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The exact multiplicity of the Wilson supercongruence in F_q[t]

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  • Anthropic Claude Opus
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Abstract

Let q = p^s with p an odd prime, and let P be a monic irreducible polynomial of degree d >= 2 in F_q[t]. The Wilson analogue F_d = -1 mod P holds for the product F_d of all nonzero polynomials of degree less than d, and Thakur proved that P is a Wilson prime, i.e. F_d = -1 mod P^2, exactly when all exponents of P are congruent to 0 or 1 mod p, in which case the congruence holds modulo P^(p-1). He asked whether it can hold modulo a higher power, and what the exact multiplicities are. Let r be the largest integer such that all exponents of P are congruent to 0 or 1 modulo p^r. We prove that the exact multiplicity m = v_P(F_d + 1) is 1 if r = 0, p^r - 1 if 1 <= r <= s, and q + 1 if r > s. In particular m <= q + 1, and the multiplicity of a Wilson prime in the numerator of the sum over i < d of 1/(t^(q^i) - t) is exactly m - 1. Examples over F_3, F_5 and F_9 show that all regimes occur. A script checks the theorem on all primes of small degree and on these examples.

Introduction

Let q=psq=p^s with pp an odd prime, A=Fq[t]A=\mathbb{F}_q[t], and [i]=tqi−t[i]=t^{q^i}-t. For a monic irreducible ℘∈A\wp\in A of degree dd let FdF_d be the product of all nonzero polynomials of degree less than dd. Then Fd≡−1(mod℘)F_d\equiv-1\pmod{\wp}, the analogue of Wilson’s theorem, and

Fd=(−1)dDdLd=(−1)d∏i=1d−1[i]qd−i−1,(1)F_d=(-1)^d\frac{D_d}{L_d}=(-1)^d\prod_{i=1}^{d-1}[i]^{q^{d-i}-1}, \tag*{(1)}

where Dd=∏i=1d−1[i]qd−iD_d=\prod_{i=1}^{d-1}[i]^{q^{d-i}} and Ld=∏i=1d−1[i]L_d=\prod_{i=1}^{d-1}[i] [2 p. 1842]. Following Thakur, ℘\wp is a Wilson prime if Fd≡−1(mod℘2)F_d\equiv-1\pmod{\wp^2}. We write

m(℘)=v℘(Fd+1)m(\wp)=v_\wp(F_d+1)

for the exact multiplicity of the Wilson congruence. For d=1d=1 one has F1=−1F_1=-1, so we assume d≥2d\geq2 throughout.

Thakur proved that ℘\wp is a Wilson prime if and only if d2℘/dt2=0d^2\wp/dt^2=0, that is, all exponents of ℘\wp are ≡0\equiv0 or 1(modp)1\pmod p, and that in this case the congruence holds modulo ℘p−1\wp^{p-1} [2 Thm. 2.9]; see also the remarks after [3 Thm. 5.1]. For the primes tp−t−at^p-t-a over Fp\mathbb{F}_p the exponent p−1p-1 was already known to be exact [1]; see also [2 Rem. 2.12]. Thakur also reported numerical data of G. Todd suggesting that p−1p-1 is exact even when qq is not prime, and noted that it was unclear whether the power can be increased [2 Rem. 2.11]. In Question (1) of the closing list of questions of [3], he asked whether, for d>1d>1 and p>2p>2, the congruence ever (or infinitely often) holds modulo a higher power, and what the exact multiplicities are.

Definition. The depth r(℘)r(\wp) is the largest integer r≥0r\geq0 such that every exponent nn with a nonzero coefficient in ℘\wp satisfies n≡0n\equiv0 or 1(modpr)1\pmod{p^r}. Since d≥2d\geq2 is an exponent of ℘\wp, the depth is finite. Equivalently, r(℘)≥ρr(\wp)\geq\rho if and only if ℘=U(tpρ)+tV(tpρ)\wp=U(t^{p^\rho})+tV(t^{p^\rho}) for some polynomials U,VU,V.

