ( m o d 3 ) \ell\equiv2\pmod3 ℓ ≡ 2 ( mod 3 ) be prime and j = v 3 ( ℓ + 1 ) j=v_3(\ell+1) j = v 3 ( ℓ + 1 ) . For every eigenform f f f of level 1 1 1 and weight k k k ,
a ℓ 2 ≡ s ℓ 2 ( m o d 3 min ( 2 j + 2 , 10 ) O ) . a_\ell^2\equiv s_\ell^2\pmod{3^{\min(2j+2,10)}O}. a ℓ 2 ≡ s ℓ 2 ( mod 3 m i n ( 2 j + 2 , 10 ) O ) . In particular a ℓ 2 ≡ s ℓ 2 ( m o d 3 8 ) a_\ell^2\equiv s_\ell^2\pmod{3^8} a ℓ 2 ≡ s ℓ 2 ( mod 3 8 ) if ℓ ≡ − 1 ( m o d 27 ) \ell\equiv-1\pmod{27} ℓ ≡ − 1 ( mod 27 ) , and ( m o d 3 10 ) \pmod{3^{10}} ( mod 3 10 ) if ℓ ≡ − 1 ( m o d 81 ) \ell\equiv-1\pmod{81} ℓ ≡ − 1 ( mod 81 ) .
Proof. Let f ℓ f_\ell f ℓ be a Frobenius element at ℓ \ell ℓ and h = c f ℓ ∈ G K h=cf_\ell\in G_K h = c f ℓ ∈ G K ; then f ℓ 2 = c h c h = σ ( h ) h f_\ell^2=chch=\sigma(h)h f ℓ 2 = c h c h = σ ( h ) h , χ ( h ) = − ℓ \chi(h)=-\ell χ ( h ) = − ℓ , and T ( f ℓ 2 ) − T E ( f ℓ 2 ) = a ℓ 2 − 2 ℓ κ − ( 1 + ℓ 2 κ ) = a ℓ 2 − s ℓ 2 T(f_\ell^2)-T_E(f_\ell^2)=a_\ell^2-2\ell^\kappa-(1+\ell^{2\kappa})=a_\ell^2-s_\ell^2 T ( f ℓ 2 ) − T E ( f ℓ 2 ) = a ℓ 2 − 2 ℓ κ − ( 1 + ℓ 2 κ ) = a ℓ 2 − s ℓ 2 . One has v 3 ( λ ( h ) ) = v 3 ( log 3 ( − ℓ ) ) − 1 = j − 1 v_3(\lambda(h))=v_3(\log_3(-\ell))-1=j-1 v 3 ( λ ( h )) = v 3 ( log 3 ( − ℓ )) − 1 = j − 1 , hence v 3 ( θ ( h ) − 1 ) = j + w v_3(\theta(h)-1)=j+w v 3 ( θ ( h ) − 1 ) = j + w , v 3 ( λ ( f ℓ 2 ) ) = j − 1 v_3(\lambda(f_\ell^2))=j-1 v 3 ( λ ( f ℓ 2 )) = j − 1 and v 3 ( θ ( f ℓ 2 ) − 1 ) = j + w v_3(\theta(f_\ell^2)-1)=j+w v 3 ( θ ( f ℓ 2 ) − 1 ) = j + w ; finally u ( h ) = 0 u(h)=0 u ( h ) = 0 if and only if j ≥ 2 j\ge2 j ≥ 2 . Write T − T E = ( M s − T E ) + ( T − M s ) T-T_E=(M_s-T_E)+(T-M_s) T − T E = ( M s − T E ) + ( T − M s ) at f ℓ 2 f_\ell^2 f ℓ 2 and estimate the terms. (i) M s − T E = − ( ψ s − 1 ) ( χ κ ψ s − 1 − 1 ) M_s-T_E=-(\psi_s-1)(\chi^\kappa\psi_s^{-1}-1) M s − T E = − ( ψ s − 1 ) ( χ κ ψ s − 1 − 1 ) has valuation at least ( j + v 3 ( s ) ) + ( j + v 3 ( κ − s ) ) ≥ 2 j + 2 (j+v_3(s))+(j+v_3(\kappa-s))\ge2j+2 ( j + v 3 ( s )) + ( j + v 3 ( κ − s )) ≥ 2 j + 2 , since v 3 ( s ) ≥ 2 v_3(s)\ge2 v 3 ( s ) ≥ 2 if 3 ∤ κ 3\nmid\kappa 3 ∤ κ , and v 3 ( s ) , v 3 ( κ − s ) ≥ 1 v_3(s),v_3(\kappa-s)\ge1 v 3 ( s ) , v 3 ( κ − s ) ≥ 1 if 3 ∣ κ 3\mid\kappa 3 ∣ κ . (ii) A ′ e r ( f ℓ 2 ) A'e_r(f_\ell^2) A ′ e r ( f ℓ 2 ) has valuation at least ( 4 − w ) + ( j − 1 ) + ( j + w ) = 2 j + 3 (4-w)+(j-1)+(j+w)=2j+3 ( 4 − w ) + ( j − 1 ) + ( j + w ) = 2 j + 3 . (iii) By Lemma 16 (a), B ′ e ( f ℓ 2 ) = 2 B ′ ψ 2 ( h ) 2 ( 1 − θ ( h ) ) F ( h ) B'e(f_\ell^2)=2B'\psi_2(h)^2(1-\theta(h))F(h) B ′ e ( f ℓ 2 ) = 2 B ′ ψ 2 ( h ) 2 ( 1 − θ ( h )) F ( h ) has valuation at least 5 + j + w + v 3 ( F ( h ) ) 5+j+w+v_3(F(h)) 5 + j + w + v 3 ( F ( h )) , and v 3 ( F ( h ) ) ≥ 1 v_3(F(h))\ge1 v 3 ( F ( h )) ≥ 1 if j ≥ 2 j\ge2 j ≥ 2 by Lemma 16 (b): hence at least j + 6 ≥ min ( 2 j + 2 , 10 ) j+6\ge\min(2j+2,10) j + 6 ≥ min ( 2 j + 2 , 10 ) if j ≥ 2 j\ge2 j ≥ 2 , and at least 6 6 6 if j = 1 j=1 j = 1 . Lemma 17 concludes.
Status: PROVED. From Theorem R. For j = 1 j=1 j = 1 and j = 2 j=2 j = 2 , one recovers a ℓ 2 ≡ s ℓ 2 a_\ell^2\equiv s_\ell^2 a ℓ 2 ≡ s ℓ 2 modulo 81 81 81 and modulo 729 729 729 (Theorems O and R).
Corollary Y′ (non-vanishing, 3-adic). If k ≠ 4 ( m o d 6 ) k\ne4\pmod6 k = 4 ( mod 6 ) and if ℓ ≡ 2 ( m o d 3 ) \ell\equiv2\pmod3 ℓ ≡ 2 ( mod 3 ) is a prime with v 3 ( ℓ + 1 ) ≤ 4 v_3(\ell+1)\le4 v 3 ( ℓ + 1 ) ≤ 4 , then v 3 ( a ℓ ( f ) ) = v 3 ( ℓ + 1 ) v_3(a_\ell(f))=v_3(\ell+1) v 3 ( a ℓ ( f )) = v 3 ( ℓ + 1 ) . Consequently, if k ≠ 4 ( m o d 6 ) k\ne4\pmod6 k = 4 ( mod 6 ) , a ℓ ( f ) = 0 a_\ell(f)=0 a ℓ ( f ) = 0 implies ℓ ≡ − 1 ( m o d 2 11 ⋅ 3 5 ) \ell\equiv-1\pmod{2^{11}\cdot3^5} ℓ ≡ − 1 ( mod 2 11 ⋅ 3 5 ) .
Proof. If 3 ∤ k 3\nmid k 3 ∤ k , v 3 ( s ℓ ) = v 3 ( ℓ + 1 ) + v 3 ( κ ) = j v_3(s_\ell)=v_3(\ell+1)+v_3(\kappa)=j v 3 ( s ℓ ) = v 3 ( ℓ + 1 ) + v 3 ( κ ) = j , and Theorem R′ gives a ℓ 2 ≡ s ℓ 2 ( m o d 3 2 j + 2 ) a_\ell^2\equiv s_\ell^2\pmod{3^{2j+2}} a ℓ 2 ≡ s ℓ 2 ( mod 3 2 j + 2 ) for j ≤ 4 j\le4 j ≤ 4 , whence v 3 ( a ℓ 2 ) = 2 j v_3(a_\ell^2)=2j v 3 ( a ℓ 2 ) = 2 j . If a ℓ = 0 a_\ell=0 a ℓ = 0 , then ℓ ≠ 2 \ell\ne2 ℓ = 2 (Corollary L), ℓ ≠ 3 \ell\ne3 ℓ = 3 (Corollary Y), ℓ ≠ 1 ( m o d 3 ) \ell\ne1\pmod3 ℓ = 1 ( mod 3 ) (a ℓ ≡ s ℓ ≡ 2 ( m o d 3 ) a_\ell\equiv s_\ell\equiv2\pmod3 a ℓ ≡ s ℓ ≡ 2 ( mod 3 ) ), and, by what precedes, j ≥ 5 j\ge5 j ≥ 5 ; one concludes with Corollary Y.
Status: PROVED.
Theorem R″ (split primes). Let ℓ ≡ 1 ( m o d 27 ) \ell\equiv1\pmod{27} ℓ ≡ 1 ( mod 27 ) be a prime such that $3$ is a cube modulo ℓ \ell ℓ . For every eigenform f f f of level $1 and weight k k k , a ℓ ≡ s ℓ ( m o d 3 7 O ) a_\ell\equiv s_\ell\pmod{3^7O} a ℓ ≡ s ℓ ( mod 3 7 O ) . If moreover k ≡ 4 ( m o d 6 ) k\equiv4\pmod6 k ≡ 4 ( mod 6 ) and ℓ = X 2 + X Y + 547 Y 2 \ell=X^2+XY+547Y^2 ℓ = X 2 + X Y + 547 Y 2 (X , Y ∈ Z X,Y\in\mathbb Z X , Y ∈ Z ), then a ℓ ≡ s ℓ ( m o d 3 8 O ) a_\ell\equiv s_\ell\pmod{3^8O} a ℓ ≡ s ℓ ( mod 3 8 O ) , and ( m o d 3 9 O ) \pmod{3^9O} ( mod 3 9 O ) if ℓ ≡ 1 ( m o d 81 ) \ell\equiv1\pmod{81} ℓ ≡ 1 ( mod 81 ) .
Proof. Let h = Frob ℓ h=\operatorname{Frob}_{\ell} h = Frob ℓ , ℓ ∣ ℓ \ell\mid\ell ℓ ∣ ℓ , and n = v 3 ( λ ( h ) ) = v 3 ( ℓ − 1 ) − 1 ≥ 2 n=v_3(\lambda(h))=v_3(\ell-1)-1\ge2 n = v 3 ( λ ( h )) = v 3 ( ℓ − 1 ) − 1 ≥ 2 ; v ( h ) = 0 v(h)=0 v ( h ) = 0 , so β ( h ) , γ ( h ) ∈ 3 O ′ \beta(h),\gamma(h)\in3\mathcal{O}' β ( h ) , γ ( h ) ∈ 3 O ′ (Lemma 16(b)). (i) M s ( h ) − T E ( h ) M_s(h)-T_E(h) M s ( h ) − T E ( h ) has valuation at least ( 1 + v 3 ( s ) + n ) + ( 1 + v 3 ( κ − s ) + n ) ≥ 2 n + 4 (1+v_3(s)+n)+(1+v_3(\kappa-s)+n)\ge2n+4 ( 1 + v 3 ( s ) + n ) + ( 1 + v 3 ( κ − s ) + n ) ≥ 2 n + 4 . (ii) A e r ′ ( h ) A'_{{\rm er}}(h) A er ′ ( h ) has valuation at least ( 4 − w ) + n + ( 1 + w + n ) = 2 n + 5 (4-w)+n+(1+w+n)=2n+5 ( 4 − w ) + n + ( 1 + w + n ) = 2 n + 5 . (iii) e ( h ) = ψ 2 ( h ) ( ( 1 − θ ( h ) ) z ( h ) + θ ( h ) β ( h ) γ ( h ) ) e(h)=\psi_2(h)((1-\theta(h))z(h)+\theta(h)\beta(h)\gamma(h)) e ( h ) = ψ 2 ( h ) (( 1 − θ ( h )) z ( h ) + θ ( h ) β ( h ) γ ( h )) has valuation at least min ( 1 + w + n , 2 ) = 2 \min(1+w+n,2)=2 min ( 1 + w + n , 2 ) = 2 , so B ′ e ( h ) B'e(h) B ′ e ( h ) has valuation at least 7. Lemma 17 gives the first assertion. If k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) , then w ≥ 1 w\ge1 w ≥ 1 ; if moreover ℓ = X 2 + X Y + 547 Y 2 \ell=X^2+XY+547Y^2 ℓ = X 2 + X Y + 547 Y 2 , then μ ( h ) ∈ 9 Z 3 \mu(h)\in9\mathbb{Z}_3 μ ( h ) ∈ 9 Z 3 , so β ( h ) , γ ( h ) ∈ 9 O ′ \beta(h),\gamma(h)\in9\mathcal{O}' β ( h ) , γ ( h ) ∈ 9 O ′ by Lemma 16(c), and e ( h ) e(h) e ( h ) has valuation at least min ( 2 + n , 4 ) \min(2+n,4) min ( 2 + n , 4 ) ; the minimum of 2 n + 4 2n+4 2 n + 4 , 2 n + 5 2n+5 2 n + 5 , 5 + min ( 2 + n , 4 ) 5+\min(2+n,4) 5 + min ( 2 + n , 4 ) and 10 is 8 if n = 2 n=2 n = 2 and 9 if n ≥ 3 n\ge3 n ≥ 3 .
Status: PROVED. From Theorem R.
Remark. VERIFIED (PARI/GP, exact Newton polygons on S k S_k S k ). Inert primes , $12\le k\le 94$: the minimal depth of a ℓ 2 − s ℓ 2 a_\ell^2-s_\ell^2 a ℓ 2 − s ℓ 2 is exactly 8 for the eight primes ℓ ≡ − 1 ( m o d 27 ) \ell\equiv-1\pmod{27} ℓ ≡ − 1 ( mod 27 ) , ℓ ≢ − 1 ( m o d 81 ) \ell\not\equiv-1\pmod{81} ℓ ≡ − 1 ( mod 81 ) , ℓ < 1200 \ell<1200 ℓ < 1200 (53, 107, 269, 431, 593, 701, 863, 1187), and 10 for ℓ = 647 \ell=647 ℓ = 647 and 809 (j = 4 j=4 j = 4 ), except for k = 12 k=12 k = 12 and k = 22 k=22 k = 22 , where it is 9 and 11: the exponent 2 j + 2 2j+2 2 j + 2 is attained for j ≤ 4 j\le4 j ≤ 4 . For ℓ = 971 \ell=971 ℓ = 971 (j = 5 j=5 j = 5 ), it is 11 if k ≠ 4 ( m o d 6 ) k\ne4\pmod{6} k = 4 ( mod 6 ) (12 for k = 12 k=12 k = 12 ) and 12 if k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) (13 for $k=22): the exponent 2 j + 2 2j+2 2 j + 2 does not hold for j = 5 j=5 j = 5 , which corresponds to term (iii) of the proof. Split primes , 12 ≤ k ≤ 78 12\le k\le78 12 ≤ k ≤ 78 , for the seven primes ℓ ≡ 1 ( m o d 27 ) \ell\equiv1\pmod{27} ℓ ≡ 1 ( mod 27 ) , ℓ < 3000 \ell<3000 ℓ < 3000 , such that 3 is a cube modulo ℓ \ell ℓ (271, 757, 919, 1621, 1783, 2269, 2971): if k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) , the minimal depth of a ℓ − s ℓ a_\ell-s_\ell a ℓ − s ℓ is 7 for 271, 919, 1621, 1783, which are not of the form X 2 + X Y + 