Theorem 1. Let ℘\wp be monic irreducible of degree d≥2d\geq2 in Fq[t]\mathbb{F}_q[t], q=psq=p^s, pp odd, and r=r(℘)r=r(\wp). Then

v℘(Fd+1)={1if r=0,pr−1if 1≤r≤s,q+1if r>s.v_\wp(F_d+1)= \begin{cases} 1 & \text{if } r=0,\\ p^r-1 & \text{if } 1\leq r\leq s,\\ q+1 & \text{if } r>s. \end{cases}

Thus the only possible exact multiplicities are 11, p−1p-1, p2−1p^2-1, …\ldots, q−1q-1 and q+1q+1, and the Wilson congruence never holds modulo ℘q+2\wp^{q+2}. Over Fp\mathbb{F}_p the only possible values are 11, p−1p-1 and p+1p+1. Since depth rr forces d≥prd \ge p^r, the depth is at most 1 when d<p2d < p^2, and then the value p−1p-1 of [2] is exact, in agreement with the data of [2 Rem. 2.11]. The case r=1r=1 of Lemma 4 below is [2 Thm. 2.9(iii)]. We assume pp odd, as in the question; for p=2p=2 see [2 Thm. 2.9(iv)]. The answer to the first part of the question is positive: the examples of Section 4 have multiplicity q+1q+1 for q=3,5,9q=3,5,9, and p2−1=8p^2-1=8 for q=9q=9. We do not address the infinitude of such primes.

Thakur also proved [3 Thm. 7.1] that the primes of degree dd dividing the numerator of Hd=1/[1]+⋯+1/[d−1]H_d = 1/[1] + \cdots+ 1/[d-1] are exactly the Wilson primes, with multiplicity at least p−2p-2. Theorem 1 makes this exact.

Corollary 2. If ℘\wp is a Wilson prime of degree dd and depth rr, then v℘(Hd)=pr−2v_{\wp}(H_d)=p^r-2 if r≤sr \le s and v℘(Hd)=qv_{\wp}(H_d)=q if r>sr>s. In all cases v℘(Hd)=m(℘)−1v_{\wp}(H_d)=m(\wp)-1.

Proof. Since [i]′=−1[i]'=-1 and qd−i−1≡−1(modp)q^{d-i}-1\equiv-1\pmod p, logarithmic differentiation of (1) gives Fd′=FdHdF'_d=F_dH_d. As ℘∤Fd\wp\nmid F_d, v℘(Hd)=v℘(Fd′)=v℘((Fd+1)′)v_{\wp}(H_d)=v_{\wp}(F'_d)=v_{\wp}((F_d+1)'). Write Fd+1=℘mGF_d+1=\wp^mG with ℘∤G\wp\nmid G; then (Fd+1)′=℘m−1(m℘′G+℘G′)(F_d+1)'=\wp^{m-1}(m\wp'G+\wp G'), and ℘∤℘′\wp\nmid\wp' because ℘\wp is separable. Since none of the values pr−1p^r-1, q+1q+1 is divisible by pp, the valuation is m−1m-1. The primes ℘\wp of degree dd do not divide Ld−1=[1]⋯[d−1]L_{d-1}=[1]\cdots[d-1], so v℘(Hd)v_{\wp}(H_d) is also the valuation of the numerator of HdH_d. □

Local expansion at a root

Fix ℘\wp as in Theorem 1 and a root θ\theta of ℘\wp, so that Fq(θ)=Fqd\mathbb{F}_q(\theta)=\mathbb{F}_{q^d} and θqd=θ\theta^{q^d}=\theta. Put

βi=θqi−θ(1≤i≤d−1);\beta_i=\theta^{q^i}-\theta\qquad(1\le i\le d-1);

these are nonzero, and β1,…,βd−1\beta_1,\ldots,\beta_{d-1} together with 0 are the roots of ℘(X+θ)\wp(X+\theta). For a polynomial G∈Fq[t]G\in\mathbb{F}_q[t], the Hasse derivatives G[k]G^{[k]} are defined by G(t+u)=∑kG[k](t)ukG(t+u)=\sum_k G^{[k]}(t)u^k. Since ℘\wp is separable, v℘(G)v_{\wp}(G) is the order of vanishing of GG at θ\theta, that is

v℘(G)=min⁡{k≥0:G[k](θ)≠0}.(2)v_{\wp}(G)=\min\{k\ge0:G^{[k]}(\theta)\ne0\}. \tag*{(2)}

Lemma 3. With ei=qd−i−1e_i=q^{d-i}-1,

Fd(θ+u)=(−1)d∏i=1d−1(βi−u+uqi)eiin Fqd[u].F_d(\theta+u)=(-1)^d\prod_{i=1}^{d-1}(\beta_i-u+u^{q^i})^{e_i}\qquad\text{in }\mathbb{F}_{q^d}[u].