547 Y 2 X^2+XY+547Y^2 X 2 + X Y + 547 Y 2 , 8 for 757 and 2971, and 9 for 2269 (except k = 22 k=22 k = 22 , where it is larger); if k ≠ 4 ( m o d 6 ) k\ne4\pmod{6} k = 4 ( mod 6 ) , it is 7 for 757 and 2971, and at least 8 for the other five. The depth 8 for ℓ ≡ 1 ( m o d 27 ) \ell\equiv1\pmod{27} ℓ ≡ 1 ( mod 27 ) when k ≠ 4 ( m o d 6 ) k\ne4\pmod{6} k = 4 ( mod 6 ) remains OPEN : modulo 3 8 3^8 3 8 , only the term B ′ ψ 2 θ β γ B'\psi_2\theta\beta\gamma B ′ ψ 2 θ β γ of the proof can obstruct it, and β / 3 \beta/3 β /3 , γ / 3 \gamma/3 γ /3 are then characters of Gal ( E / K ( 3 3 ) ) \operatorname{Gal}(E/K(\sqrt[3]{3})) Gal ( E / K ( 3 3 )) which, unlike the case 3 ∣ κ 3\mid\kappa 3 ∣ κ (Lemma 16(c)), do not factor through Gal ( H 27 / K ) \operatorname{Gal}(H_{27}/K) Gal ( H 27 / K ) (script VERIF_INERTES.py, part A).
What remains open
Hatada’s question: SOLVED (Corollary X): affirmative answer for $6\le a\le 10$, negative for a = 11 , 12 , 13 a=11,12,13 a = 11 , 12 , 13 . “Lattice” form for $a\le 10: verified (Statement V′), not proved.
Gain in depth for ℓ ≡ ± 1 ( m o d 9 ) \ell\equiv\pm1\pmod{9} ℓ ≡ ± 1 ( mod 9 ) : PROVED in every weight (Corollary Q, Theorem R). Beyond: PROVED for inert primes up to 3 10 3^{10} 3 10 , with the optimal exponent 2 v 3 ( ℓ + 1 ) + 2 2v_3(\ell+1)+2 2 v 3 ( ℓ + 1 ) + 2 for v 3 ( ℓ + 1 ) ≤ 4 v_3(\ell+1)\le4 v 3 ( ℓ + 1 ) ≤ 4 (Theorem R′), and, for ℓ ≡ 1 ( m o d 27 ) \ell\equiv1\pmod{27} ℓ ≡ 1 ( mod 27 ) with 3 a cube, up to 3 7 3^7 3 7 , or 3 8 3^8 3 8 and 3 9 3^9 3 9 if k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) and ℓ = X 2 + X Y + 547 Y 2 \ell=X^2+XY+547Y^2 ℓ = X 2 + X Y + 547 Y 2 (Theorem R′′). OPEN : the depth 8 for ℓ ≡ 1 ( m o d 27 ) \ell\equiv1\pmod{27} ℓ ≡ 1 ( mod 27 ) when k ≠ 4 ( m o d 6 ) k\ne4\pmod{6} k = 4 ( mod 6 ) (Remark of §9), and the depths beyond 3 10 3^{10} 3 10 .
Value of a 2 ( f ) a_2(f) a 2 ( f ) modulo 27 when k ≡ 4 ( m o d 6 ) k\equiv4\pmod{6} k ≡ 4 ( mod 6 ) : there is no uniform law (Remark (3) of §6), but a 2 a_2 a 2 determines the other a ℓ a_\ell a ℓ , ℓ ≡ 2 ( m o d 3 ) \ell\equiv2\pmod{3} ℓ ≡ 2 ( mod 3 ) , by Theorem S; the possible values of a 2 ( f ) a_2(f) a 2 ( f ) modulo 81 (valuative sense) are listed, by class of k k k modulo 54, in [18 Thm 1.5 and Table 3] .