Proof. In characteristic pp, [i](θ+u)=θqi+uqi−θ−u=βi−u+uqi[i](\theta+u)=\theta^{q^i}+u^{q^i}-\theta-u=\beta_i-u+u^{q^i}; apply (1). □

Lemma 4. Let xi=βi−1x_i=\beta_i^{-1} and let hk=hk(x1,…,xd−1)h_k=h_k(x_1,\ldots,x_{d-1}) be the complete homogeneous symmetric polynomials, so ∑k≥0hkuk=∏i(1−xiu)−1\sum_{k\ge0}h_ku^k=\prod_i(1-x_iu)^{-1}. Then

∑k≥0hkuk=℘′(θ)∑j≥1℘[j](θ)uj−1.\sum_{k\ge0}h_ku^k=\frac{\wp'(\theta)}{\sum_{j\ge1}\wp^{[j]}(\theta)u^{j-1}}.

Moreover ℘[j](θ)=0\wp^{[j]}(\theta)=0 for $2\le j\le p^r-1$, and ℘[pr](θ)≠0\wp^{[p^r]}(\theta)\ne0 if r≥1r\ge1. Consequently h1=⋯=hpr−2=0h_1=\cdots=h_{p^r-2}=0 and hpr−1≠0h_{p^r-1}\ne0 when r≥1r\ge1, and h1≠0h_1\ne0 when $r=0.

Proof. We have ℘(u+θ)=∑j℘[j](θ)uj=u∏i=1d−1(u−βi)\wp(u+\theta)=\sum_j\wp^{[j]}(\theta)u^j=u\prod_{i=1}^{d-1}(u-\beta_i), so Q(u):=∑j≥1℘[j](θ)uj−1=∏i(u−βi)Q(u):=\sum_{j\ge1}\wp^{[j]}(\theta)u^{j-1}=\prod_i(u-\beta_i) and Q(0)=℘′(θ)Q(0)=\wp'(\theta). Hence ∏i(1−xiu)=Q(u)/Q(0)\prod_i(1-x_iu)=Q(u)/Q(0), which is the first identity.

Write ℘=∑ncntn\wp=\sum_n c_nt^n, so that ℘[j]=∑n(nj)cntn−j\wp^{[j]}=\sum_n\binom{n}{j}c_nt^{n-j}. For j≥1j\ge1 this polynomial has degree less than dd, so it vanishes at θ\theta if and only if it is zero, that is, if and only if p∣(nj)p\mid\binom{n}{j} for every nn with cn≠0c_n\ne0. Let 2≤j≤pr−12\le j\le p^r-1 and cn≠0c_n\ne0. The lowest rr base-pp digits of nn are all 0, or are 1,0,…,01,0,\ldots,0; since j<prj<p^r has j≥2j\ge2, some digit of jj exceeds the corresponding digit of nn, and Lucas’ theorem gives p∣(nj)p\mid\binom{n}{j}. If r≥1r\ge1, by maximality of rr some exponent nn has n mod pr+1∉{0,1}n\bmod p^{r+1}\notin\{0,1\}; as n≡0n\equiv0 or 1(modpr)1\pmod{p^r}, its digit nrn_r is nonzero, and Lucas’ theorem gives (npr)≡nr≠0\binom{n}{p^r}\equiv n_r\ne0. Distinct nn give distinct monomials tn−prt^{n-p^r}, so ℘[pr]≠0\wp^{[p^r]}\ne0. Finally ℘′(θ)≠0\wp'(\theta)\ne0 by separability, and if r=0r=0 some exponent has n≢0,1(modp)n\not\equiv0,1\pmod p, so (n2)=n(n−1)/2≠0\binom{n}{2}=n(n-1)/2\ne0 and ℘[2](θ)≠0\wp^{[2]}(\theta)\ne0.

If r≥1r \ge1, the denominator in the first identity is ℘′(θ)(1+cupr−1+O(upr))\wp'(\theta)(1+cu^{p^r-1}+O(u^{p^r})) with c=℘[pr](θ)/℘′(θ)≠0c=\wp^{[p^r]}(\theta)/\wp'(\theta)\ne0, so the quotient is 1−cupr−1+O(upr)1-cu^{p^r-1}+O(u^{p^r}). If r=0r=0, the same computation gives h1=−℘[2](θ)/℘′(θ)≠0h_1=-\wp^{[2]}(\theta)/\wp'(\theta)\ne0.

Proof of Theorem 1

Let fk=Fd[k](θ)f_k=F_d^{[k]}(\theta), the coefficient of uku^k in Fd(θ+u)F_d(\theta+u). By (2), m=min⁡{k≥1:fk≠0}m=\min\{k\ge1:f_k\ne0\} and f0=Fd(θ)=−1f_0=F_d(\theta)=-1.