Verification
ramanujantau(12289)
F = mfeigenbasis(mfinit([1,16],1))[1]; mfcoef(F,13313)
charpoly(mfheckemat(mfinit([1,k],1),3)) (3-adic slopes of T_3)
In Sage: pari(’ramanujantau(12289)’).
Script VERIF_HATADA.py (Python, numpy only, a few seconds): self-test on known values and on the exact value of τ ( 12289 ) \tau(12289) τ ( 12289 ) ; the 24 class congruences for all odd n ≤ 2000 n \le2000 n ≤ 2000 ; the two witnesses; a scan of all primes p ≤ 13313 p \le13313 p ≤ 13313 , which shows that the smallest witness at each failing level is 12289, and that no a ≤ 10 a \le10 a ≤ 10 fails for the six forms.
Script VERIF_MOD9.py (Python only): the criteria of Theorems G and H (T 2 T_2 T 2 and T 3 T_3 T 3 ), for increasing weights until a time budget set in the file is exhausted, with self-test. With the values set in the file it covers 12 ≤ k ≤ 400 12 \le k \le400 12 ≤ k ≤ 400 in a few minutes; the range k ≤ 1000 k \le1000 k ≤ 1000 of Theorem G (494 spaces) was covered by the same certificate computed independently with FLINT and PARI/GP (Miller basis, characteristic polynomials of T 2 T_2 T 2 and T 3 T_3 T 3 , Newton polygons at 3), in about forty minutes.
Script VERIF_A3.py (Python only, a few minutes at most): the checks of Theorem F described above, with self-test on the period of Δ \Delta Δ , proportional to ( 48 , − 25 , 20 , − 25 , 48 ) (48, -25, 20, -25, 48) ( 48 , − 25 , 20 , − 25 , 48 ) , and on τ ( 3 ) = 252 \tau(3) = 252 τ ( 3 ) = 252 .
Script VERIF_A2.py (Python only, under a minute): the certificate of Lemma 6 in ( Z / 9 Z ) [ G ] (\mathbb{Z}/9\mathbb{Z})[G] ( Z /9 Z ) [ G ] (290 terms); the three certificates of Lemma 8 and the criterion of Lemma 7, which prove Theorem K; direct check of Theorems I and K on L k L_k L k for 12 ≤ k ≤ 100 12 \le k \le100 12 ≤ k ≤ 100 ; the identity of Lemma 5 on all solutions modulo 3 of the relations, and the condition of Lemma 6 on L k L_k L k , for k ≤ 40 k \le40 k ≤ 40 ; direct action of the remainders of Lemma 8 on Z [ x , y ] w \mathbb{Z}[x,y]_w Z [ x , y ] w for w ≤ 60 w \le60 w ≤ 60 , with out-of-class witnesses; self-test on the period of Δ \Delta Δ and on τ ( 2 ) = − 24 \tau(2) = -24 τ ( 2 ) = − 24 .
Script VERIF_EISENSTEIN.py (Python only, about two minutes): the nineteen certificates of Theorem N (criterion of Lemma 7, moduli 27, 81, 243), their check by direct action on Z [ x , y ] w \mathbb{Z}[x,y]_w Z [ x , y ] w , statement (i) of Theorem O for k ≤ 44 k \le44 k ≤ 44 (characteristic polynomials of T n T_n T n on L k L_k L k , n ≡ 1 ( m o d 3 ) n \equiv1 \pmod{3} n ≡ 1 ( mod 3 ) , n ≤ k n \le k n ≤ k ), and Theorems P, R, S for k ≤ 40 k \le40 k ≤ 40 and ℓ ≤ 43 \ell\le43 ℓ ≤ 43 , ℓ = 73 \ell= 73 ℓ = 73 , on L k L_k L k , with witnesses where the correction term is necessary; self-test on τ ( 2 ) \tau(2) τ ( 2 ) and τ ( 7 ) \tau(7) τ ( 7 ) .