Step 1: fk=−hkf_k=-h_k for 0≤k≤q−10\le k\le q-1. Modulo uqu^q all terms uqiu^{q^i} in Lemma 3 vanish. Moreover

(βi−u)ei=(βi−u)qd−i/(βi−u)=(βiqd−i−uqd−i)/(βi−u),(\beta_i-u)^{e_i}=(\beta_i-u)^{q^{d-i}}/(\beta_i-u)=(\beta_i^{q^{d-i}}-u^{q^{d-i}})/(\beta_i-u),

and qd−i≥qq^{d-i}\ge q. Hence, modulo uqu^q,

Fd(θ+u)≡(−1)d∏i=1d−1βiqd−iβi−u=(−1)d∏i=1d−1βiei⋅∏i=1d−1(1−xiu)−1=Fd(θ)∑khkuk=−∑khkuk.F_d(\theta+u)\equiv(-1)^d\prod_{i=1}^{d-1}\frac{\beta_i^{q^{d-i}}}{\beta_i-u}=(-1)^d\prod_{i=1}^{d-1}\beta_i^{e_i}\cdot\prod_{i=1}^{d-1}(1-x_i u)^{-1}=F_d(\theta)\sum_k h_k u^k=-\sum_k h_k u^k.

Step 2: the case r≤sr\le s. If r=0r=0, Step 1 and Lemma 4 give f1=−h1≠0f_1=-h_1\ne0, so m=1m=1. If 1≤r≤s1\le r\le s, then pr−1≤q−1p^r-1\le q-1, and Step 1 with Lemma 4 gives f1=⋯=fpr−2=0f_1=\cdots=f_{p^r-2}=0 and fpr−1≠0f_{p^r-1}\ne0, so m=pr−1m=p^r-1.

Step 3: the case r>sr>s. Then pr−1≥pq−1≥q+2p^r-1\ge pq-1\ge q+2, so Lemma 4 gives h1=⋯=hq+1=0h_1=\cdots=h_{q+1}=0, and by Step 1 f1=⋯=fq−1=0f_1=\cdots=f_{q-1}=0. We compute modulo uq+2u^{q+2}. For i≥2i\ge2 the term uqiu^{q^i} vanishes, since q2≥q+2q^2\ge q+2. As in Step 1, (βi−u+δi,1uq)ei=Ni/Di(\beta_i-u+\delta_{i,1}u^q)^{e_i}=N_i/D_i with Di=βi−u+δi,1uqD_i=\beta_i-u+\delta_{i,1}u^q and Ni=Diqd−iN_i=D_i^{q^{d-i}}. Modulo uq+2u^{q+2}, Ni=βiqd−iN_i=\beta_i^{q^{d-i}} for i≤d−2i\le d-2, since qd−i≥q2q^{d-i}\ge q^2, while Nd−1=βd−1q−uqN_{d-1}=\beta_{d-1}^q-u^q; here d≥pr≥pq≥9d\ge p^r\ge pq\ge9, so the factors i=1i=1 and i=d−1i=d-1 are distinct. Hence, with y=βd−1−qy=\beta_{d-1}^{-q},

Fd(θ+u)≡−(1−yuq)11−x1u+x1uq∏i=2d−111−xiu.F_d(\theta+u)\equiv-(1-yu^q)\frac{1}{1-x_1u+x_1u^q}\prod_{i=2}^{d-1}\frac{1}{1-x_i u}.

Now (1−x1u+x1uq)−1=(1−x1u)−1−x1uq(1−x1u)−2+O(u2q)(1-x_1u+x_1u^q)^{-1}=(1-x_1u)^{-1}-x_1u^q(1-x_1u)^{-2}+O(u^{2q}), so

Fd(θ+u)≡−(1−yuq)(∑khkuk−x1uq(1−x1u)−1∑khkuk)≡−(1−yuq)(∑khkuk−x1uq(1+(x1+h1)u)).\begin{aligned} F_d(\theta+u)\equiv-(1-yu^q)\left(\sum_k h_k u^k-x_1u^q(1-x_1u)^{-1}\sum_k h_k u^k\right) \\ &\equiv-(1-yu^q)\left(\sum_k h_k u^k-x_1u^q(1+(x_1+h_1)u)\right). \end{aligned}

Reading off coefficients,

fq=−(hq−x1−y),fq+1=−(hq+1−(x1+y)h1−x12).f_q=-(h_q-x_1-y),\qquad f_{q+1}=-(h_{q+1}-(x_1+y)h_1-x_1^2).

Since θqd=θ\theta^{q^d}=\theta, we have βd−1q=θqd−θq=−β1\beta_{d-1}^q=\theta^{q^d}-\theta^q=-\beta_1, so y=−x1y=-x_1. With hq=hq+1=h1=0h_q=h_{q+1}=h_1=0 we get fq=0f_q=0 and fq+1=x12=β1−2≠0f_{q+1}=x_1^2=\beta_1^{-2}\ne0. Hence m=q+1m=q+1.

Remark 5. In Step 3 the vanishing of fqf_q depends on the identity βd−1q=−β1\beta_{d-1}^q=-\beta_1, which links the factors i=1i=1 and i=d−1i=d-1 of Lemma 3: the term −x1-x_1 coming from i=1i=1 cancels the term −y-y coming from i=d−1i=d-1.

Examples and verification

We write F9=F3[a]/(a2−a−1)\mathbb{F}_9=\mathbb{F}_3[a]/(a^2-a-1). The following polynomials are irreducible, with the stated depth and multiplicity:

qq℘\wprrregimemm
3t3−t−1t^3-t-11r≤sr\le s2
3t18−t10+1t^{18}-t^{10}+12r>sr>s4
5t5−t−1t^5-t-11r≤sr\le s4
5t51−2t50−t26+1t^{51}-2t^{50}-t^{26}+12r>sr>s6
9t3−(a+1)t−(a+1)t^3-(a+1)t-(a+1)1r≤sr\le s2
9t10+(a+1)t9+t+1t^{10}+(a+1)t^9+t+12r=sr=s8
9t54−at28+at27+at+1t^{54}-at^{28}+at^{27}+at+13r>sr>s10

Table 1.

The ancillary file verify_wilson_multiplicity.py (Python 3, no dependency, exact arithmetic in Fq[t]\mathbb{F}_q[t], about fifteen seconds) checks:

  • the product formula (1) against the definition of FdF_d over F3\mathbb{F}_3 for d=2,3d=2,3;

  • for every monic irreducible ℘\wp of degree 2≤d≤72 \le d \le7 over F3\mathbb{F}_3, 2≤d≤42 \le d \le4 over F5\mathbb{F}_5 and 2≤d≤32 \le d \le3 over F9\mathbb{F}_9 (981 primes in all): the valuation v℘(Fd+1)v_\wp(F_d+1), computed in Fq[t]\mathbb{F}_q[t] modulo a power of ℘\wp from (1), equals the value of Theorem 1, and v℘(Hd)v_\wp(H_d) equals m−1m-1 (Corollary 2);

  • for the examples above: irreducibility (Rabin’s test), the depth, and the same two valuations computed directly in Fq[t]\mathbb{F}_q[t] for the five examples of degree at most 18;

  • for all the examples, the coefficients fkf_k of Fd(θ+u)F_d(\theta+u) computed in the residue field Fq[t]/℘\mathbb{F}_q[t]/\wp from Lemma 3: the first nonzero one is fmf_m; fk=−hkf_k=-h_k for k<qk<q, with hkh_k computed from the first identity of Lemma 4; the vanishing of ℘[j](θ)\wp^{[j]}(\theta) for 2≤j≤min⁡(pr−1,q+3)2 \le j \le\min(p^r-1,q+3), and ℘[pr]≠0\wp^{[p^r]} \ne0; βd−1q=−β1\beta_{d-1}^q=-\beta_1; and, when r>sr>s, fq=0f_q=0 and fq+1=β1−2f_{q+1}=\beta_1^{-2}.

In small degree only the depths 0 and 1 occur, and the multiplicity p−1p-1 of [2] is then exact. These computations check the statements; the proofs do not depend on them.

Acknowledgement

Acknowledgement. Technical assistance: Claude (Anthropic).

ORCID 0009-0009-1526-1178

References

  1. [1][SSTT] J. Sauerberg, L. Shu, D. S. Thakur and G. Todd, Infinitude of Wilson primes for F_q[t], Acta Arith. 157 (2013), 91–100.DOI
  2. [2][Th13] D. S. Thakur, Differential characterization of Wilson primes for F_q[t], Algebra Number Theory 7 (2013), 1841–1848.
  3. [3][Th24] D. S. Thakur, Fermat–Wilson supercongruences, arithmetic derivatives and strange factorizations, J. Théor. Nombres Bordeaux 36 (2024), no. 2, 481–491, doi:10.5802/jtnb.1285; arXiv:2211.01076.DOI

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