Script VERIF_HATADA2.py (Python only, under a minute): the certificate of Lemma 13 (190 terms, criterion of Lemma 12 modulo 512), the direct action of the remainder on Z [ x , y ] w \mathbb{Z}[x,y]_w Z [ x , y ] w for w ≤ 40 w \le40 w ≤ 40 (witnesses of odd degree), the Kummer symbols in the proof of Theorem U, the five laws of that theorem on L k L_k L k for k ≤ 40 k \le40 k ≤ 40 , and the enumeration of the finite groups of Theorem W (part E; part F, heavier, is optional); self-test on τ ( 3 ) \tau(3) τ ( 3 ) and τ ( 5 ) \tau(5) τ ( 5 ) .
Script VERIF_INERTES.py (Python only, under a minute): the identities of Lemma 16 and the valuations of the system of Lemma 17 in the dual-number representation, on random words modulo 3 14 3^{14} 3 14 , with witnesses; Theorem R′ ' ′ and Corollary Y′ ' ′ on L k L_k L k for k ≤ 40 k \le40 k ≤ 40 and ℓ ∈ { 5 , 11 , 17 , 53 , 71 , 107 } \ell\in\{5,11,17,53,71,107\} ℓ ∈ { 5 , 11 , 17 , 53 , 71 , 107 } , the exponent being attained for each ℓ \ell ℓ ; Theorems R′ ' ′ , R′ ′ '' ′′ and Corollary Y′ ' ′ for the six weights of dimension 1 and all primes ℓ < 3000 \ell< 3000 ℓ < 3000 (1332 inert cases, 42 split cases), with the witnesses v 3 ( a 271 2 − s 271 2 ) = 11 v_3(a_{271}^2-s_{271}^2) = 11 v 3 ( a 271 2 − s 271 2 ) = 11 for k = 18 k = 18 k = 18 and v 3 ( a 271 − s 271 ) = 7 v_3(a_{271}-s_{271}) = 7 v 3 ( a 271 − s 271 ) = 7 for k = 16 k = 16 k = 16 ; finally the cyclicity of the Picard groups of the orders of conductor 9 and 27 in Z [ ζ 3 ] \mathbb{Z}[\zeta_3] Z [ ζ 3 ] and their consistency with the forms X 2 + X Y + 61 Y 2 X^2 + XY + 61Y^2 X 2 + X Y + 61 Y 2 , X 2 + X Y + 547 Y 2 X^2 + XY + 547Y^2 X 2 + X Y + 547 Y 2 and the cube criterion for ℓ < 20 000 \ell< 20\,000 ℓ < 20 000 ; self-test on τ ( n ) \tau(n) τ ( n ) , n ≤ 11 n \le11 n ≤ 11 .
Theorem E (PARI/GP): for 12 ≤ k ≤ 100 12 \le k \le100 12 ≤ k ≤ 100 , k ≠ 14 k \ne14 k = 14 ,
P = charpoly(mfheckemat(mfinit([1,k],1),12289)); newtonpoly(subst(P,x,x+12290),2)
contains the slope 10 if k ≡ 0 , 2 ( m o d 8 ) k \equiv0, 2 \pmod{8} k ≡ 0 , 2 ( mod 8 ) (k ≥ 16 k \ge16 k ≥ 16 ) and the slope 11 if k ≡ 4 , 6 ( m o d 8 ) k \equiv4, 6 \pmod{8} k ≡ 4 , 6 ( mod 8 ) and k ∈ { 12 } ∪ [ 28 , 100 ] k \in\{12\} \cup[28,100] k ∈ { 12 } ∪ [ 28 , 100 ] .
Check of Theorem O by Sturm’s theorem (PARI/GP): Newton polygons of charpoly ( T n − σ k − 1 ( n ) ) \operatorname{charpoly}(T_n-\sigma_{k-1}(n)) charpoly ( T n − σ k − 1 ( n )) on S k S_k S k for n ≡ 1 ( m o d 3 ) n \equiv1 \pmod{3} n ≡ 1 ( mod 3 ) , n ≤ k n \le k n ≤ k , 12 ≤ k ≤ 212 12 \le k \le212 12 ≤ k ≤ 212 ; statement (ii) on an eigenbasis embedded in Q 3 \mathbb{Q}_3 Q 3 .
Acknowledgements
Technical assistance: Claude (Anthropic).
References